list files in ascending order

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-1















I am trying to display file names(with complete path) based on the created timestamp in ascending order.
if files exists: display files with complete directory path in asc order.
if files do not exists: display nothing.



But first line in output displays "total xxxx". (I don't want this one)



ls -ltr /dir1/subdir1 | awk 'print $9'









share|improve this question
























  • Thank you. would it be possible to get the list line by line.

    – sunshine737
    Jun 2 '15 at 16:24











  • ls -1trd /dir1/subdir1/*. Try man ls

    – Stéphane Chazelas
    Jun 2 '15 at 16:26

















-1















I am trying to display file names(with complete path) based on the created timestamp in ascending order.
if files exists: display files with complete directory path in asc order.
if files do not exists: display nothing.



But first line in output displays "total xxxx". (I don't want this one)



ls -ltr /dir1/subdir1 | awk 'print $9'









share|improve this question
























  • Thank you. would it be possible to get the list line by line.

    – sunshine737
    Jun 2 '15 at 16:24











  • ls -1trd /dir1/subdir1/*. Try man ls

    – Stéphane Chazelas
    Jun 2 '15 at 16:26













-1












-1








-1








I am trying to display file names(with complete path) based on the created timestamp in ascending order.
if files exists: display files with complete directory path in asc order.
if files do not exists: display nothing.



But first line in output displays "total xxxx". (I don't want this one)



ls -ltr /dir1/subdir1 | awk 'print $9'









share|improve this question
















I am trying to display file names(with complete path) based on the created timestamp in ascending order.
if files exists: display files with complete directory path in asc order.
if files do not exists: display nothing.



But first line in output displays "total xxxx". (I don't want this one)



ls -ltr /dir1/subdir1 | awk 'print $9'






ls






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 9 at 13:29









Rui F Ribeiro

41.9k1483142




41.9k1483142










asked Jun 2 '15 at 15:49









sunshine737sunshine737

8125




8125












  • Thank you. would it be possible to get the list line by line.

    – sunshine737
    Jun 2 '15 at 16:24











  • ls -1trd /dir1/subdir1/*. Try man ls

    – Stéphane Chazelas
    Jun 2 '15 at 16:26

















  • Thank you. would it be possible to get the list line by line.

    – sunshine737
    Jun 2 '15 at 16:24











  • ls -1trd /dir1/subdir1/*. Try man ls

    – Stéphane Chazelas
    Jun 2 '15 at 16:26
















Thank you. would it be possible to get the list line by line.

– sunshine737
Jun 2 '15 at 16:24





Thank you. would it be possible to get the list line by line.

– sunshine737
Jun 2 '15 at 16:24













ls -1trd /dir1/subdir1/*. Try man ls

– Stéphane Chazelas
Jun 2 '15 at 16:26





ls -1trd /dir1/subdir1/*. Try man ls

– Stéphane Chazelas
Jun 2 '15 at 16:26










1 Answer
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0














You don't need the -l option to make ls sort by modification time.



To remove the “total …” line, pipe through tail -n +2 (start printing at the second line, i.e. skip the first line).



ls -tr /dir/subdir1 | tail -n +2


Note that this uses the modification time, not the creation time. Most unix variants don't store the creation time, and anyway it's a dubious concept (there's an ambiguity between modifying a file, and creating a new file which is moved on top of the existing one).






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    1 Answer
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    1 Answer
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    active

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    active

    oldest

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    0














    You don't need the -l option to make ls sort by modification time.



    To remove the “total …” line, pipe through tail -n +2 (start printing at the second line, i.e. skip the first line).



    ls -tr /dir/subdir1 | tail -n +2


    Note that this uses the modification time, not the creation time. Most unix variants don't store the creation time, and anyway it's a dubious concept (there's an ambiguity between modifying a file, and creating a new file which is moved on top of the existing one).






    share|improve this answer



























      0














      You don't need the -l option to make ls sort by modification time.



      To remove the “total …” line, pipe through tail -n +2 (start printing at the second line, i.e. skip the first line).



      ls -tr /dir/subdir1 | tail -n +2


      Note that this uses the modification time, not the creation time. Most unix variants don't store the creation time, and anyway it's a dubious concept (there's an ambiguity between modifying a file, and creating a new file which is moved on top of the existing one).






      share|improve this answer

























        0












        0








        0







        You don't need the -l option to make ls sort by modification time.



        To remove the “total …” line, pipe through tail -n +2 (start printing at the second line, i.e. skip the first line).



        ls -tr /dir/subdir1 | tail -n +2


        Note that this uses the modification time, not the creation time. Most unix variants don't store the creation time, and anyway it's a dubious concept (there's an ambiguity between modifying a file, and creating a new file which is moved on top of the existing one).






        share|improve this answer













        You don't need the -l option to make ls sort by modification time.



        To remove the “total …” line, pipe through tail -n +2 (start printing at the second line, i.e. skip the first line).



        ls -tr /dir/subdir1 | tail -n +2


        Note that this uses the modification time, not the creation time. Most unix variants don't store the creation time, and anyway it's a dubious concept (there's an ambiguity between modifying a file, and creating a new file which is moved on top of the existing one).







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jun 4 '15 at 0:08









        GillesGilles

        546k12911111624




        546k12911111624



























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