mjhjmtu

Now here is the commit id 41f9f4e392ab50db264e0328de7d69f1f10646eb, I want to get this commit id code which were modified only.

I use git show 41f9f4e392ab50db264e0328de7d69f1f10646eb to see modified files, how can I download these both after modified and before modified version via Linux git command? In a word, I just want to compare the differences from before and after commit id 41f9f4e392ab50db264e0328de7d69f1f10646eb to merge code easily.

Any idea will be helpful, thanks in advance.

To see the state of files before and after a given commit, check out its parent:

git checkout 41f9f4e3~1

then the commit itself:

git checkout 41f9f4e3

However, it’s hardly ever necessary to look at details of a change in this way. In your case, to apply a commit to another branch, cherry pick it:

git checkout $target_branch
git cherry-pick -x 41f9f4e3

(replacing $target_branch as appropriate). The -x option adds a comment in the commit message with the origin of the cherry-pick.

Thanks all, I have found the correct way, here it is.

#!/bin/bash
from_id=$1
to_id=$2
#echo $from_id
#echo $to_id
diffpath='patch/diff.log'
newpath='patch/new/'
oldpath='patch/old/'
rm -rf patch
mkdir -p $newpath
mkdir -p $oldpath
git diff $from_id $to_id --raw > $diffpath
cat $diffpath | while read line
do 
 #echo =====================================
 #echo $line
 OLD_IFS="$IFS"
 IFS=" "
 arr=($line)
 IFS="$OLD_IFS" 
 #echo $arr[4]
 filepath=$arr[4]##* 
 #echo $filepath
 newid=$arr[2]%%...
 #echo $newid
 oldid=$arr[3]%%...
 #echo $oldid 

 if [ "$newid"x != "0000000"x ]; then 
 newfilepath=$newpath$filepath
 echo $newfilepath
 dirpath=$newfilepath%/*
 echo $dirpath
 mkdir -p $dirpath
 git cat-file -p $newid > $newfilepath
 fi

 if [ "$oldid"x != "0000000"x ]; then 
 oldfilepath=$oldpath$filepath 
 echo $oldfilepath
 dirpath=$oldfilepath%/*
 echo $dirpath 
 mkdir -p $dirpath
 git cat-file -p $oldid > $oldfilepath
 fi 
done 

You will found the new directory named patch in current working directory after doing this.