mjhjmtu

How to replace all the Double quotes into both open and close curly brackets.

let str = "This" is my "new" key "string";

I tried with this regex

str.replace(/"/,'').replace(/"/,'')

But I end up with this:

This is my "new" key "string"

Here am getting only the first word is changing but i would like to change all the words.
I want the result to be:

This is my new key string

Thanks in advance.

Try using a global regex and use capture groups:

let str = '"This" is my "new" key "string"';
str = str.replace(/"([^"]*)"/g, '$1');
console.log(str);

The "([^"]*)" regex captures a ", followed by 0 or more things that aren't another ", and a closing ". The replacement uses $1 as a reference for the things that were wrapped in quotes.

Your code currently is only working for the first occurrence of each and . The easiest way to fix this would be to loop while there is still a " in str:

let str = '"This" is my "new" key "string"';
while (str.includes('"')) 
 str = str.replace(/"/,'').replace(/"/,'');

console.log(str);

Try like this

str.replace(/"(.*?)"/g, "$1")

we need to use g-gobal flag. Here capturing string between double quotes "", then replace with matched string curly braces

A very simple way to do that is to iterate over string as an array and every time it encounters character " replace it either by or by repeatedly.

let str = '"This" is my "new" key "string"';
let strArray = str.split("");
let open = true;
for (let i = 0; i < strArray.length; ++i) 
 if (strArray[i] == '"') 
 if (open === true) 
 strArray[i] = '';
 
 else 
 strArray[i] = '';
 
 open = (open == true) ? false : true;
 

str = strArray.join("");
console.log(str)