How to pass argument to subshell

up vote
0
down vote

favorite

Is it possible to pass DBNAME argument to subshell without manually writing it?

mysqldump -u USERNAME -p DBNAME > "$(date +"%Y-%m-%d_%H-%M-%S")_DBNAME.sql"

asked Apr 10 at 15:15

J. Doe

Similar (no dupe): unix.stackexchange.com/questions/436784/â€¦
â€“Â Kusalananda
Apr 10 at 17:03

add a commentÂ |Â

up vote
0
down vote

favorite

Is it possible to pass DBNAME argument to subshell without manually writing it?

mysqldump -u USERNAME -p DBNAME > "$(date +"%Y-%m-%d_%H-%M-%S")_DBNAME.sql"

asked Apr 10 at 15:15

J. Doe

Similar (no dupe): unix.stackexchange.com/questions/436784/â€¦
â€“Â Kusalananda
Apr 10 at 17:03

add a commentÂ |Â

up vote
0
down vote

favorite

Is it possible to pass DBNAME argument to subshell without manually writing it?

mysqldump -u USERNAME -p DBNAME > "$(date +"%Y-%m-%d_%H-%M-%S")_DBNAME.sql"

asked Apr 10 at 15:15

J. Doe

Is it possible to pass DBNAME argument to subshell without manually writing it?

mysqldump -u USERNAME -p DBNAME > "$(date +"%Y-%m-%d_%H-%M-%S")_DBNAME.sql"

asked Apr 10 at 15:15

J. Doe

asked Apr 10 at 15:15

J. Doe

asked Apr 10 at 15:15

J. Doe

asked Apr 10 at 15:15

J. Doe

Similar (no dupe): unix.stackexchange.com/questions/436784/â€¦
â€“Â Kusalananda
Apr 10 at 17:03

add a commentÂ |Â

Similar (no dupe): unix.stackexchange.com/questions/436784/â€¦
â€“Â Kusalananda
Apr 10 at 17:03

Similar (no dupe): unix.stackexchange.com/questions/436784/â€¦
â€“Â Kusalananda
Apr 10 at 17:03

add a commentÂ |Â

1 Answer
1

active

oldest

votes

up vote
1
down vote

There is no sub-shell here, but a command substitution (the $(...)). If DBNAME is a variable, you can use

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" > "$(date +"%F_%H-%M-%S")_$DBNAME.sql"

or even

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" >"$(date +"%F_%H-%M-%S_$DBNAME.sql")"

DBNAME=mydatabase
outfilename=$(date +"%F_%H-%M-%S_$DBNAME.sql")
mysqldump -u USERNAME -p "$DBNAME" >"$outfilename"

or variations thereof.

edited Apr 10 at 15:37

answered Apr 10 at 15:19

Kusalananda

102k13200317

add a commentÂ |Â

Your Answer

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "106"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
convertImagesToLinks: false,
noModals: false,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);

);

draft saved

draft discarded

StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f436800%2fhow-to-pass-argument-to-subshell%23new-answer', 'question_page');

);

Post as a guest

Name

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
1
down vote

There is no sub-shell here, but a command substitution (the $(...)). If DBNAME is a variable, you can use

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" > "$(date +"%F_%H-%M-%S")_$DBNAME.sql"

or even

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" >"$(date +"%F_%H-%M-%S_$DBNAME.sql")"

DBNAME=mydatabase
outfilename=$(date +"%F_%H-%M-%S_$DBNAME.sql")
mysqldump -u USERNAME -p "$DBNAME" >"$outfilename"

or variations thereof.

edited Apr 10 at 15:37

answered Apr 10 at 15:19

Kusalananda

102k13200317

add a commentÂ |Â

up vote
1
down vote

There is no sub-shell here, but a command substitution (the $(...)). If DBNAME is a variable, you can use

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" > "$(date +"%F_%H-%M-%S")_$DBNAME.sql"

or even

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" >"$(date +"%F_%H-%M-%S_$DBNAME.sql")"

DBNAME=mydatabase
outfilename=$(date +"%F_%H-%M-%S_$DBNAME.sql")
mysqldump -u USERNAME -p "$DBNAME" >"$outfilename"

or variations thereof.

edited Apr 10 at 15:37

answered Apr 10 at 15:19

Kusalananda

102k13200317

add a commentÂ |Â

up vote
1
down vote

There is no sub-shell here, but a command substitution (the $(...)). If DBNAME is a variable, you can use

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" > "$(date +"%F_%H-%M-%S")_$DBNAME.sql"

or even

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" >"$(date +"%F_%H-%M-%S_$DBNAME.sql")"

DBNAME=mydatabase
outfilename=$(date +"%F_%H-%M-%S_$DBNAME.sql")
mysqldump -u USERNAME -p "$DBNAME" >"$outfilename"

or variations thereof.

edited Apr 10 at 15:37

answered Apr 10 at 15:19

Kusalananda

102k13200317

There is no sub-shell here, but a command substitution (the $(...)). If DBNAME is a variable, you can use

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" > "$(date +"%F_%H-%M-%S")_$DBNAME.sql"

or even

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" >"$(date +"%F_%H-%M-%S_$DBNAME.sql")"

DBNAME=mydatabase
outfilename=$(date +"%F_%H-%M-%S_$DBNAME.sql")
mysqldump -u USERNAME -p "$DBNAME" >"$outfilename"

or variations thereof.

edited Apr 10 at 15:37

answered Apr 10 at 15:19

Kusalananda

102k13200317

edited Apr 10 at 15:37

answered Apr 10 at 15:19

Kusalananda

102k13200317

answered Apr 10 at 15:19

Kusalananda

102k13200317

answered Apr 10 at 15:19

Kusalananda

102k13200317

add a commentÂ |Â

draft saved

draft discarded

draft saved

draft discarded

Post as a guest

Name

jO3hH 8H GmXHkh5N,RmF gvKfLHgsjCL

搜尋此網誌

mjhjmtu