What is “exterior” about an exterior product?

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This is a question about terminology. What is "inner" about an inner product, or "outer" about an outer product?










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    I think there might be some confusion among the answers since your title asks about exterior products, but the question asks about outer products - so three of the answers talk about exterior products, while one talks about outer products.
    – Milo Brandt
    Dec 23 '18 at 5:13















7














This is a question about terminology. What is "inner" about an inner product, or "outer" about an outer product?










share|cite|improve this question

















  • 4




    I think there might be some confusion among the answers since your title asks about exterior products, but the question asks about outer products - so three of the answers talk about exterior products, while one talks about outer products.
    – Milo Brandt
    Dec 23 '18 at 5:13













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7








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This is a question about terminology. What is "inner" about an inner product, or "outer" about an outer product?










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This is a question about terminology. What is "inner" about an inner product, or "outer" about an outer product?







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asked Dec 23 '18 at 0:34









Tobin Fricke

1,482818




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  • 4




    I think there might be some confusion among the answers since your title asks about exterior products, but the question asks about outer products - so three of the answers talk about exterior products, while one talks about outer products.
    – Milo Brandt
    Dec 23 '18 at 5:13












  • 4




    I think there might be some confusion among the answers since your title asks about exterior products, but the question asks about outer products - so three of the answers talk about exterior products, while one talks about outer products.
    – Milo Brandt
    Dec 23 '18 at 5:13







4




4




I think there might be some confusion among the answers since your title asks about exterior products, but the question asks about outer products - so three of the answers talk about exterior products, while one talks about outer products.
– Milo Brandt
Dec 23 '18 at 5:13




I think there might be some confusion among the answers since your title asks about exterior products, but the question asks about outer products - so three of the answers talk about exterior products, while one talks about outer products.
– Milo Brandt
Dec 23 '18 at 5:13










4 Answers
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7














This terminology (or rather its literal German translation) was introduced by Grassmann.




I named the former product exterior, the latter interior, reflecting that the former was nonzero only when involving independent directions, the latter only when involving a shared, i.e., partly common one.



H. Grassmann, Die lineale Ausdehnungslehre [archive.org] (1844) x-xi.




NB the words in the original text translated in the above excerpt to exterior and interior are respectively äussere and innere, but they can also be translated respectively to outer and inner, and now all four terms have distinct meanings in this context.



For more detail, see the answer to essentially the same question on MathOverflow, from where the above translation was lifted (this borrowing motivated setting this answer as a community wiki answer):




Etymology of "exterior" in "exterior calculus".







share|cite|improve this answer






























    3














    Consider the case n=3. The interior product of two vectors is non-zero when one lives in the span of the other. The outer product of two vectors is non-zero when one lives outside the span of the other.



    This terminology can be traced back to one of the earlier German texts on linear algebra but I can't quite recall the name. I'll come back if I recall it.



    EDIT: Found my source. Take a look at section 1.2 of this.






    share|cite|improve this answer




























      0














      The exterior (= outer) product takes values in a "higher" dimensional space: if $V$ has dimension $n$ and $v, w in V$ then $v wedge w in Lambda^2(V)$ and that space has dimension $binomn2$, which is bigger than $n$ when $n > 3$. In Euclidean space, the wedge product of two vectors is represented by a parallelogram with the original vectors as its edges.



      The inner/outer terminology goes back to Grassmann.






      share|cite|improve this answer




























        0














        Well if I take the inner product of two vectors I go from the full vector space down to the base field over which it's defined so its internal in that regard. As for the outer product I think of this in terms of matrix multiplication, if we reverse the inner product $x^Ty$ to $xy^T$ for column vectors in a space of dimension $n$ instead we end up with a matrix which is a larger vector space than the original space with $n^2$ dimensions. Metaphorically I think of this as identifying a vector space with a subspace of a larger space, and the rest of that space is "outer space" in the same way the Earth is in a much larger universe.






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          4 Answers
          4






          active

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          4 Answers
          4






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          7














          This terminology (or rather its literal German translation) was introduced by Grassmann.




          I named the former product exterior, the latter interior, reflecting that the former was nonzero only when involving independent directions, the latter only when involving a shared, i.e., partly common one.



          H. Grassmann, Die lineale Ausdehnungslehre [archive.org] (1844) x-xi.




          NB the words in the original text translated in the above excerpt to exterior and interior are respectively äussere and innere, but they can also be translated respectively to outer and inner, and now all four terms have distinct meanings in this context.



          For more detail, see the answer to essentially the same question on MathOverflow, from where the above translation was lifted (this borrowing motivated setting this answer as a community wiki answer):




          Etymology of "exterior" in "exterior calculus".







          share|cite|improve this answer



























            7














            This terminology (or rather its literal German translation) was introduced by Grassmann.




            I named the former product exterior, the latter interior, reflecting that the former was nonzero only when involving independent directions, the latter only when involving a shared, i.e., partly common one.



            H. Grassmann, Die lineale Ausdehnungslehre [archive.org] (1844) x-xi.




            NB the words in the original text translated in the above excerpt to exterior and interior are respectively äussere and innere, but they can also be translated respectively to outer and inner, and now all four terms have distinct meanings in this context.



            For more detail, see the answer to essentially the same question on MathOverflow, from where the above translation was lifted (this borrowing motivated setting this answer as a community wiki answer):




            Etymology of "exterior" in "exterior calculus".







            share|cite|improve this answer

























              7












              7








              7






              This terminology (or rather its literal German translation) was introduced by Grassmann.




              I named the former product exterior, the latter interior, reflecting that the former was nonzero only when involving independent directions, the latter only when involving a shared, i.e., partly common one.



              H. Grassmann, Die lineale Ausdehnungslehre [archive.org] (1844) x-xi.




              NB the words in the original text translated in the above excerpt to exterior and interior are respectively äussere and innere, but they can also be translated respectively to outer and inner, and now all four terms have distinct meanings in this context.



              For more detail, see the answer to essentially the same question on MathOverflow, from where the above translation was lifted (this borrowing motivated setting this answer as a community wiki answer):




              Etymology of "exterior" in "exterior calculus".







              share|cite|improve this answer














              This terminology (or rather its literal German translation) was introduced by Grassmann.




              I named the former product exterior, the latter interior, reflecting that the former was nonzero only when involving independent directions, the latter only when involving a shared, i.e., partly common one.



              H. Grassmann, Die lineale Ausdehnungslehre [archive.org] (1844) x-xi.




              NB the words in the original text translated in the above excerpt to exterior and interior are respectively äussere and innere, but they can also be translated respectively to outer and inner, and now all four terms have distinct meanings in this context.



              For more detail, see the answer to essentially the same question on MathOverflow, from where the above translation was lifted (this borrowing motivated setting this answer as a community wiki answer):




              Etymology of "exterior" in "exterior calculus".








              share|cite|improve this answer














              share|cite|improve this answer



              share|cite|improve this answer








              edited Dec 25 '18 at 9:35


























              community wiki





              3 revs
              Travis






















                  3














                  Consider the case n=3. The interior product of two vectors is non-zero when one lives in the span of the other. The outer product of two vectors is non-zero when one lives outside the span of the other.



                  This terminology can be traced back to one of the earlier German texts on linear algebra but I can't quite recall the name. I'll come back if I recall it.



                  EDIT: Found my source. Take a look at section 1.2 of this.






                  share|cite|improve this answer

























                    3














                    Consider the case n=3. The interior product of two vectors is non-zero when one lives in the span of the other. The outer product of two vectors is non-zero when one lives outside the span of the other.



                    This terminology can be traced back to one of the earlier German texts on linear algebra but I can't quite recall the name. I'll come back if I recall it.



                    EDIT: Found my source. Take a look at section 1.2 of this.






                    share|cite|improve this answer























                      3












                      3








                      3






                      Consider the case n=3. The interior product of two vectors is non-zero when one lives in the span of the other. The outer product of two vectors is non-zero when one lives outside the span of the other.



                      This terminology can be traced back to one of the earlier German texts on linear algebra but I can't quite recall the name. I'll come back if I recall it.



                      EDIT: Found my source. Take a look at section 1.2 of this.






                      share|cite|improve this answer












                      Consider the case n=3. The interior product of two vectors is non-zero when one lives in the span of the other. The outer product of two vectors is non-zero when one lives outside the span of the other.



                      This terminology can be traced back to one of the earlier German texts on linear algebra but I can't quite recall the name. I'll come back if I recall it.



                      EDIT: Found my source. Take a look at section 1.2 of this.







                      share|cite|improve this answer












                      share|cite|improve this answer



                      share|cite|improve this answer










                      answered Dec 23 '18 at 1:11









                      Wraith1995

                      618315




                      618315





















                          0














                          The exterior (= outer) product takes values in a "higher" dimensional space: if $V$ has dimension $n$ and $v, w in V$ then $v wedge w in Lambda^2(V)$ and that space has dimension $binomn2$, which is bigger than $n$ when $n > 3$. In Euclidean space, the wedge product of two vectors is represented by a parallelogram with the original vectors as its edges.



                          The inner/outer terminology goes back to Grassmann.






                          share|cite|improve this answer

























                            0














                            The exterior (= outer) product takes values in a "higher" dimensional space: if $V$ has dimension $n$ and $v, w in V$ then $v wedge w in Lambda^2(V)$ and that space has dimension $binomn2$, which is bigger than $n$ when $n > 3$. In Euclidean space, the wedge product of two vectors is represented by a parallelogram with the original vectors as its edges.



                            The inner/outer terminology goes back to Grassmann.






                            share|cite|improve this answer























                              0












                              0








                              0






                              The exterior (= outer) product takes values in a "higher" dimensional space: if $V$ has dimension $n$ and $v, w in V$ then $v wedge w in Lambda^2(V)$ and that space has dimension $binomn2$, which is bigger than $n$ when $n > 3$. In Euclidean space, the wedge product of two vectors is represented by a parallelogram with the original vectors as its edges.



                              The inner/outer terminology goes back to Grassmann.






                              share|cite|improve this answer












                              The exterior (= outer) product takes values in a "higher" dimensional space: if $V$ has dimension $n$ and $v, w in V$ then $v wedge w in Lambda^2(V)$ and that space has dimension $binomn2$, which is bigger than $n$ when $n > 3$. In Euclidean space, the wedge product of two vectors is represented by a parallelogram with the original vectors as its edges.



                              The inner/outer terminology goes back to Grassmann.







                              share|cite|improve this answer












                              share|cite|improve this answer



                              share|cite|improve this answer










                              answered Dec 23 '18 at 1:10









                              KCd

                              16.6k4075




                              16.6k4075





















                                  0














                                  Well if I take the inner product of two vectors I go from the full vector space down to the base field over which it's defined so its internal in that regard. As for the outer product I think of this in terms of matrix multiplication, if we reverse the inner product $x^Ty$ to $xy^T$ for column vectors in a space of dimension $n$ instead we end up with a matrix which is a larger vector space than the original space with $n^2$ dimensions. Metaphorically I think of this as identifying a vector space with a subspace of a larger space, and the rest of that space is "outer space" in the same way the Earth is in a much larger universe.






                                  share|cite|improve this answer

























                                    0














                                    Well if I take the inner product of two vectors I go from the full vector space down to the base field over which it's defined so its internal in that regard. As for the outer product I think of this in terms of matrix multiplication, if we reverse the inner product $x^Ty$ to $xy^T$ for column vectors in a space of dimension $n$ instead we end up with a matrix which is a larger vector space than the original space with $n^2$ dimensions. Metaphorically I think of this as identifying a vector space with a subspace of a larger space, and the rest of that space is "outer space" in the same way the Earth is in a much larger universe.






                                    share|cite|improve this answer























                                      0












                                      0








                                      0






                                      Well if I take the inner product of two vectors I go from the full vector space down to the base field over which it's defined so its internal in that regard. As for the outer product I think of this in terms of matrix multiplication, if we reverse the inner product $x^Ty$ to $xy^T$ for column vectors in a space of dimension $n$ instead we end up with a matrix which is a larger vector space than the original space with $n^2$ dimensions. Metaphorically I think of this as identifying a vector space with a subspace of a larger space, and the rest of that space is "outer space" in the same way the Earth is in a much larger universe.






                                      share|cite|improve this answer












                                      Well if I take the inner product of two vectors I go from the full vector space down to the base field over which it's defined so its internal in that regard. As for the outer product I think of this in terms of matrix multiplication, if we reverse the inner product $x^Ty$ to $xy^T$ for column vectors in a space of dimension $n$ instead we end up with a matrix which is a larger vector space than the original space with $n^2$ dimensions. Metaphorically I think of this as identifying a vector space with a subspace of a larger space, and the rest of that space is "outer space" in the same way the Earth is in a much larger universe.







                                      share|cite|improve this answer












                                      share|cite|improve this answer



                                      share|cite|improve this answer










                                      answered Dec 23 '18 at 1:11









                                      CyclotomicField

                                      2,1921313




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