How to pass argument to subshell

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Is it possible to pass DBNAME argument to subshell without manually writing it?



mysqldump -u USERNAME -p DBNAME > "$(date +"%Y-%m-%d_%H-%M-%S")_DBNAME.sql"



bash shell command-line command




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  • Similar (no dupe): unix.stackexchange.com/questions/436784/…
    – Kusalananda
    Apr 10 at 17:03














up vote
0
down vote

favorite












Is it possible to pass DBNAME argument to subshell without manually writing it?



mysqldump -u USERNAME -p DBNAME > "$(date +"%Y-%m-%d_%H-%M-%S")_DBNAME.sql"



bash shell command-line command




share|improve this question




















  • Similar (no dupe): unix.stackexchange.com/questions/436784/…
    – Kusalananda
    Apr 10 at 17:03












up vote
0
down vote

favorite









up vote
0
down vote

favorite











Is it possible to pass DBNAME argument to subshell without manually writing it?



mysqldump -u USERNAME -p DBNAME > "$(date +"%Y-%m-%d_%H-%M-%S")_DBNAME.sql"



bash shell command-line command




share|improve this question












Is it possible to pass DBNAME argument to subshell without manually writing it?



mysqldump -u USERNAME -p DBNAME > "$(date +"%Y-%m-%d_%H-%M-%S")_DBNAME.sql"




bash shell command-line command





share|improve this question











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share|improve this question










asked Apr 10 at 15:15









J. Doe

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11











  • Similar (no dupe): unix.stackexchange.com/questions/436784/…
    – Kusalananda
    Apr 10 at 17:03
















  • Similar (no dupe): unix.stackexchange.com/questions/436784/…
    – Kusalananda
    Apr 10 at 17:03















Similar (no dupe): unix.stackexchange.com/questions/436784/…
– Kusalananda
Apr 10 at 17:03




Similar (no dupe): unix.stackexchange.com/questions/436784/…
– Kusalananda
Apr 10 at 17:03










1 Answer
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up vote
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There is no sub-shell here, but a command substitution (the $(...)). If DBNAME is a variable, you can use



DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" > "$(date +"%F_%H-%M-%S")_$DBNAME.sql"


or even



DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" >"$(date +"%F_%H-%M-%S_$DBNAME.sql")"


or



DBNAME=mydatabase
outfilename=$(date +"%F_%H-%M-%S_$DBNAME.sql")
mysqldump -u USERNAME -p "$DBNAME" >"$outfilename"


or variations thereof.






share|improve this answer






















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    up vote
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    There is no sub-shell here, but a command substitution (the $(...)). If DBNAME is a variable, you can use



    DBNAME=mydatabase
    mysqldump -u USERNAME -p "$DBNAME" > "$(date +"%F_%H-%M-%S")_$DBNAME.sql"


    or even



    DBNAME=mydatabase
    mysqldump -u USERNAME -p "$DBNAME" >"$(date +"%F_%H-%M-%S_$DBNAME.sql")"


    or



    DBNAME=mydatabase
    outfilename=$(date +"%F_%H-%M-%S_$DBNAME.sql")
    mysqldump -u USERNAME -p "$DBNAME" >"$outfilename"


    or variations thereof.






    share|improve this answer


























      up vote
      1
      down vote













      There is no sub-shell here, but a command substitution (the $(...)). If DBNAME is a variable, you can use



      DBNAME=mydatabase
      mysqldump -u USERNAME -p "$DBNAME" > "$(date +"%F_%H-%M-%S")_$DBNAME.sql"


      or even



      DBNAME=mydatabase
      mysqldump -u USERNAME -p "$DBNAME" >"$(date +"%F_%H-%M-%S_$DBNAME.sql")"


      or



      DBNAME=mydatabase
      outfilename=$(date +"%F_%H-%M-%S_$DBNAME.sql")
      mysqldump -u USERNAME -p "$DBNAME" >"$outfilename"


      or variations thereof.






      share|improve this answer
























        up vote
        1
        down vote










        up vote
        1
        down vote









        There is no sub-shell here, but a command substitution (the $(...)). If DBNAME is a variable, you can use



        DBNAME=mydatabase
        mysqldump -u USERNAME -p "$DBNAME" > "$(date +"%F_%H-%M-%S")_$DBNAME.sql"


        or even



        DBNAME=mydatabase
        mysqldump -u USERNAME -p "$DBNAME" >"$(date +"%F_%H-%M-%S_$DBNAME.sql")"


        or



        DBNAME=mydatabase
        outfilename=$(date +"%F_%H-%M-%S_$DBNAME.sql")
        mysqldump -u USERNAME -p "$DBNAME" >"$outfilename"


        or variations thereof.






        share|improve this answer














        There is no sub-shell here, but a command substitution (the $(...)). If DBNAME is a variable, you can use



        DBNAME=mydatabase
        mysqldump -u USERNAME -p "$DBNAME" > "$(date +"%F_%H-%M-%S")_$DBNAME.sql"


        or even



        DBNAME=mydatabase
        mysqldump -u USERNAME -p "$DBNAME" >"$(date +"%F_%H-%M-%S_$DBNAME.sql")"


        or



        DBNAME=mydatabase
        outfilename=$(date +"%F_%H-%M-%S_$DBNAME.sql")
        mysqldump -u USERNAME -p "$DBNAME" >"$outfilename"


        or variations thereof.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Apr 10 at 15:37

























        answered Apr 10 at 15:19









        Kusalananda

        102k13200317




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