How to replace single quotes and &apos in a file

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0















I am trying to replace single quotes in a file and I used the command as
sed /s/'//g filename and this command works fine but I have &apos character also in my file and which is not getting replaced. Can I use below code



sed "/s/'//g" -e '/s/&apos//g' filename









share|improve this question
























  • Why not try the code and see what happens? If it works, great... if it doesn't post the error here and people will be happy to help.

    – Munir
    Jan 13 '16 at 18:29











  • Try sed "s/'//g" -e 's/&apos//g'

    – Costas
    Jan 13 '16 at 18:53











  • You probably want to search for ' (with the semicolon)

    – glenn jackman
    Jan 13 '16 at 19:10

















0















I am trying to replace single quotes in a file and I used the command as
sed /s/'//g filename and this command works fine but I have &apos character also in my file and which is not getting replaced. Can I use below code



sed "/s/'//g" -e '/s/&apos//g' filename









share|improve this question
























  • Why not try the code and see what happens? If it works, great... if it doesn't post the error here and people will be happy to help.

    – Munir
    Jan 13 '16 at 18:29











  • Try sed "s/'//g" -e 's/&apos//g'

    – Costas
    Jan 13 '16 at 18:53











  • You probably want to search for ' (with the semicolon)

    – glenn jackman
    Jan 13 '16 at 19:10













0












0








0








I am trying to replace single quotes in a file and I used the command as
sed /s/'//g filename and this command works fine but I have &apos character also in my file and which is not getting replaced. Can I use below code



sed "/s/'//g" -e '/s/&apos//g' filename









share|improve this question
















I am trying to replace single quotes in a file and I used the command as
sed /s/'//g filename and this command works fine but I have &apos character also in my file and which is not getting replaced. Can I use below code



sed "/s/'//g" -e '/s/&apos//g' filename






bash shell shell-script






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share|improve this question













share|improve this question




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edited Mar 9 at 12:17









Rui F Ribeiro

41.9k1483142




41.9k1483142










asked Jan 13 '16 at 18:16









AzharAzhar

116




116












  • Why not try the code and see what happens? If it works, great... if it doesn't post the error here and people will be happy to help.

    – Munir
    Jan 13 '16 at 18:29











  • Try sed "s/'//g" -e 's/&apos//g'

    – Costas
    Jan 13 '16 at 18:53











  • You probably want to search for ' (with the semicolon)

    – glenn jackman
    Jan 13 '16 at 19:10

















  • Why not try the code and see what happens? If it works, great... if it doesn't post the error here and people will be happy to help.

    – Munir
    Jan 13 '16 at 18:29











  • Try sed "s/'//g" -e 's/&apos//g'

    – Costas
    Jan 13 '16 at 18:53











  • You probably want to search for ' (with the semicolon)

    – glenn jackman
    Jan 13 '16 at 19:10
















Why not try the code and see what happens? If it works, great... if it doesn't post the error here and people will be happy to help.

– Munir
Jan 13 '16 at 18:29





Why not try the code and see what happens? If it works, great... if it doesn't post the error here and people will be happy to help.

– Munir
Jan 13 '16 at 18:29













Try sed "s/'//g" -e 's/&apos//g'

– Costas
Jan 13 '16 at 18:53





Try sed "s/'//g" -e 's/&apos//g'

– Costas
Jan 13 '16 at 18:53













You probably want to search for ' (with the semicolon)

– glenn jackman
Jan 13 '16 at 19:10





You probably want to search for ' (with the semicolon)

– glenn jackman
Jan 13 '16 at 19:10










1 Answer
1






active

oldest

votes


















1














You seem to have a stray leading forward slash in your sed command:



sed "/s/'//g"


should be:



sed "s/'//g"


If you want multiple expressions, just use -e for both of them (here I'm assuming with Glenn Jackman that you want ' instead of just &apos):



sed -e "s/'//g" -e "s/'//g" filename





share|improve this answer























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    1 Answer
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    active

    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    You seem to have a stray leading forward slash in your sed command:



    sed "/s/'//g"


    should be:



    sed "s/'//g"


    If you want multiple expressions, just use -e for both of them (here I'm assuming with Glenn Jackman that you want ' instead of just &apos):



    sed -e "s/'//g" -e "s/'//g" filename





    share|improve this answer



























      1














      You seem to have a stray leading forward slash in your sed command:



      sed "/s/'//g"


      should be:



      sed "s/'//g"


      If you want multiple expressions, just use -e for both of them (here I'm assuming with Glenn Jackman that you want ' instead of just &apos):



      sed -e "s/'//g" -e "s/'//g" filename





      share|improve this answer

























        1












        1








        1







        You seem to have a stray leading forward slash in your sed command:



        sed "/s/'//g"


        should be:



        sed "s/'//g"


        If you want multiple expressions, just use -e for both of them (here I'm assuming with Glenn Jackman that you want ' instead of just &apos):



        sed -e "s/'//g" -e "s/'//g" filename





        share|improve this answer













        You seem to have a stray leading forward slash in your sed command:



        sed "/s/'//g"


        should be:



        sed "s/'//g"


        If you want multiple expressions, just use -e for both of them (here I'm assuming with Glenn Jackman that you want ' instead of just &apos):



        sed -e "s/'//g" -e "s/'//g" filename






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 13 '16 at 19:45









        Jeff SchallerJeff Schaller

        44.7k1163145




        44.7k1163145



























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