Using GAWK to sum certain numbers line by line

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My lines will look as such



X 2.63766751981802 Y 1.68326762144808 Z 0 XX 2.63577810877244 YY 1.67475013544567 ZZ 0


Using GNU awk, how do I print (X-XX) + (Y-YY) on the end of every line?
Just to complicate things I need the () numbers to always be converted to plain numbers ie strip the negatives.

Looking to "mark" lines that the ending sum is greater than say 1.




sed gawk




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  • 1) format your description; 2) post the expected final result
    – RomanPerekhrest
    Apr 11 at 14:54











  • What are () numbers?
    – glenn jackman
    Apr 11 at 16:31










  • Ideally ouput would be-
    – Lance Humbert
    Apr 11 at 19:26










  • Ideally ouput would be-" X 2.63766751981802 Y 1.68326762144808 Z 0 XX 2.63577810877244 YY 1.67475013544567 ZZ 0 Q 0.010406897 Q being (2.63766751981802-2.63577810877244) + (1.68326762144808-1.67475013544567)
    – Lance Humbert
    Apr 11 at 19:32















up vote
1
down vote

favorite












My lines will look as such



X 2.63766751981802 Y 1.68326762144808 Z 0 XX 2.63577810877244 YY 1.67475013544567 ZZ 0


Using GNU awk, how do I print (X-XX) + (Y-YY) on the end of every line?
Just to complicate things I need the () numbers to always be converted to plain numbers ie strip the negatives.

Looking to "mark" lines that the ending sum is greater than say 1.




sed gawk




share|improve this question






















  • 1) format your description; 2) post the expected final result
    – RomanPerekhrest
    Apr 11 at 14:54











  • What are () numbers?
    – glenn jackman
    Apr 11 at 16:31










  • Ideally ouput would be-
    – Lance Humbert
    Apr 11 at 19:26










  • Ideally ouput would be-" X 2.63766751981802 Y 1.68326762144808 Z 0 XX 2.63577810877244 YY 1.67475013544567 ZZ 0 Q 0.010406897 Q being (2.63766751981802-2.63577810877244) + (1.68326762144808-1.67475013544567)
    – Lance Humbert
    Apr 11 at 19:32













up vote
1
down vote

favorite









up vote
1
down vote

favorite











My lines will look as such



X 2.63766751981802 Y 1.68326762144808 Z 0 XX 2.63577810877244 YY 1.67475013544567 ZZ 0


Using GNU awk, how do I print (X-XX) + (Y-YY) on the end of every line?
Just to complicate things I need the () numbers to always be converted to plain numbers ie strip the negatives.

Looking to "mark" lines that the ending sum is greater than say 1.




sed gawk




share|improve this question














My lines will look as such



X 2.63766751981802 Y 1.68326762144808 Z 0 XX 2.63577810877244 YY 1.67475013544567 ZZ 0


Using GNU awk, how do I print (X-XX) + (Y-YY) on the end of every line?
Just to complicate things I need the () numbers to always be converted to plain numbers ie strip the negatives.

Looking to "mark" lines that the ending sum is greater than say 1.





sed gawk





share|improve this question













share|improve this question




share|improve this question








edited Apr 11 at 15:22









Kusalananda

102k13199316




102k13199316










asked Apr 11 at 14:48









Lance Humbert

61




61











  • 1) format your description; 2) post the expected final result
    – RomanPerekhrest
    Apr 11 at 14:54











  • What are () numbers?
    – glenn jackman
    Apr 11 at 16:31










  • Ideally ouput would be-
    – Lance Humbert
    Apr 11 at 19:26










  • Ideally ouput would be-" X 2.63766751981802 Y 1.68326762144808 Z 0 XX 2.63577810877244 YY 1.67475013544567 ZZ 0 Q 0.010406897 Q being (2.63766751981802-2.63577810877244) + (1.68326762144808-1.67475013544567)
    – Lance Humbert
    Apr 11 at 19:32

















  • 1) format your description; 2) post the expected final result
    – RomanPerekhrest
    Apr 11 at 14:54











  • What are () numbers?
    – glenn jackman
    Apr 11 at 16:31










  • Ideally ouput would be-
    – Lance Humbert
    Apr 11 at 19:26










  • Ideally ouput would be-" X 2.63766751981802 Y 1.68326762144808 Z 0 XX 2.63577810877244 YY 1.67475013544567 ZZ 0 Q 0.010406897 Q being (2.63766751981802-2.63577810877244) + (1.68326762144808-1.67475013544567)
    – Lance Humbert
    Apr 11 at 19:32
















1) format your description; 2) post the expected final result
– RomanPerekhrest
Apr 11 at 14:54





1) format your description; 2) post the expected final result
– RomanPerekhrest
Apr 11 at 14:54













What are () numbers?
– glenn jackman
Apr 11 at 16:31




What are () numbers?
– glenn jackman
Apr 11 at 16:31












Ideally ouput would be-
– Lance Humbert
Apr 11 at 19:26




Ideally ouput would be-
– Lance Humbert
Apr 11 at 19:26












Ideally ouput would be-" X 2.63766751981802 Y 1.68326762144808 Z 0 XX 2.63577810877244 YY 1.67475013544567 ZZ 0 Q 0.010406897 Q being (2.63766751981802-2.63577810877244) + (1.68326762144808-1.67475013544567)
– Lance Humbert
Apr 11 at 19:32





Ideally ouput would be-" X 2.63766751981802 Y 1.68326762144808 Z 0 XX 2.63577810877244 YY 1.67475013544567 ZZ 0 Q 0.010406897 Q being (2.63766751981802-2.63577810877244) + (1.68326762144808-1.67475013544567)
– Lance Humbert
Apr 11 at 19:32











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$ awk ' print $0, "("$2"-"$8") + ("$4"-"$10")"' inputfile
X 2.63766751981802 Y 1.68326762144808 Z 0 XX 2.63577810877244 YY 1.67475013544567 ZZ 0 (2.63766751981802-2.63577810877244) + (1.68326762144808-1.67475013544567)





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    $ awk ' print $0, "("$2"-"$8") + ("$4"-"$10")"' inputfile
    X 2.63766751981802 Y 1.68326762144808 Z 0 XX 2.63577810877244 YY 1.67475013544567 ZZ 0 (2.63766751981802-2.63577810877244) + (1.68326762144808-1.67475013544567)





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      up vote
      0
      down vote













      $ awk ' print $0, "("$2"-"$8") + ("$4"-"$10")"' inputfile
      X 2.63766751981802 Y 1.68326762144808 Z 0 XX 2.63577810877244 YY 1.67475013544567 ZZ 0 (2.63766751981802-2.63577810877244) + (1.68326762144808-1.67475013544567)





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        $ awk ' print $0, "("$2"-"$8") + ("$4"-"$10")"' inputfile
        X 2.63766751981802 Y 1.68326762144808 Z 0 XX 2.63577810877244 YY 1.67475013544567 ZZ 0 (2.63766751981802-2.63577810877244) + (1.68326762144808-1.67475013544567)





        share|improve this answer












        $ awk ' print $0, "("$2"-"$8") + ("$4"-"$10")"' inputfile
        X 2.63766751981802 Y 1.68326762144808 Z 0 XX 2.63577810877244 YY 1.67475013544567 ZZ 0 (2.63766751981802-2.63577810877244) + (1.68326762144808-1.67475013544567)






        share|improve this answer












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        share|improve this answer










        answered Apr 11 at 16:13









        DopeGhoti

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