Match with sed between 2 different patterns [duplicate]

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Print lines between (and excluding) two patterns

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I want to catch the output between 2 different patterns, for example :

sed -n '/^pattern1/,/^pattern2/p;/^pattern2/q'

But I want to catch the output without the patterns in cause.

I know that grep -Ev will help me, but I wonder how it's done with sed.

edited Apr 10 at 9:48

Jeff Schaller

31.1k846105

asked Apr 10 at 9:32

Andrei N

marked as duplicate by don_crissti, Jeff Schaller, Kiwy, Philippos, Timothy Martin Apr 10 at 17:12

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

I don't quite understand the "without the patterns in cause" bit.
â€“Â Kusalananda
Apr 10 at 9:34

add a commentÂ |Â

up vote
0
down vote

favorite

This question already has an answer here:

Print lines between (and excluding) two patterns

3 answers

I want to catch the output between 2 different patterns, for example :

sed -n '/^pattern1/,/^pattern2/p;/^pattern2/q'

But I want to catch the output without the patterns in cause.

I know that grep -Ev will help me, but I wonder how it's done with sed.

edited Apr 10 at 9:48

Jeff Schaller

31.1k846105

asked Apr 10 at 9:32

Andrei N

marked as duplicate by don_crissti, Jeff Schaller, Kiwy, Philippos, Timothy Martin Apr 10 at 17:12

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

I don't quite understand the "without the patterns in cause" bit.
â€“Â Kusalananda
Apr 10 at 9:34

add a commentÂ |Â

up vote
0
down vote

favorite

This question already has an answer here:

Print lines between (and excluding) two patterns

3 answers

I want to catch the output between 2 different patterns, for example :

sed -n '/^pattern1/,/^pattern2/p;/^pattern2/q'

But I want to catch the output without the patterns in cause.

I know that grep -Ev will help me, but I wonder how it's done with sed.

edited Apr 10 at 9:48

Jeff Schaller

31.1k846105

asked Apr 10 at 9:32

Andrei N

This question already has an answer here:

Print lines between (and excluding) two patterns

3 answers

I want to catch the output between 2 different patterns, for example :

sed -n '/^pattern1/,/^pattern2/p;/^pattern2/q'

But I want to catch the output without the patterns in cause.

I know that grep -Ev will help me, but I wonder how it's done with sed.

This question already has an answer here:

Print lines between (and excluding) two patterns

3 answers

edited Apr 10 at 9:48

Jeff Schaller

31.1k846105

asked Apr 10 at 9:32

Andrei N

edited Apr 10 at 9:48

Jeff Schaller

31.1k846105

edited Apr 10 at 9:48

Jeff Schaller

31.1k846105

edited Apr 10 at 9:48

Jeff Schaller

31.1k846105

asked Apr 10 at 9:32

Andrei N

asked Apr 10 at 9:32

Andrei N

asked Apr 10 at 9:32

Andrei N

marked as duplicate by don_crissti, Jeff Schaller, Kiwy, Philippos, Timothy Martin Apr 10 at 17:12

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

marked as duplicate by don_crissti, Jeff Schaller, Kiwy, Philippos, Timothy Martin Apr 10 at 17:12

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

I don't quite understand the "without the patterns in cause" bit.
â€“Â Kusalananda
Apr 10 at 9:34

add a commentÂ |Â

I don't quite understand the "without the patterns in cause" bit.
â€“Â Kusalananda
Apr 10 at 9:34

I don't quite understand the "without the patterns in cause" bit.
â€“Â Kusalananda
Apr 10 at 9:34

add a commentÂ |Â

1 Answer
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You can try using awk:

awk '/^pattern1/p=1;next/^pattern2/p=0p' file

The variable p is set when the pattern pattern1 is found, and the variable is reset when the second pattern is met.

The p at the end of the script will trigger the default awk action, i.e. print the line if p==1.

answered Apr 10 at 9:46

oliv

92427

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
0
down vote

You can try using awk:

awk '/^pattern1/p=1;next/^pattern2/p=0p' file

The variable p is set when the pattern pattern1 is found, and the variable is reset when the second pattern is met.

The p at the end of the script will trigger the default awk action, i.e. print the line if p==1.

answered Apr 10 at 9:46

oliv

92427

add a commentÂ |Â

up vote
0
down vote

You can try using awk:

awk '/^pattern1/p=1;next/^pattern2/p=0p' file

The variable p is set when the pattern pattern1 is found, and the variable is reset when the second pattern is met.

The p at the end of the script will trigger the default awk action, i.e. print the line if p==1.

answered Apr 10 at 9:46

oliv

92427

add a commentÂ |Â

up vote
0
down vote

You can try using awk:

awk '/^pattern1/p=1;next/^pattern2/p=0p' file

The variable p is set when the pattern pattern1 is found, and the variable is reset when the second pattern is met.

The p at the end of the script will trigger the default awk action, i.e. print the line if p==1.

answered Apr 10 at 9:46

oliv

92427

You can try using awk:

awk '/^pattern1/p=1;next/^pattern2/p=0p' file

The variable p is set when the pattern pattern1 is found, and the variable is reset when the second pattern is met.

The p at the end of the script will trigger the default awk action, i.e. print the line if p==1.

answered Apr 10 at 9:46

oliv

92427

answered Apr 10 at 9:46

oliv

92427

answered Apr 10 at 9:46

oliv

92427

answered Apr 10 at 9:46

oliv

92427

add a commentÂ |Â

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