echo full command to file

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I have the following command



echo “more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST” >> NOTNY.sh && chmod 0777 NOTNY.sh


However when I run the command and view the content of NOTNY.sh it contains



“more PHONEBOOK.lst


It should contain



more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST


How do I copy the text from the command and not the result I am getting?




bash echo




share|improve this question
















  • 4




    I'm guessing those are "smart" quotes, which your shell saw as just more bytes instead of actual quotes.
    – Jeff Schaller
    Oct 15 '17 at 22:03










  • How do I make it see the command as a whole and not evaluate the command?
    – John Hamlett IV
    Oct 15 '17 at 22:11






  • 2




    Quote the string. Your example contains the characters “ and ” (U+201C and U+201D) which are not quotes as far as the shell is concerned. The shell understands ' (U+0027) and " (U+0022). The fancy curly characters featured in your example are just ordinary fancy curly characters.
    – AlexP
    Oct 15 '17 at 23:11














up vote
0
down vote

favorite












I have the following command



echo “more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST” >> NOTNY.sh && chmod 0777 NOTNY.sh


However when I run the command and view the content of NOTNY.sh it contains



“more PHONEBOOK.lst


It should contain



more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST


How do I copy the text from the command and not the result I am getting?




bash echo




share|improve this question
















  • 4




    I'm guessing those are "smart" quotes, which your shell saw as just more bytes instead of actual quotes.
    – Jeff Schaller
    Oct 15 '17 at 22:03










  • How do I make it see the command as a whole and not evaluate the command?
    – John Hamlett IV
    Oct 15 '17 at 22:11






  • 2




    Quote the string. Your example contains the characters “ and ” (U+201C and U+201D) which are not quotes as far as the shell is concerned. The shell understands ' (U+0027) and " (U+0022). The fancy curly characters featured in your example are just ordinary fancy curly characters.
    – AlexP
    Oct 15 '17 at 23:11












up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have the following command



echo “more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST” >> NOTNY.sh && chmod 0777 NOTNY.sh


However when I run the command and view the content of NOTNY.sh it contains



“more PHONEBOOK.lst


It should contain



more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST


How do I copy the text from the command and not the result I am getting?




bash echo




share|improve this question












I have the following command



echo “more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST” >> NOTNY.sh && chmod 0777 NOTNY.sh


However when I run the command and view the content of NOTNY.sh it contains



“more PHONEBOOK.lst


It should contain



more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST


How do I copy the text from the command and not the result I am getting?





bash echo





share|improve this question











share|improve this question




share|improve this question










asked Oct 15 '17 at 21:49









John Hamlett IV

11




11







  • 4




    I'm guessing those are "smart" quotes, which your shell saw as just more bytes instead of actual quotes.
    – Jeff Schaller
    Oct 15 '17 at 22:03










  • How do I make it see the command as a whole and not evaluate the command?
    – John Hamlett IV
    Oct 15 '17 at 22:11






  • 2




    Quote the string. Your example contains the characters “ and ” (U+201C and U+201D) which are not quotes as far as the shell is concerned. The shell understands ' (U+0027) and " (U+0022). The fancy curly characters featured in your example are just ordinary fancy curly characters.
    – AlexP
    Oct 15 '17 at 23:11












  • 4




    I'm guessing those are "smart" quotes, which your shell saw as just more bytes instead of actual quotes.
    – Jeff Schaller
    Oct 15 '17 at 22:03










  • How do I make it see the command as a whole and not evaluate the command?
    – John Hamlett IV
    Oct 15 '17 at 22:11






  • 2




    Quote the string. Your example contains the characters “ and ” (U+201C and U+201D) which are not quotes as far as the shell is concerned. The shell understands ' (U+0027) and " (U+0022). The fancy curly characters featured in your example are just ordinary fancy curly characters.
    – AlexP
    Oct 15 '17 at 23:11







4




4




I'm guessing those are "smart" quotes, which your shell saw as just more bytes instead of actual quotes.
– Jeff Schaller
Oct 15 '17 at 22:03




I'm guessing those are "smart" quotes, which your shell saw as just more bytes instead of actual quotes.
– Jeff Schaller
Oct 15 '17 at 22:03












How do I make it see the command as a whole and not evaluate the command?
– John Hamlett IV
Oct 15 '17 at 22:11




How do I make it see the command as a whole and not evaluate the command?
– John Hamlett IV
Oct 15 '17 at 22:11




2




2




Quote the string. Your example contains the characters “ and ” (U+201C and U+201D) which are not quotes as far as the shell is concerned. The shell understands ' (U+0027) and " (U+0022). The fancy curly characters featured in your example are just ordinary fancy curly characters.
– AlexP
Oct 15 '17 at 23:11




Quote the string. Your example contains the characters “ and ” (U+201C and U+201D) which are not quotes as far as the shell is concerned. The shell understands ' (U+0027) and " (U+0022). The fancy curly characters featured in your example are just ordinary fancy curly characters.
– AlexP
Oct 15 '17 at 23:11










1 Answer
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1
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Instead of “smart” quotes, use normal "double-quotes": 



printf "%sn" "more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh


Or, saving a pointless call to more, since awk will read the files you tell it to:



printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh


Or, since the second sort will just override the first one:



printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh





share|improve this answer






















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    1 Answer
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    up vote
    1
    down vote













    Instead of “smart” quotes, use normal "double-quotes": 



    printf "%sn" "more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh


    Or, saving a pointless call to more, since awk will read the files you tell it to:



    printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh


    Or, since the second sort will just override the first one:



    printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh





    share|improve this answer


























      up vote
      1
      down vote













      Instead of “smart” quotes, use normal "double-quotes": 



      printf "%sn" "more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh


      Or, saving a pointless call to more, since awk will read the files you tell it to:



      printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh


      Or, since the second sort will just override the first one:



      printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh





      share|improve this answer
























        up vote
        1
        down vote










        up vote
        1
        down vote









        Instead of “smart” quotes, use normal "double-quotes": 



        printf "%sn" "more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh


        Or, saving a pointless call to more, since awk will read the files you tell it to:



        printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh


        Or, since the second sort will just override the first one:



        printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh





        share|improve this answer














        Instead of “smart” quotes, use normal "double-quotes": 



        printf "%sn" "more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh


        Or, saving a pointless call to more, since awk will read the files you tell it to:



        printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh


        Or, since the second sort will just override the first one:



        printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Oct 16 '17 at 21:49

























        answered Oct 15 '17 at 23:17









        Jeff Schaller

        32.1k849109




        32.1k849109



























             

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