mjhjmtu

Good day,

So I am working on an install script for a program that needs the device id from lsusb in it's configuration so I was thinking of doing the following:

$usblist=(lsusb)
#put the list into a array for each line.
#use the array to give the user a selection list usinging whiptail.
#from that line strip out the device id and vender id from the selected line.

The line looks as follows:

Bus 001 Device 004: ID 0665:5161 Cypress Semiconductor USB to Serial

So I want only the 9 characters after "IDspace"
Sorry I haven't gotten very far with my code but I am stuck on this and have no idea how to do what I would like to do. Please can someone help. I am very new to shell scripting

The first errors that I see are.
You wrote $usblist=(lsusb | awk 'print $6')

You need to remove the $ from the start, and add a $ before the (. Some quotes will also help. i.e.

usblist="$(lsusb | awk 'print $6')"

Just use, this uses awk to print out the 6th field which in your case is the ID of the device

usblist="$(lsusb | awk 'print $6')"

So you print any field you want, here are the mapping:

• $1 : Bus


• $2 : 001


• $3 : Device


• $4 : 004:


• $5 : ID


• $6 : 0665:5161


• $7 : Cypress


• $8 : Semiconductor


• $9 : USB


• $10 : to


• $11 : Serial

If you want to print more than one field , such as name , you can do like this

usblist="$(lsusb | awk 'print $7,$8,$9')"