get rid of multiple words using sed

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1
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I'm trying to get rid of the following input using sed:

branch
branch

not
"git
"git

That is an empty line, the term branch, not and "git. However the following line does not work:

git status 2>&1 | awk 'print $2' | sed 's/^$//g' | sed 's/^branch||^not||^changes||^"git//g'

How can I write this line correctly to get rid of all of this at once?

edited Aug 7 at 1:03

muru

128k19268458

asked Aug 6 at 21:07

user99201

1083

add a commentÂ |Â

up vote
1
down vote

favorite

I'm trying to get rid of the following input using sed:

branch
branch

not
"git
"git

That is an empty line, the term branch, not and "git. However the following line does not work:

git status 2>&1 | awk 'print $2' | sed 's/^$//g' | sed 's/^branch||^not||^changes||^"git//g'

How can I write this line correctly to get rid of all of this at once?

edited Aug 7 at 1:03

muru

128k19268458

asked Aug 6 at 21:07

user99201

1083

add a commentÂ |Â

up vote
1
down vote

favorite

I'm trying to get rid of the following input using sed:

branch
branch

not
"git
"git

That is an empty line, the term branch, not and "git. However the following line does not work:

git status 2>&1 | awk 'print $2' | sed 's/^$//g' | sed 's/^branch||^not||^changes||^"git//g'

How can I write this line correctly to get rid of all of this at once?

edited Aug 7 at 1:03

muru

128k19268458

asked Aug 6 at 21:07

user99201

1083

I'm trying to get rid of the following input using sed:

branch
branch

not
"git
"git

That is an empty line, the term branch, not and "git. However the following line does not work:

git status 2>&1 | awk 'print $2' | sed 's/^$//g' | sed 's/^branch||^not||^changes||^"git//g'

How can I write this line correctly to get rid of all of this at once?

edited Aug 7 at 1:03

muru

128k19268458

asked Aug 6 at 21:07

user99201

1083

edited Aug 7 at 1:03

muru

128k19268458

edited Aug 7 at 1:03

muru

128k19268458

edited Aug 7 at 1:03

muru

128k19268458

asked Aug 6 at 21:07

user99201

1083

asked Aug 6 at 21:07

user99201

1083

asked Aug 6 at 21:07

user99201

1083

add a commentÂ |Â

1 Answer
1

active

oldest

votes

up vote
3
down vote

accepted

The correct way of doing what you are trying to achieve:

git status --porcelain | sed s/^...//

From git help status:

--porcelain[=]

Give the output in an easy-to-parse format for scripts. This is similar to the short output.

And here is what you want to use with your commands:

Using sed:

... | sed -r '/(^"git|^branch|^not|^$)/d'

Using grep:

... | grep -Ev '^branch|^not|^"git|^$'

Which returns file names from your git and awk command.

edited Aug 6 at 21:32

answered Aug 6 at 21:18

Ravexina

24.5k136185

That is REALLY helpful. Thank you!
â€“Â user99201
Aug 6 at 21:39

@user99201 You're welcome ;)
â€“Â Ravexina
Aug 6 at 21:41

add a commentÂ |Â

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
3
down vote

accepted

The correct way of doing what you are trying to achieve:

git status --porcelain | sed s/^...//

From git help status:

--porcelain[=]

Give the output in an easy-to-parse format for scripts. This is similar to the short output.

And here is what you want to use with your commands:

Using sed:

... | sed -r '/(^"git|^branch|^not|^$)/d'

Using grep:

... | grep -Ev '^branch|^not|^"git|^$'

Which returns file names from your git and awk command.

edited Aug 6 at 21:32

answered Aug 6 at 21:18

Ravexina

24.5k136185

That is REALLY helpful. Thank you!
â€“Â user99201
Aug 6 at 21:39

@user99201 You're welcome ;)
â€“Â Ravexina
Aug 6 at 21:41

add a commentÂ |Â

up vote
3
down vote

accepted

The correct way of doing what you are trying to achieve:

git status --porcelain | sed s/^...//

From git help status:

--porcelain[=]

Give the output in an easy-to-parse format for scripts. This is similar to the short output.

And here is what you want to use with your commands:

Using sed:

... | sed -r '/(^"git|^branch|^not|^$)/d'

Using grep:

... | grep -Ev '^branch|^not|^"git|^$'

Which returns file names from your git and awk command.

edited Aug 6 at 21:32

answered Aug 6 at 21:18

Ravexina

24.5k136185

That is REALLY helpful. Thank you!
â€“Â user99201
Aug 6 at 21:39

@user99201 You're welcome ;)
â€“Â Ravexina
Aug 6 at 21:41

add a commentÂ |Â

up vote
3
down vote

accepted

The correct way of doing what you are trying to achieve:

git status --porcelain | sed s/^...//

From git help status:

--porcelain[=]

Give the output in an easy-to-parse format for scripts. This is similar to the short output.

And here is what you want to use with your commands:

Using sed:

... | sed -r '/(^"git|^branch|^not|^$)/d'

Using grep:

... | grep -Ev '^branch|^not|^"git|^$'

Which returns file names from your git and awk command.

edited Aug 6 at 21:32

answered Aug 6 at 21:18

Ravexina

24.5k136185

The correct way of doing what you are trying to achieve:

git status --porcelain | sed s/^...//

From git help status:

--porcelain[=]

Give the output in an easy-to-parse format for scripts. This is similar to the short output.

And here is what you want to use with your commands:

Using sed:

... | sed -r '/(^"git|^branch|^not|^$)/d'

Using grep:

... | grep -Ev '^branch|^not|^"git|^$'

Which returns file names from your git and awk command.

edited Aug 6 at 21:32

answered Aug 6 at 21:18

Ravexina

24.5k136185

edited Aug 6 at 21:32

answered Aug 6 at 21:18

Ravexina

24.5k136185

answered Aug 6 at 21:18

Ravexina

24.5k136185

answered Aug 6 at 21:18

Ravexina

24.5k136185

That is REALLY helpful. Thank you!
â€“Â user99201
Aug 6 at 21:39

@user99201 You're welcome ;)
â€“Â Ravexina
Aug 6 at 21:41

add a commentÂ |Â

That is REALLY helpful. Thank you!
â€“Â user99201
Aug 6 at 21:39

@user99201 You're welcome ;)
â€“Â Ravexina
Aug 6 at 21:41

That is REALLY helpful. Thank you!
â€“Â user99201
Aug 6 at 21:39

@user99201 You're welcome ;)
â€“Â Ravexina
Aug 6 at 21:41

add a commentÂ |Â

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