Try to grep out varnish version does not work
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I try to read the varnish version from a Linux Command line, but the following does not work:
varnishd -V | grep -P '(?<=varnish-)[0-9.]+' -o
This always returns this
varnishd (varnish-3.0.3 revision 9e6a70f)
Copyright (c) 2006 Verdens Gang AS
Copyright (c) 2006-2011 Varnish Software AS
instead of just this
3.0.3
Any hints on what I do wrong?
Thanks
linux grep varnish
asked Oct 9 '17 at 12:33
Klaus Hörmann-Engl
31
add a comment |Â
up vote
0
down vote
favorite
1
I try to read the varnish version from a Linux Command line, but the following does not work:
varnishd -V | grep -P '(?<=varnish-)[0-9.]+' -o
This always returns this
varnishd (varnish-3.0.3 revision 9e6a70f)
Copyright (c) 2006 Verdens Gang AS
Copyright (c) 2006-2011 Varnish Software AS
instead of just this
3.0.3
Any hints on what I do wrong?
Thanks
linux grep varnish
asked Oct 9 '17 at 12:33
Klaus Hörmann-Engl
31
1
If you just want the digits in decimal form, you will need something like grep -o '[0-9].[0.9].[0-9]'
– Raman Sailopal
Oct 9 '17 at 12:43
But this works: "httpd -version | grep -P '(?<=Apache/)[0-9.]+' -o". So why should this not work on the varnish version command?
– Klaus Hörmann-Engl
Oct 9 '17 at 12:46
1
Perhapsvarnishd -Vwrites tostderrnotstdout? Try appending2>&1
– steeldriver
Oct 9 '17 at 12:47
@steeldriver You were absolutely right. I needed to redirect the stderr to the stdout. Now it works like a charm: 'varnishd -V 2>&1 | grep -P '(?<=varnish-)[0-9.]+' -o' If you make an answer out of it, I will mark it as solved.
– Klaus Hörmann-Engl
Oct 9 '17 at 12:53
add a comment |Â
up vote
0
down vote
favorite
1
up vote
0
down vote
favorite
1
1
I try to read the varnish version from a Linux Command line, but the following does not work:
varnishd -V | grep -P '(?<=varnish-)[0-9.]+' -o
This always returns this
varnishd (varnish-3.0.3 revision 9e6a70f)
Copyright (c) 2006 Verdens Gang AS
Copyright (c) 2006-2011 Varnish Software AS
instead of just this
3.0.3
Any hints on what I do wrong?
Thanks
linux grep varnish
asked Oct 9 '17 at 12:33
Klaus Hörmann-Engl
31
I try to read the varnish version from a Linux Command line, but the following does not work:
varnishd -V | grep -P '(?<=varnish-)[0-9.]+' -o
This always returns this
varnishd (varnish-3.0.3 revision 9e6a70f)
Copyright (c) 2006 Verdens Gang AS
Copyright (c) 2006-2011 Varnish Software AS
instead of just this
3.0.3
Any hints on what I do wrong?
Thanks
linux grep varnish
linux grep varnish
asked Oct 9 '17 at 12:33
Klaus Hörmann-Engl
31
asked Oct 9 '17 at 12:33
Klaus Hörmann-Engl
31
asked Oct 9 '17 at 12:33
Klaus Hörmann-Engl
31
asked Oct 9 '17 at 12:33
Klaus Hörmann-Engl
31
asked Oct 9 '17 at 12:33
Klaus Hörmann-Engl
31
31
1
If you just want the digits in decimal form, you will need something like grep -o '[0-9].[0.9].[0-9]'
– Raman Sailopal
Oct 9 '17 at 12:43
But this works: "httpd -version | grep -P '(?<=Apache/)[0-9.]+' -o". So why should this not work on the varnish version command?
– Klaus Hörmann-Engl
Oct 9 '17 at 12:46
1
Perhapsvarnishd -Vwrites tostderrnotstdout? Try appending2>&1
– steeldriver
Oct 9 '17 at 12:47
@steeldriver You were absolutely right. I needed to redirect the stderr to the stdout. Now it works like a charm: 'varnishd -V 2>&1 | grep -P '(?<=varnish-)[0-9.]+' -o' If you make an answer out of it, I will mark it as solved.
– Klaus Hörmann-Engl
Oct 9 '17 at 12:53
add a comment |Â
1
If you just want the digits in decimal form, you will need something like grep -o '[0-9].[0.9].[0-9]'
– Raman Sailopal
Oct 9 '17 at 12:43
But this works: "httpd -version | grep -P '(?<=Apache/)[0-9.]+' -o". So why should this not work on the varnish version command?
– Klaus Hörmann-Engl
Oct 9 '17 at 12:46
1
Perhapsvarnishd -Vwrites tostderrnotstdout? Try appending2>&1
– steeldriver
Oct 9 '17 at 12:47
@steeldriver You were absolutely right. I needed to redirect the stderr to the stdout. Now it works like a charm: 'varnishd -V 2>&1 | grep -P '(?<=varnish-)[0-9.]+' -o' If you make an answer out of it, I will mark it as solved.
– Klaus Hörmann-Engl
Oct 9 '17 at 12:53
1
1
If you just want the digits in decimal form, you will need something like grep -o '[0-9].[0.9].[0-9]'
– Raman Sailopal
Oct 9 '17 at 12:43
If you just want the digits in decimal form, you will need something like grep -o '[0-9].[0.9].[0-9]'
– Raman Sailopal
Oct 9 '17 at 12:43
But this works: "httpd -version | grep -P '(?<=Apache/)[0-9.]+' -o". So why should this not work on the varnish version command?
– Klaus Hörmann-Engl
Oct 9 '17 at 12:46
But this works: "httpd -version | grep -P '(?<=Apache/)[0-9.]+' -o". So why should this not work on the varnish version command?
– Klaus Hörmann-Engl
Oct 9 '17 at 12:46
1
1
Perhaps
varnishd -V writes to stderr not stdout? Try appending 2>&1– steeldriver
Oct 9 '17 at 12:47
Perhaps
varnishd -V writes to stderr not stdout? Try appending 2>&1– steeldriver
Oct 9 '17 at 12:47
@steeldriver You were absolutely right. I needed to redirect the stderr to the stdout. Now it works like a charm: 'varnishd -V 2>&1 | grep -P '(?<=varnish-)[0-9.]+' -o' If you make an answer out of it, I will mark it as solved.
– Klaus Hörmann-Engl
Oct 9 '17 at 12:53
@steeldriver You were absolutely right. I needed to redirect the stderr to the stdout. Now it works like a charm: 'varnishd -V 2>&1 | grep -P '(?<=varnish-)[0-9.]+' -o' If you make an answer out of it, I will mark it as solved.
– Klaus Hörmann-Engl
Oct 9 '17 at 12:53
add a comment |Â
1 Answer
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oldest
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0
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Apparently varnishd -V writes to stderr not stdout. In order to pipe the result into grep, you will need to redirect the stream e.g.
varnishd -V 2>&1 | grep -P '(?<=varnish-)[0-9.]+' -o
answered Oct 9 '17 at 13:12
steeldriver
32.1k34979
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
Apparently varnishd -V writes to stderr not stdout. In order to pipe the result into grep, you will need to redirect the stream e.g.
varnishd -V 2>&1 | grep -P '(?<=varnish-)[0-9.]+' -o
answered Oct 9 '17 at 13:12
steeldriver
32.1k34979
add a comment |Â
up vote
0
down vote
accepted
Apparently varnishd -V writes to stderr not stdout. In order to pipe the result into grep, you will need to redirect the stream e.g.
varnishd -V 2>&1 | grep -P '(?<=varnish-)[0-9.]+' -o
answered Oct 9 '17 at 13:12
steeldriver
32.1k34979
add a comment |Â
up vote
0
down vote
accepted
up vote
0
down vote
accepted
Apparently varnishd -V writes to stderr not stdout. In order to pipe the result into grep, you will need to redirect the stream e.g.
varnishd -V 2>&1 | grep -P '(?<=varnish-)[0-9.]+' -o
answered Oct 9 '17 at 13:12
steeldriver
32.1k34979
Apparently varnishd -V writes to stderr not stdout. In order to pipe the result into grep, you will need to redirect the stream e.g.
varnishd -V 2>&1 | grep -P '(?<=varnish-)[0-9.]+' -o
answered Oct 9 '17 at 13:12
steeldriver
32.1k34979
answered Oct 9 '17 at 13:12
steeldriver
32.1k34979
answered Oct 9 '17 at 13:12
steeldriver
32.1k34979
answered Oct 9 '17 at 13:12
steeldriver
32.1k34979
32.1k34979
add a comment |Â
add a comment |Â
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1
If you just want the digits in decimal form, you will need something like grep -o '[0-9].[0.9].[0-9]'
– Raman Sailopal
Oct 9 '17 at 12:43
But this works: "httpd -version | grep -P '(?<=Apache/)[0-9.]+' -o". So why should this not work on the varnish version command?
– Klaus Hörmann-Engl
Oct 9 '17 at 12:46
1
Perhaps
varnishd -Vwrites tostderrnotstdout? Try appending2>&1– steeldriver
Oct 9 '17 at 12:47
@steeldriver You were absolutely right. I needed to redirect the stderr to the stdout. Now it works like a charm: 'varnishd -V 2>&1 | grep -P '(?<=varnish-)[0-9.]+' -o' If you make an answer out of it, I will mark it as solved.
– Klaus Hörmann-Engl
Oct 9 '17 at 12:53