mjhjmtu

In bash language, how can I define a list of paths?

I need something like below:

list_of_paths = ["$Home/MyDir/test.c", "$Home/YourDir/file.c"]

An array my be created in bash using

mypaths=( "/my/first/path" "/my/second/path" )

Elements of the array may also be assigned individually:

mypaths[0]="/my/first/path"
mypaths[1]="/my/second/path" 

Note that there should be no spaces around the =.

This is described in the section called "Arrays" in the bash manual.

Using the array:

printf 'The 1st path is %sn' "$mypaths[0]"
printf 'The 2nd path is %sn' "$mypaths[1]"

for thepath in "$mypaths[@]"; do
 # use "$thepath" here
done

Alternative for /bin/sh (will also work in bash and in a number of other sh-like shells):

set -- "/my/first/path" "/my/second/path"

printf 'The 1st path is %sn' "$1"
printf 'The 2nd path is %sn' "$2"

for thepath do
 # use "$thepath" here
done

This uses the only array there is in a /bin/sh shell, which is the list of positional parameters ($1, $2, $3, etc., or collectively $@). This list usually contains the command line arguments for the script or shell function, but can be set explicitly in a script with set.

The loop at the end may also be written

for thepath in "$@"; do
 # use "$thepath" here
done

Note that the quoting of every single variable expansion is significant.