Use Variable Date in Sed Command

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up vote
3
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I want to use sed command as below:

$ sed -n '/MONTH_TODAY DATE_YEST/,/MONTH_TODAY DATE_TODAY/p' 
 /home/crmiib/TESTUSERLOG/XYZ/user.log

I can print logs using:

$ sed -n '/Jul 27/,/Jul 28/p' /home/crmiib/TESTUSERLOG/XYZ/user.log

But I want to view logs using variables instead of hard coded dates?

edited Jul 28 at 19:10

slmâ™¦

232k65479649

asked Jul 28 at 18:28

Hamas Rizwan

404

add a commentÂ |Â

up vote
3
down vote

favorite

I want to use sed command as below:

$ sed -n '/MONTH_TODAY DATE_YEST/,/MONTH_TODAY DATE_TODAY/p' 
 /home/crmiib/TESTUSERLOG/XYZ/user.log

I can print logs using:

$ sed -n '/Jul 27/,/Jul 28/p' /home/crmiib/TESTUSERLOG/XYZ/user.log

But I want to view logs using variables instead of hard coded dates?

edited Jul 28 at 19:10

slmâ™¦

232k65479649

asked Jul 28 at 18:28

Hamas Rizwan

404

add a commentÂ |Â

up vote
3
down vote

favorite

I want to use sed command as below:

$ sed -n '/MONTH_TODAY DATE_YEST/,/MONTH_TODAY DATE_TODAY/p' 
 /home/crmiib/TESTUSERLOG/XYZ/user.log

I can print logs using:

$ sed -n '/Jul 27/,/Jul 28/p' /home/crmiib/TESTUSERLOG/XYZ/user.log

But I want to view logs using variables instead of hard coded dates?

edited Jul 28 at 19:10

slmâ™¦

232k65479649

asked Jul 28 at 18:28

Hamas Rizwan

404

I want to use sed command as below:

$ sed -n '/MONTH_TODAY DATE_YEST/,/MONTH_TODAY DATE_TODAY/p' 
 /home/crmiib/TESTUSERLOG/XYZ/user.log

I can print logs using:

$ sed -n '/Jul 27/,/Jul 28/p' /home/crmiib/TESTUSERLOG/XYZ/user.log

But I want to view logs using variables instead of hard coded dates?

edited Jul 28 at 19:10

slmâ™¦

232k65479649

asked Jul 28 at 18:28

Hamas Rizwan

404

edited Jul 28 at 19:10

slmâ™¦

232k65479649

edited Jul 28 at 19:10

slmâ™¦

232k65479649

edited Jul 28 at 19:10

slmâ™¦

232k65479649

asked Jul 28 at 18:28

Hamas Rizwan

404

asked Jul 28 at 18:28

Hamas Rizwan

404

asked Jul 28 at 18:28

Hamas Rizwan

404

add a commentÂ |Â

1 Answer
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votes

up vote
4
down vote

accepted

Use double quotes so the shell evaluates the variables before sed runs:

DATE_YEST="Jul 27"
DATE_TODAY="Jul 28"
sed -n "/$DATE_YEST/,/$DATE_TODAY/p" /home/crmiib/TESTUSERLOG/XYZ/user.log

edited Jul 28 at 18:41

answered Jul 28 at 18:38

JRFerguson

9,06532228

Thanks Man.! :)
â€“Â Hamas Rizwan
Jul 28 at 18:59

add a commentÂ |Â

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
4
down vote

accepted

Use double quotes so the shell evaluates the variables before sed runs:

DATE_YEST="Jul 27"
DATE_TODAY="Jul 28"
sed -n "/$DATE_YEST/,/$DATE_TODAY/p" /home/crmiib/TESTUSERLOG/XYZ/user.log

edited Jul 28 at 18:41

answered Jul 28 at 18:38

JRFerguson

9,06532228

Thanks Man.! :)
â€“Â Hamas Rizwan
Jul 28 at 18:59

add a commentÂ |Â

up vote
4
down vote

accepted

Use double quotes so the shell evaluates the variables before sed runs:

DATE_YEST="Jul 27"
DATE_TODAY="Jul 28"
sed -n "/$DATE_YEST/,/$DATE_TODAY/p" /home/crmiib/TESTUSERLOG/XYZ/user.log

edited Jul 28 at 18:41

answered Jul 28 at 18:38

JRFerguson

9,06532228

Thanks Man.! :)
â€“Â Hamas Rizwan
Jul 28 at 18:59

add a commentÂ |Â

up vote
4
down vote

accepted

Use double quotes so the shell evaluates the variables before sed runs:

DATE_YEST="Jul 27"
DATE_TODAY="Jul 28"
sed -n "/$DATE_YEST/,/$DATE_TODAY/p" /home/crmiib/TESTUSERLOG/XYZ/user.log

edited Jul 28 at 18:41

answered Jul 28 at 18:38

JRFerguson

9,06532228

Use double quotes so the shell evaluates the variables before sed runs:

DATE_YEST="Jul 27"
DATE_TODAY="Jul 28"
sed -n "/$DATE_YEST/,/$DATE_TODAY/p" /home/crmiib/TESTUSERLOG/XYZ/user.log

edited Jul 28 at 18:41

answered Jul 28 at 18:38

JRFerguson

9,06532228

edited Jul 28 at 18:41

answered Jul 28 at 18:38

JRFerguson

9,06532228

answered Jul 28 at 18:38

JRFerguson

9,06532228

answered Jul 28 at 18:38

JRFerguson

9,06532228

Thanks Man.! :)
â€“Â Hamas Rizwan
Jul 28 at 18:59

add a commentÂ |Â

Thanks Man.! :)
â€“Â Hamas Rizwan
Jul 28 at 18:59

Thanks Man.! :)
â€“Â Hamas Rizwan
Jul 28 at 18:59

add a commentÂ |Â

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