Figuring out the remaining seconds left until a certain time with bash?
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I'm thinking about extracting the time from the 'date' command, subtracting a certain time in the future from it to get the number of seconds left until 'date' reaches that time, then to divide that number by 60 for minutes, and 60 for hours.
I want to use this as an argument for the 'shutdown' command for example.
how do I do this?
bash shell-script scripting
edited Dec 7 at 6:26
Rui F Ribeiro
38.6k1479128
asked Dec 7 at 6:14
dudawe
31
add a comment |
up vote
0
down vote
favorite
I'm thinking about extracting the time from the 'date' command, subtracting a certain time in the future from it to get the number of seconds left until 'date' reaches that time, then to divide that number by 60 for minutes, and 60 for hours.
I want to use this as an argument for the 'shutdown' command for example.
how do I do this?
bash shell-script scripting
edited Dec 7 at 6:26
Rui F Ribeiro
38.6k1479128
asked Dec 7 at 6:14
dudawe
31
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I'm thinking about extracting the time from the 'date' command, subtracting a certain time in the future from it to get the number of seconds left until 'date' reaches that time, then to divide that number by 60 for minutes, and 60 for hours.
I want to use this as an argument for the 'shutdown' command for example.
how do I do this?
bash shell-script scripting
edited Dec 7 at 6:26
Rui F Ribeiro
38.6k1479128
asked Dec 7 at 6:14
dudawe
31
I'm thinking about extracting the time from the 'date' command, subtracting a certain time in the future from it to get the number of seconds left until 'date' reaches that time, then to divide that number by 60 for minutes, and 60 for hours.
I want to use this as an argument for the 'shutdown' command for example.
how do I do this?
bash shell-script scripting
bash shell-script scripting
edited Dec 7 at 6:26
Rui F Ribeiro
38.6k1479128
asked Dec 7 at 6:14
dudawe
31
edited Dec 7 at 6:26
Rui F Ribeiro
38.6k1479128
asked Dec 7 at 6:14
dudawe
31
edited Dec 7 at 6:26
Rui F Ribeiro
38.6k1479128
edited Dec 7 at 6:26
Rui F Ribeiro
38.6k1479128
edited Dec 7 at 6:26
Rui F Ribeiro
38.6k1479128
38.6k1479128
asked Dec 7 at 6:14
dudawe
31
asked Dec 7 at 6:14
dudawe
31
asked Dec 7 at 6:14
dudawe
31
31
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
1
down vote
accepted
Something like this?
echo $(( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ))
59856
answered Dec 7 at 6:23
tink
4,11811218
Great! Thank you, foot man
– dudawe
Dec 7 at 6:27
You're welcome ;) Feel free to up-vote or accept :D the answer.
– tink
Dec 7 at 6:28
how do I divide by 60? in the same command?
– dudawe
Dec 7 at 6:30
` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
– tink
Dec 7 at 6:33
1
Awesome! I tried without the additional brackets (noob)
– dudawe
Dec 7 at 6:36
add a comment |
up vote
0
down vote
The conversion to a time string could be done directly in bash (less than 24 hours):
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' 123
00:02:03
The time difference could be found with simple math:
$ now=$(printf '%(%s)T')
$ future=$(date -d '+10 hours' '+%s')
$ tdiff=$(( future - now ))
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' "$tdiff"
10:00:00
To get up to 364 days use this:
now=$(printf '%(%s)T')
future=$(date -d '+10 hour' '+%s')
tdiff=$(( future - now ))
j=$(( $(TZ=UTC0 printf '%(%j)T' "$tdiff") - 1 ))
TZ=UTC0 printf '%s days %(%H:%M:%S)Tn' "$j" "$tdiff"
0 days 10:00:00
answered Dec 7 at 8:15
Isaac
11k11648
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Something like this?
echo $(( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ))
59856
answered Dec 7 at 6:23
tink
4,11811218
Great! Thank you, foot man
– dudawe
Dec 7 at 6:27
You're welcome ;) Feel free to up-vote or accept :D the answer.
– tink
Dec 7 at 6:28
how do I divide by 60? in the same command?
– dudawe
Dec 7 at 6:30
` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
– tink
Dec 7 at 6:33
1
Awesome! I tried without the additional brackets (noob)
– dudawe
Dec 7 at 6:36
add a comment |
up vote
1
down vote
accepted
Something like this?
echo $(( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ))
59856
answered Dec 7 at 6:23
tink
4,11811218
Great! Thank you, foot man
– dudawe
Dec 7 at 6:27
You're welcome ;) Feel free to up-vote or accept :D the answer.
– tink
Dec 7 at 6:28
how do I divide by 60? in the same command?
– dudawe
Dec 7 at 6:30
` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
– tink
Dec 7 at 6:33
1
Awesome! I tried without the additional brackets (noob)
– dudawe
Dec 7 at 6:36
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Something like this?
echo $(( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ))
59856
answered Dec 7 at 6:23
tink
4,11811218
Something like this?
echo $(( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ))
59856
answered Dec 7 at 6:23
tink
4,11811218
answered Dec 7 at 6:23
tink
4,11811218
answered Dec 7 at 6:23
tink
4,11811218
answered Dec 7 at 6:23
tink
4,11811218
4,11811218
Great! Thank you, foot man
– dudawe
Dec 7 at 6:27
You're welcome ;) Feel free to up-vote or accept :D the answer.
– tink
Dec 7 at 6:28
how do I divide by 60? in the same command?
– dudawe
Dec 7 at 6:30
` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
– tink
Dec 7 at 6:33
1
Awesome! I tried without the additional brackets (noob)
– dudawe
Dec 7 at 6:36
add a comment |
Great! Thank you, foot man
– dudawe
Dec 7 at 6:27
You're welcome ;) Feel free to up-vote or accept :D the answer.
– tink
Dec 7 at 6:28
how do I divide by 60? in the same command?
– dudawe
Dec 7 at 6:30
` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
– tink
Dec 7 at 6:33
1
Awesome! I tried without the additional brackets (noob)
– dudawe
Dec 7 at 6:36
Great! Thank you, foot man
– dudawe
Dec 7 at 6:27
Great! Thank you, foot man
– dudawe
Dec 7 at 6:27
You're welcome ;) Feel free to up-vote or accept :D the answer.
– tink
Dec 7 at 6:28
You're welcome ;) Feel free to up-vote or accept :D the answer.
– tink
Dec 7 at 6:28
how do I divide by 60? in the same command?
– dudawe
Dec 7 at 6:30
how do I divide by 60? in the same command?
– dudawe
Dec 7 at 6:30
` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
– tink
Dec 7 at 6:33
` echo $(( ( $(date +%s -d "tomorrow 12:00") - $( date +%s ) ) / 60 ))`
– tink
Dec 7 at 6:33
1
1
Awesome! I tried without the additional brackets (noob)
– dudawe
Dec 7 at 6:36
Awesome! I tried without the additional brackets (noob)
– dudawe
Dec 7 at 6:36
add a comment |
up vote
0
down vote
The conversion to a time string could be done directly in bash (less than 24 hours):
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' 123
00:02:03
The time difference could be found with simple math:
$ now=$(printf '%(%s)T')
$ future=$(date -d '+10 hours' '+%s')
$ tdiff=$(( future - now ))
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' "$tdiff"
10:00:00
To get up to 364 days use this:
now=$(printf '%(%s)T')
future=$(date -d '+10 hour' '+%s')
tdiff=$(( future - now ))
j=$(( $(TZ=UTC0 printf '%(%j)T' "$tdiff") - 1 ))
TZ=UTC0 printf '%s days %(%H:%M:%S)Tn' "$j" "$tdiff"
0 days 10:00:00
answered Dec 7 at 8:15
Isaac
11k11648
add a comment |
up vote
0
down vote
The conversion to a time string could be done directly in bash (less than 24 hours):
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' 123
00:02:03
The time difference could be found with simple math:
$ now=$(printf '%(%s)T')
$ future=$(date -d '+10 hours' '+%s')
$ tdiff=$(( future - now ))
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' "$tdiff"
10:00:00
To get up to 364 days use this:
now=$(printf '%(%s)T')
future=$(date -d '+10 hour' '+%s')
tdiff=$(( future - now ))
j=$(( $(TZ=UTC0 printf '%(%j)T' "$tdiff") - 1 ))
TZ=UTC0 printf '%s days %(%H:%M:%S)Tn' "$j" "$tdiff"
0 days 10:00:00
answered Dec 7 at 8:15
Isaac
11k11648
add a comment |
up vote
0
down vote
up vote
0
down vote
The conversion to a time string could be done directly in bash (less than 24 hours):
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' 123
00:02:03
The time difference could be found with simple math:
$ now=$(printf '%(%s)T')
$ future=$(date -d '+10 hours' '+%s')
$ tdiff=$(( future - now ))
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' "$tdiff"
10:00:00
To get up to 364 days use this:
now=$(printf '%(%s)T')
future=$(date -d '+10 hour' '+%s')
tdiff=$(( future - now ))
j=$(( $(TZ=UTC0 printf '%(%j)T' "$tdiff") - 1 ))
TZ=UTC0 printf '%s days %(%H:%M:%S)Tn' "$j" "$tdiff"
0 days 10:00:00
answered Dec 7 at 8:15
Isaac
11k11648
The conversion to a time string could be done directly in bash (less than 24 hours):
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' 123
00:02:03
The time difference could be found with simple math:
$ now=$(printf '%(%s)T')
$ future=$(date -d '+10 hours' '+%s')
$ tdiff=$(( future - now ))
$ TZ=UTC0 printf '%(%H:%M:%S)Tn' "$tdiff"
10:00:00
To get up to 364 days use this:
now=$(printf '%(%s)T')
future=$(date -d '+10 hour' '+%s')
tdiff=$(( future - now ))
j=$(( $(TZ=UTC0 printf '%(%j)T' "$tdiff") - 1 ))
TZ=UTC0 printf '%s days %(%H:%M:%S)Tn' "$j" "$tdiff"
0 days 10:00:00
answered Dec 7 at 8:15
Isaac
11k11648
edited Dec 7 at 8:36
answered Dec 7 at 8:15
Isaac
11k11648
answered Dec 7 at 8:15
Isaac
11k11648
answered Dec 7 at 8:15
Isaac
11k11648
11k11648
add a comment |
add a comment |
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