global sections of locally free sheaf on projective space

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Let $mathcalE$ be a locally free sheaf on $mathbbP^n_A=mathbbP^ntimes_Spec k Spec A$, where $A$ is a finitely generated algebra over a field $k$. By a well known theorem (see e.g. Hartshorne's Algebraic Geometry, Thm 5.19) $H^0(mathbbP^n_A, mathcalE)$ is a finitely generated $A$- module.



  1. Is it true that $H^0(mathbbP^n_A, mathcalE)$ is a projective module?

Let $B$ be a finitely generated $k$-algebra, $f: Spec B to Spec A$ a morphism and $f^*mathcalE$ the pullback of $mathcalE$ to $Spec B$.



  1. Is it true that $H^0(mathbbP^n_A, mathcalE)otimes _A B= H^0(mathbbP^n_B, f^*mathcalE)$ ?

1 and 2 above are true when $mathcal E$ is a direct sum of line bundles of the form $mathcal O(n)$. I was wondering if they are true for general $mathcalE$.










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    Have a look at Base change for quasi-coherent sheaves.
    – abx
    Nov 27 at 5:27














up vote
4
down vote

favorite
1












Let $mathcalE$ be a locally free sheaf on $mathbbP^n_A=mathbbP^ntimes_Spec k Spec A$, where $A$ is a finitely generated algebra over a field $k$. By a well known theorem (see e.g. Hartshorne's Algebraic Geometry, Thm 5.19) $H^0(mathbbP^n_A, mathcalE)$ is a finitely generated $A$- module.



  1. Is it true that $H^0(mathbbP^n_A, mathcalE)$ is a projective module?

Let $B$ be a finitely generated $k$-algebra, $f: Spec B to Spec A$ a morphism and $f^*mathcalE$ the pullback of $mathcalE$ to $Spec B$.



  1. Is it true that $H^0(mathbbP^n_A, mathcalE)otimes _A B= H^0(mathbbP^n_B, f^*mathcalE)$ ?

1 and 2 above are true when $mathcal E$ is a direct sum of line bundles of the form $mathcal O(n)$. I was wondering if they are true for general $mathcalE$.










share|cite|improve this question



















  • 1




    Have a look at Base change for quasi-coherent sheaves.
    – abx
    Nov 27 at 5:27












up vote
4
down vote

favorite
1









up vote
4
down vote

favorite
1






1





Let $mathcalE$ be a locally free sheaf on $mathbbP^n_A=mathbbP^ntimes_Spec k Spec A$, where $A$ is a finitely generated algebra over a field $k$. By a well known theorem (see e.g. Hartshorne's Algebraic Geometry, Thm 5.19) $H^0(mathbbP^n_A, mathcalE)$ is a finitely generated $A$- module.



  1. Is it true that $H^0(mathbbP^n_A, mathcalE)$ is a projective module?

Let $B$ be a finitely generated $k$-algebra, $f: Spec B to Spec A$ a morphism and $f^*mathcalE$ the pullback of $mathcalE$ to $Spec B$.



  1. Is it true that $H^0(mathbbP^n_A, mathcalE)otimes _A B= H^0(mathbbP^n_B, f^*mathcalE)$ ?

1 and 2 above are true when $mathcal E$ is a direct sum of line bundles of the form $mathcal O(n)$. I was wondering if they are true for general $mathcalE$.










share|cite|improve this question















Let $mathcalE$ be a locally free sheaf on $mathbbP^n_A=mathbbP^ntimes_Spec k Spec A$, where $A$ is a finitely generated algebra over a field $k$. By a well known theorem (see e.g. Hartshorne's Algebraic Geometry, Thm 5.19) $H^0(mathbbP^n_A, mathcalE)$ is a finitely generated $A$- module.



  1. Is it true that $H^0(mathbbP^n_A, mathcalE)$ is a projective module?

Let $B$ be a finitely generated $k$-algebra, $f: Spec B to Spec A$ a morphism and $f^*mathcalE$ the pullback of $mathcalE$ to $Spec B$.



  1. Is it true that $H^0(mathbbP^n_A, mathcalE)otimes _A B= H^0(mathbbP^n_B, f^*mathcalE)$ ?

1 and 2 above are true when $mathcal E$ is a direct sum of line bundles of the form $mathcal O(n)$. I was wondering if they are true for general $mathcalE$.







ag.algebraic-geometry vector-bundles






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edited Nov 26 at 22:30

























asked Nov 26 at 22:23









mike

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  • 1




    Have a look at Base change for quasi-coherent sheaves.
    – abx
    Nov 27 at 5:27












  • 1




    Have a look at Base change for quasi-coherent sheaves.
    – abx
    Nov 27 at 5:27







1




1




Have a look at Base change for quasi-coherent sheaves.
– abx
Nov 27 at 5:27




Have a look at Base change for quasi-coherent sheaves.
– abx
Nov 27 at 5:27










1 Answer
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8
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accepted










The answer to both questions is negative, see counterexamples below.



1) Let $A = k[x,y,z]$, $n = 1$. Note that
$$
H^1(mathbbP^n_A,O(-2)) cong A.
$$

Consider the extension
$$
0 to O(-2) to E to O oplus O oplus O to 0
$$

whose extension class is $(x,y,z)$. Then the cohomolopgy exact sequence
$$
0 to H^0(mathbbP^n_A,E) to A oplus A oplus A stackrel(x,y,z)to A
$$

shows that $H^0(mathbbP^n_A,E)$ is reflexive but not locally free (hence not projective). In fact, this is the simplest example of a reflexive non-locally free sheaf.



2) Take $A = k[x,y,z,w]$ and define $E$ as the extension
$$
0 to O(-2) to E to O oplus O oplus O oplus O to 0
$$

whose extension class is $(x,y,z,w)$. Let $B = k$ with the morphism $A to B$ defined by $x,y,z,w mapsto 0$. Then $f^*E cong O(-2) oplus O oplus O oplus O oplus O$, hence
$$
H^0(mathbbP^n_B,f^*E) = B oplus B oplus B oplus B.
$$

On the other hand, tensoring
$$
0 to H^0(mathbbP^n_A,E) to A oplus A oplus A oplus A stackrel(x,y,z,w)to A to B to 0
$$

by $B$ (over $A$), we deduce
$$
H^0(mathbbP^n_A,E) otimes_A B cong Tor_2^A(B,B) cong B^oplus 6.
$$






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    1 Answer
    1






    active

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    1 Answer
    1






    active

    oldest

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    active

    oldest

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    active

    oldest

    votes








    up vote
    8
    down vote



    accepted










    The answer to both questions is negative, see counterexamples below.



    1) Let $A = k[x,y,z]$, $n = 1$. Note that
    $$
    H^1(mathbbP^n_A,O(-2)) cong A.
    $$

    Consider the extension
    $$
    0 to O(-2) to E to O oplus O oplus O to 0
    $$

    whose extension class is $(x,y,z)$. Then the cohomolopgy exact sequence
    $$
    0 to H^0(mathbbP^n_A,E) to A oplus A oplus A stackrel(x,y,z)to A
    $$

    shows that $H^0(mathbbP^n_A,E)$ is reflexive but not locally free (hence not projective). In fact, this is the simplest example of a reflexive non-locally free sheaf.



    2) Take $A = k[x,y,z,w]$ and define $E$ as the extension
    $$
    0 to O(-2) to E to O oplus O oplus O oplus O to 0
    $$

    whose extension class is $(x,y,z,w)$. Let $B = k$ with the morphism $A to B$ defined by $x,y,z,w mapsto 0$. Then $f^*E cong O(-2) oplus O oplus O oplus O oplus O$, hence
    $$
    H^0(mathbbP^n_B,f^*E) = B oplus B oplus B oplus B.
    $$

    On the other hand, tensoring
    $$
    0 to H^0(mathbbP^n_A,E) to A oplus A oplus A oplus A stackrel(x,y,z,w)to A to B to 0
    $$

    by $B$ (over $A$), we deduce
    $$
    H^0(mathbbP^n_A,E) otimes_A B cong Tor_2^A(B,B) cong B^oplus 6.
    $$






    share|cite|improve this answer
























      up vote
      8
      down vote



      accepted










      The answer to both questions is negative, see counterexamples below.



      1) Let $A = k[x,y,z]$, $n = 1$. Note that
      $$
      H^1(mathbbP^n_A,O(-2)) cong A.
      $$

      Consider the extension
      $$
      0 to O(-2) to E to O oplus O oplus O to 0
      $$

      whose extension class is $(x,y,z)$. Then the cohomolopgy exact sequence
      $$
      0 to H^0(mathbbP^n_A,E) to A oplus A oplus A stackrel(x,y,z)to A
      $$

      shows that $H^0(mathbbP^n_A,E)$ is reflexive but not locally free (hence not projective). In fact, this is the simplest example of a reflexive non-locally free sheaf.



      2) Take $A = k[x,y,z,w]$ and define $E$ as the extension
      $$
      0 to O(-2) to E to O oplus O oplus O oplus O to 0
      $$

      whose extension class is $(x,y,z,w)$. Let $B = k$ with the morphism $A to B$ defined by $x,y,z,w mapsto 0$. Then $f^*E cong O(-2) oplus O oplus O oplus O oplus O$, hence
      $$
      H^0(mathbbP^n_B,f^*E) = B oplus B oplus B oplus B.
      $$

      On the other hand, tensoring
      $$
      0 to H^0(mathbbP^n_A,E) to A oplus A oplus A oplus A stackrel(x,y,z,w)to A to B to 0
      $$

      by $B$ (over $A$), we deduce
      $$
      H^0(mathbbP^n_A,E) otimes_A B cong Tor_2^A(B,B) cong B^oplus 6.
      $$






      share|cite|improve this answer






















        up vote
        8
        down vote



        accepted







        up vote
        8
        down vote



        accepted






        The answer to both questions is negative, see counterexamples below.



        1) Let $A = k[x,y,z]$, $n = 1$. Note that
        $$
        H^1(mathbbP^n_A,O(-2)) cong A.
        $$

        Consider the extension
        $$
        0 to O(-2) to E to O oplus O oplus O to 0
        $$

        whose extension class is $(x,y,z)$. Then the cohomolopgy exact sequence
        $$
        0 to H^0(mathbbP^n_A,E) to A oplus A oplus A stackrel(x,y,z)to A
        $$

        shows that $H^0(mathbbP^n_A,E)$ is reflexive but not locally free (hence not projective). In fact, this is the simplest example of a reflexive non-locally free sheaf.



        2) Take $A = k[x,y,z,w]$ and define $E$ as the extension
        $$
        0 to O(-2) to E to O oplus O oplus O oplus O to 0
        $$

        whose extension class is $(x,y,z,w)$. Let $B = k$ with the morphism $A to B$ defined by $x,y,z,w mapsto 0$. Then $f^*E cong O(-2) oplus O oplus O oplus O oplus O$, hence
        $$
        H^0(mathbbP^n_B,f^*E) = B oplus B oplus B oplus B.
        $$

        On the other hand, tensoring
        $$
        0 to H^0(mathbbP^n_A,E) to A oplus A oplus A oplus A stackrel(x,y,z,w)to A to B to 0
        $$

        by $B$ (over $A$), we deduce
        $$
        H^0(mathbbP^n_A,E) otimes_A B cong Tor_2^A(B,B) cong B^oplus 6.
        $$






        share|cite|improve this answer












        The answer to both questions is negative, see counterexamples below.



        1) Let $A = k[x,y,z]$, $n = 1$. Note that
        $$
        H^1(mathbbP^n_A,O(-2)) cong A.
        $$

        Consider the extension
        $$
        0 to O(-2) to E to O oplus O oplus O to 0
        $$

        whose extension class is $(x,y,z)$. Then the cohomolopgy exact sequence
        $$
        0 to H^0(mathbbP^n_A,E) to A oplus A oplus A stackrel(x,y,z)to A
        $$

        shows that $H^0(mathbbP^n_A,E)$ is reflexive but not locally free (hence not projective). In fact, this is the simplest example of a reflexive non-locally free sheaf.



        2) Take $A = k[x,y,z,w]$ and define $E$ as the extension
        $$
        0 to O(-2) to E to O oplus O oplus O oplus O to 0
        $$

        whose extension class is $(x,y,z,w)$. Let $B = k$ with the morphism $A to B$ defined by $x,y,z,w mapsto 0$. Then $f^*E cong O(-2) oplus O oplus O oplus O oplus O$, hence
        $$
        H^0(mathbbP^n_B,f^*E) = B oplus B oplus B oplus B.
        $$

        On the other hand, tensoring
        $$
        0 to H^0(mathbbP^n_A,E) to A oplus A oplus A oplus A stackrel(x,y,z,w)to A to B to 0
        $$

        by $B$ (over $A$), we deduce
        $$
        H^0(mathbbP^n_A,E) otimes_A B cong Tor_2^A(B,B) cong B^oplus 6.
        $$







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        answered Nov 27 at 0:01









        Sasha

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        19.8k22652



























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