How can I strip out a numeric prefix from multiple filenames?
Clash Royale CLAN TAG#URR8PPP
up vote
1
down vote
favorite
1
I am new to Unix. I have >2000 files which are named like
123-FILENAME_TEXT_M101K_20150929.CSV
where 123 can be any three or four-digit number. The files are all within the same directory. I would like a script that removes the prefixing number and the dash. (i.e. the leading 123- should be removed from the example name)
I have tried mv **-FILENAME* FILENAME*.rename is not an available function
Any advice would be greatly appreciated.
rename mv
edited Jan 31 at 14:35
ilkkachu
49.8k674137
asked Jan 31 at 14:22
Kim
84
add a comment |Â
up vote
1
down vote
favorite
1
I am new to Unix. I have >2000 files which are named like
123-FILENAME_TEXT_M101K_20150929.CSV
where 123 can be any three or four-digit number. The files are all within the same directory. I would like a script that removes the prefixing number and the dash. (i.e. the leading 123- should be removed from the example name)
I have tried mv **-FILENAME* FILENAME*.rename is not an available function
Any advice would be greatly appreciated.
rename mv
edited Jan 31 at 14:35
ilkkachu
49.8k674137
asked Jan 31 at 14:22
Kim
84
add a comment |Â
up vote
1
down vote
favorite
1
up vote
1
down vote
favorite
1
1
I am new to Unix. I have >2000 files which are named like
123-FILENAME_TEXT_M101K_20150929.CSV
where 123 can be any three or four-digit number. The files are all within the same directory. I would like a script that removes the prefixing number and the dash. (i.e. the leading 123- should be removed from the example name)
I have tried mv **-FILENAME* FILENAME*.rename is not an available function
Any advice would be greatly appreciated.
rename mv
edited Jan 31 at 14:35
ilkkachu
49.8k674137
asked Jan 31 at 14:22
Kim
84
I am new to Unix. I have >2000 files which are named like
123-FILENAME_TEXT_M101K_20150929.CSV
where 123 can be any three or four-digit number. The files are all within the same directory. I would like a script that removes the prefixing number and the dash. (i.e. the leading 123- should be removed from the example name)
I have tried mv **-FILENAME* FILENAME*.rename is not an available function
Any advice would be greatly appreciated.
rename mv
edited Jan 31 at 14:35
ilkkachu
49.8k674137
asked Jan 31 at 14:22
Kim
84
edited Jan 31 at 14:35
ilkkachu
49.8k674137
edited Jan 31 at 14:35
ilkkachu
49.8k674137
edited Jan 31 at 14:35
ilkkachu
49.8k674137
49.8k674137
asked Jan 31 at 14:22
Kim
84
asked Jan 31 at 14:22
Kim
84
asked Jan 31 at 14:22
Kim
84
84
add a comment |Â
add a comment |Â
2 Answers
2
active
oldest
votes
up vote
4
down vote
accepted
You could try something like this, it will remove everything before the first -
for file in *-*.CSV
do
newName="$file#*-"
mv -- "$file" "$newName"
done
edited Jan 31 at 14:51
Jeff Schaller
31.4k846105
answered Jan 31 at 14:32
mmoisse
584
1
The assignment is actually one of the few places that don't need the quotes (unless you use an unquoted$*there in Bash; It's had a bunch of bugs with that)
– ilkkachu
Jan 31 at 14:42
Quotes are indeed a source of bug, but I didn't know that it was not needed on assignment. Tx
– mmoisse
Jan 31 at 14:45
1
Quotes won't harm anyway. To clarify @ilkkachu's comment, in the case of bash'svar=$*, it's the absence of quotes that cause problems.
– Stéphane Chazelas
Jan 31 at 15:12
Sorry I am a bit stuck, I have tried running this as a shell script but getting bad substitution - any ideas where I am going wrong?
– Kim
Jan 31 at 15:41
Solved, I was running as a .sh rather than .bash, even thou in my script I had #!/bin/bash. Any all work now tysm
– Kim
Jan 31 at 15:56
add a comment |Â
up vote
0
down vote
I have tried by using combination of sed,awk and find . Tested and working fine
find . -type f -iname "*.CSV"| sed "s/^.///g"| sed -n '/^[0-9]4/p' | awk -F "-" 'print "mv" " " $0 " " $2'| sh
answered Jan 31 at 19:18
Praveen Kumar BS
1,010128
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
4
down vote
accepted
You could try something like this, it will remove everything before the first -
for file in *-*.CSV
do
newName="$file#*-"
mv -- "$file" "$newName"
done
edited Jan 31 at 14:51
Jeff Schaller
31.4k846105
answered Jan 31 at 14:32
mmoisse
584
1
The assignment is actually one of the few places that don't need the quotes (unless you use an unquoted$*there in Bash; It's had a bunch of bugs with that)
– ilkkachu
Jan 31 at 14:42
Quotes are indeed a source of bug, but I didn't know that it was not needed on assignment. Tx
– mmoisse
Jan 31 at 14:45
1
Quotes won't harm anyway. To clarify @ilkkachu's comment, in the case of bash'svar=$*, it's the absence of quotes that cause problems.
– Stéphane Chazelas
Jan 31 at 15:12
Sorry I am a bit stuck, I have tried running this as a shell script but getting bad substitution - any ideas where I am going wrong?
– Kim
Jan 31 at 15:41
Solved, I was running as a .sh rather than .bash, even thou in my script I had #!/bin/bash. Any all work now tysm
– Kim
Jan 31 at 15:56
add a comment |Â
up vote
4
down vote
accepted
You could try something like this, it will remove everything before the first -
for file in *-*.CSV
do
newName="$file#*-"
mv -- "$file" "$newName"
done
edited Jan 31 at 14:51
Jeff Schaller
31.4k846105
answered Jan 31 at 14:32
mmoisse
584
1
The assignment is actually one of the few places that don't need the quotes (unless you use an unquoted$*there in Bash; It's had a bunch of bugs with that)
– ilkkachu
Jan 31 at 14:42
Quotes are indeed a source of bug, but I didn't know that it was not needed on assignment. Tx
– mmoisse
Jan 31 at 14:45
1
Quotes won't harm anyway. To clarify @ilkkachu's comment, in the case of bash'svar=$*, it's the absence of quotes that cause problems.
– Stéphane Chazelas
Jan 31 at 15:12
Sorry I am a bit stuck, I have tried running this as a shell script but getting bad substitution - any ideas where I am going wrong?
– Kim
Jan 31 at 15:41
Solved, I was running as a .sh rather than .bash, even thou in my script I had #!/bin/bash. Any all work now tysm
– Kim
Jan 31 at 15:56
add a comment |Â
up vote
4
down vote
accepted
up vote
4
down vote
accepted
You could try something like this, it will remove everything before the first -
for file in *-*.CSV
do
newName="$file#*-"
mv -- "$file" "$newName"
done
edited Jan 31 at 14:51
Jeff Schaller
31.4k846105
answered Jan 31 at 14:32
mmoisse
584
You could try something like this, it will remove everything before the first -
for file in *-*.CSV
do
newName="$file#*-"
mv -- "$file" "$newName"
done
edited Jan 31 at 14:51
Jeff Schaller
31.4k846105
answered Jan 31 at 14:32
mmoisse
584
edited Jan 31 at 14:51
Jeff Schaller
31.4k846105
edited Jan 31 at 14:51
Jeff Schaller
31.4k846105
edited Jan 31 at 14:51
Jeff Schaller
31.4k846105
31.4k846105
answered Jan 31 at 14:32
mmoisse
584
answered Jan 31 at 14:32
mmoisse
584
answered Jan 31 at 14:32
mmoisse
584
584
1
The assignment is actually one of the few places that don't need the quotes (unless you use an unquoted$*there in Bash; It's had a bunch of bugs with that)
– ilkkachu
Jan 31 at 14:42
Quotes are indeed a source of bug, but I didn't know that it was not needed on assignment. Tx
– mmoisse
Jan 31 at 14:45
1
Quotes won't harm anyway. To clarify @ilkkachu's comment, in the case of bash'svar=$*, it's the absence of quotes that cause problems.
– Stéphane Chazelas
Jan 31 at 15:12
Sorry I am a bit stuck, I have tried running this as a shell script but getting bad substitution - any ideas where I am going wrong?
– Kim
Jan 31 at 15:41
Solved, I was running as a .sh rather than .bash, even thou in my script I had #!/bin/bash. Any all work now tysm
– Kim
Jan 31 at 15:56
add a comment |Â
1
The assignment is actually one of the few places that don't need the quotes (unless you use an unquoted$*there in Bash; It's had a bunch of bugs with that)
– ilkkachu
Jan 31 at 14:42
Quotes are indeed a source of bug, but I didn't know that it was not needed on assignment. Tx
– mmoisse
Jan 31 at 14:45
1
Quotes won't harm anyway. To clarify @ilkkachu's comment, in the case of bash'svar=$*, it's the absence of quotes that cause problems.
– Stéphane Chazelas
Jan 31 at 15:12
Sorry I am a bit stuck, I have tried running this as a shell script but getting bad substitution - any ideas where I am going wrong?
– Kim
Jan 31 at 15:41
Solved, I was running as a .sh rather than .bash, even thou in my script I had #!/bin/bash. Any all work now tysm
– Kim
Jan 31 at 15:56
1
1
The assignment is actually one of the few places that don't need the quotes (unless you use an unquoted
$* there in Bash; It's had a bunch of bugs with that)– ilkkachu
Jan 31 at 14:42
The assignment is actually one of the few places that don't need the quotes (unless you use an unquoted
$* there in Bash; It's had a bunch of bugs with that)– ilkkachu
Jan 31 at 14:42
Quotes are indeed a source of bug, but I didn't know that it was not needed on assignment. Tx
– mmoisse
Jan 31 at 14:45
Quotes are indeed a source of bug, but I didn't know that it was not needed on assignment. Tx
– mmoisse
Jan 31 at 14:45
1
1
Quotes won't harm anyway. To clarify @ilkkachu's comment, in the case of bash's
var=$*, it's the absence of quotes that cause problems.– Stéphane Chazelas
Jan 31 at 15:12
Quotes won't harm anyway. To clarify @ilkkachu's comment, in the case of bash's
var=$*, it's the absence of quotes that cause problems.– Stéphane Chazelas
Jan 31 at 15:12
Sorry I am a bit stuck, I have tried running this as a shell script but getting bad substitution - any ideas where I am going wrong?
– Kim
Jan 31 at 15:41
Sorry I am a bit stuck, I have tried running this as a shell script but getting bad substitution - any ideas where I am going wrong?
– Kim
Jan 31 at 15:41
Solved, I was running as a .sh rather than .bash, even thou in my script I had #!/bin/bash. Any all work now tysm
– Kim
Jan 31 at 15:56
Solved, I was running as a .sh rather than .bash, even thou in my script I had #!/bin/bash. Any all work now tysm
– Kim
Jan 31 at 15:56
add a comment |Â
up vote
0
down vote
I have tried by using combination of sed,awk and find . Tested and working fine
find . -type f -iname "*.CSV"| sed "s/^.///g"| sed -n '/^[0-9]4/p' | awk -F "-" 'print "mv" " " $0 " " $2'| sh
answered Jan 31 at 19:18
Praveen Kumar BS
1,010128
add a comment |Â
up vote
0
down vote
I have tried by using combination of sed,awk and find . Tested and working fine
find . -type f -iname "*.CSV"| sed "s/^.///g"| sed -n '/^[0-9]4/p' | awk -F "-" 'print "mv" " " $0 " " $2'| sh
answered Jan 31 at 19:18
Praveen Kumar BS
1,010128
add a comment |Â
up vote
0
down vote
up vote
0
down vote
I have tried by using combination of sed,awk and find . Tested and working fine
find . -type f -iname "*.CSV"| sed "s/^.///g"| sed -n '/^[0-9]4/p' | awk -F "-" 'print "mv" " " $0 " " $2'| sh
answered Jan 31 at 19:18
Praveen Kumar BS
1,010128
I have tried by using combination of sed,awk and find . Tested and working fine
find . -type f -iname "*.CSV"| sed "s/^.///g"| sed -n '/^[0-9]4/p' | awk -F "-" 'print "mv" " " $0 " " $2'| sh
answered Jan 31 at 19:18
Praveen Kumar BS
1,010128
answered Jan 31 at 19:18
Praveen Kumar BS
1,010128
answered Jan 31 at 19:18
Praveen Kumar BS
1,010128
answered Jan 31 at 19:18
Praveen Kumar BS
1,010128
1,010128
add a comment |Â
add a comment |Â
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