Tar command in a bash script [closed]

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I'm using the command in a script:



tar -czf -"$fsrc"/* > ./"$fdest"/"$fname"


In a script to take user defined source folder and redirect to a user defined destination with a user defined name.



When I use the command in the terminal by itself like:



tar -czf - Documents/* >./backup/test.tar.gz


It works fine but when run in my script I get:



archive.sh: line 172: .//: Is a directory


And nothing happens.




shell-script tar




share|improve this question











closed as off-topic by roaima, DopeGhoti, Kusalananda, Jeff Schaller, steve Jun 26 at 18:10


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "Questions describing a problem that can't be reproduced and seemingly went away on its own (or went away when a typo was fixed) are off-topic as they are unlikely to help future readers." – roaima, DopeGhoti, Kusalananda, Jeff Schaller, steve
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 2




    It looks like your script is not assigning values to fdest or fname
    – steeldriver
    Jun 26 at 15:42






  • 2




    Immediately above the tar line you should consider a debugging statement such as "echo fsrc='$fsrc', fdest='$fdest', fname='$fname'" and then fix your code appropriately
    – roaima
    Jun 26 at 15:45











  • Or use set -x so that you are shown exactly what your script is trying to do before it does it. Or set -u to abort with error if trying to reference an unset variable.
    – DopeGhoti
    Jun 26 at 15:46











  • You're right my script wasn't assigning values to my variables. Fixed now. Thank you!
    – Drunkpacman
    Jun 26 at 16:04














up vote
0
down vote

favorite












I'm using the command in a script:



tar -czf -"$fsrc"/* > ./"$fdest"/"$fname"


In a script to take user defined source folder and redirect to a user defined destination with a user defined name.



When I use the command in the terminal by itself like:



tar -czf - Documents/* >./backup/test.tar.gz


It works fine but when run in my script I get:



archive.sh: line 172: .//: Is a directory


And nothing happens.




shell-script tar




share|improve this question











closed as off-topic by roaima, DopeGhoti, Kusalananda, Jeff Schaller, steve Jun 26 at 18:10


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "Questions describing a problem that can't be reproduced and seemingly went away on its own (or went away when a typo was fixed) are off-topic as they are unlikely to help future readers." – roaima, DopeGhoti, Kusalananda, Jeff Schaller, steve
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 2




    It looks like your script is not assigning values to fdest or fname
    – steeldriver
    Jun 26 at 15:42






  • 2




    Immediately above the tar line you should consider a debugging statement such as "echo fsrc='$fsrc', fdest='$fdest', fname='$fname'" and then fix your code appropriately
    – roaima
    Jun 26 at 15:45











  • Or use set -x so that you are shown exactly what your script is trying to do before it does it. Or set -u to abort with error if trying to reference an unset variable.
    – DopeGhoti
    Jun 26 at 15:46











  • You're right my script wasn't assigning values to my variables. Fixed now. Thank you!
    – Drunkpacman
    Jun 26 at 16:04












up vote
0
down vote

favorite









up vote
0
down vote

favorite











I'm using the command in a script:



tar -czf -"$fsrc"/* > ./"$fdest"/"$fname"


In a script to take user defined source folder and redirect to a user defined destination with a user defined name.



When I use the command in the terminal by itself like:



tar -czf - Documents/* >./backup/test.tar.gz


It works fine but when run in my script I get:



archive.sh: line 172: .//: Is a directory


And nothing happens.




shell-script tar




share|improve this question











I'm using the command in a script:



tar -czf -"$fsrc"/* > ./"$fdest"/"$fname"


In a script to take user defined source folder and redirect to a user defined destination with a user defined name.



When I use the command in the terminal by itself like:



tar -czf - Documents/* >./backup/test.tar.gz


It works fine but when run in my script I get:



archive.sh: line 172: .//: Is a directory


And nothing happens.





shell-script tar





share|improve this question










share|improve this question




share|improve this question









asked Jun 26 at 15:40









Drunkpacman

233




233




closed as off-topic by roaima, DopeGhoti, Kusalananda, Jeff Schaller, steve Jun 26 at 18:10


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "Questions describing a problem that can't be reproduced and seemingly went away on its own (or went away when a typo was fixed) are off-topic as they are unlikely to help future readers." – roaima, DopeGhoti, Kusalananda, Jeff Schaller, steve
If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by roaima, DopeGhoti, Kusalananda, Jeff Schaller, steve Jun 26 at 18:10


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "Questions describing a problem that can't be reproduced and seemingly went away on its own (or went away when a typo was fixed) are off-topic as they are unlikely to help future readers." – roaima, DopeGhoti, Kusalananda, Jeff Schaller, steve
If this question can be reworded to fit the rules in the help center, please edit the question.







  • 2




    It looks like your script is not assigning values to fdest or fname
    – steeldriver
    Jun 26 at 15:42






  • 2




    Immediately above the tar line you should consider a debugging statement such as "echo fsrc='$fsrc', fdest='$fdest', fname='$fname'" and then fix your code appropriately
    – roaima
    Jun 26 at 15:45











  • Or use set -x so that you are shown exactly what your script is trying to do before it does it. Or set -u to abort with error if trying to reference an unset variable.
    – DopeGhoti
    Jun 26 at 15:46











  • You're right my script wasn't assigning values to my variables. Fixed now. Thank you!
    – Drunkpacman
    Jun 26 at 16:04












  • 2




    It looks like your script is not assigning values to fdest or fname
    – steeldriver
    Jun 26 at 15:42






  • 2




    Immediately above the tar line you should consider a debugging statement such as "echo fsrc='$fsrc', fdest='$fdest', fname='$fname'" and then fix your code appropriately
    – roaima
    Jun 26 at 15:45











  • Or use set -x so that you are shown exactly what your script is trying to do before it does it. Or set -u to abort with error if trying to reference an unset variable.
    – DopeGhoti
    Jun 26 at 15:46











  • You're right my script wasn't assigning values to my variables. Fixed now. Thank you!
    – Drunkpacman
    Jun 26 at 16:04







2




2




It looks like your script is not assigning values to fdest or fname
– steeldriver
Jun 26 at 15:42




It looks like your script is not assigning values to fdest or fname
– steeldriver
Jun 26 at 15:42




2




2




Immediately above the tar line you should consider a debugging statement such as "echo fsrc='$fsrc', fdest='$fdest', fname='$fname'" and then fix your code appropriately
– roaima
Jun 26 at 15:45





Immediately above the tar line you should consider a debugging statement such as "echo fsrc='$fsrc', fdest='$fdest', fname='$fname'" and then fix your code appropriately
– roaima
Jun 26 at 15:45













Or use set -x so that you are shown exactly what your script is trying to do before it does it. Or set -u to abort with error if trying to reference an unset variable.
– DopeGhoti
Jun 26 at 15:46





Or use set -x so that you are shown exactly what your script is trying to do before it does it. Or set -u to abort with error if trying to reference an unset variable.
– DopeGhoti
Jun 26 at 15:46













You're right my script wasn't assigning values to my variables. Fixed now. Thank you!
– Drunkpacman
Jun 26 at 16:04




You're right my script wasn't assigning values to my variables. Fixed now. Thank you!
– Drunkpacman
Jun 26 at 16:04










1 Answer
1






active

oldest

votes

















up vote
2
down vote













As the comments said, my scripts wasn't assigning values to my variables. I have now fixed that. Thanks a lot!






share|improve this answer





















  • You might want to mark this as the correct answer.
    – steve
    Jun 26 at 18:01






  • 1




    It won't let me accept my own answer for another 2 days.
    – Drunkpacman
    Jun 26 at 18:09

















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
2
down vote













As the comments said, my scripts wasn't assigning values to my variables. I have now fixed that. Thanks a lot!






share|improve this answer





















  • You might want to mark this as the correct answer.
    – steve
    Jun 26 at 18:01






  • 1




    It won't let me accept my own answer for another 2 days.
    – Drunkpacman
    Jun 26 at 18:09














up vote
2
down vote













As the comments said, my scripts wasn't assigning values to my variables. I have now fixed that. Thanks a lot!






share|improve this answer





















  • You might want to mark this as the correct answer.
    – steve
    Jun 26 at 18:01






  • 1




    It won't let me accept my own answer for another 2 days.
    – Drunkpacman
    Jun 26 at 18:09












up vote
2
down vote










up vote
2
down vote









As the comments said, my scripts wasn't assigning values to my variables. I have now fixed that. Thanks a lot!






share|improve this answer













As the comments said, my scripts wasn't assigning values to my variables. I have now fixed that. Thanks a lot!







share|improve this answer













share|improve this answer



share|improve this answer











answered Jun 26 at 16:05









Drunkpacman

233




233











  • You might want to mark this as the correct answer.
    – steve
    Jun 26 at 18:01






  • 1




    It won't let me accept my own answer for another 2 days.
    – Drunkpacman
    Jun 26 at 18:09
















  • You might want to mark this as the correct answer.
    – steve
    Jun 26 at 18:01






  • 1




    It won't let me accept my own answer for another 2 days.
    – Drunkpacman
    Jun 26 at 18:09















You might want to mark this as the correct answer.
– steve
Jun 26 at 18:01




You might want to mark this as the correct answer.
– steve
Jun 26 at 18:01




1




1




It won't let me accept my own answer for another 2 days.
– Drunkpacman
Jun 26 at 18:09




It won't let me accept my own answer for another 2 days.
– Drunkpacman
Jun 26 at 18:09


-

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