Grepping and sedding IP from ip addr show
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I'm trying to get just the local IP of my Arch VM. I've managed to get just the line containing what I want with grep, but I also want to trim it down with sed.
inet <<192.168.0.16>>/24 brd 192.1680.255 scope global enp0s3 $ I want the IP in <<>>
ip addr show | grep 'inet ' | sed -n -e 's/^.*inet (.*)/.*$/1/p'
-n # print nothing by default
s # replacement command
^ # begin line
.* # anything
inet # inet and then a space
(.*) # capture anything
/ # end capture at the / that comes before 24
.* # anything
$ # end
1 # replace all that with the first capture group which should be the IP
p # print the output
But as soon as I add the sed, it gives me nothing. I assume something is wrong with my regex.
sed arch-linux grep ip
edited Mar 18 at 3:10
Rui F Ribeiro
42.1k1484142
asked Nov 28 '15 at 21:47
RogueRogue
1508
add a comment |
I'm trying to get just the local IP of my Arch VM. I've managed to get just the line containing what I want with grep, but I also want to trim it down with sed.
inet <<192.168.0.16>>/24 brd 192.1680.255 scope global enp0s3 $ I want the IP in <<>>
ip addr show | grep 'inet ' | sed -n -e 's/^.*inet (.*)/.*$/1/p'
-n # print nothing by default
s # replacement command
^ # begin line
.* # anything
inet # inet and then a space
(.*) # capture anything
/ # end capture at the / that comes before 24
.* # anything
$ # end
1 # replace all that with the first capture group which should be the IP
p # print the output
But as soon as I add the sed, it gives me nothing. I assume something is wrong with my regex.
sed arch-linux grep ip
edited Mar 18 at 3:10
Rui F Ribeiro
42.1k1484142
asked Nov 28 '15 at 21:47
RogueRogue
1508
@don_crissti Oh right! Thanks, I forgot about that. That actually fixes my problem. Sorry for the bad information.
– Rogue
Nov 28 '15 at 21:52
add a comment |
I'm trying to get just the local IP of my Arch VM. I've managed to get just the line containing what I want with grep, but I also want to trim it down with sed.
inet <<192.168.0.16>>/24 brd 192.1680.255 scope global enp0s3 $ I want the IP in <<>>
ip addr show | grep 'inet ' | sed -n -e 's/^.*inet (.*)/.*$/1/p'
-n # print nothing by default
s # replacement command
^ # begin line
.* # anything
inet # inet and then a space
(.*) # capture anything
/ # end capture at the / that comes before 24
.* # anything
$ # end
1 # replace all that with the first capture group which should be the IP
p # print the output
But as soon as I add the sed, it gives me nothing. I assume something is wrong with my regex.
sed arch-linux grep ip
edited Mar 18 at 3:10
Rui F Ribeiro
42.1k1484142
asked Nov 28 '15 at 21:47
RogueRogue
1508
I'm trying to get just the local IP of my Arch VM. I've managed to get just the line containing what I want with grep, but I also want to trim it down with sed.
inet <<192.168.0.16>>/24 brd 192.1680.255 scope global enp0s3 $ I want the IP in <<>>
ip addr show | grep 'inet ' | sed -n -e 's/^.*inet (.*)/.*$/1/p'
-n # print nothing by default
s # replacement command
^ # begin line
.* # anything
inet # inet and then a space
(.*) # capture anything
/ # end capture at the / that comes before 24
.* # anything
$ # end
1 # replace all that with the first capture group which should be the IP
p # print the output
But as soon as I add the sed, it gives me nothing. I assume something is wrong with my regex.
sed arch-linux grep ip
sed arch-linux grep ip
edited Mar 18 at 3:10
Rui F Ribeiro
42.1k1484142
asked Nov 28 '15 at 21:47
RogueRogue
1508
edited Mar 18 at 3:10
Rui F Ribeiro
42.1k1484142
asked Nov 28 '15 at 21:47
RogueRogue
1508
edited Mar 18 at 3:10
Rui F Ribeiro
42.1k1484142
edited Mar 18 at 3:10
Rui F Ribeiro
42.1k1484142
edited Mar 18 at 3:10
Rui F Ribeiro
42.1k1484142
42.1k1484142
asked Nov 28 '15 at 21:47
RogueRogue
1508
asked Nov 28 '15 at 21:47
RogueRogue
1508
asked Nov 28 '15 at 21:47
RogueRogue
1508
1508
@don_crissti Oh right! Thanks, I forgot about that. That actually fixes my problem. Sorry for the bad information.
– Rogue
Nov 28 '15 at 21:52
add a comment |
@don_crissti Oh right! Thanks, I forgot about that. That actually fixes my problem. Sorry for the bad information.
– Rogue
Nov 28 '15 at 21:52
@don_crissti Oh right! Thanks, I forgot about that. That actually fixes my problem. Sorry for the bad information.
– Rogue
Nov 28 '15 at 21:52
@don_crissti Oh right! Thanks, I forgot about that. That actually fixes my problem. Sorry for the bad information.
– Rogue
Nov 28 '15 at 21:52
add a comment |
1 Answer
1
active
oldest
votes
This is easier to do with awk than grep and sed:
ip addr show eth0 | awk '/inet / print $2'
If you want to strip the CIDR netmask from the IP:
ip addr show eth0 | awk '/inet / gsub(//.*/,"",$2); print $2'
Note that an interface may have more than one IP address - e.g. ip addr show br0 | awk '/inet / print $2' on my system has 11 IPv4 addresses, some of them being public IP addresses and some of them RFC1918 private addresses.
answered Nov 28 '15 at 22:05
cascas
39.6k456103
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
This is easier to do with awk than grep and sed:
ip addr show eth0 | awk '/inet / print $2'
If you want to strip the CIDR netmask from the IP:
ip addr show eth0 | awk '/inet / gsub(//.*/,"",$2); print $2'
Note that an interface may have more than one IP address - e.g. ip addr show br0 | awk '/inet / print $2' on my system has 11 IPv4 addresses, some of them being public IP addresses and some of them RFC1918 private addresses.
answered Nov 28 '15 at 22:05
cascas
39.6k456103
add a comment |
This is easier to do with awk than grep and sed:
ip addr show eth0 | awk '/inet / print $2'
If you want to strip the CIDR netmask from the IP:
ip addr show eth0 | awk '/inet / gsub(//.*/,"",$2); print $2'
Note that an interface may have more than one IP address - e.g. ip addr show br0 | awk '/inet / print $2' on my system has 11 IPv4 addresses, some of them being public IP addresses and some of them RFC1918 private addresses.
answered Nov 28 '15 at 22:05
cascas
39.6k456103
add a comment |
This is easier to do with awk than grep and sed:
ip addr show eth0 | awk '/inet / print $2'
If you want to strip the CIDR netmask from the IP:
ip addr show eth0 | awk '/inet / gsub(//.*/,"",$2); print $2'
Note that an interface may have more than one IP address - e.g. ip addr show br0 | awk '/inet / print $2' on my system has 11 IPv4 addresses, some of them being public IP addresses and some of them RFC1918 private addresses.
answered Nov 28 '15 at 22:05
cascas
39.6k456103
This is easier to do with awk than grep and sed:
ip addr show eth0 | awk '/inet / print $2'
If you want to strip the CIDR netmask from the IP:
ip addr show eth0 | awk '/inet / gsub(//.*/,"",$2); print $2'
Note that an interface may have more than one IP address - e.g. ip addr show br0 | awk '/inet / print $2' on my system has 11 IPv4 addresses, some of them being public IP addresses and some of them RFC1918 private addresses.
answered Nov 28 '15 at 22:05
cascas
39.6k456103
answered Nov 28 '15 at 22:05
cascas
39.6k456103
answered Nov 28 '15 at 22:05
cascas
39.6k456103
answered Nov 28 '15 at 22:05
cascas
39.6k456103
39.6k456103
add a comment |
add a comment |
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@don_crissti Oh right! Thanks, I forgot about that. That actually fixes my problem. Sorry for the bad information.
– Rogue
Nov 28 '15 at 21:52