Help Me simplify: C*(A+B) + ~A*B
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$begingroup$
I know the answer is AC + ~AB, but how?
I have tried:
B(~A+C) + AC and stop.
Also, I have tried:
AC + BC + ~AB and have stopped.
There seems nowhere to go in either case.
digital-logic electrical
edited Mar 3 at 3:36
phuclv
385210
asked Mar 1 at 18:32
Ronaldinho10Ronaldinho10
143
$endgroup$
add a comment |
$begingroup$
I know the answer is AC + ~AB, but how?
I have tried:
B(~A+C) + AC and stop.
Also, I have tried:
AC + BC + ~AB and have stopped.
There seems nowhere to go in either case.
digital-logic electrical
edited Mar 3 at 3:36
phuclv
385210
asked Mar 1 at 18:32
Ronaldinho10Ronaldinho10
143
$endgroup$
4
$begingroup$
Show what you've tried and be explicit with where you are confused. Help us to help you.
$endgroup$
– Bort
Mar 1 at 18:37
add a comment |
$begingroup$
I know the answer is AC + ~AB, but how?
I have tried:
B(~A+C) + AC and stop.
Also, I have tried:
AC + BC + ~AB and have stopped.
There seems nowhere to go in either case.
digital-logic electrical
edited Mar 3 at 3:36
phuclv
385210
asked Mar 1 at 18:32
Ronaldinho10Ronaldinho10
143
$endgroup$
I know the answer is AC + ~AB, but how?
I have tried:
B(~A+C) + AC and stop.
Also, I have tried:
AC + BC + ~AB and have stopped.
There seems nowhere to go in either case.
digital-logic electrical
digital-logic electrical
edited Mar 3 at 3:36
phuclv
385210
asked Mar 1 at 18:32
Ronaldinho10Ronaldinho10
143
edited Mar 3 at 3:36
phuclv
385210
asked Mar 1 at 18:32
Ronaldinho10Ronaldinho10
143
edited Mar 3 at 3:36
phuclv
385210
edited Mar 3 at 3:36
phuclv
385210
edited Mar 3 at 3:36
phuclv
385210
385210
asked Mar 1 at 18:32
Ronaldinho10Ronaldinho10
143
asked Mar 1 at 18:32
Ronaldinho10Ronaldinho10
143
asked Mar 1 at 18:32
Ronaldinho10Ronaldinho10
143
143
4
$begingroup$
Show what you've tried and be explicit with where you are confused. Help us to help you.
$endgroup$
– Bort
Mar 1 at 18:37
add a comment |
4
$begingroup$
Show what you've tried and be explicit with where you are confused. Help us to help you.
$endgroup$
– Bort
Mar 1 at 18:37
4
4
$begingroup$
Show what you've tried and be explicit with where you are confused. Help us to help you.
$endgroup$
– Bort
Mar 1 at 18:37
$begingroup$
Show what you've tried and be explicit with where you are confused. Help us to help you.
$endgroup$
– Bort
Mar 1 at 18:37
add a comment |
1 Answer
1
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oldest
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I will not give you the full solution, but the required non-trivial sidestep. You have got this far:
C(A + B) + A'B = AC + BC + A'B =
Now here is the sidestep. We know that (A+A') is 1, so we can do:
= AC + (A + A')BC + A'B
From here you will need to expand it and use the "OR absorption law" twice.
answered Mar 1 at 18:44
Eugene Sh.Eugene Sh.
7,5931830
$endgroup$
$begingroup$
@AlanKazemian (Be sure and hit the check mark so you can close the question)
$endgroup$
– KingDuken
Mar 1 at 19:11
$begingroup$
@Eugene Sh. Expanding the brackets was an obvious step but your "sidestep" was one that I had not considered. Very useful and I will bear this in mind for future tasks. A Karnaugh Map would also have provided a easy solution to the problem.
$endgroup$
– Pzy
Mar 1 at 21:00
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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votes
$begingroup$
I will not give you the full solution, but the required non-trivial sidestep. You have got this far:
C(A + B) + A'B = AC + BC + A'B =
Now here is the sidestep. We know that (A+A') is 1, so we can do:
= AC + (A + A')BC + A'B
From here you will need to expand it and use the "OR absorption law" twice.
answered Mar 1 at 18:44
Eugene Sh.Eugene Sh.
7,5931830
$endgroup$
$begingroup$
@AlanKazemian (Be sure and hit the check mark so you can close the question)
$endgroup$
– KingDuken
Mar 1 at 19:11
$begingroup$
@Eugene Sh. Expanding the brackets was an obvious step but your "sidestep" was one that I had not considered. Very useful and I will bear this in mind for future tasks. A Karnaugh Map would also have provided a easy solution to the problem.
$endgroup$
– Pzy
Mar 1 at 21:00
add a comment |
$begingroup$
I will not give you the full solution, but the required non-trivial sidestep. You have got this far:
C(A + B) + A'B = AC + BC + A'B =
Now here is the sidestep. We know that (A+A') is 1, so we can do:
= AC + (A + A')BC + A'B
From here you will need to expand it and use the "OR absorption law" twice.
answered Mar 1 at 18:44
Eugene Sh.Eugene Sh.
7,5931830
$endgroup$
$begingroup$
@AlanKazemian (Be sure and hit the check mark so you can close the question)
$endgroup$
– KingDuken
Mar 1 at 19:11
$begingroup$
@Eugene Sh. Expanding the brackets was an obvious step but your "sidestep" was one that I had not considered. Very useful and I will bear this in mind for future tasks. A Karnaugh Map would also have provided a easy solution to the problem.
$endgroup$
– Pzy
Mar 1 at 21:00
add a comment |
$begingroup$
I will not give you the full solution, but the required non-trivial sidestep. You have got this far:
C(A + B) + A'B = AC + BC + A'B =
Now here is the sidestep. We know that (A+A') is 1, so we can do:
= AC + (A + A')BC + A'B
From here you will need to expand it and use the "OR absorption law" twice.
answered Mar 1 at 18:44
Eugene Sh.Eugene Sh.
7,5931830
$endgroup$
I will not give you the full solution, but the required non-trivial sidestep. You have got this far:
C(A + B) + A'B = AC + BC + A'B =
Now here is the sidestep. We know that (A+A') is 1, so we can do:
= AC + (A + A')BC + A'B
From here you will need to expand it and use the "OR absorption law" twice.
answered Mar 1 at 18:44
Eugene Sh.Eugene Sh.
7,5931830
edited Mar 1 at 21:13
answered Mar 1 at 18:44
Eugene Sh.Eugene Sh.
7,5931830
answered Mar 1 at 18:44
Eugene Sh.Eugene Sh.
7,5931830
answered Mar 1 at 18:44
Eugene Sh.Eugene Sh.
7,5931830
7,5931830
$begingroup$
@AlanKazemian (Be sure and hit the check mark so you can close the question)
$endgroup$
– KingDuken
Mar 1 at 19:11
$begingroup$
@Eugene Sh. Expanding the brackets was an obvious step but your "sidestep" was one that I had not considered. Very useful and I will bear this in mind for future tasks. A Karnaugh Map would also have provided a easy solution to the problem.
$endgroup$
– Pzy
Mar 1 at 21:00
add a comment |
$begingroup$
@AlanKazemian (Be sure and hit the check mark so you can close the question)
$endgroup$
– KingDuken
Mar 1 at 19:11
$begingroup$
@Eugene Sh. Expanding the brackets was an obvious step but your "sidestep" was one that I had not considered. Very useful and I will bear this in mind for future tasks. A Karnaugh Map would also have provided a easy solution to the problem.
$endgroup$
– Pzy
Mar 1 at 21:00
$begingroup$
@AlanKazemian (Be sure and hit the check mark so you can close the question)
$endgroup$
– KingDuken
Mar 1 at 19:11
$begingroup$
@AlanKazemian (Be sure and hit the check mark so you can close the question)
$endgroup$
– KingDuken
Mar 1 at 19:11
$begingroup$
@Eugene Sh. Expanding the brackets was an obvious step but your "sidestep" was one that I had not considered. Very useful and I will bear this in mind for future tasks. A Karnaugh Map would also have provided a easy solution to the problem.
$endgroup$
– Pzy
Mar 1 at 21:00
$begingroup$
@Eugene Sh. Expanding the brackets was an obvious step but your "sidestep" was one that I had not considered. Very useful and I will bear this in mind for future tasks. A Karnaugh Map would also have provided a easy solution to the problem.
$endgroup$
– Pzy
Mar 1 at 21:00
add a comment |
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Show what you've tried and be explicit with where you are confused. Help us to help you.
$endgroup$
– Bort
Mar 1 at 18:37