Can't capture regex group? [duplicate]

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This question already has an answer here:

Why does my regular expression work in X but not in Y?

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I have Bash script below, trying to capture last digits of 'pingnet' but can not get a match. I verified in regex101 and my regex is correct:

pingnet="pingcount,site=DC,cur=200 total-up=988"
regex='(d+)$'
if [[ $pingnet =~ $regex ]]
then
 echo "YES"
 echo "$BASH_REMATCH[1]"
else
 echo "NOT"
 echo "$BASH_REMATCH[1]"
fi

The result of running script is NOT.

edited Jul 19 at 20:26

slmâ™¦

232k65479649

asked Jul 19 at 20:23

irom

184110

marked as duplicate by Jesse_b, slmâ™¦Â bash
Users with the Â bash badge can single-handedly close bash questions as duplicates and reopen them as needed.

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Jul 19 at 20:26

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

2

d doesn't work with bash's ERE, you need to use [0-9]
â€“Â Jesse_b
Jul 19 at 20:27

2

Maybe this will help: bash ERE regular expressions do not have the d as explained in Bash =~ regex and https://regex101.com/
â€“Â Isaac
Jul 19 at 20:32

add a commentÂ |Â

up vote
0
down vote

favorite

This question already has an answer here:

Why does my regular expression work in X but not in Y?

1 answer

I have Bash script below, trying to capture last digits of 'pingnet' but can not get a match. I verified in regex101 and my regex is correct:

pingnet="pingcount,site=DC,cur=200 total-up=988"
regex='(d+)$'
if [[ $pingnet =~ $regex ]]
then
 echo "YES"
 echo "$BASH_REMATCH[1]"
else
 echo "NOT"
 echo "$BASH_REMATCH[1]"
fi

The result of running script is NOT.

edited Jul 19 at 20:26

slmâ™¦

232k65479649

asked Jul 19 at 20:23

irom

184110

marked as duplicate by Jesse_b, slmâ™¦Â bash
Users with the Â bash badge can single-handedly close bash questions as duplicates and reopen them as needed.

StackExchange.ready(function()
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
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StackExchange.helpers.removeMessages();

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Jul 19 at 20:26

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

2

d doesn't work with bash's ERE, you need to use [0-9]
â€“Â Jesse_b
Jul 19 at 20:27

2

Maybe this will help: bash ERE regular expressions do not have the d as explained in Bash =~ regex and https://regex101.com/
â€“Â Isaac
Jul 19 at 20:32

add a commentÂ |Â

up vote
0
down vote

favorite

This question already has an answer here:

Why does my regular expression work in X but not in Y?

1 answer

I have Bash script below, trying to capture last digits of 'pingnet' but can not get a match. I verified in regex101 and my regex is correct:

pingnet="pingcount,site=DC,cur=200 total-up=988"
regex='(d+)$'
if [[ $pingnet =~ $regex ]]
then
 echo "YES"
 echo "$BASH_REMATCH[1]"
else
 echo "NOT"
 echo "$BASH_REMATCH[1]"
fi

The result of running script is NOT.

edited Jul 19 at 20:26

slmâ™¦

232k65479649

asked Jul 19 at 20:23

irom

184110

This question already has an answer here:

Why does my regular expression work in X but not in Y?

1 answer

I have Bash script below, trying to capture last digits of 'pingnet' but can not get a match. I verified in regex101 and my regex is correct:

pingnet="pingcount,site=DC,cur=200 total-up=988"
regex='(d+)$'
if [[ $pingnet =~ $regex ]]
then
 echo "YES"
 echo "$BASH_REMATCH[1]"
else
 echo "NOT"
 echo "$BASH_REMATCH[1]"
fi

The result of running script is NOT.

This question already has an answer here:

Why does my regular expression work in X but not in Y?

1 answer

edited Jul 19 at 20:26

slmâ™¦

232k65479649

asked Jul 19 at 20:23

irom

184110

edited Jul 19 at 20:26

slmâ™¦

232k65479649

edited Jul 19 at 20:26

slmâ™¦

232k65479649

edited Jul 19 at 20:26

slmâ™¦

232k65479649

asked Jul 19 at 20:23

irom

184110

asked Jul 19 at 20:23

irom

184110

asked Jul 19 at 20:23

irom

184110

marked as duplicate by Jesse_b, slmâ™¦Â bash
Users with the Â bash badge can single-handedly close bash questions as duplicates and reopen them as needed.

StackExchange.ready(function()
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$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
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StackExchange.helpers.removeMessages();

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Jul 19 at 20:26

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

marked as duplicate by Jesse_b, slmâ™¦Â bash
Users with the Â bash badge can single-handedly close bash questions as duplicates and reopen them as needed.

StackExchange.ready(function()
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();

);
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);
Jul 19 at 20:26

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

2

d doesn't work with bash's ERE, you need to use [0-9]
â€“Â Jesse_b
Jul 19 at 20:27

2

Maybe this will help: bash ERE regular expressions do not have the d as explained in Bash =~ regex and https://regex101.com/
â€“Â Isaac
Jul 19 at 20:32

add a commentÂ |Â

2

d doesn't work with bash's ERE, you need to use [0-9]
â€“Â Jesse_b
Jul 19 at 20:27

2

Maybe this will help: bash ERE regular expressions do not have the d as explained in Bash =~ regex and https://regex101.com/
â€“Â Isaac
Jul 19 at 20:32

d doesn't work with bash's ERE, you need to use [0-9]
â€“Â Jesse_b
Jul 19 at 20:27

Maybe this will help: bash ERE regular expressions do not have the d as explained in Bash =~ regex and https://regex101.com/
â€“Â Isaac
Jul 19 at 20:32

add a commentÂ |Â

1 Answer
1

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oldest

votes

up vote
3
down vote

accepted

Bash's regex syntax does not recognize d; use [[:digit:]] instead:

pingnet="pingcount,site=DC,cur=200 total-up=988"
regex='([[:digit:]]+)$'

answered Jul 19 at 20:27

Jeff Schaller

30.8k846104

add a commentÂ |Â

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
3
down vote

accepted

Bash's regex syntax does not recognize d; use [[:digit:]] instead:

pingnet="pingcount,site=DC,cur=200 total-up=988"
regex='([[:digit:]]+)$'

answered Jul 19 at 20:27

Jeff Schaller

30.8k846104

add a commentÂ |Â

up vote
3
down vote

accepted

Bash's regex syntax does not recognize d; use [[:digit:]] instead:

pingnet="pingcount,site=DC,cur=200 total-up=988"
regex='([[:digit:]]+)$'

answered Jul 19 at 20:27

Jeff Schaller

30.8k846104

add a commentÂ |Â

up vote
3
down vote

accepted

Bash's regex syntax does not recognize d; use [[:digit:]] instead:

pingnet="pingcount,site=DC,cur=200 total-up=988"
regex='([[:digit:]]+)$'

answered Jul 19 at 20:27

Jeff Schaller

30.8k846104

Bash's regex syntax does not recognize d; use [[:digit:]] instead:

pingnet="pingcount,site=DC,cur=200 total-up=988"
regex='([[:digit:]]+)$'

answered Jul 19 at 20:27

Jeff Schaller

30.8k846104

answered Jul 19 at 20:27

Jeff Schaller

30.8k846104

answered Jul 19 at 20:27

Jeff Schaller

30.8k846104

answered Jul 19 at 20:27

Jeff Schaller

30.8k846104

add a commentÂ |Â

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