Fetch a number of variable length from a file using pattern matching?

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
-1
down vote

favorite












I have many files on UNIX and wish to fetch number in that file associated with a specified pattern.



Most of the file will have a unique pattern in file like below



some text abc
some text abc
some text abc
(3 rows)


The number could vary from file to file, it could be 35644 or any numeric value as well.



I want to find that number using grep or sed not awk. so far I was able to get this. I want to do this using single line unix command including redirection if applicable.



grep 'rows' file.txt


Edit - Removed the requirement if pattern is not found what should happen.




text-processing sed grep hp-ux




share|improve this question






















  • So, are you saying that your example file is four lines long, and the fourth line contains the text (3 rows)?  And that you want to extract the 3 from the (3 rows) line (regardless of the actual number of lines in the file)?  Do you guarantee that only one row in the file contains the word row — or that only one line will begin with (, followed by a sequence of digits, followed by a space and rows)? (If there are only two lines in the file, will the second one say (1 row) or (1 rows)?) Please do not respond in comments; edit your question to make it clearer and more complete.
    – G-Man
    Jan 22 at 6:34










  • That one row will begin with (numbercount rows) and will have this pattern. It might possible rows might come as string somewhere else but not as this pattern (numbercount rows).
    – Minsec
    Jan 22 at 6:44















up vote
-1
down vote

favorite












I have many files on UNIX and wish to fetch number in that file associated with a specified pattern.



Most of the file will have a unique pattern in file like below



some text abc
some text abc
some text abc
(3 rows)


The number could vary from file to file, it could be 35644 or any numeric value as well.



I want to find that number using grep or sed not awk. so far I was able to get this. I want to do this using single line unix command including redirection if applicable.



grep 'rows' file.txt


Edit - Removed the requirement if pattern is not found what should happen.




text-processing sed grep hp-ux




share|improve this question






















  • So, are you saying that your example file is four lines long, and the fourth line contains the text (3 rows)?  And that you want to extract the 3 from the (3 rows) line (regardless of the actual number of lines in the file)?  Do you guarantee that only one row in the file contains the word row — or that only one line will begin with (, followed by a sequence of digits, followed by a space and rows)? (If there are only two lines in the file, will the second one say (1 row) or (1 rows)?) Please do not respond in comments; edit your question to make it clearer and more complete.
    – G-Man
    Jan 22 at 6:34










  • That one row will begin with (numbercount rows) and will have this pattern. It might possible rows might come as string somewhere else but not as this pattern (numbercount rows).
    – Minsec
    Jan 22 at 6:44













up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











I have many files on UNIX and wish to fetch number in that file associated with a specified pattern.



Most of the file will have a unique pattern in file like below



some text abc
some text abc
some text abc
(3 rows)


The number could vary from file to file, it could be 35644 or any numeric value as well.



I want to find that number using grep or sed not awk. so far I was able to get this. I want to do this using single line unix command including redirection if applicable.



grep 'rows' file.txt


Edit - Removed the requirement if pattern is not found what should happen.




text-processing sed grep hp-ux




share|improve this question














I have many files on UNIX and wish to fetch number in that file associated with a specified pattern.



Most of the file will have a unique pattern in file like below



some text abc
some text abc
some text abc
(3 rows)


The number could vary from file to file, it could be 35644 or any numeric value as well.



I want to find that number using grep or sed not awk. so far I was able to get this. I want to do this using single line unix command including redirection if applicable.



grep 'rows' file.txt


Edit - Removed the requirement if pattern is not found what should happen.





text-processing sed grep hp-ux





share|improve this question













share|improve this question




share|improve this question








edited Jan 22 at 7:04









cas

37.7k44393




37.7k44393










asked Jan 22 at 6:15









Minsec

11




11











  • So, are you saying that your example file is four lines long, and the fourth line contains the text (3 rows)?  And that you want to extract the 3 from the (3 rows) line (regardless of the actual number of lines in the file)?  Do you guarantee that only one row in the file contains the word row — or that only one line will begin with (, followed by a sequence of digits, followed by a space and rows)? (If there are only two lines in the file, will the second one say (1 row) or (1 rows)?) Please do not respond in comments; edit your question to make it clearer and more complete.
    – G-Man
    Jan 22 at 6:34










  • That one row will begin with (numbercount rows) and will have this pattern. It might possible rows might come as string somewhere else but not as this pattern (numbercount rows).
    – Minsec
    Jan 22 at 6:44

















  • So, are you saying that your example file is four lines long, and the fourth line contains the text (3 rows)?  And that you want to extract the 3 from the (3 rows) line (regardless of the actual number of lines in the file)?  Do you guarantee that only one row in the file contains the word row — or that only one line will begin with (, followed by a sequence of digits, followed by a space and rows)? (If there are only two lines in the file, will the second one say (1 row) or (1 rows)?) Please do not respond in comments; edit your question to make it clearer and more complete.
    – G-Man
    Jan 22 at 6:34










  • That one row will begin with (numbercount rows) and will have this pattern. It might possible rows might come as string somewhere else but not as this pattern (numbercount rows).
    – Minsec
    Jan 22 at 6:44
















So, are you saying that your example file is four lines long, and the fourth line contains the text (3 rows)?  And that you want to extract the 3 from the (3 rows) line (regardless of the actual number of lines in the file)?  Do you guarantee that only one row in the file contains the word row — or that only one line will begin with (, followed by a sequence of digits, followed by a space and rows)? (If there are only two lines in the file, will the second one say (1 row) or (1 rows)?) Please do not respond in comments; edit your question to make it clearer and more complete.
– G-Man
Jan 22 at 6:34




So, are you saying that your example file is four lines long, and the fourth line contains the text (3 rows)?  And that you want to extract the 3 from the (3 rows) line (regardless of the actual number of lines in the file)?  Do you guarantee that only one row in the file contains the word row — or that only one line will begin with (, followed by a sequence of digits, followed by a space and rows)? (If there are only two lines in the file, will the second one say (1 row) or (1 rows)?) Please do not respond in comments; edit your question to make it clearer and more complete.
– G-Man
Jan 22 at 6:34












That one row will begin with (numbercount rows) and will have this pattern. It might possible rows might come as string somewhere else but not as this pattern (numbercount rows).
– Minsec
Jan 22 at 6:44





That one row will begin with (numbercount rows) and will have this pattern. It might possible rows might come as string somewhere else but not as this pattern (numbercount rows).
– Minsec
Jan 22 at 6:44











1 Answer
1






active

oldest

votes

















up vote
0
down vote













sed -n -e 's/^(([0-9]+) rows)$/1/p'


This prints the digits immediately following the ( on lines that contain only (nnn rows) (where nnn is any positive integer).



No other lines are printed.






share|improve this answer




















  • I tried this by specifying file name with pattern didn'print anything. sed -n -e 's/^(([0-9]+) rows)$/1/p' file.txt
    – Minsec
    Jan 22 at 6:54











  • then your file doesn't match what you specified in your question. did your files come from a windows machine? (i.e. do they have CR+LF line endings rather than unix-style LF-only?). Try adding r? immediately before the $ in the sed script - that will match either unix or windows line-endings. or convert them to unix text files with fromdos or similar.
    – cas
    Jan 22 at 6:58











  • file is created in unix only with LF style.
    – Minsec
    Jan 22 at 7:00










  • then what you stated in your question is incorrect - it does not accurately describe your files. I tested it before I posted using the sample text you provided and it printed 3.
    – cas
    Jan 22 at 7:01











  • I'm on HP UNIX will sed command differ all versions of UNIX? As command is getting executed successfully but doesn't print anything. My requirement is clear and same as what I have posted.
    – Minsec
    Jan 22 at 7:03











Your Answer







StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "106"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
convertImagesToLinks: false,
noModals: false,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);








 

draft saved


draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f418758%2ffetch-a-number-of-variable-length-from-a-file-using-pattern-matching%23new-answer', 'question_page');

);

Post as a guest

















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
0
down vote













sed -n -e 's/^(([0-9]+) rows)$/1/p'


This prints the digits immediately following the ( on lines that contain only (nnn rows) (where nnn is any positive integer).



No other lines are printed.






share|improve this answer




















  • I tried this by specifying file name with pattern didn'print anything. sed -n -e 's/^(([0-9]+) rows)$/1/p' file.txt
    – Minsec
    Jan 22 at 6:54











  • then your file doesn't match what you specified in your question. did your files come from a windows machine? (i.e. do they have CR+LF line endings rather than unix-style LF-only?). Try adding r? immediately before the $ in the sed script - that will match either unix or windows line-endings. or convert them to unix text files with fromdos or similar.
    – cas
    Jan 22 at 6:58











  • file is created in unix only with LF style.
    – Minsec
    Jan 22 at 7:00










  • then what you stated in your question is incorrect - it does not accurately describe your files. I tested it before I posted using the sample text you provided and it printed 3.
    – cas
    Jan 22 at 7:01











  • I'm on HP UNIX will sed command differ all versions of UNIX? As command is getting executed successfully but doesn't print anything. My requirement is clear and same as what I have posted.
    – Minsec
    Jan 22 at 7:03















up vote
0
down vote













sed -n -e 's/^(([0-9]+) rows)$/1/p'


This prints the digits immediately following the ( on lines that contain only (nnn rows) (where nnn is any positive integer).



No other lines are printed.






share|improve this answer




















  • I tried this by specifying file name with pattern didn'print anything. sed -n -e 's/^(([0-9]+) rows)$/1/p' file.txt
    – Minsec
    Jan 22 at 6:54











  • then your file doesn't match what you specified in your question. did your files come from a windows machine? (i.e. do they have CR+LF line endings rather than unix-style LF-only?). Try adding r? immediately before the $ in the sed script - that will match either unix or windows line-endings. or convert them to unix text files with fromdos or similar.
    – cas
    Jan 22 at 6:58











  • file is created in unix only with LF style.
    – Minsec
    Jan 22 at 7:00










  • then what you stated in your question is incorrect - it does not accurately describe your files. I tested it before I posted using the sample text you provided and it printed 3.
    – cas
    Jan 22 at 7:01











  • I'm on HP UNIX will sed command differ all versions of UNIX? As command is getting executed successfully but doesn't print anything. My requirement is clear and same as what I have posted.
    – Minsec
    Jan 22 at 7:03













up vote
0
down vote










up vote
0
down vote









sed -n -e 's/^(([0-9]+) rows)$/1/p'


This prints the digits immediately following the ( on lines that contain only (nnn rows) (where nnn is any positive integer).



No other lines are printed.






share|improve this answer












sed -n -e 's/^(([0-9]+) rows)$/1/p'


This prints the digits immediately following the ( on lines that contain only (nnn rows) (where nnn is any positive integer).



No other lines are printed.







share|improve this answer












share|improve this answer



share|improve this answer










answered Jan 22 at 6:50









cas

37.7k44393




37.7k44393











  • I tried this by specifying file name with pattern didn'print anything. sed -n -e 's/^(([0-9]+) rows)$/1/p' file.txt
    – Minsec
    Jan 22 at 6:54











  • then your file doesn't match what you specified in your question. did your files come from a windows machine? (i.e. do they have CR+LF line endings rather than unix-style LF-only?). Try adding r? immediately before the $ in the sed script - that will match either unix or windows line-endings. or convert them to unix text files with fromdos or similar.
    – cas
    Jan 22 at 6:58











  • file is created in unix only with LF style.
    – Minsec
    Jan 22 at 7:00










  • then what you stated in your question is incorrect - it does not accurately describe your files. I tested it before I posted using the sample text you provided and it printed 3.
    – cas
    Jan 22 at 7:01











  • I'm on HP UNIX will sed command differ all versions of UNIX? As command is getting executed successfully but doesn't print anything. My requirement is clear and same as what I have posted.
    – Minsec
    Jan 22 at 7:03

















  • I tried this by specifying file name with pattern didn'print anything. sed -n -e 's/^(([0-9]+) rows)$/1/p' file.txt
    – Minsec
    Jan 22 at 6:54











  • then your file doesn't match what you specified in your question. did your files come from a windows machine? (i.e. do they have CR+LF line endings rather than unix-style LF-only?). Try adding r? immediately before the $ in the sed script - that will match either unix or windows line-endings. or convert them to unix text files with fromdos or similar.
    – cas
    Jan 22 at 6:58











  • file is created in unix only with LF style.
    – Minsec
    Jan 22 at 7:00










  • then what you stated in your question is incorrect - it does not accurately describe your files. I tested it before I posted using the sample text you provided and it printed 3.
    – cas
    Jan 22 at 7:01











  • I'm on HP UNIX will sed command differ all versions of UNIX? As command is getting executed successfully but doesn't print anything. My requirement is clear and same as what I have posted.
    – Minsec
    Jan 22 at 7:03
















I tried this by specifying file name with pattern didn'print anything. sed -n -e 's/^(([0-9]+) rows)$/1/p' file.txt
– Minsec
Jan 22 at 6:54





I tried this by specifying file name with pattern didn'print anything. sed -n -e 's/^(([0-9]+) rows)$/1/p' file.txt
– Minsec
Jan 22 at 6:54













then your file doesn't match what you specified in your question. did your files come from a windows machine? (i.e. do they have CR+LF line endings rather than unix-style LF-only?). Try adding r? immediately before the $ in the sed script - that will match either unix or windows line-endings. or convert them to unix text files with fromdos or similar.
– cas
Jan 22 at 6:58





then your file doesn't match what you specified in your question. did your files come from a windows machine? (i.e. do they have CR+LF line endings rather than unix-style LF-only?). Try adding r? immediately before the $ in the sed script - that will match either unix or windows line-endings. or convert them to unix text files with fromdos or similar.
– cas
Jan 22 at 6:58













file is created in unix only with LF style.
– Minsec
Jan 22 at 7:00




file is created in unix only with LF style.
– Minsec
Jan 22 at 7:00












then what you stated in your question is incorrect - it does not accurately describe your files. I tested it before I posted using the sample text you provided and it printed 3.
– cas
Jan 22 at 7:01





then what you stated in your question is incorrect - it does not accurately describe your files. I tested it before I posted using the sample text you provided and it printed 3.
– cas
Jan 22 at 7:01













I'm on HP UNIX will sed command differ all versions of UNIX? As command is getting executed successfully but doesn't print anything. My requirement is clear and same as what I have posted.
– Minsec
Jan 22 at 7:03





I'm on HP UNIX will sed command differ all versions of UNIX? As command is getting executed successfully but doesn't print anything. My requirement is clear and same as what I have posted.
– Minsec
Jan 22 at 7:03













 

draft saved


draft discarded


























 


draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f418758%2ffetch-a-number-of-variable-length-from-a-file-using-pattern-matching%23new-answer', 'question_page');

);

Post as a guest
































































-

Popular posts from this blog

How to check contact read email or not when send email to Individual?

Image
Clash Royale CLAN TAG #URR8PPP up vote 1 down vote favorite I'm using WordPress 4.9.8, CiviCRM to 5.5.1, I usually send email to contact by Search> Find contacts View contact details Action> Send email Send email ok, Contact received mail ok like picture But status only Email sent though contact read email or not. So, can CiviCRM can change status to Email read when contact read email? wordpress email share | improve this question asked Sep 26 at 0:12 ToanLuong 49 9 add a comment  |  up vote 1 down vote favorite I'm using WordPress 4.9.8, CiviCRM to 5.5.1, I usually send email to contact by Search> Find contacts View contact details Action> Send email Send email ok, Contact received mail ok like picture But status only Email sent though contact read email or not. So, can CiviCRM can change status to Email read when contact read email? wordpress email share | improve this questi...
Read more

Displaying single band from multi-band raster using QGIS

Image
Clash Royale CLAN TAG #URR8PPP 1 How can I extract a single band from multi-band raster in QGIS? I have an remote sensed image which has 6 bands (including NDVI band), I want to display each band separately, but have no idea how to do. I have seen some questions similar here but none worked for me. The original image (has 6 bands) is: I want to display the band 6 which should be like this: But I tried gdal_translate, and couldn't get the correct result. What I have got is: qgis raster multi-band share | improve this question edited Mar 5 at 0:53 Summer asked Mar 4 at 6:42 Summer Summer 23 6 Is this any help gis.stackexchange.com/questions/220658/… ? if not gis.stackexchange.com/questions/62133/… might help. – Michael Stimson Mar 4 at 6:46 Thanks for answering but when I used gdal_translate, qgis showed that 'Error 4: Kayena.tif: No such file or directory". Would you know how to fi...
Read more

How many registers does an x86_64 CPU actually have?

Image
Clash Royale CLAN TAG #URR8PPP up vote 2 down vote favorite I am currently learning reverse engineering and am studying the flags register. I had in my mind that rflags was just another name for one of the 16 general purpose registers, for example rax or rbx . But it looks like rflags is actually an additional register. So that makes 17 registers in total... how many more could there be? I have spent at least an hour on this and found numerous different answers. The best answer so far is this, which says that there are 40 registers in total. 16 General Purpose Registers 2 Status Registers 6 Code Segment Registers 16 SSE Registers 8 FPU/MMX Registers But if I add that up, I get 48. Could anybody provide an official answer on how many registers an x86_64 CPU has (e.g. an Intel i7). Additionally, I have seen references to 'hardware' and 'architectural' registers. What are those registers and how many are there? register x86-64 share | improve this...
Read more