How does a kernel mount the root partition?
Clash Royale CLAN TAG#URR8PPP
up vote
23
down vote
favorite
My question is with regards to booting a Linux system from a separate /boot partition. If most configuration files are located on a separate / partition, how does the kernel correctly mount it at boot time?
Any elaboration on this would be great. I feel as though I am missing something basic. I am mostly concerned with the process and order of operations.
Thanks!
EDIT: I think what I needed to ask was more along the lines of the dev file that is used in the root kernel parameter. For instance, say I give my root param as root=/dev/sda2. How does the kernel have a mapping of the /dev/sda2 file?
linux kernel boot mount
add a comment |
up vote
23
down vote
favorite
My question is with regards to booting a Linux system from a separate /boot partition. If most configuration files are located on a separate / partition, how does the kernel correctly mount it at boot time?
Any elaboration on this would be great. I feel as though I am missing something basic. I am mostly concerned with the process and order of operations.
Thanks!
EDIT: I think what I needed to ask was more along the lines of the dev file that is used in the root kernel parameter. For instance, say I give my root param as root=/dev/sda2. How does the kernel have a mapping of the /dev/sda2 file?
linux kernel boot mount
Though people below cover initrd, there is little discussion about why initrd is used. My impression is that is because distributions like Debian want to use one kernel on many different machines of the same architecture, but possibly widely different hardware. This is made possible by modularizing hardware support via kernel modules. The initrd does not require much hardware support to boot, and once it does, it loads the necessary hardware modules to proceed. Elaborations/corrections to this are appreciated.
– Faheem Mitha
Mar 26 '11 at 18:32
You can't mount /boot without having / mounted first, since there is no /boot directory without /.
– psusi
Aug 4 '11 at 15:02
add a comment |
up vote
23
down vote
favorite
up vote
23
down vote
favorite
My question is with regards to booting a Linux system from a separate /boot partition. If most configuration files are located on a separate / partition, how does the kernel correctly mount it at boot time?
Any elaboration on this would be great. I feel as though I am missing something basic. I am mostly concerned with the process and order of operations.
Thanks!
EDIT: I think what I needed to ask was more along the lines of the dev file that is used in the root kernel parameter. For instance, say I give my root param as root=/dev/sda2. How does the kernel have a mapping of the /dev/sda2 file?
linux kernel boot mount
My question is with regards to booting a Linux system from a separate /boot partition. If most configuration files are located on a separate / partition, how does the kernel correctly mount it at boot time?
Any elaboration on this would be great. I feel as though I am missing something basic. I am mostly concerned with the process and order of operations.
Thanks!
EDIT: I think what I needed to ask was more along the lines of the dev file that is used in the root kernel parameter. For instance, say I give my root param as root=/dev/sda2. How does the kernel have a mapping of the /dev/sda2 file?
linux kernel boot mount
linux kernel boot mount
edited Mar 23 '11 at 18:34
asked Mar 23 '11 at 12:26
Mr. Shickadance
2,19961825
2,19961825
Though people below cover initrd, there is little discussion about why initrd is used. My impression is that is because distributions like Debian want to use one kernel on many different machines of the same architecture, but possibly widely different hardware. This is made possible by modularizing hardware support via kernel modules. The initrd does not require much hardware support to boot, and once it does, it loads the necessary hardware modules to proceed. Elaborations/corrections to this are appreciated.
– Faheem Mitha
Mar 26 '11 at 18:32
You can't mount /boot without having / mounted first, since there is no /boot directory without /.
– psusi
Aug 4 '11 at 15:02
add a comment |
Though people below cover initrd, there is little discussion about why initrd is used. My impression is that is because distributions like Debian want to use one kernel on many different machines of the same architecture, but possibly widely different hardware. This is made possible by modularizing hardware support via kernel modules. The initrd does not require much hardware support to boot, and once it does, it loads the necessary hardware modules to proceed. Elaborations/corrections to this are appreciated.
– Faheem Mitha
Mar 26 '11 at 18:32
You can't mount /boot without having / mounted first, since there is no /boot directory without /.
– psusi
Aug 4 '11 at 15:02
Though people below cover initrd, there is little discussion about why initrd is used. My impression is that is because distributions like Debian want to use one kernel on many different machines of the same architecture, but possibly widely different hardware. This is made possible by modularizing hardware support via kernel modules. The initrd does not require much hardware support to boot, and once it does, it loads the necessary hardware modules to proceed. Elaborations/corrections to this are appreciated.
– Faheem Mitha
Mar 26 '11 at 18:32
Though people below cover initrd, there is little discussion about why initrd is used. My impression is that is because distributions like Debian want to use one kernel on many different machines of the same architecture, but possibly widely different hardware. This is made possible by modularizing hardware support via kernel modules. The initrd does not require much hardware support to boot, and once it does, it loads the necessary hardware modules to proceed. Elaborations/corrections to this are appreciated.
– Faheem Mitha
Mar 26 '11 at 18:32
You can't mount /boot without having / mounted first, since there is no /boot directory without /.
– psusi
Aug 4 '11 at 15:02
You can't mount /boot without having / mounted first, since there is no /boot directory without /.
– psusi
Aug 4 '11 at 15:02
add a comment |
6 Answers
6
active
oldest
votes
up vote
17
down vote
accepted
Linux initially boots with a ramdisk (called an initrd
, for "INITial RamDisk") as /
. This disk has just enough on it to be able to find the real root partition (including any driver and filesystem modules required). It mounts the root partition onto a temporary mount point on the initrd
, then invokes pivot_root(8)
to swap the root and temporary mount points, leaving the initrd
in a position to be umount
ed and the actual root filesystem on /
.
1
What if you don't have an initrd like LFS (linuxfromscratch.org)?
– Mr. Shickadance
Mar 23 '11 at 12:38
@Mr. Shickadance: Not having looked into how LFS does things, I would guess that they make sure the kernel has all necessary modules compiled into it (or loaded via GRUB 2, which possibility is new enough that not many distributions have noticed it yet) so it can start on the actual root partition.
– geekosaur
Mar 23 '11 at 12:55
3
@mr. Shickadance. It's not just LFS that doesn't have an initrd. Anyone who compiles their own kernel has the option of not using an initrd, which is what I do on Gentoo.
– jonescb
Mar 23 '11 at 19:44
1
@Faheem: grub2 modules are not the same as kernel modules. I see some ability for grub2 to load kernel modules, but one thing I don't know is whether that will work for the Linux kernel or only for *BSD (where the bootloader loading kernel modules is normal). I suspect the kernel needs to be taught where to find the address map for loaded modules, and everyone needs to move to grub2 (grub1 is still standard in some distributions).
– geekosaur
Mar 26 '11 at 18:41
1
The initrd has been replaced by initramfs, since pivot_root was regarded as a dirty hack.
– psusi
Aug 4 '11 at 14:32
|
show 1 more comment
up vote
37
down vote
In ancient times, the kernel was hard coded to know the device major/minor number of the root fs and mounted that device after initializing all device drivers, which were built into the kernel. The rdev
utility could be used to modify the root device number in the kernel image without having to recompile it.
Eventually boot loaders came along and could pass a command line to the kernel. If the root=
argument was passed, that told the kernel where the root fs was instead of the built in value. The drivers needed to access that still had to be built into the kernel. While the argument looks like a normal device node in the /dev
directory, there obviously is no /dev
directory before the root fs is mounted, so the kernel can not look up a dev node there. Instead, certain well known device names are hard coded into the kernel so the string can be translated to the device number. Because of this, the kernel can recognize things like /dev/sda1
, but not more exotic things like /dev/mapper/vg0-root
or a volume UUID.
Later, the initrd
came into the picture. Along with the kernel, the boot loader would load the initrd
image, which was some kind of compressed filesystem image (gzipped ext2 image, gzipped romfs image, squashfs finally became dominant). The kernel would decompress this image into a ramdisk and mount the ramdisk as the root fs. This image contained some additional drivers and boot scripts instead of a real init
. These boot scripts performed various tasks to recognize hardware, activate things like raid arrays and LVM, detect UUIDs, and parse the kernel command line to find the real root, which could now be specified by UUID, volume label and other advanced things. It then mounted the real root fs in /initrd
, then executed the pivot_root
system call to have the kernel swap /
and /initrd
, then exec /sbin/init
on the real root, which would then unmount /initrd
and free the ramdisk.
Finally, today we have the initramfs
. This is similar to the initrd
, but instead of being a compressed filesystem image that is loaded into a ramdisk, it is a compressed cpio archive. A tmpfs is mounted as the root, and the archive is extracted there. Instead of using pivot_root
, which was regarded as a dirty hack, the initramfs
boot scripts mount the real root in /root
, delete all files in the tmpfs root, then chroot
into /root
, and exec /sbin/init
.
1
After the chroot, is the tmpfs automatically unmounted? Does it just disappear?
– jiggunjer
Jan 17 '17 at 3:54
@jiggunjer, no, it is still there, it is just empty ( aside from containing the /root directory ), and no longer used.
– psusi
Jan 18 '17 at 13:43
I learned something new about every iteration of root fs that you mentioned. Great answer!
– jpaugh
Sep 2 '17 at 1:04
add a comment |
up vote
3
down vote
Sounds like you're asking how does the kernel "know" which partition is the root partition, without access to configuration files on /etc.
The kernel can accept command line arguments like any other program. GRUB, or most other bootloaders can accept command line arguments as user input, or store them and make various combinations of command line arguments available via a menu. The bootloader passes the command line arguments to the kernel when it loads it (I don't know the name or mechanics of this convention but it's probably similar to how an application receives command line arguments from a calling process in a running kernel).
One of those command line options is root
, where you can specify the root filesystem, i.e. root=/dev/sda1
.
If the kernel uses an initrd, the bootloader is responsible for telling the kernel where it is, or putting the initrd in a standard memory location (I think) - that's at least the way it works on my Guruplug.
It's entirely possible to not specify one and then have your kernel panic immediately after starting complaining that it can't find a root filesystem.
There might be other ways of passing this option to the kernel.
3
This is the right explanation when there's no initrd/initramfs, but it's missing a piece of the puzzle. Normally the kernel identifies a device such as/dev/sda1
because it's an entry in a filesystem. You could docp -p /dev/sda1 /tmp/foo
and/tmp/foo
would represent the same device. On the kernel command line, the kernel uses a built-in parser that follows the usual device naming convention:sda1
means the first partition of the first SCSI-like disk.
– Gilles
Mar 23 '11 at 20:44
@Gilles so modern kernels still can't handle mounting a volume based on UUID? withoutinitrd
orinitramfs
I mean. It has to be a "simple" partition in the/dev/sdx
form?
– jiggunjer
Jan 17 '17 at 4:00
1
@jiggunjer Modern kernels do support searching for a volume by UUID. Seeinit/do_mounts.c
.
– Gilles
Jan 17 '17 at 13:41
add a comment |
up vote
1
down vote
Grub mounts the /boot
partition and then executes the kernel. In Grub's configuration, it tells the kernel what to use as the root device.
For example in Grub's menu.lst
:
kernel /boot/linux root=/dev/sda2
add a comment |
up vote
1
down vote
C'mon, GRUB doesn't "mount" /boot, it just reads 'menu.lst' and some modules, it isn't part of LINUX kernel either. When you call the kernel, you will pass a "root" argument with the root partition. At worst, the kernel knows that just /boot has been mounted (LOL).
Next: geekosaur is right, Linux uses an initial ramdisk in compressed image format, and then mounts the real root filesystem by calling pivot_root
. So Linux starts running from an image, and then from your local disk drive.
Grub most definitely does have the ability to 'mount' a filesystem, especially in grub2. Of course, all it's capable of /doing/ with it is look for bootable kernels of one stripe or another, but that's still mounting. Also, linux doesn't require an initrd unless your kernel compiled drivers crucial to your hard drive as modules.
– Shadur
Mar 23 '11 at 12:55
5
ibm.com/developerworks/linux/library/l-linuxboot This is a fairly concise summary of what the Linux Kernel does when booting.
– jsbillings
Mar 23 '11 at 12:58
2
@Shadur, from the mount manpage: All files accessible in a Unix system are arranged in one big tree, the file hierarchy, rooted at /. These files can be spread out over several devices. The mount command serves to attach the file system found on some device to the big file tree. - Since filesystems used by GRUB aren't attached to the file hierarchy, it's NOT mounting.
– D4RIO
Mar 23 '11 at 13:02
1
@Shadur, BTW: It's obvious that initrd isn't necessary since it's just another root filesystem, but it's generally used as small boot-time root, since kernel loads the necessary to boot, then boots, and finally loads everything else.
– D4RIO
Mar 23 '11 at 13:10
@d4rio They're mounted by GRUB, not linux -- it gets easier to comprehend when you regard grub as a microkernel OS of its own rather than just a bootloader.
– Shadur
Mar 23 '11 at 13:21
|
show 2 more comments
up vote
1
down vote
The boot loader, be it grub or lilo or whatever, tells the kernel where to look with the root=
flag, and optionally loads an initial ramdisk into memory via initrd
before booting the kernel.
The kernel then loads, tests its hardware and device drivers and looks around the system for what it can see (you can review this diagnostic info by typing dmesg
; nowadays it likely scrolls by way too fast to see) then attempts to mount the partition mentioned in the root=
parameter.
If an initrd is present, it's mounted first and any modules/device drivers on it are loaded and probed out before the root filesystem is mounted. This way you can compile the drivers for your hard drives as modules and still be able to boot.
add a comment |
6 Answers
6
active
oldest
votes
6 Answers
6
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
17
down vote
accepted
Linux initially boots with a ramdisk (called an initrd
, for "INITial RamDisk") as /
. This disk has just enough on it to be able to find the real root partition (including any driver and filesystem modules required). It mounts the root partition onto a temporary mount point on the initrd
, then invokes pivot_root(8)
to swap the root and temporary mount points, leaving the initrd
in a position to be umount
ed and the actual root filesystem on /
.
1
What if you don't have an initrd like LFS (linuxfromscratch.org)?
– Mr. Shickadance
Mar 23 '11 at 12:38
@Mr. Shickadance: Not having looked into how LFS does things, I would guess that they make sure the kernel has all necessary modules compiled into it (or loaded via GRUB 2, which possibility is new enough that not many distributions have noticed it yet) so it can start on the actual root partition.
– geekosaur
Mar 23 '11 at 12:55
3
@mr. Shickadance. It's not just LFS that doesn't have an initrd. Anyone who compiles their own kernel has the option of not using an initrd, which is what I do on Gentoo.
– jonescb
Mar 23 '11 at 19:44
1
@Faheem: grub2 modules are not the same as kernel modules. I see some ability for grub2 to load kernel modules, but one thing I don't know is whether that will work for the Linux kernel or only for *BSD (where the bootloader loading kernel modules is normal). I suspect the kernel needs to be taught where to find the address map for loaded modules, and everyone needs to move to grub2 (grub1 is still standard in some distributions).
– geekosaur
Mar 26 '11 at 18:41
1
The initrd has been replaced by initramfs, since pivot_root was regarded as a dirty hack.
– psusi
Aug 4 '11 at 14:32
|
show 1 more comment
up vote
17
down vote
accepted
Linux initially boots with a ramdisk (called an initrd
, for "INITial RamDisk") as /
. This disk has just enough on it to be able to find the real root partition (including any driver and filesystem modules required). It mounts the root partition onto a temporary mount point on the initrd
, then invokes pivot_root(8)
to swap the root and temporary mount points, leaving the initrd
in a position to be umount
ed and the actual root filesystem on /
.
1
What if you don't have an initrd like LFS (linuxfromscratch.org)?
– Mr. Shickadance
Mar 23 '11 at 12:38
@Mr. Shickadance: Not having looked into how LFS does things, I would guess that they make sure the kernel has all necessary modules compiled into it (or loaded via GRUB 2, which possibility is new enough that not many distributions have noticed it yet) so it can start on the actual root partition.
– geekosaur
Mar 23 '11 at 12:55
3
@mr. Shickadance. It's not just LFS that doesn't have an initrd. Anyone who compiles their own kernel has the option of not using an initrd, which is what I do on Gentoo.
– jonescb
Mar 23 '11 at 19:44
1
@Faheem: grub2 modules are not the same as kernel modules. I see some ability for grub2 to load kernel modules, but one thing I don't know is whether that will work for the Linux kernel or only for *BSD (where the bootloader loading kernel modules is normal). I suspect the kernel needs to be taught where to find the address map for loaded modules, and everyone needs to move to grub2 (grub1 is still standard in some distributions).
– geekosaur
Mar 26 '11 at 18:41
1
The initrd has been replaced by initramfs, since pivot_root was regarded as a dirty hack.
– psusi
Aug 4 '11 at 14:32
|
show 1 more comment
up vote
17
down vote
accepted
up vote
17
down vote
accepted
Linux initially boots with a ramdisk (called an initrd
, for "INITial RamDisk") as /
. This disk has just enough on it to be able to find the real root partition (including any driver and filesystem modules required). It mounts the root partition onto a temporary mount point on the initrd
, then invokes pivot_root(8)
to swap the root and temporary mount points, leaving the initrd
in a position to be umount
ed and the actual root filesystem on /
.
Linux initially boots with a ramdisk (called an initrd
, for "INITial RamDisk") as /
. This disk has just enough on it to be able to find the real root partition (including any driver and filesystem modules required). It mounts the root partition onto a temporary mount point on the initrd
, then invokes pivot_root(8)
to swap the root and temporary mount points, leaving the initrd
in a position to be umount
ed and the actual root filesystem on /
.
edited Mar 26 '11 at 17:57
Kevin M
1,71211212
1,71211212
answered Mar 23 '11 at 12:31
geekosaur
22.2k25853
22.2k25853
1
What if you don't have an initrd like LFS (linuxfromscratch.org)?
– Mr. Shickadance
Mar 23 '11 at 12:38
@Mr. Shickadance: Not having looked into how LFS does things, I would guess that they make sure the kernel has all necessary modules compiled into it (or loaded via GRUB 2, which possibility is new enough that not many distributions have noticed it yet) so it can start on the actual root partition.
– geekosaur
Mar 23 '11 at 12:55
3
@mr. Shickadance. It's not just LFS that doesn't have an initrd. Anyone who compiles their own kernel has the option of not using an initrd, which is what I do on Gentoo.
– jonescb
Mar 23 '11 at 19:44
1
@Faheem: grub2 modules are not the same as kernel modules. I see some ability for grub2 to load kernel modules, but one thing I don't know is whether that will work for the Linux kernel or only for *BSD (where the bootloader loading kernel modules is normal). I suspect the kernel needs to be taught where to find the address map for loaded modules, and everyone needs to move to grub2 (grub1 is still standard in some distributions).
– geekosaur
Mar 26 '11 at 18:41
1
The initrd has been replaced by initramfs, since pivot_root was regarded as a dirty hack.
– psusi
Aug 4 '11 at 14:32
|
show 1 more comment
1
What if you don't have an initrd like LFS (linuxfromscratch.org)?
– Mr. Shickadance
Mar 23 '11 at 12:38
@Mr. Shickadance: Not having looked into how LFS does things, I would guess that they make sure the kernel has all necessary modules compiled into it (or loaded via GRUB 2, which possibility is new enough that not many distributions have noticed it yet) so it can start on the actual root partition.
– geekosaur
Mar 23 '11 at 12:55
3
@mr. Shickadance. It's not just LFS that doesn't have an initrd. Anyone who compiles their own kernel has the option of not using an initrd, which is what I do on Gentoo.
– jonescb
Mar 23 '11 at 19:44
1
@Faheem: grub2 modules are not the same as kernel modules. I see some ability for grub2 to load kernel modules, but one thing I don't know is whether that will work for the Linux kernel or only for *BSD (where the bootloader loading kernel modules is normal). I suspect the kernel needs to be taught where to find the address map for loaded modules, and everyone needs to move to grub2 (grub1 is still standard in some distributions).
– geekosaur
Mar 26 '11 at 18:41
1
The initrd has been replaced by initramfs, since pivot_root was regarded as a dirty hack.
– psusi
Aug 4 '11 at 14:32
1
1
What if you don't have an initrd like LFS (linuxfromscratch.org)?
– Mr. Shickadance
Mar 23 '11 at 12:38
What if you don't have an initrd like LFS (linuxfromscratch.org)?
– Mr. Shickadance
Mar 23 '11 at 12:38
@Mr. Shickadance: Not having looked into how LFS does things, I would guess that they make sure the kernel has all necessary modules compiled into it (or loaded via GRUB 2, which possibility is new enough that not many distributions have noticed it yet) so it can start on the actual root partition.
– geekosaur
Mar 23 '11 at 12:55
@Mr. Shickadance: Not having looked into how LFS does things, I would guess that they make sure the kernel has all necessary modules compiled into it (or loaded via GRUB 2, which possibility is new enough that not many distributions have noticed it yet) so it can start on the actual root partition.
– geekosaur
Mar 23 '11 at 12:55
3
3
@mr. Shickadance. It's not just LFS that doesn't have an initrd. Anyone who compiles their own kernel has the option of not using an initrd, which is what I do on Gentoo.
– jonescb
Mar 23 '11 at 19:44
@mr. Shickadance. It's not just LFS that doesn't have an initrd. Anyone who compiles their own kernel has the option of not using an initrd, which is what I do on Gentoo.
– jonescb
Mar 23 '11 at 19:44
1
1
@Faheem: grub2 modules are not the same as kernel modules. I see some ability for grub2 to load kernel modules, but one thing I don't know is whether that will work for the Linux kernel or only for *BSD (where the bootloader loading kernel modules is normal). I suspect the kernel needs to be taught where to find the address map for loaded modules, and everyone needs to move to grub2 (grub1 is still standard in some distributions).
– geekosaur
Mar 26 '11 at 18:41
@Faheem: grub2 modules are not the same as kernel modules. I see some ability for grub2 to load kernel modules, but one thing I don't know is whether that will work for the Linux kernel or only for *BSD (where the bootloader loading kernel modules is normal). I suspect the kernel needs to be taught where to find the address map for loaded modules, and everyone needs to move to grub2 (grub1 is still standard in some distributions).
– geekosaur
Mar 26 '11 at 18:41
1
1
The initrd has been replaced by initramfs, since pivot_root was regarded as a dirty hack.
– psusi
Aug 4 '11 at 14:32
The initrd has been replaced by initramfs, since pivot_root was regarded as a dirty hack.
– psusi
Aug 4 '11 at 14:32
|
show 1 more comment
up vote
37
down vote
In ancient times, the kernel was hard coded to know the device major/minor number of the root fs and mounted that device after initializing all device drivers, which were built into the kernel. The rdev
utility could be used to modify the root device number in the kernel image without having to recompile it.
Eventually boot loaders came along and could pass a command line to the kernel. If the root=
argument was passed, that told the kernel where the root fs was instead of the built in value. The drivers needed to access that still had to be built into the kernel. While the argument looks like a normal device node in the /dev
directory, there obviously is no /dev
directory before the root fs is mounted, so the kernel can not look up a dev node there. Instead, certain well known device names are hard coded into the kernel so the string can be translated to the device number. Because of this, the kernel can recognize things like /dev/sda1
, but not more exotic things like /dev/mapper/vg0-root
or a volume UUID.
Later, the initrd
came into the picture. Along with the kernel, the boot loader would load the initrd
image, which was some kind of compressed filesystem image (gzipped ext2 image, gzipped romfs image, squashfs finally became dominant). The kernel would decompress this image into a ramdisk and mount the ramdisk as the root fs. This image contained some additional drivers and boot scripts instead of a real init
. These boot scripts performed various tasks to recognize hardware, activate things like raid arrays and LVM, detect UUIDs, and parse the kernel command line to find the real root, which could now be specified by UUID, volume label and other advanced things. It then mounted the real root fs in /initrd
, then executed the pivot_root
system call to have the kernel swap /
and /initrd
, then exec /sbin/init
on the real root, which would then unmount /initrd
and free the ramdisk.
Finally, today we have the initramfs
. This is similar to the initrd
, but instead of being a compressed filesystem image that is loaded into a ramdisk, it is a compressed cpio archive. A tmpfs is mounted as the root, and the archive is extracted there. Instead of using pivot_root
, which was regarded as a dirty hack, the initramfs
boot scripts mount the real root in /root
, delete all files in the tmpfs root, then chroot
into /root
, and exec /sbin/init
.
1
After the chroot, is the tmpfs automatically unmounted? Does it just disappear?
– jiggunjer
Jan 17 '17 at 3:54
@jiggunjer, no, it is still there, it is just empty ( aside from containing the /root directory ), and no longer used.
– psusi
Jan 18 '17 at 13:43
I learned something new about every iteration of root fs that you mentioned. Great answer!
– jpaugh
Sep 2 '17 at 1:04
add a comment |
up vote
37
down vote
In ancient times, the kernel was hard coded to know the device major/minor number of the root fs and mounted that device after initializing all device drivers, which were built into the kernel. The rdev
utility could be used to modify the root device number in the kernel image without having to recompile it.
Eventually boot loaders came along and could pass a command line to the kernel. If the root=
argument was passed, that told the kernel where the root fs was instead of the built in value. The drivers needed to access that still had to be built into the kernel. While the argument looks like a normal device node in the /dev
directory, there obviously is no /dev
directory before the root fs is mounted, so the kernel can not look up a dev node there. Instead, certain well known device names are hard coded into the kernel so the string can be translated to the device number. Because of this, the kernel can recognize things like /dev/sda1
, but not more exotic things like /dev/mapper/vg0-root
or a volume UUID.
Later, the initrd
came into the picture. Along with the kernel, the boot loader would load the initrd
image, which was some kind of compressed filesystem image (gzipped ext2 image, gzipped romfs image, squashfs finally became dominant). The kernel would decompress this image into a ramdisk and mount the ramdisk as the root fs. This image contained some additional drivers and boot scripts instead of a real init
. These boot scripts performed various tasks to recognize hardware, activate things like raid arrays and LVM, detect UUIDs, and parse the kernel command line to find the real root, which could now be specified by UUID, volume label and other advanced things. It then mounted the real root fs in /initrd
, then executed the pivot_root
system call to have the kernel swap /
and /initrd
, then exec /sbin/init
on the real root, which would then unmount /initrd
and free the ramdisk.
Finally, today we have the initramfs
. This is similar to the initrd
, but instead of being a compressed filesystem image that is loaded into a ramdisk, it is a compressed cpio archive. A tmpfs is mounted as the root, and the archive is extracted there. Instead of using pivot_root
, which was regarded as a dirty hack, the initramfs
boot scripts mount the real root in /root
, delete all files in the tmpfs root, then chroot
into /root
, and exec /sbin/init
.
1
After the chroot, is the tmpfs automatically unmounted? Does it just disappear?
– jiggunjer
Jan 17 '17 at 3:54
@jiggunjer, no, it is still there, it is just empty ( aside from containing the /root directory ), and no longer used.
– psusi
Jan 18 '17 at 13:43
I learned something new about every iteration of root fs that you mentioned. Great answer!
– jpaugh
Sep 2 '17 at 1:04
add a comment |
up vote
37
down vote
up vote
37
down vote
In ancient times, the kernel was hard coded to know the device major/minor number of the root fs and mounted that device after initializing all device drivers, which were built into the kernel. The rdev
utility could be used to modify the root device number in the kernel image without having to recompile it.
Eventually boot loaders came along and could pass a command line to the kernel. If the root=
argument was passed, that told the kernel where the root fs was instead of the built in value. The drivers needed to access that still had to be built into the kernel. While the argument looks like a normal device node in the /dev
directory, there obviously is no /dev
directory before the root fs is mounted, so the kernel can not look up a dev node there. Instead, certain well known device names are hard coded into the kernel so the string can be translated to the device number. Because of this, the kernel can recognize things like /dev/sda1
, but not more exotic things like /dev/mapper/vg0-root
or a volume UUID.
Later, the initrd
came into the picture. Along with the kernel, the boot loader would load the initrd
image, which was some kind of compressed filesystem image (gzipped ext2 image, gzipped romfs image, squashfs finally became dominant). The kernel would decompress this image into a ramdisk and mount the ramdisk as the root fs. This image contained some additional drivers and boot scripts instead of a real init
. These boot scripts performed various tasks to recognize hardware, activate things like raid arrays and LVM, detect UUIDs, and parse the kernel command line to find the real root, which could now be specified by UUID, volume label and other advanced things. It then mounted the real root fs in /initrd
, then executed the pivot_root
system call to have the kernel swap /
and /initrd
, then exec /sbin/init
on the real root, which would then unmount /initrd
and free the ramdisk.
Finally, today we have the initramfs
. This is similar to the initrd
, but instead of being a compressed filesystem image that is loaded into a ramdisk, it is a compressed cpio archive. A tmpfs is mounted as the root, and the archive is extracted there. Instead of using pivot_root
, which was regarded as a dirty hack, the initramfs
boot scripts mount the real root in /root
, delete all files in the tmpfs root, then chroot
into /root
, and exec /sbin/init
.
In ancient times, the kernel was hard coded to know the device major/minor number of the root fs and mounted that device after initializing all device drivers, which were built into the kernel. The rdev
utility could be used to modify the root device number in the kernel image without having to recompile it.
Eventually boot loaders came along and could pass a command line to the kernel. If the root=
argument was passed, that told the kernel where the root fs was instead of the built in value. The drivers needed to access that still had to be built into the kernel. While the argument looks like a normal device node in the /dev
directory, there obviously is no /dev
directory before the root fs is mounted, so the kernel can not look up a dev node there. Instead, certain well known device names are hard coded into the kernel so the string can be translated to the device number. Because of this, the kernel can recognize things like /dev/sda1
, but not more exotic things like /dev/mapper/vg0-root
or a volume UUID.
Later, the initrd
came into the picture. Along with the kernel, the boot loader would load the initrd
image, which was some kind of compressed filesystem image (gzipped ext2 image, gzipped romfs image, squashfs finally became dominant). The kernel would decompress this image into a ramdisk and mount the ramdisk as the root fs. This image contained some additional drivers and boot scripts instead of a real init
. These boot scripts performed various tasks to recognize hardware, activate things like raid arrays and LVM, detect UUIDs, and parse the kernel command line to find the real root, which could now be specified by UUID, volume label and other advanced things. It then mounted the real root fs in /initrd
, then executed the pivot_root
system call to have the kernel swap /
and /initrd
, then exec /sbin/init
on the real root, which would then unmount /initrd
and free the ramdisk.
Finally, today we have the initramfs
. This is similar to the initrd
, but instead of being a compressed filesystem image that is loaded into a ramdisk, it is a compressed cpio archive. A tmpfs is mounted as the root, and the archive is extracted there. Instead of using pivot_root
, which was regarded as a dirty hack, the initramfs
boot scripts mount the real root in /root
, delete all files in the tmpfs root, then chroot
into /root
, and exec /sbin/init
.
edited Jan 23 '17 at 10:06
Benoit Duffez
236211
236211
answered Aug 4 '11 at 14:58
psusi
13.4k22439
13.4k22439
1
After the chroot, is the tmpfs automatically unmounted? Does it just disappear?
– jiggunjer
Jan 17 '17 at 3:54
@jiggunjer, no, it is still there, it is just empty ( aside from containing the /root directory ), and no longer used.
– psusi
Jan 18 '17 at 13:43
I learned something new about every iteration of root fs that you mentioned. Great answer!
– jpaugh
Sep 2 '17 at 1:04
add a comment |
1
After the chroot, is the tmpfs automatically unmounted? Does it just disappear?
– jiggunjer
Jan 17 '17 at 3:54
@jiggunjer, no, it is still there, it is just empty ( aside from containing the /root directory ), and no longer used.
– psusi
Jan 18 '17 at 13:43
I learned something new about every iteration of root fs that you mentioned. Great answer!
– jpaugh
Sep 2 '17 at 1:04
1
1
After the chroot, is the tmpfs automatically unmounted? Does it just disappear?
– jiggunjer
Jan 17 '17 at 3:54
After the chroot, is the tmpfs automatically unmounted? Does it just disappear?
– jiggunjer
Jan 17 '17 at 3:54
@jiggunjer, no, it is still there, it is just empty ( aside from containing the /root directory ), and no longer used.
– psusi
Jan 18 '17 at 13:43
@jiggunjer, no, it is still there, it is just empty ( aside from containing the /root directory ), and no longer used.
– psusi
Jan 18 '17 at 13:43
I learned something new about every iteration of root fs that you mentioned. Great answer!
– jpaugh
Sep 2 '17 at 1:04
I learned something new about every iteration of root fs that you mentioned. Great answer!
– jpaugh
Sep 2 '17 at 1:04
add a comment |
up vote
3
down vote
Sounds like you're asking how does the kernel "know" which partition is the root partition, without access to configuration files on /etc.
The kernel can accept command line arguments like any other program. GRUB, or most other bootloaders can accept command line arguments as user input, or store them and make various combinations of command line arguments available via a menu. The bootloader passes the command line arguments to the kernel when it loads it (I don't know the name or mechanics of this convention but it's probably similar to how an application receives command line arguments from a calling process in a running kernel).
One of those command line options is root
, where you can specify the root filesystem, i.e. root=/dev/sda1
.
If the kernel uses an initrd, the bootloader is responsible for telling the kernel where it is, or putting the initrd in a standard memory location (I think) - that's at least the way it works on my Guruplug.
It's entirely possible to not specify one and then have your kernel panic immediately after starting complaining that it can't find a root filesystem.
There might be other ways of passing this option to the kernel.
3
This is the right explanation when there's no initrd/initramfs, but it's missing a piece of the puzzle. Normally the kernel identifies a device such as/dev/sda1
because it's an entry in a filesystem. You could docp -p /dev/sda1 /tmp/foo
and/tmp/foo
would represent the same device. On the kernel command line, the kernel uses a built-in parser that follows the usual device naming convention:sda1
means the first partition of the first SCSI-like disk.
– Gilles
Mar 23 '11 at 20:44
@Gilles so modern kernels still can't handle mounting a volume based on UUID? withoutinitrd
orinitramfs
I mean. It has to be a "simple" partition in the/dev/sdx
form?
– jiggunjer
Jan 17 '17 at 4:00
1
@jiggunjer Modern kernels do support searching for a volume by UUID. Seeinit/do_mounts.c
.
– Gilles
Jan 17 '17 at 13:41
add a comment |
up vote
3
down vote
Sounds like you're asking how does the kernel "know" which partition is the root partition, without access to configuration files on /etc.
The kernel can accept command line arguments like any other program. GRUB, or most other bootloaders can accept command line arguments as user input, or store them and make various combinations of command line arguments available via a menu. The bootloader passes the command line arguments to the kernel when it loads it (I don't know the name or mechanics of this convention but it's probably similar to how an application receives command line arguments from a calling process in a running kernel).
One of those command line options is root
, where you can specify the root filesystem, i.e. root=/dev/sda1
.
If the kernel uses an initrd, the bootloader is responsible for telling the kernel where it is, or putting the initrd in a standard memory location (I think) - that's at least the way it works on my Guruplug.
It's entirely possible to not specify one and then have your kernel panic immediately after starting complaining that it can't find a root filesystem.
There might be other ways of passing this option to the kernel.
3
This is the right explanation when there's no initrd/initramfs, but it's missing a piece of the puzzle. Normally the kernel identifies a device such as/dev/sda1
because it's an entry in a filesystem. You could docp -p /dev/sda1 /tmp/foo
and/tmp/foo
would represent the same device. On the kernel command line, the kernel uses a built-in parser that follows the usual device naming convention:sda1
means the first partition of the first SCSI-like disk.
– Gilles
Mar 23 '11 at 20:44
@Gilles so modern kernels still can't handle mounting a volume based on UUID? withoutinitrd
orinitramfs
I mean. It has to be a "simple" partition in the/dev/sdx
form?
– jiggunjer
Jan 17 '17 at 4:00
1
@jiggunjer Modern kernels do support searching for a volume by UUID. Seeinit/do_mounts.c
.
– Gilles
Jan 17 '17 at 13:41
add a comment |
up vote
3
down vote
up vote
3
down vote
Sounds like you're asking how does the kernel "know" which partition is the root partition, without access to configuration files on /etc.
The kernel can accept command line arguments like any other program. GRUB, or most other bootloaders can accept command line arguments as user input, or store them and make various combinations of command line arguments available via a menu. The bootloader passes the command line arguments to the kernel when it loads it (I don't know the name or mechanics of this convention but it's probably similar to how an application receives command line arguments from a calling process in a running kernel).
One of those command line options is root
, where you can specify the root filesystem, i.e. root=/dev/sda1
.
If the kernel uses an initrd, the bootloader is responsible for telling the kernel where it is, or putting the initrd in a standard memory location (I think) - that's at least the way it works on my Guruplug.
It's entirely possible to not specify one and then have your kernel panic immediately after starting complaining that it can't find a root filesystem.
There might be other ways of passing this option to the kernel.
Sounds like you're asking how does the kernel "know" which partition is the root partition, without access to configuration files on /etc.
The kernel can accept command line arguments like any other program. GRUB, or most other bootloaders can accept command line arguments as user input, or store them and make various combinations of command line arguments available via a menu. The bootloader passes the command line arguments to the kernel when it loads it (I don't know the name or mechanics of this convention but it's probably similar to how an application receives command line arguments from a calling process in a running kernel).
One of those command line options is root
, where you can specify the root filesystem, i.e. root=/dev/sda1
.
If the kernel uses an initrd, the bootloader is responsible for telling the kernel where it is, or putting the initrd in a standard memory location (I think) - that's at least the way it works on my Guruplug.
It's entirely possible to not specify one and then have your kernel panic immediately after starting complaining that it can't find a root filesystem.
There might be other ways of passing this option to the kernel.
answered Mar 23 '11 at 15:19
LawrenceC
8,41222240
8,41222240
3
This is the right explanation when there's no initrd/initramfs, but it's missing a piece of the puzzle. Normally the kernel identifies a device such as/dev/sda1
because it's an entry in a filesystem. You could docp -p /dev/sda1 /tmp/foo
and/tmp/foo
would represent the same device. On the kernel command line, the kernel uses a built-in parser that follows the usual device naming convention:sda1
means the first partition of the first SCSI-like disk.
– Gilles
Mar 23 '11 at 20:44
@Gilles so modern kernels still can't handle mounting a volume based on UUID? withoutinitrd
orinitramfs
I mean. It has to be a "simple" partition in the/dev/sdx
form?
– jiggunjer
Jan 17 '17 at 4:00
1
@jiggunjer Modern kernels do support searching for a volume by UUID. Seeinit/do_mounts.c
.
– Gilles
Jan 17 '17 at 13:41
add a comment |
3
This is the right explanation when there's no initrd/initramfs, but it's missing a piece of the puzzle. Normally the kernel identifies a device such as/dev/sda1
because it's an entry in a filesystem. You could docp -p /dev/sda1 /tmp/foo
and/tmp/foo
would represent the same device. On the kernel command line, the kernel uses a built-in parser that follows the usual device naming convention:sda1
means the first partition of the first SCSI-like disk.
– Gilles
Mar 23 '11 at 20:44
@Gilles so modern kernels still can't handle mounting a volume based on UUID? withoutinitrd
orinitramfs
I mean. It has to be a "simple" partition in the/dev/sdx
form?
– jiggunjer
Jan 17 '17 at 4:00
1
@jiggunjer Modern kernels do support searching for a volume by UUID. Seeinit/do_mounts.c
.
– Gilles
Jan 17 '17 at 13:41
3
3
This is the right explanation when there's no initrd/initramfs, but it's missing a piece of the puzzle. Normally the kernel identifies a device such as
/dev/sda1
because it's an entry in a filesystem. You could do cp -p /dev/sda1 /tmp/foo
and /tmp/foo
would represent the same device. On the kernel command line, the kernel uses a built-in parser that follows the usual device naming convention: sda1
means the first partition of the first SCSI-like disk.– Gilles
Mar 23 '11 at 20:44
This is the right explanation when there's no initrd/initramfs, but it's missing a piece of the puzzle. Normally the kernel identifies a device such as
/dev/sda1
because it's an entry in a filesystem. You could do cp -p /dev/sda1 /tmp/foo
and /tmp/foo
would represent the same device. On the kernel command line, the kernel uses a built-in parser that follows the usual device naming convention: sda1
means the first partition of the first SCSI-like disk.– Gilles
Mar 23 '11 at 20:44
@Gilles so modern kernels still can't handle mounting a volume based on UUID? without
initrd
or initramfs
I mean. It has to be a "simple" partition in the /dev/sdx
form?– jiggunjer
Jan 17 '17 at 4:00
@Gilles so modern kernels still can't handle mounting a volume based on UUID? without
initrd
or initramfs
I mean. It has to be a "simple" partition in the /dev/sdx
form?– jiggunjer
Jan 17 '17 at 4:00
1
1
@jiggunjer Modern kernels do support searching for a volume by UUID. See
init/do_mounts.c
.– Gilles
Jan 17 '17 at 13:41
@jiggunjer Modern kernels do support searching for a volume by UUID. See
init/do_mounts.c
.– Gilles
Jan 17 '17 at 13:41
add a comment |
up vote
1
down vote
Grub mounts the /boot
partition and then executes the kernel. In Grub's configuration, it tells the kernel what to use as the root device.
For example in Grub's menu.lst
:
kernel /boot/linux root=/dev/sda2
add a comment |
up vote
1
down vote
Grub mounts the /boot
partition and then executes the kernel. In Grub's configuration, it tells the kernel what to use as the root device.
For example in Grub's menu.lst
:
kernel /boot/linux root=/dev/sda2
add a comment |
up vote
1
down vote
up vote
1
down vote
Grub mounts the /boot
partition and then executes the kernel. In Grub's configuration, it tells the kernel what to use as the root device.
For example in Grub's menu.lst
:
kernel /boot/linux root=/dev/sda2
Grub mounts the /boot
partition and then executes the kernel. In Grub's configuration, it tells the kernel what to use as the root device.
For example in Grub's menu.lst
:
kernel /boot/linux root=/dev/sda2
answered Mar 23 '11 at 12:29
jonescb
1,60811120
1,60811120
add a comment |
add a comment |
up vote
1
down vote
C'mon, GRUB doesn't "mount" /boot, it just reads 'menu.lst' and some modules, it isn't part of LINUX kernel either. When you call the kernel, you will pass a "root" argument with the root partition. At worst, the kernel knows that just /boot has been mounted (LOL).
Next: geekosaur is right, Linux uses an initial ramdisk in compressed image format, and then mounts the real root filesystem by calling pivot_root
. So Linux starts running from an image, and then from your local disk drive.
Grub most definitely does have the ability to 'mount' a filesystem, especially in grub2. Of course, all it's capable of /doing/ with it is look for bootable kernels of one stripe or another, but that's still mounting. Also, linux doesn't require an initrd unless your kernel compiled drivers crucial to your hard drive as modules.
– Shadur
Mar 23 '11 at 12:55
5
ibm.com/developerworks/linux/library/l-linuxboot This is a fairly concise summary of what the Linux Kernel does when booting.
– jsbillings
Mar 23 '11 at 12:58
2
@Shadur, from the mount manpage: All files accessible in a Unix system are arranged in one big tree, the file hierarchy, rooted at /. These files can be spread out over several devices. The mount command serves to attach the file system found on some device to the big file tree. - Since filesystems used by GRUB aren't attached to the file hierarchy, it's NOT mounting.
– D4RIO
Mar 23 '11 at 13:02
1
@Shadur, BTW: It's obvious that initrd isn't necessary since it's just another root filesystem, but it's generally used as small boot-time root, since kernel loads the necessary to boot, then boots, and finally loads everything else.
– D4RIO
Mar 23 '11 at 13:10
@d4rio They're mounted by GRUB, not linux -- it gets easier to comprehend when you regard grub as a microkernel OS of its own rather than just a bootloader.
– Shadur
Mar 23 '11 at 13:21
|
show 2 more comments
up vote
1
down vote
C'mon, GRUB doesn't "mount" /boot, it just reads 'menu.lst' and some modules, it isn't part of LINUX kernel either. When you call the kernel, you will pass a "root" argument with the root partition. At worst, the kernel knows that just /boot has been mounted (LOL).
Next: geekosaur is right, Linux uses an initial ramdisk in compressed image format, and then mounts the real root filesystem by calling pivot_root
. So Linux starts running from an image, and then from your local disk drive.
Grub most definitely does have the ability to 'mount' a filesystem, especially in grub2. Of course, all it's capable of /doing/ with it is look for bootable kernels of one stripe or another, but that's still mounting. Also, linux doesn't require an initrd unless your kernel compiled drivers crucial to your hard drive as modules.
– Shadur
Mar 23 '11 at 12:55
5
ibm.com/developerworks/linux/library/l-linuxboot This is a fairly concise summary of what the Linux Kernel does when booting.
– jsbillings
Mar 23 '11 at 12:58
2
@Shadur, from the mount manpage: All files accessible in a Unix system are arranged in one big tree, the file hierarchy, rooted at /. These files can be spread out over several devices. The mount command serves to attach the file system found on some device to the big file tree. - Since filesystems used by GRUB aren't attached to the file hierarchy, it's NOT mounting.
– D4RIO
Mar 23 '11 at 13:02
1
@Shadur, BTW: It's obvious that initrd isn't necessary since it's just another root filesystem, but it's generally used as small boot-time root, since kernel loads the necessary to boot, then boots, and finally loads everything else.
– D4RIO
Mar 23 '11 at 13:10
@d4rio They're mounted by GRUB, not linux -- it gets easier to comprehend when you regard grub as a microkernel OS of its own rather than just a bootloader.
– Shadur
Mar 23 '11 at 13:21
|
show 2 more comments
up vote
1
down vote
up vote
1
down vote
C'mon, GRUB doesn't "mount" /boot, it just reads 'menu.lst' and some modules, it isn't part of LINUX kernel either. When you call the kernel, you will pass a "root" argument with the root partition. At worst, the kernel knows that just /boot has been mounted (LOL).
Next: geekosaur is right, Linux uses an initial ramdisk in compressed image format, and then mounts the real root filesystem by calling pivot_root
. So Linux starts running from an image, and then from your local disk drive.
C'mon, GRUB doesn't "mount" /boot, it just reads 'menu.lst' and some modules, it isn't part of LINUX kernel either. When you call the kernel, you will pass a "root" argument with the root partition. At worst, the kernel knows that just /boot has been mounted (LOL).
Next: geekosaur is right, Linux uses an initial ramdisk in compressed image format, and then mounts the real root filesystem by calling pivot_root
. So Linux starts running from an image, and then from your local disk drive.
answered Mar 23 '11 at 12:46
D4RIO
8771613
8771613
Grub most definitely does have the ability to 'mount' a filesystem, especially in grub2. Of course, all it's capable of /doing/ with it is look for bootable kernels of one stripe or another, but that's still mounting. Also, linux doesn't require an initrd unless your kernel compiled drivers crucial to your hard drive as modules.
– Shadur
Mar 23 '11 at 12:55
5
ibm.com/developerworks/linux/library/l-linuxboot This is a fairly concise summary of what the Linux Kernel does when booting.
– jsbillings
Mar 23 '11 at 12:58
2
@Shadur, from the mount manpage: All files accessible in a Unix system are arranged in one big tree, the file hierarchy, rooted at /. These files can be spread out over several devices. The mount command serves to attach the file system found on some device to the big file tree. - Since filesystems used by GRUB aren't attached to the file hierarchy, it's NOT mounting.
– D4RIO
Mar 23 '11 at 13:02
1
@Shadur, BTW: It's obvious that initrd isn't necessary since it's just another root filesystem, but it's generally used as small boot-time root, since kernel loads the necessary to boot, then boots, and finally loads everything else.
– D4RIO
Mar 23 '11 at 13:10
@d4rio They're mounted by GRUB, not linux -- it gets easier to comprehend when you regard grub as a microkernel OS of its own rather than just a bootloader.
– Shadur
Mar 23 '11 at 13:21
|
show 2 more comments
Grub most definitely does have the ability to 'mount' a filesystem, especially in grub2. Of course, all it's capable of /doing/ with it is look for bootable kernels of one stripe or another, but that's still mounting. Also, linux doesn't require an initrd unless your kernel compiled drivers crucial to your hard drive as modules.
– Shadur
Mar 23 '11 at 12:55
5
ibm.com/developerworks/linux/library/l-linuxboot This is a fairly concise summary of what the Linux Kernel does when booting.
– jsbillings
Mar 23 '11 at 12:58
2
@Shadur, from the mount manpage: All files accessible in a Unix system are arranged in one big tree, the file hierarchy, rooted at /. These files can be spread out over several devices. The mount command serves to attach the file system found on some device to the big file tree. - Since filesystems used by GRUB aren't attached to the file hierarchy, it's NOT mounting.
– D4RIO
Mar 23 '11 at 13:02
1
@Shadur, BTW: It's obvious that initrd isn't necessary since it's just another root filesystem, but it's generally used as small boot-time root, since kernel loads the necessary to boot, then boots, and finally loads everything else.
– D4RIO
Mar 23 '11 at 13:10
@d4rio They're mounted by GRUB, not linux -- it gets easier to comprehend when you regard grub as a microkernel OS of its own rather than just a bootloader.
– Shadur
Mar 23 '11 at 13:21
Grub most definitely does have the ability to 'mount' a filesystem, especially in grub2. Of course, all it's capable of /doing/ with it is look for bootable kernels of one stripe or another, but that's still mounting. Also, linux doesn't require an initrd unless your kernel compiled drivers crucial to your hard drive as modules.
– Shadur
Mar 23 '11 at 12:55
Grub most definitely does have the ability to 'mount' a filesystem, especially in grub2. Of course, all it's capable of /doing/ with it is look for bootable kernels of one stripe or another, but that's still mounting. Also, linux doesn't require an initrd unless your kernel compiled drivers crucial to your hard drive as modules.
– Shadur
Mar 23 '11 at 12:55
5
5
ibm.com/developerworks/linux/library/l-linuxboot This is a fairly concise summary of what the Linux Kernel does when booting.
– jsbillings
Mar 23 '11 at 12:58
ibm.com/developerworks/linux/library/l-linuxboot This is a fairly concise summary of what the Linux Kernel does when booting.
– jsbillings
Mar 23 '11 at 12:58
2
2
@Shadur, from the mount manpage: All files accessible in a Unix system are arranged in one big tree, the file hierarchy, rooted at /. These files can be spread out over several devices. The mount command serves to attach the file system found on some device to the big file tree. - Since filesystems used by GRUB aren't attached to the file hierarchy, it's NOT mounting.
– D4RIO
Mar 23 '11 at 13:02
@Shadur, from the mount manpage: All files accessible in a Unix system are arranged in one big tree, the file hierarchy, rooted at /. These files can be spread out over several devices. The mount command serves to attach the file system found on some device to the big file tree. - Since filesystems used by GRUB aren't attached to the file hierarchy, it's NOT mounting.
– D4RIO
Mar 23 '11 at 13:02
1
1
@Shadur, BTW: It's obvious that initrd isn't necessary since it's just another root filesystem, but it's generally used as small boot-time root, since kernel loads the necessary to boot, then boots, and finally loads everything else.
– D4RIO
Mar 23 '11 at 13:10
@Shadur, BTW: It's obvious that initrd isn't necessary since it's just another root filesystem, but it's generally used as small boot-time root, since kernel loads the necessary to boot, then boots, and finally loads everything else.
– D4RIO
Mar 23 '11 at 13:10
@d4rio They're mounted by GRUB, not linux -- it gets easier to comprehend when you regard grub as a microkernel OS of its own rather than just a bootloader.
– Shadur
Mar 23 '11 at 13:21
@d4rio They're mounted by GRUB, not linux -- it gets easier to comprehend when you regard grub as a microkernel OS of its own rather than just a bootloader.
– Shadur
Mar 23 '11 at 13:21
|
show 2 more comments
up vote
1
down vote
The boot loader, be it grub or lilo or whatever, tells the kernel where to look with the root=
flag, and optionally loads an initial ramdisk into memory via initrd
before booting the kernel.
The kernel then loads, tests its hardware and device drivers and looks around the system for what it can see (you can review this diagnostic info by typing dmesg
; nowadays it likely scrolls by way too fast to see) then attempts to mount the partition mentioned in the root=
parameter.
If an initrd is present, it's mounted first and any modules/device drivers on it are loaded and probed out before the root filesystem is mounted. This way you can compile the drivers for your hard drives as modules and still be able to boot.
add a comment |
up vote
1
down vote
The boot loader, be it grub or lilo or whatever, tells the kernel where to look with the root=
flag, and optionally loads an initial ramdisk into memory via initrd
before booting the kernel.
The kernel then loads, tests its hardware and device drivers and looks around the system for what it can see (you can review this diagnostic info by typing dmesg
; nowadays it likely scrolls by way too fast to see) then attempts to mount the partition mentioned in the root=
parameter.
If an initrd is present, it's mounted first and any modules/device drivers on it are loaded and probed out before the root filesystem is mounted. This way you can compile the drivers for your hard drives as modules and still be able to boot.
add a comment |
up vote
1
down vote
up vote
1
down vote
The boot loader, be it grub or lilo or whatever, tells the kernel where to look with the root=
flag, and optionally loads an initial ramdisk into memory via initrd
before booting the kernel.
The kernel then loads, tests its hardware and device drivers and looks around the system for what it can see (you can review this diagnostic info by typing dmesg
; nowadays it likely scrolls by way too fast to see) then attempts to mount the partition mentioned in the root=
parameter.
If an initrd is present, it's mounted first and any modules/device drivers on it are loaded and probed out before the root filesystem is mounted. This way you can compile the drivers for your hard drives as modules and still be able to boot.
The boot loader, be it grub or lilo or whatever, tells the kernel where to look with the root=
flag, and optionally loads an initial ramdisk into memory via initrd
before booting the kernel.
The kernel then loads, tests its hardware and device drivers and looks around the system for what it can see (you can review this diagnostic info by typing dmesg
; nowadays it likely scrolls by way too fast to see) then attempts to mount the partition mentioned in the root=
parameter.
If an initrd is present, it's mounted first and any modules/device drivers on it are loaded and probed out before the root filesystem is mounted. This way you can compile the drivers for your hard drives as modules and still be able to boot.
answered Mar 23 '11 at 12:54
Shadur
19.1k64357
19.1k64357
add a comment |
add a comment |
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f9944%2fhow-does-a-kernel-mount-the-root-partition%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Though people below cover initrd, there is little discussion about why initrd is used. My impression is that is because distributions like Debian want to use one kernel on many different machines of the same architecture, but possibly widely different hardware. This is made possible by modularizing hardware support via kernel modules. The initrd does not require much hardware support to boot, and once it does, it loads the necessary hardware modules to proceed. Elaborations/corrections to this are appreciated.
– Faheem Mitha
Mar 26 '11 at 18:32
You can't mount /boot without having / mounted first, since there is no /boot directory without /.
– psusi
Aug 4 '11 at 15:02