mjhjmtu

I have a to find for list of words in a list of files. Hence I have put the list of words in a file, and using for loop trying to read each word in a file and use find command to grep for that word in list of found files.

I am using the mentioned flavor of Linux

bash-3.1$ uname
HP-UX

And below mentioned is my shell script.

 #!/bin/sh
PATH="/NO/20171013"
STRING=`/usr/bin/cat /home/test/STAT44_test.txt`
for LINE in $STRING
do
 echo "find $PATH -type f -name "*.txt" -exec grep -w "$LINE" ; 2>/dev/null | /usr/bin/wc -l"
 LINES=`find $PATH -type f -name "*.txt" -exec grep -w "$LINE" ; 2>/dev/null | /usr/bin/wc -l`
 echo "LINES count is $LINES"
 if [ $LINES -eq 0 ]
 then
 echo "In not found"
# echo "$LINE is not found in $PATH" >> /home/test/STAT44_not_found.out
 else
 echo "In Found"
# echo "$LINE is found in $PATH" >> /home/test/STAT44_found.out
 fi
done

The find command find $PATH -type f -name "*.txt" -exec grep -w '$LINE' ; 2>/dev/null works perfectly in the command prompt, whereas it is not at giving any output, if used in the shell script as mentioned above.

The output of echo $? is 0 but the find command doesn't produce any output.

The output of the script is

find /NO/20171013 -type f -name "*.txt" -exec grep -w 655044810645 ; 2>/dev/null | /usr/bin/wc -l
LINES count is 0
In not found
find /NO/20171013 -type f -name "*.txt" -exec grep -w 734729751028 ; 2>/dev/null | /usr/bin/wc -l
LINES count is 0
In not found

Actually the *.txt files under /NO/20171013 has files with pattern 655044810645 and 734729751028 . Hence the Word count should not be 0 and it has to get into else part.

What could be missing?

First, set up a proper $PATH (and see answer by Kamil Maciorowski):

Logg in with suitable user (root?) and execute:

echo PATH=$PATH

Add the output in the start of your script

OR you can add a full path to find command. If you don't know where find are placed, execute:

which find

Output will be like this: /usr/bin/find

And you have a mistake inside loop:

You need to replace single quotes with doublequotes (around of $LINE), otherwise the variable will not be interpreted:

echo "find $PATHS -type f -name "*.txt" -exec grep -w "$LINE" ; 2>/dev/null | wc -l"
LINES=`find $PATHS -type f -name "*.txt" -exec grep -w "$LINE" ; 2>/dev/null | wc -l`

Some notes:

1. You do not need cat file, try to use loop instead. But use only while, not for! Read Why you don't read lines with "for" and How can I read a file (data stream, variable) line-by-line (and/or field-by-field)?
   

$PATH is important variable with meaning. You should choose another name.

In this case find executable cannot be found because $PATH doesn't lead to it. You are not notified because of 2>/dev/null.

echo is probably a shell builtin, it needs no $PATH to work. The same for for etc.