BASH script: declare a variable inside CASE statement to use globally
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up vote
0
down vote
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case $location in
ColocationOne)
# Define MOSES LAKE workerarray
server[0]=serverone
server[1]=servertwo
esac
echo $server[0]
How do I get this to echo: serverone
?
bash shell-script variable
add a comment |
up vote
0
down vote
favorite
case $location in
ColocationOne)
# Define MOSES LAKE workerarray
server[0]=serverone
server[1]=servertwo
esac
echo $server[0]
How do I get this to echo: serverone
?
bash shell-script variable
@Peschke I am echoing$server[0]
after my initial edit. The first was a typo. I am just trying to use a variable that I declared inside thecase
statement from outside the case statement.
– stone212
Dec 4 at 7:54
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
case $location in
ColocationOne)
# Define MOSES LAKE workerarray
server[0]=serverone
server[1]=servertwo
esac
echo $server[0]
How do I get this to echo: serverone
?
bash shell-script variable
case $location in
ColocationOne)
# Define MOSES LAKE workerarray
server[0]=serverone
server[1]=servertwo
esac
echo $server[0]
How do I get this to echo: serverone
?
bash shell-script variable
bash shell-script variable
edited Dec 4 at 7:39
asked Dec 4 at 7:33
stone212
176112
176112
@Peschke I am echoing$server[0]
after my initial edit. The first was a typo. I am just trying to use a variable that I declared inside thecase
statement from outside the case statement.
– stone212
Dec 4 at 7:54
add a comment |
@Peschke I am echoing$server[0]
after my initial edit. The first was a typo. I am just trying to use a variable that I declared inside thecase
statement from outside the case statement.
– stone212
Dec 4 at 7:54
@Peschke I am echoing
$server[0]
after my initial edit. The first was a typo. I am just trying to use a variable that I declared inside the case
statement from outside the case statement.– stone212
Dec 4 at 7:54
@Peschke I am echoing
$server[0]
after my initial edit. The first was a typo. I am just trying to use a variable that I declared inside the case
statement from outside the case statement.– stone212
Dec 4 at 7:54
add a comment |
1 Answer
1
active
oldest
votes
up vote
3
down vote
accepted
You set location
to the string ColocationOne
:
#!/bin/bash
location=ColocationOne
case $location in
ColocationOne)
# Define MOSES LAKE workerarray
server[0]=serverone
server[1]=servertwo
# or: server=( serverone servertwo )
esac
echo "$server[0]"
This script would print serverone
.
1
yes you are correct. My actual script has the quotes. My actual script referenced server[1]. My actual script had server[1] commented out. stone212 is very tired. Thank you.
– stone212
Dec 4 at 7:58
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
You set location
to the string ColocationOne
:
#!/bin/bash
location=ColocationOne
case $location in
ColocationOne)
# Define MOSES LAKE workerarray
server[0]=serverone
server[1]=servertwo
# or: server=( serverone servertwo )
esac
echo "$server[0]"
This script would print serverone
.
1
yes you are correct. My actual script has the quotes. My actual script referenced server[1]. My actual script had server[1] commented out. stone212 is very tired. Thank you.
– stone212
Dec 4 at 7:58
add a comment |
up vote
3
down vote
accepted
You set location
to the string ColocationOne
:
#!/bin/bash
location=ColocationOne
case $location in
ColocationOne)
# Define MOSES LAKE workerarray
server[0]=serverone
server[1]=servertwo
# or: server=( serverone servertwo )
esac
echo "$server[0]"
This script would print serverone
.
1
yes you are correct. My actual script has the quotes. My actual script referenced server[1]. My actual script had server[1] commented out. stone212 is very tired. Thank you.
– stone212
Dec 4 at 7:58
add a comment |
up vote
3
down vote
accepted
up vote
3
down vote
accepted
You set location
to the string ColocationOne
:
#!/bin/bash
location=ColocationOne
case $location in
ColocationOne)
# Define MOSES LAKE workerarray
server[0]=serverone
server[1]=servertwo
# or: server=( serverone servertwo )
esac
echo "$server[0]"
This script would print serverone
.
You set location
to the string ColocationOne
:
#!/bin/bash
location=ColocationOne
case $location in
ColocationOne)
# Define MOSES LAKE workerarray
server[0]=serverone
server[1]=servertwo
# or: server=( serverone servertwo )
esac
echo "$server[0]"
This script would print serverone
.
answered Dec 4 at 7:42
Kusalananda
119k16225367
119k16225367
1
yes you are correct. My actual script has the quotes. My actual script referenced server[1]. My actual script had server[1] commented out. stone212 is very tired. Thank you.
– stone212
Dec 4 at 7:58
add a comment |
1
yes you are correct. My actual script has the quotes. My actual script referenced server[1]. My actual script had server[1] commented out. stone212 is very tired. Thank you.
– stone212
Dec 4 at 7:58
1
1
yes you are correct. My actual script has the quotes. My actual script referenced server[1]. My actual script had server[1] commented out. stone212 is very tired. Thank you.
– stone212
Dec 4 at 7:58
yes you are correct. My actual script has the quotes. My actual script referenced server[1]. My actual script had server[1] commented out. stone212 is very tired. Thank you.
– stone212
Dec 4 at 7:58
add a comment |
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@Peschke I am echoing
$server[0]
after my initial edit. The first was a typo. I am just trying to use a variable that I declared inside thecase
statement from outside the case statement.– stone212
Dec 4 at 7:54