mjhjmtu

I am trying to extract the value(number) between two variables and store the value in another variable.

I am using sed command, but I am not getting any output.

#!/usr/bin/env bash
variable1=`cat $1`
variable2=`echo "$variable1" | cut -c 18`
echo "$variable2"
variable3=`echo "$variable1" | cut -c 60`
echo "$variable3"
string="$variable3xyz$variable2"
echo $string
line=`sed -n '/'"$string"'/,/'"$variable2"'/ p' $1`
echo $line

Please suggest me a way to extract number between $searchString and $variable2, lets say between $string which is : &xyz! and $variable2 which is : ! , I have 60 ie &xyz!60!
So I need to extract 60.

I also tried with

line=`sed -nr "s/$string([0-9]+),$variable2/1/ p" $1` 

but when I echoed $line it printed the entire file content

Thanks in advance

This can be done just with shell parameter substutition:

# setup
line='hello&xyz!60!world'
string='&xyz!'
variable2='!'

# now, remove from the beginning up to the first instance of "&xyz!"
tmp=$line#*$string

# $tmp now holds 60!world

# remove from the end the last "!" and all following characters
result=$tmp%$variable2*
echo $result
# => 60

It looks like your sed command is failing due to the comma

1. 
   

   no comma in input, so nothing matches, thus nothing printed

   
   
   

   $ set -x
   $ echo "$line" | sed -nr "s/$string([0-9]+),$variable2/1/ p"
   + sed -nr 's/&xyz!([0-9]+),!/1/ p'
   + echo 'hello&xyz!60!world'
   

   
   


2. 
   

   remove the comma, now we have a match, but the prefix and suffix remain

   
   
   

   $ echo "$line" | sed -nr "s/$string([0-9]+)$variable2/1/ p"
   + sed -nr 's/&xyz!([0-9]+)!/1/ p'
   + echo 'hello&xyz!60!world'
   hello60world
   

   
   


3. 
   

   also match pre and post text

   
   
   

   $ echo "$line" | sed -nr "s/.*$string([0-9]+)$variable2.*/1/ p"
   + sed -nr 's/.*&xyz!([0-9]+)!.*/1/ p'
   + echo 'hello&xyz!60!world'
   60