Regular expression to match only last folder
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I would like to get the name of the last folder in a path for use in bash script.
For example: I have a path /media/devicename/folder1/ I would like to get a variable called foldername that has in it the word folder1. If I do sed 's//.*/$//' /media/devicename/folder1/ that matches the entire line. How can I limit the regular expression to only the first occurrence of the backslash?
linux bash text-processing sed regular-expression
asked 6 mins ago
novice
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up vote
0
down vote
favorite
I would like to get the name of the last folder in a path for use in bash script.
For example: I have a path /media/devicename/folder1/ I would like to get a variable called foldername that has in it the word folder1. If I do sed 's//.*/$//' /media/devicename/folder1/ that matches the entire line. How can I limit the regular expression to only the first occurrence of the backslash?
linux bash text-processing sed regular-expression
asked 6 mins ago
novice
205
Hello @novice if you want the last folder name you can usebasename, you don't need regular expression for that? I meanbasename /media/devicename/folder1/==>folder1
– Goro
2 mins ago
Possible duplicate of How to get last part of http link in Bash?
– don_crissti
2 mins ago
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I would like to get the name of the last folder in a path for use in bash script.
For example: I have a path /media/devicename/folder1/ I would like to get a variable called foldername that has in it the word folder1. If I do sed 's//.*/$//' /media/devicename/folder1/ that matches the entire line. How can I limit the regular expression to only the first occurrence of the backslash?
linux bash text-processing sed regular-expression
asked 6 mins ago
novice
205
I would like to get the name of the last folder in a path for use in bash script.
For example: I have a path /media/devicename/folder1/ I would like to get a variable called foldername that has in it the word folder1. If I do sed 's//.*/$//' /media/devicename/folder1/ that matches the entire line. How can I limit the regular expression to only the first occurrence of the backslash?
linux bash text-processing sed regular-expression
linux bash text-processing sed regular-expression
asked 6 mins ago
novice
205
asked 6 mins ago
novice
205
asked 6 mins ago
novice
205
asked 6 mins ago
novice
205
asked 6 mins ago
novice
205
205
Hello @novice if you want the last folder name you can usebasename, you don't need regular expression for that? I meanbasename /media/devicename/folder1/==>folder1
– Goro
2 mins ago
Possible duplicate of How to get last part of http link in Bash?
– don_crissti
2 mins ago
add a comment |Â
Hello @novice if you want the last folder name you can usebasename, you don't need regular expression for that? I meanbasename /media/devicename/folder1/==>folder1
– Goro
2 mins ago
Possible duplicate of How to get last part of http link in Bash?
– don_crissti
2 mins ago
Hello @novice if you want the last folder name you can use
basename, you don't need regular expression for that? I mean basename /media/devicename/folder1/ ==> folder1– Goro
2 mins ago
Hello @novice if you want the last folder name you can use
basename, you don't need regular expression for that? I mean basename /media/devicename/folder1/ ==> folder1– Goro
2 mins ago
Possible duplicate of How to get last part of http link in Bash?
– don_crissti
2 mins ago
Possible duplicate of How to get last part of http link in Bash?
– don_crissti
2 mins ago
add a comment |Â
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Hello @novice if you want the last folder name you can use
basename, you don't need regular expression for that? I meanbasename /media/devicename/folder1/==>folder1– Goro
2 mins ago
Possible duplicate of How to get last part of http link in Bash?
– don_crissti
2 mins ago