grep [a-z] producing 1 character

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1
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I'm trying to grep for a specific string with two identifiable characters.. example of this is

grep -rhIo '[a-zA-z]@[a-zA-z].com]

input file example:

name:phone:example@example.com

which should theoretically output:

example@example.com

but it will only output

e@e

so some how I need to indicate that a-z can be unlimited length and not just one char

edited Mar 23 at 20:27

Jeff Schaller

31.2k846105

asked Mar 23 at 20:26

Uni VPS

The expression [a-zA-Z] is a pattern which will match exactly one character. If you want zero or more of those, use [a-zA-z]*]. + will, in an extended regex, match on one or more. So you probably want to use for your pattern: [a-zA-Z]+@[a-zA-z.-]+.[a-z]+.
â€“Â DopeGhoti
Mar 23 at 20:55

I assume you left off the trailing single quote by accident?
â€“Â Jeff Schaller
Mar 23 at 21:04

add a commentÂ |Â

up vote
1
down vote

favorite

I'm trying to grep for a specific string with two identifiable characters.. example of this is

grep -rhIo '[a-zA-z]@[a-zA-z].com]

input file example:

name:phone:example@example.com

which should theoretically output:

example@example.com

but it will only output

e@e

so some how I need to indicate that a-z can be unlimited length and not just one char

edited Mar 23 at 20:27

Jeff Schaller

31.2k846105

asked Mar 23 at 20:26

Uni VPS

The expression [a-zA-Z] is a pattern which will match exactly one character. If you want zero or more of those, use [a-zA-z]*]. + will, in an extended regex, match on one or more. So you probably want to use for your pattern: [a-zA-Z]+@[a-zA-z.-]+.[a-z]+.
â€“Â DopeGhoti
Mar 23 at 20:55

I assume you left off the trailing single quote by accident?
â€“Â Jeff Schaller
Mar 23 at 21:04

add a commentÂ |Â

up vote
1
down vote

favorite

I'm trying to grep for a specific string with two identifiable characters.. example of this is

grep -rhIo '[a-zA-z]@[a-zA-z].com]

input file example:

name:phone:example@example.com

which should theoretically output:

example@example.com

but it will only output

e@e

so some how I need to indicate that a-z can be unlimited length and not just one char

edited Mar 23 at 20:27

Jeff Schaller

31.2k846105

asked Mar 23 at 20:26

Uni VPS

I'm trying to grep for a specific string with two identifiable characters.. example of this is

grep -rhIo '[a-zA-z]@[a-zA-z].com]

input file example:

name:phone:example@example.com

which should theoretically output:

example@example.com

but it will only output

e@e

so some how I need to indicate that a-z can be unlimited length and not just one char

edited Mar 23 at 20:27

Jeff Schaller

31.2k846105

asked Mar 23 at 20:26

Uni VPS

edited Mar 23 at 20:27

Jeff Schaller

31.2k846105

edited Mar 23 at 20:27

Jeff Schaller

31.2k846105

edited Mar 23 at 20:27

Jeff Schaller

31.2k846105

asked Mar 23 at 20:26

Uni VPS

asked Mar 23 at 20:26

Uni VPS

asked Mar 23 at 20:26

Uni VPS

The expression [a-zA-Z] is a pattern which will match exactly one character. If you want zero or more of those, use [a-zA-z]*]. + will, in an extended regex, match on one or more. So you probably want to use for your pattern: [a-zA-Z]+@[a-zA-z.-]+.[a-z]+.
â€“Â DopeGhoti
Mar 23 at 20:55

I assume you left off the trailing single quote by accident?
â€“Â Jeff Schaller
Mar 23 at 21:04

add a commentÂ |Â

The expression [a-zA-Z] is a pattern which will match exactly one character. If you want zero or more of those, use [a-zA-z]*]. + will, in an extended regex, match on one or more. So you probably want to use for your pattern: [a-zA-Z]+@[a-zA-z.-]+.[a-z]+.
â€“Â DopeGhoti
Mar 23 at 20:55

I assume you left off the trailing single quote by accident?
â€“Â Jeff Schaller
Mar 23 at 21:04

The expression [a-zA-Z] is a pattern which will match exactly one character. If you want zero or more of those, use [a-zA-z]*]. + will, in an extended regex, match on one or more. So you probably want to use for your pattern: [a-zA-Z]+@[a-zA-z.-]+.[a-z]+.
â€“Â DopeGhoti
Mar 23 at 20:55

I assume you left off the trailing single quote by accident?
â€“Â Jeff Schaller
Mar 23 at 21:04

add a commentÂ |Â

1 Answer
1

active

oldest

votes

up vote
1
down vote

accepted

I wouldn't even use grep in the example you posted, it's simple enough to be handled by cut:

$ echo name:phone:example@example.com | rev | cut -d: -f1 | rev
example@example.com

EDIT:

But if you want grep it would be something like this:

$ echo name:phone:example@example.com | grep -oE '[a-zA-Z]+@[a-zA-Z]+.com'
example@example.com

Note that + is used which stands one or more instances of the previous character in regular expressions and that -E has to be used with grep for that to work:

-E, --extended-regexp

 Interpret PATTERN as an extended regular expression (ERE, see below).
 (-E is specified by POSIX.)

edited Mar 23 at 20:41

answered Mar 23 at 20:35

Arkadiusz Drabczyk

7,18521532

Thank you sir for the information, it solved the problem that was occurring :)!
â€“Â Uni VPS
Mar 23 at 20:41

Why do you use rev? Why not just cut the third field?
â€“Â wjandrea
Mar 24 at 17:56

In the case the were more fields - with rev we'll always get the last one.
â€“Â Arkadiusz Drabczyk
Mar 24 at 18:54

add a commentÂ |Â

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1 Answer
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active

oldest

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up vote
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accepted

I wouldn't even use grep in the example you posted, it's simple enough to be handled by cut:

$ echo name:phone:example@example.com | rev | cut -d: -f1 | rev
example@example.com

EDIT:

But if you want grep it would be something like this:

$ echo name:phone:example@example.com | grep -oE '[a-zA-Z]+@[a-zA-Z]+.com'
example@example.com

Note that + is used which stands one or more instances of the previous character in regular expressions and that -E has to be used with grep for that to work:

-E, --extended-regexp

 Interpret PATTERN as an extended regular expression (ERE, see below).
 (-E is specified by POSIX.)

edited Mar 23 at 20:41

answered Mar 23 at 20:35

Arkadiusz Drabczyk

7,18521532

Thank you sir for the information, it solved the problem that was occurring :)!
â€“Â Uni VPS
Mar 23 at 20:41

Why do you use rev? Why not just cut the third field?
â€“Â wjandrea
Mar 24 at 17:56

In the case the were more fields - with rev we'll always get the last one.
â€“Â Arkadiusz Drabczyk
Mar 24 at 18:54

add a commentÂ |Â

up vote
1
down vote

accepted

I wouldn't even use grep in the example you posted, it's simple enough to be handled by cut:

$ echo name:phone:example@example.com | rev | cut -d: -f1 | rev
example@example.com

EDIT:

But if you want grep it would be something like this:

$ echo name:phone:example@example.com | grep -oE '[a-zA-Z]+@[a-zA-Z]+.com'
example@example.com

Note that + is used which stands one or more instances of the previous character in regular expressions and that -E has to be used with grep for that to work:

-E, --extended-regexp

 Interpret PATTERN as an extended regular expression (ERE, see below).
 (-E is specified by POSIX.)

edited Mar 23 at 20:41

answered Mar 23 at 20:35

Arkadiusz Drabczyk

7,18521532

Thank you sir for the information, it solved the problem that was occurring :)!
â€“Â Uni VPS
Mar 23 at 20:41

Why do you use rev? Why not just cut the third field?
â€“Â wjandrea
Mar 24 at 17:56

In the case the were more fields - with rev we'll always get the last one.
â€“Â Arkadiusz Drabczyk
Mar 24 at 18:54

add a commentÂ |Â

up vote
1
down vote

accepted

I wouldn't even use grep in the example you posted, it's simple enough to be handled by cut:

$ echo name:phone:example@example.com | rev | cut -d: -f1 | rev
example@example.com

EDIT:

But if you want grep it would be something like this:

$ echo name:phone:example@example.com | grep -oE '[a-zA-Z]+@[a-zA-Z]+.com'
example@example.com

Note that + is used which stands one or more instances of the previous character in regular expressions and that -E has to be used with grep for that to work:

-E, --extended-regexp

 Interpret PATTERN as an extended regular expression (ERE, see below).
 (-E is specified by POSIX.)

edited Mar 23 at 20:41

answered Mar 23 at 20:35

Arkadiusz Drabczyk

7,18521532

I wouldn't even use grep in the example you posted, it's simple enough to be handled by cut:

$ echo name:phone:example@example.com | rev | cut -d: -f1 | rev
example@example.com

EDIT:

But if you want grep it would be something like this:

$ echo name:phone:example@example.com | grep -oE '[a-zA-Z]+@[a-zA-Z]+.com'
example@example.com

Note that + is used which stands one or more instances of the previous character in regular expressions and that -E has to be used with grep for that to work:

-E, --extended-regexp

 Interpret PATTERN as an extended regular expression (ERE, see below).
 (-E is specified by POSIX.)

edited Mar 23 at 20:41

answered Mar 23 at 20:35

Arkadiusz Drabczyk

7,18521532

edited Mar 23 at 20:41

answered Mar 23 at 20:35

Arkadiusz Drabczyk

7,18521532

answered Mar 23 at 20:35

Arkadiusz Drabczyk

7,18521532

answered Mar 23 at 20:35

Arkadiusz Drabczyk

7,18521532

Thank you sir for the information, it solved the problem that was occurring :)!
â€“Â Uni VPS
Mar 23 at 20:41

Why do you use rev? Why not just cut the third field?
â€“Â wjandrea
Mar 24 at 17:56

In the case the were more fields - with rev we'll always get the last one.
â€“Â Arkadiusz Drabczyk
Mar 24 at 18:54

add a commentÂ |Â

Thank you sir for the information, it solved the problem that was occurring :)!
â€“Â Uni VPS
Mar 23 at 20:41

Why do you use rev? Why not just cut the third field?
â€“Â wjandrea
Mar 24 at 17:56

In the case the were more fields - with rev we'll always get the last one.
â€“Â Arkadiusz Drabczyk
Mar 24 at 18:54

Thank you sir for the information, it solved the problem that was occurring :)!
â€“Â Uni VPS
Mar 23 at 20:41

Why do you use rev? Why not just cut the third field?
â€“Â wjandrea
Mar 24 at 17:56

In the case the were more fields - with rev we'll always get the last one.
â€“Â Arkadiusz Drabczyk
Mar 24 at 18:54

add a commentÂ |Â

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