mjhjmtu

I have number of text files line fruit1, fruit2, fruit3, fruit4 and so on in one directory. Now I want to find the files which contains all three words "Appale" , "Banana" & "Orange".

All three must be present in single file.

for filename in *; do
 if [ -f "$filename" ] &&
 grep -qF Appale -- "$filename" &&
 grep -qF Banana -- "$filename" &&
 grep -qF Orange -- "$filename"
 then
 printf '%s contains all three stringsn' "$filename"
 fi
done

This would report any regular file (or symbolic link to a regular file) in the current directory that contains the all the given strings (not necessarily on the same line). If your grep supports -w, then you may use this as well to stop substrings from being found (such as the substring Banana in the word Bananas).

The -F makes grep do string matching rather than full regular expression matching, and the -q makes it quiet (we are only interested in the exit status of the utility).

A solution that generalises the above to any set of words:

set -- Appale Banana Orange Bumblebee Botswana

for filename in *; do
 if [ ! -f "$filename" ] && continue

 found=1
 for string do
 if ! grep -qF -e "$string" -- "$filename"; then
 found=0
 break
 fi
 done

 if [ "$found" -eq 1 ]; then
 printf '%s contains all stringsn' "$filename"
 fi
done

How about

grep -E "Appale|Banana|Orange" fi* | cut -d: -f1 | uniq -c | grep "^ *3"
 3 file2
 3 file3

Should patterns occur multiple times in a file, i.e. a count > 3, we need a different approach.