mjhjmtu

I'm using this command to search for a specific file:

find . -type f -name Client.php | xargs grep WARNING

I can't figure out how to add the delete command so that way the user is prompted before the delete command happens.

You can't pipe to xargs here and rejoin the find, find can run commands like grep on its own.

The -exec primary runs a command for a file or files. It succeeds and continues processing the operands to the right only when the command itself exits with a successful result, so

find . -type f -name Client.php -exec grep -q WARNING ; -exec echo ;

will print out the path of every file named "Client.php" that contains "WARNING" inside it. You can change that second -exec ... ; to -delete to have it delete, or change the command to use rm or mv to deal with them.

The semicolons make sure only one file is checked at a time, and that we get this true-on-success behaviour:

If the primary expression is punctuated by a <semicolon>, the utility utility_name shall be invoked once for each pathname and the primary shall evaluate as true if the utility returns a zero value as exit status.

The whole -exec ... ; is one chunk, so if you're using -delete you want to remove the semicolon along with -exec and the command.

I suggest running the command above first and making sure that it really does only include only the files you want before you actually delete them. However, a full delete-without-asking command would be

find . -type f -name Client.php -exec grep -q WARNING ; -delete

Proceed with caution!

You could write a script:

#!/bin/bash

FINDFILE=Client.php
if [[ $(find . -type f -name $FINDFILE | xargs grep "WARNING") ]] ; then
rm -i $FINDFILE
else
echo "File with warning not found."
fi

Place the script in your /usr/local/bin, chmod +x /usr/local/bin/scriptname.

Now you can execute it from anywhere at any time. (It's also best to leave off the .sh extension)