MySQL - query to show guests with same last_name + booking_date [closed]

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
1
down vote

favorite












I have a guest table and a booking table and I am attempting to query how to find guests who share the same last names with the same booking date.



The result should output their last_name and first_names without any duplicate results.



SELECT g1.first_name, 
 g2.first_name,
 g1.last_name, 
 b.booking_date
FROM guest g1, guest g2 JOIN booking b ON id=booking_id
WHERE g1.last_name = g2.last_name AND g1.id<>g2.id AND b.booking_date=b.booking_date;


When I run this, I get back the empty set.



Where am I going wrong?






mysql sql mariadb







share|improve this question















closed as off-topic by Christopher, ctrl-alt-delor, mosvy, RalfFriedl, thrig Nov 20 at 18:48



  • This question does not appear to be about Unix or Linux within the scope defined in the help center.
If this question can be reworded to fit the rules in the help center, please edit the question.












  • it has been a while, and I have not done much sql, but do you need two joins.
    – ctrl-alt-delor
    Nov 20 at 14:18










  • @ctrl-alt-delor perhaps, join g1 to b1 and g2 to b2?
    – qoph
    Nov 20 at 14:26






  • 3




    I'm voting to close this question, because it would be better served on dba.stackexchange.com
    – ctrl-alt-delor
    Nov 20 at 14:33










  • thanks, wrong exchange
    – qoph
    Nov 20 at 14:36














up vote
1
down vote

favorite












I have a guest table and a booking table and I am attempting to query how to find guests who share the same last names with the same booking date.



The result should output their last_name and first_names without any duplicate results.



SELECT g1.first_name, 
 g2.first_name,
 g1.last_name, 
 b.booking_date
FROM guest g1, guest g2 JOIN booking b ON id=booking_id
WHERE g1.last_name = g2.last_name AND g1.id<>g2.id AND b.booking_date=b.booking_date;


When I run this, I get back the empty set.



Where am I going wrong?






mysql sql mariadb







share|improve this question















closed as off-topic by Christopher, ctrl-alt-delor, mosvy, RalfFriedl, thrig Nov 20 at 18:48



  • This question does not appear to be about Unix or Linux within the scope defined in the help center.
If this question can be reworded to fit the rules in the help center, please edit the question.












  • it has been a while, and I have not done much sql, but do you need two joins.
    – ctrl-alt-delor
    Nov 20 at 14:18










  • @ctrl-alt-delor perhaps, join g1 to b1 and g2 to b2?
    – qoph
    Nov 20 at 14:26






  • 3




    I'm voting to close this question, because it would be better served on dba.stackexchange.com
    – ctrl-alt-delor
    Nov 20 at 14:33










  • thanks, wrong exchange
    – qoph
    Nov 20 at 14:36












up vote
1
down vote

favorite









up vote
1
down vote

favorite











I have a guest table and a booking table and I am attempting to query how to find guests who share the same last names with the same booking date.



The result should output their last_name and first_names without any duplicate results.



SELECT g1.first_name, 
 g2.first_name,
 g1.last_name, 
 b.booking_date
FROM guest g1, guest g2 JOIN booking b ON id=booking_id
WHERE g1.last_name = g2.last_name AND g1.id<>g2.id AND b.booking_date=b.booking_date;


When I run this, I get back the empty set.



Where am I going wrong?






mysql sql mariadb







share|improve this question















I have a guest table and a booking table and I am attempting to query how to find guests who share the same last names with the same booking date.



The result should output their last_name and first_names without any duplicate results.



SELECT g1.first_name, 
 g2.first_name,
 g1.last_name, 
 b.booking_date
FROM guest g1, guest g2 JOIN booking b ON id=booking_id
WHERE g1.last_name = g2.last_name AND g1.id<>g2.id AND b.booking_date=b.booking_date;


When I run this, I get back the empty set.



Where am I going wrong?






mysql sql mariadb




mysql sql mariadb






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 20 at 14:29









ctrl-alt-delor

10.2k41955




10.2k41955










asked Nov 20 at 13:48









qoph

135




135




closed as off-topic by Christopher, ctrl-alt-delor, mosvy, RalfFriedl, thrig Nov 20 at 18:48



  • This question does not appear to be about Unix or Linux within the scope defined in the help center.
If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by Christopher, ctrl-alt-delor, mosvy, RalfFriedl, thrig Nov 20 at 18:48



  • This question does not appear to be about Unix or Linux within the scope defined in the help center.
If this question can be reworded to fit the rules in the help center, please edit the question.











  • it has been a while, and I have not done much sql, but do you need two joins.
    – ctrl-alt-delor
    Nov 20 at 14:18










  • @ctrl-alt-delor perhaps, join g1 to b1 and g2 to b2?
    – qoph
    Nov 20 at 14:26






  • 3




    I'm voting to close this question, because it would be better served on dba.stackexchange.com
    – ctrl-alt-delor
    Nov 20 at 14:33










  • thanks, wrong exchange
    – qoph
    Nov 20 at 14:36
















  • it has been a while, and I have not done much sql, but do you need two joins.
    – ctrl-alt-delor
    Nov 20 at 14:18










  • @ctrl-alt-delor perhaps, join g1 to b1 and g2 to b2?
    – qoph
    Nov 20 at 14:26






  • 3




    I'm voting to close this question, because it would be better served on dba.stackexchange.com
    – ctrl-alt-delor
    Nov 20 at 14:33










  • thanks, wrong exchange
    – qoph
    Nov 20 at 14:36















it has been a while, and I have not done much sql, but do you need two joins.
– ctrl-alt-delor
Nov 20 at 14:18




it has been a while, and I have not done much sql, but do you need two joins.
– ctrl-alt-delor
Nov 20 at 14:18












@ctrl-alt-delor perhaps, join g1 to b1 and g2 to b2?
– qoph
Nov 20 at 14:26




@ctrl-alt-delor perhaps, join g1 to b1 and g2 to b2?
– qoph
Nov 20 at 14:26




3




3




I'm voting to close this question, because it would be better served on dba.stackexchange.com
– ctrl-alt-delor
Nov 20 at 14:33




I'm voting to close this question, because it would be better served on dba.stackexchange.com
– ctrl-alt-delor
Nov 20 at 14:33












thanks, wrong exchange
– qoph
Nov 20 at 14:36




thanks, wrong exchange
– qoph
Nov 20 at 14:36















active

oldest

votes






















active

oldest

votes













active

oldest

votes









active

oldest

votes






active

oldest

votes
-

Popular posts from this blog

How to check contact read email or not when send email to Individual?

Image
Clash Royale CLAN TAG #URR8PPP up vote 1 down vote favorite I'm using WordPress 4.9.8, CiviCRM to 5.5.1, I usually send email to contact by Search> Find contacts View contact details Action> Send email Send email ok, Contact received mail ok like picture But status only Email sent though contact read email or not. So, can CiviCRM can change status to Email read when contact read email? wordpress email share | improve this question asked Sep 26 at 0:12 ToanLuong 49 9 add a comment  |  up vote 1 down vote favorite I'm using WordPress 4.9.8, CiviCRM to 5.5.1, I usually send email to contact by Search> Find contacts View contact details Action> Send email Send email ok, Contact received mail ok like picture But status only Email sent though contact read email or not. So, can CiviCRM can change status to Email read when contact read email? wordpress email share | improve this questi...
Read more

Displaying single band from multi-band raster using QGIS

Image
Clash Royale CLAN TAG #URR8PPP 1 How can I extract a single band from multi-band raster in QGIS? I have an remote sensed image which has 6 bands (including NDVI band), I want to display each band separately, but have no idea how to do. I have seen some questions similar here but none worked for me. The original image (has 6 bands) is: I want to display the band 6 which should be like this: But I tried gdal_translate, and couldn't get the correct result. What I have got is: qgis raster multi-band share | improve this question edited Mar 5 at 0:53 Summer asked Mar 4 at 6:42 Summer Summer 23 6 Is this any help gis.stackexchange.com/questions/220658/… ? if not gis.stackexchange.com/questions/62133/… might help. – Michael Stimson Mar 4 at 6:46 Thanks for answering but when I used gdal_translate, qgis showed that 'Error 4: Kayena.tif: No such file or directory". Would you know how to fi...
Read more

How many registers does an x86_64 CPU actually have?

Image
Clash Royale CLAN TAG #URR8PPP up vote 2 down vote favorite I am currently learning reverse engineering and am studying the flags register. I had in my mind that rflags was just another name for one of the 16 general purpose registers, for example rax or rbx . But it looks like rflags is actually an additional register. So that makes 17 registers in total... how many more could there be? I have spent at least an hour on this and found numerous different answers. The best answer so far is this, which says that there are 40 registers in total. 16 General Purpose Registers 2 Status Registers 6 Code Segment Registers 16 SSE Registers 8 FPU/MMX Registers But if I add that up, I get 48. Could anybody provide an official answer on how many registers an x86_64 CPU has (e.g. an Intel i7). Additionally, I have seen references to 'hardware' and 'architectural' registers. What are those registers and how many are there? register x86-64 share | improve this...
Read more