`mktemp -d` followed by `pushd` works fine on command line, but not when in a script

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If I paste these lines into a command prompt on Debian...



DIR=$(mktemp -d -t bbbrtc.XXXXXX) || exit 1
echo "tmpdir = $DIR"
cd "$DIR"


They make a new temp directory, print the directory name, and then pushd into that directory...



root@beaglebone:/tmp/bbbrtc.2mw02x# DIR=$(mktemp -d -t bbbrtc.XXXXXX) || exit 1
root@beaglebone:/tmp/bbbrtc.2mw02x# echo "tmpdir = $DIR"
tmpdir = /tmp/bbbrtc.Grti6K
root@beaglebone:/tmp/bbbrtc.2mw02x# pushd "$DIR"
/tmp/bbbrtc.Grti6K /tmp/bbbrtc.2mw02x ~/bbbphyfix
root@beaglebone:/tmp/bbbrtc.Grti6K#


... as expected.



If I run the exact same commands from inside a shell script...



root@beaglebone:/tmp/bbbrtc.2mw02x# cat test.sh
#!/bin/sh

DIR=$(mktemp -d -t bbbrtc.XXXXXX) || exit 1
echo "tmpdir = $DIR"
pushd "$DIR"

root@beaglebone:/tmp/bbbrtc.2mw02x# ./test.sh
tmpdir = /tmp/bbbrtc.O6yYgf
./test.sh: 5: ./test.sh: pushd: not found
root@beaglebone:/tmp/bbbrtc.2mw02x#


...it generates the "pushd: not found" message.



Why do these commands not work from inside a shell script, and what it the proper way to have a script create a temp dir and then pushd into that new dir?







share|improve this question















  • 5




    Your /bin/sh is not the same shell as your interactive shell.
    – Michael Homer
    May 28 at 3:24






  • 3




    Change your shebang to #!/bin/bash for example. pushd is not available in POSIX shell.
    – cuonglm
    May 28 at 3:25










  • This is it! Thank you!
    – bigjosh
    May 28 at 3:33










  • @cuonglm Post as answer and I will gratefully accept it! Thanks!
    – bigjosh
    May 28 at 3:34














up vote
1
down vote

favorite












If I paste these lines into a command prompt on Debian...



DIR=$(mktemp -d -t bbbrtc.XXXXXX) || exit 1
echo "tmpdir = $DIR"
cd "$DIR"


They make a new temp directory, print the directory name, and then pushd into that directory...



root@beaglebone:/tmp/bbbrtc.2mw02x# DIR=$(mktemp -d -t bbbrtc.XXXXXX) || exit 1
root@beaglebone:/tmp/bbbrtc.2mw02x# echo "tmpdir = $DIR"
tmpdir = /tmp/bbbrtc.Grti6K
root@beaglebone:/tmp/bbbrtc.2mw02x# pushd "$DIR"
/tmp/bbbrtc.Grti6K /tmp/bbbrtc.2mw02x ~/bbbphyfix
root@beaglebone:/tmp/bbbrtc.Grti6K#


... as expected.



If I run the exact same commands from inside a shell script...



root@beaglebone:/tmp/bbbrtc.2mw02x# cat test.sh
#!/bin/sh

DIR=$(mktemp -d -t bbbrtc.XXXXXX) || exit 1
echo "tmpdir = $DIR"
pushd "$DIR"

root@beaglebone:/tmp/bbbrtc.2mw02x# ./test.sh
tmpdir = /tmp/bbbrtc.O6yYgf
./test.sh: 5: ./test.sh: pushd: not found
root@beaglebone:/tmp/bbbrtc.2mw02x#


...it generates the "pushd: not found" message.



Why do these commands not work from inside a shell script, and what it the proper way to have a script create a temp dir and then pushd into that new dir?







share|improve this question















  • 5




    Your /bin/sh is not the same shell as your interactive shell.
    – Michael Homer
    May 28 at 3:24






  • 3




    Change your shebang to #!/bin/bash for example. pushd is not available in POSIX shell.
    – cuonglm
    May 28 at 3:25










  • This is it! Thank you!
    – bigjosh
    May 28 at 3:33










  • @cuonglm Post as answer and I will gratefully accept it! Thanks!
    – bigjosh
    May 28 at 3:34












up vote
1
down vote

favorite









up vote
1
down vote

favorite











If I paste these lines into a command prompt on Debian...



DIR=$(mktemp -d -t bbbrtc.XXXXXX) || exit 1
echo "tmpdir = $DIR"
cd "$DIR"


They make a new temp directory, print the directory name, and then pushd into that directory...



root@beaglebone:/tmp/bbbrtc.2mw02x# DIR=$(mktemp -d -t bbbrtc.XXXXXX) || exit 1
root@beaglebone:/tmp/bbbrtc.2mw02x# echo "tmpdir = $DIR"
tmpdir = /tmp/bbbrtc.Grti6K
root@beaglebone:/tmp/bbbrtc.2mw02x# pushd "$DIR"
/tmp/bbbrtc.Grti6K /tmp/bbbrtc.2mw02x ~/bbbphyfix
root@beaglebone:/tmp/bbbrtc.Grti6K#


... as expected.



If I run the exact same commands from inside a shell script...



root@beaglebone:/tmp/bbbrtc.2mw02x# cat test.sh
#!/bin/sh

DIR=$(mktemp -d -t bbbrtc.XXXXXX) || exit 1
echo "tmpdir = $DIR"
pushd "$DIR"

root@beaglebone:/tmp/bbbrtc.2mw02x# ./test.sh
tmpdir = /tmp/bbbrtc.O6yYgf
./test.sh: 5: ./test.sh: pushd: not found
root@beaglebone:/tmp/bbbrtc.2mw02x#


...it generates the "pushd: not found" message.



Why do these commands not work from inside a shell script, and what it the proper way to have a script create a temp dir and then pushd into that new dir?







share|improve this question











If I paste these lines into a command prompt on Debian...



DIR=$(mktemp -d -t bbbrtc.XXXXXX) || exit 1
echo "tmpdir = $DIR"
cd "$DIR"


They make a new temp directory, print the directory name, and then pushd into that directory...



root@beaglebone:/tmp/bbbrtc.2mw02x# DIR=$(mktemp -d -t bbbrtc.XXXXXX) || exit 1
root@beaglebone:/tmp/bbbrtc.2mw02x# echo "tmpdir = $DIR"
tmpdir = /tmp/bbbrtc.Grti6K
root@beaglebone:/tmp/bbbrtc.2mw02x# pushd "$DIR"
/tmp/bbbrtc.Grti6K /tmp/bbbrtc.2mw02x ~/bbbphyfix
root@beaglebone:/tmp/bbbrtc.Grti6K#


... as expected.



If I run the exact same commands from inside a shell script...



root@beaglebone:/tmp/bbbrtc.2mw02x# cat test.sh
#!/bin/sh

DIR=$(mktemp -d -t bbbrtc.XXXXXX) || exit 1
echo "tmpdir = $DIR"
pushd "$DIR"

root@beaglebone:/tmp/bbbrtc.2mw02x# ./test.sh
tmpdir = /tmp/bbbrtc.O6yYgf
./test.sh: 5: ./test.sh: pushd: not found
root@beaglebone:/tmp/bbbrtc.2mw02x#


...it generates the "pushd: not found" message.



Why do these commands not work from inside a shell script, and what it the proper way to have a script create a temp dir and then pushd into that new dir?









share|improve this question










share|improve this question




share|improve this question









asked May 28 at 3:19









bigjosh

24939




24939







  • 5




    Your /bin/sh is not the same shell as your interactive shell.
    – Michael Homer
    May 28 at 3:24






  • 3




    Change your shebang to #!/bin/bash for example. pushd is not available in POSIX shell.
    – cuonglm
    May 28 at 3:25










  • This is it! Thank you!
    – bigjosh
    May 28 at 3:33










  • @cuonglm Post as answer and I will gratefully accept it! Thanks!
    – bigjosh
    May 28 at 3:34












  • 5




    Your /bin/sh is not the same shell as your interactive shell.
    – Michael Homer
    May 28 at 3:24






  • 3




    Change your shebang to #!/bin/bash for example. pushd is not available in POSIX shell.
    – cuonglm
    May 28 at 3:25










  • This is it! Thank you!
    – bigjosh
    May 28 at 3:33










  • @cuonglm Post as answer and I will gratefully accept it! Thanks!
    – bigjosh
    May 28 at 3:34







5




5




Your /bin/sh is not the same shell as your interactive shell.
– Michael Homer
May 28 at 3:24




Your /bin/sh is not the same shell as your interactive shell.
– Michael Homer
May 28 at 3:24




3




3




Change your shebang to #!/bin/bash for example. pushd is not available in POSIX shell.
– cuonglm
May 28 at 3:25




Change your shebang to #!/bin/bash for example. pushd is not available in POSIX shell.
– cuonglm
May 28 at 3:25












This is it! Thank you!
– bigjosh
May 28 at 3:33




This is it! Thank you!
– bigjosh
May 28 at 3:33












@cuonglm Post as answer and I will gratefully accept it! Thanks!
– bigjosh
May 28 at 3:34




@cuonglm Post as answer and I will gratefully accept it! Thanks!
– bigjosh
May 28 at 3:34










1 Answer
1






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2
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pushd is a bash command, which is generally not implemented by /bin/sh. To use pushd in a sh script, you would have to provide a script or function with the same functionality.



The idiomatic way of temporarily changing one's working directory for the course of a few commands in a sh script is to do



( cd directory && somecommand )


This would change into directory and execute somecommand if that succeeded. The whole thing is done in a subshell, so the cd will not have any effect on the rest of the script.



Alternatively,



( cd directory || exit 1
command1
command2
command3 )





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    up vote
    2
    down vote













    pushd is a bash command, which is generally not implemented by /bin/sh. To use pushd in a sh script, you would have to provide a script or function with the same functionality.



    The idiomatic way of temporarily changing one's working directory for the course of a few commands in a sh script is to do



    ( cd directory && somecommand )


    This would change into directory and execute somecommand if that succeeded. The whole thing is done in a subshell, so the cd will not have any effect on the rest of the script.



    Alternatively,



    ( cd directory || exit 1
    command1
    command2
    command3 )





    share|improve this answer

























      up vote
      2
      down vote













      pushd is a bash command, which is generally not implemented by /bin/sh. To use pushd in a sh script, you would have to provide a script or function with the same functionality.



      The idiomatic way of temporarily changing one's working directory for the course of a few commands in a sh script is to do



      ( cd directory && somecommand )


      This would change into directory and execute somecommand if that succeeded. The whole thing is done in a subshell, so the cd will not have any effect on the rest of the script.



      Alternatively,



      ( cd directory || exit 1
      command1
      command2
      command3 )





      share|improve this answer























        up vote
        2
        down vote










        up vote
        2
        down vote









        pushd is a bash command, which is generally not implemented by /bin/sh. To use pushd in a sh script, you would have to provide a script or function with the same functionality.



        The idiomatic way of temporarily changing one's working directory for the course of a few commands in a sh script is to do



        ( cd directory && somecommand )


        This would change into directory and execute somecommand if that succeeded. The whole thing is done in a subshell, so the cd will not have any effect on the rest of the script.



        Alternatively,



        ( cd directory || exit 1
        command1
        command2
        command3 )





        share|improve this answer













        pushd is a bash command, which is generally not implemented by /bin/sh. To use pushd in a sh script, you would have to provide a script or function with the same functionality.



        The idiomatic way of temporarily changing one's working directory for the course of a few commands in a sh script is to do



        ( cd directory && somecommand )


        This would change into directory and execute somecommand if that succeeded. The whole thing is done in a subshell, so the cd will not have any effect on the rest of the script.



        Alternatively,



        ( cd directory || exit 1
        command1
        command2
        command3 )






        share|improve this answer













        share|improve this answer



        share|improve this answer











        answered May 28 at 6:43









        Kusalananda

        102k13199314




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