How to solve this syntax error of gawk (GNU awk) on OSX terminal?
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I'm using OSX terminal and trying to extract specified text of log file by regex.
awk version is
GNU Awk 4.2.1, API: 2.0 (GNU MPFR 4.0.1, GNU MP 6.1.2)
Copyright (C) 1989, 1991-2018 Free Software Foundation.
my trying operation is
$gawk '/123/ BEGINRS="DEBUG"; FS="n"print $0"n"END' ./app_108_utf8_T2.log > output.txt
but awk says
gawk: cmd. line:1: /123/ BEGINRS="DEBUG"; FS="n"print $0"n"END
gawk: cmd. line:1: ^ syntax error
Why does awk say error?
linux command-line osx
asked Apr 11 at 8:36
user74176
1125
add a comment |Â
up vote
0
down vote
favorite
I'm using OSX terminal and trying to extract specified text of log file by regex.
awk version is
GNU Awk 4.2.1, API: 2.0 (GNU MPFR 4.0.1, GNU MP 6.1.2)
Copyright (C) 1989, 1991-2018 Free Software Foundation.
my trying operation is
$gawk '/123/ BEGINRS="DEBUG"; FS="n"print $0"n"END' ./app_108_utf8_T2.log > output.txt
but awk says
gawk: cmd. line:1: /123/ BEGINRS="DEBUG"; FS="n"print $0"n"END
gawk: cmd. line:1: ^ syntax error
Why does awk say error?
linux command-line osx
asked Apr 11 at 8:36
user74176
1125
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I'm using OSX terminal and trying to extract specified text of log file by regex.
awk version is
GNU Awk 4.2.1, API: 2.0 (GNU MPFR 4.0.1, GNU MP 6.1.2)
Copyright (C) 1989, 1991-2018 Free Software Foundation.
my trying operation is
$gawk '/123/ BEGINRS="DEBUG"; FS="n"print $0"n"END' ./app_108_utf8_T2.log > output.txt
but awk says
gawk: cmd. line:1: /123/ BEGINRS="DEBUG"; FS="n"print $0"n"END
gawk: cmd. line:1: ^ syntax error
Why does awk say error?
linux command-line osx
asked Apr 11 at 8:36
user74176
1125
I'm using OSX terminal and trying to extract specified text of log file by regex.
awk version is
GNU Awk 4.2.1, API: 2.0 (GNU MPFR 4.0.1, GNU MP 6.1.2)
Copyright (C) 1989, 1991-2018 Free Software Foundation.
my trying operation is
$gawk '/123/ BEGINRS="DEBUG"; FS="n"print $0"n"END' ./app_108_utf8_T2.log > output.txt
but awk says
gawk: cmd. line:1: /123/ BEGINRS="DEBUG"; FS="n"print $0"n"END
gawk: cmd. line:1: ^ syntax error
Why does awk say error?
linux command-line osx
asked Apr 11 at 8:36
user74176
1125
asked Apr 11 at 8:36
user74176
1125
asked Apr 11 at 8:36
user74176
1125
asked Apr 11 at 8:36
user74176
1125
1125
add a comment |Â
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
3
down vote
accepted
I’m guessing you want to run
gawk 'BEGINRS="DEBUG"; FS="n" /123/print $0"n"' ./app_108_utf8_T2.log > output.txt
BEGIN defines the block of instructions which run at the start of the process, and /123/ defines the block which runs when the “123†regular expression matches the current line. You can’t specify both for a single block.
answered Apr 11 at 8:38
Stephen Kitt
140k22305365
Tangentially related: You also can't use e.g.condition && END ..., which is a pity sometimes.
– Kusalananda
Apr 11 at 8:40
@user74176 If this solves your issue, please consider accepting the answer.
– Kusalananda
Apr 11 at 8:42
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
I’m guessing you want to run
gawk 'BEGINRS="DEBUG"; FS="n" /123/print $0"n"' ./app_108_utf8_T2.log > output.txt
BEGIN defines the block of instructions which run at the start of the process, and /123/ defines the block which runs when the “123†regular expression matches the current line. You can’t specify both for a single block.
answered Apr 11 at 8:38
Stephen Kitt
140k22305365
Tangentially related: You also can't use e.g.condition && END ..., which is a pity sometimes.
– Kusalananda
Apr 11 at 8:40
@user74176 If this solves your issue, please consider accepting the answer.
– Kusalananda
Apr 11 at 8:42
add a comment |Â
up vote
3
down vote
accepted
I’m guessing you want to run
gawk 'BEGINRS="DEBUG"; FS="n" /123/print $0"n"' ./app_108_utf8_T2.log > output.txt
BEGIN defines the block of instructions which run at the start of the process, and /123/ defines the block which runs when the “123†regular expression matches the current line. You can’t specify both for a single block.
answered Apr 11 at 8:38
Stephen Kitt
140k22305365
Tangentially related: You also can't use e.g.condition && END ..., which is a pity sometimes.
– Kusalananda
Apr 11 at 8:40
@user74176 If this solves your issue, please consider accepting the answer.
– Kusalananda
Apr 11 at 8:42
add a comment |Â
up vote
3
down vote
accepted
up vote
3
down vote
accepted
I’m guessing you want to run
gawk 'BEGINRS="DEBUG"; FS="n" /123/print $0"n"' ./app_108_utf8_T2.log > output.txt
BEGIN defines the block of instructions which run at the start of the process, and /123/ defines the block which runs when the “123†regular expression matches the current line. You can’t specify both for a single block.
answered Apr 11 at 8:38
Stephen Kitt
140k22305365
I’m guessing you want to run
gawk 'BEGINRS="DEBUG"; FS="n" /123/print $0"n"' ./app_108_utf8_T2.log > output.txt
BEGIN defines the block of instructions which run at the start of the process, and /123/ defines the block which runs when the “123†regular expression matches the current line. You can’t specify both for a single block.
answered Apr 11 at 8:38
Stephen Kitt
140k22305365
answered Apr 11 at 8:38
Stephen Kitt
140k22305365
answered Apr 11 at 8:38
Stephen Kitt
140k22305365
answered Apr 11 at 8:38
Stephen Kitt
140k22305365
140k22305365
Tangentially related: You also can't use e.g.condition && END ..., which is a pity sometimes.
– Kusalananda
Apr 11 at 8:40
@user74176 If this solves your issue, please consider accepting the answer.
– Kusalananda
Apr 11 at 8:42
add a comment |Â
Tangentially related: You also can't use e.g.condition && END ..., which is a pity sometimes.
– Kusalananda
Apr 11 at 8:40
@user74176 If this solves your issue, please consider accepting the answer.
– Kusalananda
Apr 11 at 8:42
Tangentially related: You also can't use e.g.
condition && END ..., which is a pity sometimes.– Kusalananda
Apr 11 at 8:40
Tangentially related: You also can't use e.g.
condition && END ..., which is a pity sometimes.– Kusalananda
Apr 11 at 8:40
@user74176 If this solves your issue, please consider accepting the answer.
– Kusalananda
Apr 11 at 8:42
@user74176 If this solves your issue, please consider accepting the answer.
– Kusalananda
Apr 11 at 8:42
add a comment |Â
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