mjhjmtu

sed 's/.$//'

To remove the last character.

But in this specific case, you could also do:

df -Ph | awk 'NR > 1 print $5+0'

With the arithmetic expression ($5+0) we force awk to interpret the 5th field as a number, and anything after the number will be ignored.

With sed, this is pretty easy:

$ cat file
Use%
22%
1%
1%
59%
51%
63%
5%
$ sed 's/.$//' file
Use
22
1
1
59
51
63
5

The syntax is s(ubstitute)/search/replacestring/. The . indicates any character, and the $ the end of the line. So .$ will remove the last character only.

In this case, your complete command would look:

df -h | awk ' print $5' | sed 's/.$//'

I have two solutions :

1. 
   

   cut: echo "somestring1" | rev | cut -c 2- | rev

   
   
   

   Here you reverse the string and cut the string from 2nd character and reverse again.

   
   


2. 
   

   sed : echo "somestring1" | sed 's/.$//'

   
   
   

   Here you will search for regular expression .$ which means any characters followed by a last character and replace it with null // (between the two slashes)

   
   

In awk, you could do one of

awk 'sub(/%$/,"",$5); print $5'
awk 'print substr($5, 1, length($5)-1)'

another approach:

mapfile -t list < <(df -h)
printf '%sn' "$list[@]%?"

Turn it into a function:

remove_last() 
 local char=$1:-?; shift
 mapfile -t list < <("$@")
 printf '%sn' "$list[@]%$char"

Then call it like this:

remove_last '%' df -h

mapfile is a bash4 feature.

The catch here is that you must supply a character to remove; if you want it to just be whatever the last character happens to be then you must pass '?' or ''. quotes required.

$ df -h | awk 'print $5' | cut -d '%' -f1 

Try with this:

df -h | awk ' print $5 ' | sed "s/%//"

The normal use is:
(ie)

VALUE=987654321
echo X123456789X | sed "s/123456789/$VALUE/"

Response should be: X987654321X

df -h | awk 'NR > 1 print $5 ' | cut -d "%" -f1

sed -ie '$d' filename

here -i is to write changes
 e means expression
 $ means last line
 d means delete

Note:Without -e option $ wont work

Optional: To delete 1st and last line use sed -ie '1d;$d' filename