Invert last two subfolders of the directory structure
Multi tool use
Clash Royale CLAN TAG#URR8PPP
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Basically, I request a unix way (bash, perl, etc) to invert the last two subfolders, like in this windows question:
https://superuser.com/questions/221/how-can-i-invert-a-directory-structure
This is an example, the objective is to modify the path of lots of files.
i.e.
/dir1/dir2/dir3/dir4/myfile
to:
/dir1/dir2/dir4/dir3/myfile
shell-script regular-expression directory perl
asked Jan 23 at 21:18
Ferroao
1256
add a comment |Â
up vote
0
down vote
favorite
Basically, I request a unix way (bash, perl, etc) to invert the last two subfolders, like in this windows question:
https://superuser.com/questions/221/how-can-i-invert-a-directory-structure
This is an example, the objective is to modify the path of lots of files.
i.e.
/dir1/dir2/dir3/dir4/myfile
to:
/dir1/dir2/dir4/dir3/myfile
shell-script regular-expression directory perl
asked Jan 23 at 21:18
Ferroao
1256
Can we assume that there is not already a dir1/dir2/dir4 directory? What is the input to this process — the path to myfile?
– Jeff Schaller
Jan 23 at 21:24
showtree /dir1/dir2
– RomanPerekhrest
Jan 23 at 21:33
1
You are unhappy withmv /dir1/dir2/dir3/dir4,dir3 ; mv /dir1/dir2/dir3,dir4?
– Ralph Rönnquist
Jan 23 at 21:35
Jeff Shaller, I am not sure what I can answer, but it would be better to just check it in the process. and create it only when necessary. I think of several files in the example subfolder dir4. I am not sure if the input should be every file or if it would be the subfolder.
– Ferroao
Jan 23 at 21:43
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Basically, I request a unix way (bash, perl, etc) to invert the last two subfolders, like in this windows question:
https://superuser.com/questions/221/how-can-i-invert-a-directory-structure
This is an example, the objective is to modify the path of lots of files.
i.e.
/dir1/dir2/dir3/dir4/myfile
to:
/dir1/dir2/dir4/dir3/myfile
shell-script regular-expression directory perl
asked Jan 23 at 21:18
Ferroao
1256
Basically, I request a unix way (bash, perl, etc) to invert the last two subfolders, like in this windows question:
https://superuser.com/questions/221/how-can-i-invert-a-directory-structure
This is an example, the objective is to modify the path of lots of files.
i.e.
/dir1/dir2/dir3/dir4/myfile
to:
/dir1/dir2/dir4/dir3/myfile
shell-script regular-expression directory perl
asked Jan 23 at 21:18
Ferroao
1256
edited Jan 23 at 21:41
asked Jan 23 at 21:18
Ferroao
1256
asked Jan 23 at 21:18
Ferroao
1256
asked Jan 23 at 21:18
Ferroao
1256
1256
Can we assume that there is not already a dir1/dir2/dir4 directory? What is the input to this process — the path to myfile?
– Jeff Schaller
Jan 23 at 21:24
showtree /dir1/dir2
– RomanPerekhrest
Jan 23 at 21:33
1
You are unhappy withmv /dir1/dir2/dir3/dir4,dir3 ; mv /dir1/dir2/dir3,dir4?
– Ralph Rönnquist
Jan 23 at 21:35
Jeff Shaller, I am not sure what I can answer, but it would be better to just check it in the process. and create it only when necessary. I think of several files in the example subfolder dir4. I am not sure if the input should be every file or if it would be the subfolder.
– Ferroao
Jan 23 at 21:43
add a comment |Â
Can we assume that there is not already a dir1/dir2/dir4 directory? What is the input to this process — the path to myfile?
– Jeff Schaller
Jan 23 at 21:24
showtree /dir1/dir2
– RomanPerekhrest
Jan 23 at 21:33
1
You are unhappy withmv /dir1/dir2/dir3/dir4,dir3 ; mv /dir1/dir2/dir3,dir4?
– Ralph Rönnquist
Jan 23 at 21:35
Jeff Shaller, I am not sure what I can answer, but it would be better to just check it in the process. and create it only when necessary. I think of several files in the example subfolder dir4. I am not sure if the input should be every file or if it would be the subfolder.
– Ferroao
Jan 23 at 21:43
Can we assume that there is not already a dir1/dir2/dir4 directory? What is the input to this process — the path to myfile?
– Jeff Schaller
Jan 23 at 21:24
Can we assume that there is not already a dir1/dir2/dir4 directory? What is the input to this process — the path to myfile?
– Jeff Schaller
Jan 23 at 21:24
show
tree /dir1/dir2– RomanPerekhrest
Jan 23 at 21:33
show
tree /dir1/dir2– RomanPerekhrest
Jan 23 at 21:33
1
1
You are unhappy with
mv /dir1/dir2/dir3/dir4,dir3 ; mv /dir1/dir2/dir3,dir4 ?– Ralph Rönnquist
Jan 23 at 21:35
You are unhappy with
mv /dir1/dir2/dir3/dir4,dir3 ; mv /dir1/dir2/dir3,dir4 ?– Ralph Rönnquist
Jan 23 at 21:35
Jeff Shaller, I am not sure what I can answer, but it would be better to just check it in the process. and create it only when necessary. I think of several files in the example subfolder dir4. I am not sure if the input should be every file or if it would be the subfolder.
– Ferroao
Jan 23 at 21:43
Jeff Shaller, I am not sure what I can answer, but it would be better to just check it in the process. and create it only when necessary. I think of several files in the example subfolder dir4. I am not sure if the input should be every file or if it would be the subfolder.
– Ferroao
Jan 23 at 21:43
add a comment |Â
1 Answer
1
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votes
up vote
0
down vote
For a solution with four subdirectories you could use something like this:
for p4 in */*/*/*
do
p3="$p4%/*" p2="$p3%/*" d4="$p4/*/" d3="$p3/*/"
mv "$p4" "$p3/$d3" && mv "$p3" "$p2/$d4"
done
It does no error checking for the presence of a target directory before it attempts the transposition. In this situation you will end up with the third level directory being duplicated. For example, a/b/d exists and we are going to transpose a/b/c/d, we will end up with a/b/d/c/c.
If you have too many directories matching */*/*/* you could split it further with an additional loop per level. With care this will obviate the need to derive paths $p2 and $p3.
answered Jan 24 at 0:19
roaima
39.7k545108
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
For a solution with four subdirectories you could use something like this:
for p4 in */*/*/*
do
p3="$p4%/*" p2="$p3%/*" d4="$p4/*/" d3="$p3/*/"
mv "$p4" "$p3/$d3" && mv "$p3" "$p2/$d4"
done
It does no error checking for the presence of a target directory before it attempts the transposition. In this situation you will end up with the third level directory being duplicated. For example, a/b/d exists and we are going to transpose a/b/c/d, we will end up with a/b/d/c/c.
If you have too many directories matching */*/*/* you could split it further with an additional loop per level. With care this will obviate the need to derive paths $p2 and $p3.
answered Jan 24 at 0:19
roaima
39.7k545108
add a comment |Â
up vote
0
down vote
For a solution with four subdirectories you could use something like this:
for p4 in */*/*/*
do
p3="$p4%/*" p2="$p3%/*" d4="$p4/*/" d3="$p3/*/"
mv "$p4" "$p3/$d3" && mv "$p3" "$p2/$d4"
done
It does no error checking for the presence of a target directory before it attempts the transposition. In this situation you will end up with the third level directory being duplicated. For example, a/b/d exists and we are going to transpose a/b/c/d, we will end up with a/b/d/c/c.
If you have too many directories matching */*/*/* you could split it further with an additional loop per level. With care this will obviate the need to derive paths $p2 and $p3.
answered Jan 24 at 0:19
roaima
39.7k545108
add a comment |Â
up vote
0
down vote
up vote
0
down vote
For a solution with four subdirectories you could use something like this:
for p4 in */*/*/*
do
p3="$p4%/*" p2="$p3%/*" d4="$p4/*/" d3="$p3/*/"
mv "$p4" "$p3/$d3" && mv "$p3" "$p2/$d4"
done
It does no error checking for the presence of a target directory before it attempts the transposition. In this situation you will end up with the third level directory being duplicated. For example, a/b/d exists and we are going to transpose a/b/c/d, we will end up with a/b/d/c/c.
If you have too many directories matching */*/*/* you could split it further with an additional loop per level. With care this will obviate the need to derive paths $p2 and $p3.
answered Jan 24 at 0:19
roaima
39.7k545108
For a solution with four subdirectories you could use something like this:
for p4 in */*/*/*
do
p3="$p4%/*" p2="$p3%/*" d4="$p4/*/" d3="$p3/*/"
mv "$p4" "$p3/$d3" && mv "$p3" "$p2/$d4"
done
It does no error checking for the presence of a target directory before it attempts the transposition. In this situation you will end up with the third level directory being duplicated. For example, a/b/d exists and we are going to transpose a/b/c/d, we will end up with a/b/d/c/c.
If you have too many directories matching */*/*/* you could split it further with an additional loop per level. With care this will obviate the need to derive paths $p2 and $p3.
answered Jan 24 at 0:19
roaima
39.7k545108
answered Jan 24 at 0:19
roaima
39.7k545108
answered Jan 24 at 0:19
roaima
39.7k545108
answered Jan 24 at 0:19
roaima
39.7k545108
39.7k545108
add a comment |Â
add a comment |Â
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Can we assume that there is not already a dir1/dir2/dir4 directory? What is the input to this process — the path to myfile?
– Jeff Schaller
Jan 23 at 21:24
show
tree /dir1/dir2– RomanPerekhrest
Jan 23 at 21:33
1
You are unhappy with
mv /dir1/dir2/dir3/dir4,dir3 ; mv /dir1/dir2/dir3,dir4?– Ralph Rönnquist
Jan 23 at 21:35
Jeff Shaller, I am not sure what I can answer, but it would be better to just check it in the process. and create it only when necessary. I think of several files in the example subfolder dir4. I am not sure if the input should be every file or if it would be the subfolder.
– Ferroao
Jan 23 at 21:43