How to pass argument to subshell

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Is it possible to pass DBNAME argument to subshell without manually writing it?

mysqldump -u USERNAME -p DBNAME > "$(date +"%Y-%m-%d_%H-%M-%S")_DBNAME.sql"

asked Apr 10 at 15:15

J. Doe

Similar (no dupe): unix.stackexchange.com/questions/436784/â€¦
â€“Â Kusalananda
Apr 10 at 17:03

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up vote
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down vote

favorite

Is it possible to pass DBNAME argument to subshell without manually writing it?

mysqldump -u USERNAME -p DBNAME > "$(date +"%Y-%m-%d_%H-%M-%S")_DBNAME.sql"

asked Apr 10 at 15:15

J. Doe

Similar (no dupe): unix.stackexchange.com/questions/436784/â€¦
â€“Â Kusalananda
Apr 10 at 17:03

add a commentÂ |Â

up vote
0
down vote

favorite

Is it possible to pass DBNAME argument to subshell without manually writing it?

mysqldump -u USERNAME -p DBNAME > "$(date +"%Y-%m-%d_%H-%M-%S")_DBNAME.sql"

asked Apr 10 at 15:15

J. Doe

Is it possible to pass DBNAME argument to subshell without manually writing it?

mysqldump -u USERNAME -p DBNAME > "$(date +"%Y-%m-%d_%H-%M-%S")_DBNAME.sql"

asked Apr 10 at 15:15

J. Doe

asked Apr 10 at 15:15

J. Doe

asked Apr 10 at 15:15

J. Doe

asked Apr 10 at 15:15

J. Doe

Similar (no dupe): unix.stackexchange.com/questions/436784/â€¦
â€“Â Kusalananda
Apr 10 at 17:03

add a commentÂ |Â

Similar (no dupe): unix.stackexchange.com/questions/436784/â€¦
â€“Â Kusalananda
Apr 10 at 17:03

Similar (no dupe): unix.stackexchange.com/questions/436784/â€¦
â€“Â Kusalananda
Apr 10 at 17:03

add a commentÂ |Â

1 Answer
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up vote
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There is no sub-shell here, but a command substitution (the $(...)). If DBNAME is a variable, you can use

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" > "$(date +"%F_%H-%M-%S")_$DBNAME.sql"

or even

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" >"$(date +"%F_%H-%M-%S_$DBNAME.sql")"

DBNAME=mydatabase
outfilename=$(date +"%F_%H-%M-%S_$DBNAME.sql")
mysqldump -u USERNAME -p "$DBNAME" >"$outfilename"

or variations thereof.

edited Apr 10 at 15:37

answered Apr 10 at 15:19

Kusalananda

102k13200317

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1 Answer
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active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
1
down vote

There is no sub-shell here, but a command substitution (the $(...)). If DBNAME is a variable, you can use

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" > "$(date +"%F_%H-%M-%S")_$DBNAME.sql"

or even

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" >"$(date +"%F_%H-%M-%S_$DBNAME.sql")"

DBNAME=mydatabase
outfilename=$(date +"%F_%H-%M-%S_$DBNAME.sql")
mysqldump -u USERNAME -p "$DBNAME" >"$outfilename"

or variations thereof.

edited Apr 10 at 15:37

answered Apr 10 at 15:19

Kusalananda

102k13200317

add a commentÂ |Â

up vote
1
down vote

There is no sub-shell here, but a command substitution (the $(...)). If DBNAME is a variable, you can use

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" > "$(date +"%F_%H-%M-%S")_$DBNAME.sql"

or even

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" >"$(date +"%F_%H-%M-%S_$DBNAME.sql")"

DBNAME=mydatabase
outfilename=$(date +"%F_%H-%M-%S_$DBNAME.sql")
mysqldump -u USERNAME -p "$DBNAME" >"$outfilename"

or variations thereof.

edited Apr 10 at 15:37

answered Apr 10 at 15:19

Kusalananda

102k13200317

add a commentÂ |Â

up vote
1
down vote

There is no sub-shell here, but a command substitution (the $(...)). If DBNAME is a variable, you can use

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" > "$(date +"%F_%H-%M-%S")_$DBNAME.sql"

or even

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" >"$(date +"%F_%H-%M-%S_$DBNAME.sql")"

DBNAME=mydatabase
outfilename=$(date +"%F_%H-%M-%S_$DBNAME.sql")
mysqldump -u USERNAME -p "$DBNAME" >"$outfilename"

or variations thereof.

edited Apr 10 at 15:37

answered Apr 10 at 15:19

Kusalananda

102k13200317

There is no sub-shell here, but a command substitution (the $(...)). If DBNAME is a variable, you can use

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" > "$(date +"%F_%H-%M-%S")_$DBNAME.sql"

or even

DBNAME=mydatabase
mysqldump -u USERNAME -p "$DBNAME" >"$(date +"%F_%H-%M-%S_$DBNAME.sql")"

DBNAME=mydatabase
outfilename=$(date +"%F_%H-%M-%S_$DBNAME.sql")
mysqldump -u USERNAME -p "$DBNAME" >"$outfilename"

or variations thereof.

edited Apr 10 at 15:37

answered Apr 10 at 15:19

Kusalananda

102k13200317

edited Apr 10 at 15:37

answered Apr 10 at 15:19

Kusalananda

102k13200317

answered Apr 10 at 15:19

Kusalananda

102k13200317

answered Apr 10 at 15:19

Kusalananda

102k13200317

add a commentÂ |Â

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