Replacing 3 or more digits with equivalent number of *
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3
I want to replace any 3 or more digit string in a text file with equivalent number of *.For example: abc-1234-45 --> abc-****-45
echo "abc-1234-45" | sed 's/[0-9]3,/*/'
I tried this but it only replaces it with one *.
regular-expression
edited Mar 9 at 13:24
Rui F Ribeiro
41.9k1483142
asked Apr 8 '14 at 17:35
Raghavender KaviRaghavender Kavi
162
add a comment |
3
I want to replace any 3 or more digit string in a text file with equivalent number of *.For example: abc-1234-45 --> abc-****-45
echo "abc-1234-45" | sed 's/[0-9]3,/*/'
I tried this but it only replaces it with one *.
regular-expression
edited Mar 9 at 13:24
Rui F Ribeiro
41.9k1483142
asked Apr 8 '14 at 17:35
Raghavender KaviRaghavender Kavi
162
add a comment |
3
3
3
I want to replace any 3 or more digit string in a text file with equivalent number of *.For example: abc-1234-45 --> abc-****-45
echo "abc-1234-45" | sed 's/[0-9]3,/*/'
I tried this but it only replaces it with one *.
regular-expression
edited Mar 9 at 13:24
Rui F Ribeiro
41.9k1483142
asked Apr 8 '14 at 17:35
Raghavender KaviRaghavender Kavi
162
I want to replace any 3 or more digit string in a text file with equivalent number of *.For example: abc-1234-45 --> abc-****-45
echo "abc-1234-45" | sed 's/[0-9]3,/*/'
I tried this but it only replaces it with one *.
regular-expression
regular-expression
edited Mar 9 at 13:24
Rui F Ribeiro
41.9k1483142
asked Apr 8 '14 at 17:35
Raghavender KaviRaghavender Kavi
162
edited Mar 9 at 13:24
Rui F Ribeiro
41.9k1483142
asked Apr 8 '14 at 17:35
Raghavender KaviRaghavender Kavi
162
edited Mar 9 at 13:24
Rui F Ribeiro
41.9k1483142
edited Mar 9 at 13:24
Rui F Ribeiro
41.9k1483142
edited Mar 9 at 13:24
Rui F Ribeiro
41.9k1483142
41.9k1483142
asked Apr 8 '14 at 17:35
Raghavender KaviRaghavender Kavi
162
asked Apr 8 '14 at 17:35
Raghavender KaviRaghavender Kavi
162
asked Apr 8 '14 at 17:35
Raghavender KaviRaghavender Kavi
162
162
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
3
You can use perl:
$ echo "abc-1234-45" | perl -pe 's/(d3,)/"*" x length($1)/eg'
abc-****-45
/e flag causes perl evaluate the right side as an expression before replacing.
answered Apr 8 '14 at 17:46
cuonglmcuonglm
106k25211308
Thank you. Is this not possible insedorawk- I mean evaluating string as an expression before replacing?
– user64746
Apr 9 '14 at 5:58
@RaghavenderKavi AFAIK,sedandawkcan't.
– cuonglm
Apr 9 '14 at 6:44
add a comment |
0
GNU awk
echo 'abc-1234-45' |
awk --re-interval -v RS='[[:digit:]]3,' 'gsub(/[[:digit:]]/, "*", RT);
printf "%s%s", $0, RT'
abc-****-45
Or if you are willing to look at Python
echo 'abc-1234-45' | python -c 'import re; import sys; print re.sub(r"d3,",
lambda x: len(x.group())*"*", sys.stdin.readline().strip())'
answered Apr 9 '14 at 12:15
iruvariruvar
12.2k63062
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
You can use perl:
$ echo "abc-1234-45" | perl -pe 's/(d3,)/"*" x length($1)/eg'
abc-****-45
/e flag causes perl evaluate the right side as an expression before replacing.
answered Apr 8 '14 at 17:46
cuonglmcuonglm
106k25211308
Thank you. Is this not possible insedorawk- I mean evaluating string as an expression before replacing?
– user64746
Apr 9 '14 at 5:58
@RaghavenderKavi AFAIK,sedandawkcan't.
– cuonglm
Apr 9 '14 at 6:44
add a comment |
3
You can use perl:
$ echo "abc-1234-45" | perl -pe 's/(d3,)/"*" x length($1)/eg'
abc-****-45
/e flag causes perl evaluate the right side as an expression before replacing.
answered Apr 8 '14 at 17:46
cuonglmcuonglm
106k25211308
Thank you. Is this not possible insedorawk- I mean evaluating string as an expression before replacing?
– user64746
Apr 9 '14 at 5:58
@RaghavenderKavi AFAIK,sedandawkcan't.
– cuonglm
Apr 9 '14 at 6:44
add a comment |
3
3
3
You can use perl:
$ echo "abc-1234-45" | perl -pe 's/(d3,)/"*" x length($1)/eg'
abc-****-45
/e flag causes perl evaluate the right side as an expression before replacing.
answered Apr 8 '14 at 17:46
cuonglmcuonglm
106k25211308
You can use perl:
$ echo "abc-1234-45" | perl -pe 's/(d3,)/"*" x length($1)/eg'
abc-****-45
/e flag causes perl evaluate the right side as an expression before replacing.
answered Apr 8 '14 at 17:46
cuonglmcuonglm
106k25211308
edited Apr 8 '14 at 17:51
answered Apr 8 '14 at 17:46
cuonglmcuonglm
106k25211308
answered Apr 8 '14 at 17:46
cuonglmcuonglm
106k25211308
answered Apr 8 '14 at 17:46
cuonglmcuonglm
106k25211308
106k25211308
Thank you. Is this not possible insedorawk- I mean evaluating string as an expression before replacing?
– user64746
Apr 9 '14 at 5:58
@RaghavenderKavi AFAIK,sedandawkcan't.
– cuonglm
Apr 9 '14 at 6:44
add a comment |
Thank you. Is this not possible insedorawk- I mean evaluating string as an expression before replacing?
– user64746
Apr 9 '14 at 5:58
@RaghavenderKavi AFAIK,sedandawkcan't.
– cuonglm
Apr 9 '14 at 6:44
Thank you. Is this not possible in
sed or awk - I mean evaluating string as an expression before replacing?– user64746
Apr 9 '14 at 5:58
Thank you. Is this not possible in
sed or awk - I mean evaluating string as an expression before replacing?– user64746
Apr 9 '14 at 5:58
@RaghavenderKavi AFAIK,
sed and awk can't.– cuonglm
Apr 9 '14 at 6:44
@RaghavenderKavi AFAIK,
sed and awk can't.– cuonglm
Apr 9 '14 at 6:44
add a comment |
0
GNU awk
echo 'abc-1234-45' |
awk --re-interval -v RS='[[:digit:]]3,' 'gsub(/[[:digit:]]/, "*", RT);
printf "%s%s", $0, RT'
abc-****-45
Or if you are willing to look at Python
echo 'abc-1234-45' | python -c 'import re; import sys; print re.sub(r"d3,",
lambda x: len(x.group())*"*", sys.stdin.readline().strip())'
answered Apr 9 '14 at 12:15
iruvariruvar
12.2k63062
add a comment |
0
GNU awk
echo 'abc-1234-45' |
awk --re-interval -v RS='[[:digit:]]3,' 'gsub(/[[:digit:]]/, "*", RT);
printf "%s%s", $0, RT'
abc-****-45
Or if you are willing to look at Python
echo 'abc-1234-45' | python -c 'import re; import sys; print re.sub(r"d3,",
lambda x: len(x.group())*"*", sys.stdin.readline().strip())'
answered Apr 9 '14 at 12:15
iruvariruvar
12.2k63062
add a comment |
0
0
0
GNU awk
echo 'abc-1234-45' |
awk --re-interval -v RS='[[:digit:]]3,' 'gsub(/[[:digit:]]/, "*", RT);
printf "%s%s", $0, RT'
abc-****-45
Or if you are willing to look at Python
echo 'abc-1234-45' | python -c 'import re; import sys; print re.sub(r"d3,",
lambda x: len(x.group())*"*", sys.stdin.readline().strip())'
answered Apr 9 '14 at 12:15
iruvariruvar
12.2k63062
GNU awk
echo 'abc-1234-45' |
awk --re-interval -v RS='[[:digit:]]3,' 'gsub(/[[:digit:]]/, "*", RT);
printf "%s%s", $0, RT'
abc-****-45
Or if you are willing to look at Python
echo 'abc-1234-45' | python -c 'import re; import sys; print re.sub(r"d3,",
lambda x: len(x.group())*"*", sys.stdin.readline().strip())'
answered Apr 9 '14 at 12:15
iruvariruvar
12.2k63062
edited Apr 9 '14 at 12:30
answered Apr 9 '14 at 12:15
iruvariruvar
12.2k63062
answered Apr 9 '14 at 12:15
iruvariruvar
12.2k63062
answered Apr 9 '14 at 12:15
iruvariruvar
12.2k63062
12.2k63062
add a comment |
add a comment |
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