Find and copy with exec not working

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1















I'm using the following command to get the most recent file in a directory



/usr/bin/find /home/user1/folder1/ -type f -printf '%T@ %pn' | sort -n | tail -1 | cut -f2- -d" " | cut -f5 -d"/"


This returns only the file name not the entire path.



I then want to copy the file I found into another folder, so I append the following to the previous find command:



 -exec cp /home/user2/folder2 ;


So the full command looks like this:



 /usr/bin/find /home/user1/folder1/ -type f -printf '%T@ %pn' | sort -n | tail -1 | cut -f2- -d" " | cut -f5 -d"/ -exec cp /home/user2/folder2 ;


But this returns



cut: invalid option -- 'e'


What am I doing wrong here?










share|improve this question

















  • 6





    -exec belongs together with find, you can't just tuck it on at the end of the pipeline like that.

    – Kusalananda
    Jan 18 at 22:10











  • I'm realizing that now. Is there a solution for this though to accomplish my objective?

    – user53029
    Jan 18 at 22:37















1















I'm using the following command to get the most recent file in a directory



/usr/bin/find /home/user1/folder1/ -type f -printf '%T@ %pn' | sort -n | tail -1 | cut -f2- -d" " | cut -f5 -d"/"


This returns only the file name not the entire path.



I then want to copy the file I found into another folder, so I append the following to the previous find command:



 -exec cp /home/user2/folder2 ;


So the full command looks like this:



 /usr/bin/find /home/user1/folder1/ -type f -printf '%T@ %pn' | sort -n | tail -1 | cut -f2- -d" " | cut -f5 -d"/ -exec cp /home/user2/folder2 ;


But this returns



cut: invalid option -- 'e'


What am I doing wrong here?










share|improve this question

















  • 6





    -exec belongs together with find, you can't just tuck it on at the end of the pipeline like that.

    – Kusalananda
    Jan 18 at 22:10











  • I'm realizing that now. Is there a solution for this though to accomplish my objective?

    – user53029
    Jan 18 at 22:37













1












1








1








I'm using the following command to get the most recent file in a directory



/usr/bin/find /home/user1/folder1/ -type f -printf '%T@ %pn' | sort -n | tail -1 | cut -f2- -d" " | cut -f5 -d"/"


This returns only the file name not the entire path.



I then want to copy the file I found into another folder, so I append the following to the previous find command:



 -exec cp /home/user2/folder2 ;


So the full command looks like this:



 /usr/bin/find /home/user1/folder1/ -type f -printf '%T@ %pn' | sort -n | tail -1 | cut -f2- -d" " | cut -f5 -d"/ -exec cp /home/user2/folder2 ;


But this returns



cut: invalid option -- 'e'


What am I doing wrong here?










share|improve this question














I'm using the following command to get the most recent file in a directory



/usr/bin/find /home/user1/folder1/ -type f -printf '%T@ %pn' | sort -n | tail -1 | cut -f2- -d" " | cut -f5 -d"/"


This returns only the file name not the entire path.



I then want to copy the file I found into another folder, so I append the following to the previous find command:



 -exec cp /home/user2/folder2 ;


So the full command looks like this:



 /usr/bin/find /home/user1/folder1/ -type f -printf '%T@ %pn' | sort -n | tail -1 | cut -f2- -d" " | cut -f5 -d"/ -exec cp /home/user2/folder2 ;


But this returns



cut: invalid option -- 'e'


What am I doing wrong here?







find file-copy






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Jan 18 at 22:05









user53029user53029

98041845




98041845







  • 6





    -exec belongs together with find, you can't just tuck it on at the end of the pipeline like that.

    – Kusalananda
    Jan 18 at 22:10











  • I'm realizing that now. Is there a solution for this though to accomplish my objective?

    – user53029
    Jan 18 at 22:37












  • 6





    -exec belongs together with find, you can't just tuck it on at the end of the pipeline like that.

    – Kusalananda
    Jan 18 at 22:10











  • I'm realizing that now. Is there a solution for this though to accomplish my objective?

    – user53029
    Jan 18 at 22:37







6




6





-exec belongs together with find, you can't just tuck it on at the end of the pipeline like that.

– Kusalananda
Jan 18 at 22:10





-exec belongs together with find, you can't just tuck it on at the end of the pipeline like that.

– Kusalananda
Jan 18 at 22:10













I'm realizing that now. Is there a solution for this though to accomplish my objective?

– user53029
Jan 18 at 22:37





I'm realizing that now. Is there a solution for this though to accomplish my objective?

– user53029
Jan 18 at 22:37










2 Answers
2






active

oldest

votes


















2














Your command appears to have two issues, the first of which may not matter much in your case, but is nevertheless worth pointing out: (i) it is not generic in the sense that it will not be able to process arbitrary filenames, in particular filenames that contain newlines (i.e. n), and (ii) as already noted by Kusalananda, the -exec option belongs to the find command, and can thus not be separated therefrom as you have tried.



Using the GNU utilities, these issues can be fixed with the following pipeline, which will find the most recent file in (or below) the directory /home/user1/folder1/ and copy it to /home/user2/folder2/:



find /home/user1/folder1/ -type f -printf '%T@ %p' 2>/dev/null |
sort -znk1,1 | tail -zn1 | cut -zf2- -d' ' |
xargs -0 cp -t /home/user2/folder2/


As to issue (i): note the at the end of the -printf format string, and the -z and -0 options to the various commands in the pipeline, which ensure that the identified filename is passed in a NUL-delimited fashion, and thus enable it to include blanks and/or newlines.



As to issue (ii): you can use the xargs command to collect arguments from stdin and to build a new commandline with them. Part of the trick here is to use the -t option to the cp command, to specify the target directory before providing any filename to be copied there, since xargs will build a commandline by appending any arguments it receives on stdin to a given command.






share|improve this answer
































    2














    Using the zsh shell, assuming you want to copy the most recently modified file in the /home/user1/folder1 directory:



    cp /home/user1/folder1/*(.om[1]) /home/user2/folder2


    If zsh is not your interactive shell, then you may do



    zsh -c 'cp /home/user1/folder1/*(.om[1]) /home/user2/folder2'


    The pattern /home/user1/folder1/*(.om[1]) would expand to the name of the most recently modified regular file in the given directory. The *(.om[1]) at the end is what orders (o) the regular files (.) by modification time (m) and picks the first ([1]).



    If you need to match hidden filenames, then use



    zsh -c -4 'cp /home/user1/folder1/*(.om[1]) /home/user2/folder2'


    (add the -4)



    Would you need to additionally look into subdirectories, use



    zsh -c -4 'cp /home/user1/folder1/**/*(.om[1]) /home/user2/folder2'


    The shell globbing pattern ** in zsh matches across / in pathnames.






    share|improve this answer
























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      2














      Your command appears to have two issues, the first of which may not matter much in your case, but is nevertheless worth pointing out: (i) it is not generic in the sense that it will not be able to process arbitrary filenames, in particular filenames that contain newlines (i.e. n), and (ii) as already noted by Kusalananda, the -exec option belongs to the find command, and can thus not be separated therefrom as you have tried.



      Using the GNU utilities, these issues can be fixed with the following pipeline, which will find the most recent file in (or below) the directory /home/user1/folder1/ and copy it to /home/user2/folder2/:



      find /home/user1/folder1/ -type f -printf '%T@ %p' 2>/dev/null |
      sort -znk1,1 | tail -zn1 | cut -zf2- -d' ' |
      xargs -0 cp -t /home/user2/folder2/


      As to issue (i): note the at the end of the -printf format string, and the -z and -0 options to the various commands in the pipeline, which ensure that the identified filename is passed in a NUL-delimited fashion, and thus enable it to include blanks and/or newlines.



      As to issue (ii): you can use the xargs command to collect arguments from stdin and to build a new commandline with them. Part of the trick here is to use the -t option to the cp command, to specify the target directory before providing any filename to be copied there, since xargs will build a commandline by appending any arguments it receives on stdin to a given command.






      share|improve this answer





























        2














        Your command appears to have two issues, the first of which may not matter much in your case, but is nevertheless worth pointing out: (i) it is not generic in the sense that it will not be able to process arbitrary filenames, in particular filenames that contain newlines (i.e. n), and (ii) as already noted by Kusalananda, the -exec option belongs to the find command, and can thus not be separated therefrom as you have tried.



        Using the GNU utilities, these issues can be fixed with the following pipeline, which will find the most recent file in (or below) the directory /home/user1/folder1/ and copy it to /home/user2/folder2/:



        find /home/user1/folder1/ -type f -printf '%T@ %p' 2>/dev/null |
        sort -znk1,1 | tail -zn1 | cut -zf2- -d' ' |
        xargs -0 cp -t /home/user2/folder2/


        As to issue (i): note the at the end of the -printf format string, and the -z and -0 options to the various commands in the pipeline, which ensure that the identified filename is passed in a NUL-delimited fashion, and thus enable it to include blanks and/or newlines.



        As to issue (ii): you can use the xargs command to collect arguments from stdin and to build a new commandline with them. Part of the trick here is to use the -t option to the cp command, to specify the target directory before providing any filename to be copied there, since xargs will build a commandline by appending any arguments it receives on stdin to a given command.






        share|improve this answer



























          2












          2








          2







          Your command appears to have two issues, the first of which may not matter much in your case, but is nevertheless worth pointing out: (i) it is not generic in the sense that it will not be able to process arbitrary filenames, in particular filenames that contain newlines (i.e. n), and (ii) as already noted by Kusalananda, the -exec option belongs to the find command, and can thus not be separated therefrom as you have tried.



          Using the GNU utilities, these issues can be fixed with the following pipeline, which will find the most recent file in (or below) the directory /home/user1/folder1/ and copy it to /home/user2/folder2/:



          find /home/user1/folder1/ -type f -printf '%T@ %p' 2>/dev/null |
          sort -znk1,1 | tail -zn1 | cut -zf2- -d' ' |
          xargs -0 cp -t /home/user2/folder2/


          As to issue (i): note the at the end of the -printf format string, and the -z and -0 options to the various commands in the pipeline, which ensure that the identified filename is passed in a NUL-delimited fashion, and thus enable it to include blanks and/or newlines.



          As to issue (ii): you can use the xargs command to collect arguments from stdin and to build a new commandline with them. Part of the trick here is to use the -t option to the cp command, to specify the target directory before providing any filename to be copied there, since xargs will build a commandline by appending any arguments it receives on stdin to a given command.






          share|improve this answer















          Your command appears to have two issues, the first of which may not matter much in your case, but is nevertheless worth pointing out: (i) it is not generic in the sense that it will not be able to process arbitrary filenames, in particular filenames that contain newlines (i.e. n), and (ii) as already noted by Kusalananda, the -exec option belongs to the find command, and can thus not be separated therefrom as you have tried.



          Using the GNU utilities, these issues can be fixed with the following pipeline, which will find the most recent file in (or below) the directory /home/user1/folder1/ and copy it to /home/user2/folder2/:



          find /home/user1/folder1/ -type f -printf '%T@ %p' 2>/dev/null |
          sort -znk1,1 | tail -zn1 | cut -zf2- -d' ' |
          xargs -0 cp -t /home/user2/folder2/


          As to issue (i): note the at the end of the -printf format string, and the -z and -0 options to the various commands in the pipeline, which ensure that the identified filename is passed in a NUL-delimited fashion, and thus enable it to include blanks and/or newlines.



          As to issue (ii): you can use the xargs command to collect arguments from stdin and to build a new commandline with them. Part of the trick here is to use the -t option to the cp command, to specify the target directory before providing any filename to be copied there, since xargs will build a commandline by appending any arguments it receives on stdin to a given command.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Jan 19 at 9:46

























          answered Jan 18 at 23:04









          ozzyozzy

          74715




          74715























              2














              Using the zsh shell, assuming you want to copy the most recently modified file in the /home/user1/folder1 directory:



              cp /home/user1/folder1/*(.om[1]) /home/user2/folder2


              If zsh is not your interactive shell, then you may do



              zsh -c 'cp /home/user1/folder1/*(.om[1]) /home/user2/folder2'


              The pattern /home/user1/folder1/*(.om[1]) would expand to the name of the most recently modified regular file in the given directory. The *(.om[1]) at the end is what orders (o) the regular files (.) by modification time (m) and picks the first ([1]).



              If you need to match hidden filenames, then use



              zsh -c -4 'cp /home/user1/folder1/*(.om[1]) /home/user2/folder2'


              (add the -4)



              Would you need to additionally look into subdirectories, use



              zsh -c -4 'cp /home/user1/folder1/**/*(.om[1]) /home/user2/folder2'


              The shell globbing pattern ** in zsh matches across / in pathnames.






              share|improve this answer





























                2














                Using the zsh shell, assuming you want to copy the most recently modified file in the /home/user1/folder1 directory:



                cp /home/user1/folder1/*(.om[1]) /home/user2/folder2


                If zsh is not your interactive shell, then you may do



                zsh -c 'cp /home/user1/folder1/*(.om[1]) /home/user2/folder2'


                The pattern /home/user1/folder1/*(.om[1]) would expand to the name of the most recently modified regular file in the given directory. The *(.om[1]) at the end is what orders (o) the regular files (.) by modification time (m) and picks the first ([1]).



                If you need to match hidden filenames, then use



                zsh -c -4 'cp /home/user1/folder1/*(.om[1]) /home/user2/folder2'


                (add the -4)



                Would you need to additionally look into subdirectories, use



                zsh -c -4 'cp /home/user1/folder1/**/*(.om[1]) /home/user2/folder2'


                The shell globbing pattern ** in zsh matches across / in pathnames.






                share|improve this answer



























                  2












                  2








                  2







                  Using the zsh shell, assuming you want to copy the most recently modified file in the /home/user1/folder1 directory:



                  cp /home/user1/folder1/*(.om[1]) /home/user2/folder2


                  If zsh is not your interactive shell, then you may do



                  zsh -c 'cp /home/user1/folder1/*(.om[1]) /home/user2/folder2'


                  The pattern /home/user1/folder1/*(.om[1]) would expand to the name of the most recently modified regular file in the given directory. The *(.om[1]) at the end is what orders (o) the regular files (.) by modification time (m) and picks the first ([1]).



                  If you need to match hidden filenames, then use



                  zsh -c -4 'cp /home/user1/folder1/*(.om[1]) /home/user2/folder2'


                  (add the -4)



                  Would you need to additionally look into subdirectories, use



                  zsh -c -4 'cp /home/user1/folder1/**/*(.om[1]) /home/user2/folder2'


                  The shell globbing pattern ** in zsh matches across / in pathnames.






                  share|improve this answer















                  Using the zsh shell, assuming you want to copy the most recently modified file in the /home/user1/folder1 directory:



                  cp /home/user1/folder1/*(.om[1]) /home/user2/folder2


                  If zsh is not your interactive shell, then you may do



                  zsh -c 'cp /home/user1/folder1/*(.om[1]) /home/user2/folder2'


                  The pattern /home/user1/folder1/*(.om[1]) would expand to the name of the most recently modified regular file in the given directory. The *(.om[1]) at the end is what orders (o) the regular files (.) by modification time (m) and picks the first ([1]).



                  If you need to match hidden filenames, then use



                  zsh -c -4 'cp /home/user1/folder1/*(.om[1]) /home/user2/folder2'


                  (add the -4)



                  Would you need to additionally look into subdirectories, use



                  zsh -c -4 'cp /home/user1/folder1/**/*(.om[1]) /home/user2/folder2'


                  The shell globbing pattern ** in zsh matches across / in pathnames.







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Jan 19 at 9:58

























                  answered Jan 19 at 0:05









                  KusalanandaKusalananda

                  128k16241398




                  128k16241398



























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