What would the chemical name be for C13H8Cl3NO
Clash Royale CLAN TAG#URR8PPP
$begingroup$
Formula
C13H8Cl3NO
SMILES
C1=C(C(=CC(=C1)Cl)Cl)N(C(C2=CC=CC=C2)=O)Cl
I found the diagram on the left in a book and drew the one on the right using
https://pubchem.ncbi.nlm.nih.gov/edit2/index.html
And got the SMILES description from that.
Any clues as to what might be an IUPAC name and the formal way to write it out? Have I have even drawn it correctly? I could not do it exactly because the two rings kept connecting if I followed the same orientation. I don't know enough about double ring compounds to even hazard a guess.
Is there a automatic naming engine out there?
A compound called British Impregnite found in The Scientific method by Louis F. Fieser p.137
organic-chemistry nomenclature molecular-structure
edited Feb 27 at 19:36
andselisk
18.6k657122
asked Feb 27 at 19:16
KalleMPKalleMP
431218
$endgroup$
add a comment |
$begingroup$
Formula
C13H8Cl3NO
SMILES
C1=C(C(=CC(=C1)Cl)Cl)N(C(C2=CC=CC=C2)=O)Cl
I found the diagram on the left in a book and drew the one on the right using
https://pubchem.ncbi.nlm.nih.gov/edit2/index.html
And got the SMILES description from that.
Any clues as to what might be an IUPAC name and the formal way to write it out? Have I have even drawn it correctly? I could not do it exactly because the two rings kept connecting if I followed the same orientation. I don't know enough about double ring compounds to even hazard a guess.
Is there a automatic naming engine out there?
A compound called British Impregnite found in The Scientific method by Louis F. Fieser p.137
organic-chemistry nomenclature molecular-structure
edited Feb 27 at 19:36
andselisk
18.6k657122
asked Feb 27 at 19:16
KalleMPKalleMP
431218
$endgroup$
1
$begingroup$
Try Chemspider chemspider.com
$endgroup$
– Waylander
Feb 27 at 19:28
4
$begingroup$
Chemdoodle thinks it is [N-Chloro(2,4-dichlorophenyl)amino]phenylformaldehyde but there is probably a less systematic version as well.
$endgroup$
– matt_black
Feb 27 at 19:36
4
$begingroup$
@matt_black Wow, that's like most complicated, but very much not systematic name I've seen.
$endgroup$
– Mithoron
Feb 27 at 19:51
5
$begingroup$
@matt_black That's Chemdoodle being Chemdoodle, I think:)
$endgroup$
– andselisk
Feb 27 at 19:54
add a comment |
$begingroup$
Formula
C13H8Cl3NO
SMILES
C1=C(C(=CC(=C1)Cl)Cl)N(C(C2=CC=CC=C2)=O)Cl
I found the diagram on the left in a book and drew the one on the right using
https://pubchem.ncbi.nlm.nih.gov/edit2/index.html
And got the SMILES description from that.
Any clues as to what might be an IUPAC name and the formal way to write it out? Have I have even drawn it correctly? I could not do it exactly because the two rings kept connecting if I followed the same orientation. I don't know enough about double ring compounds to even hazard a guess.
Is there a automatic naming engine out there?
A compound called British Impregnite found in The Scientific method by Louis F. Fieser p.137
organic-chemistry nomenclature molecular-structure
edited Feb 27 at 19:36
andselisk
18.6k657122
asked Feb 27 at 19:16
KalleMPKalleMP
431218
$endgroup$
Formula
C13H8Cl3NO
SMILES
C1=C(C(=CC(=C1)Cl)Cl)N(C(C2=CC=CC=C2)=O)Cl
I found the diagram on the left in a book and drew the one on the right using
https://pubchem.ncbi.nlm.nih.gov/edit2/index.html
And got the SMILES description from that.
Any clues as to what might be an IUPAC name and the formal way to write it out? Have I have even drawn it correctly? I could not do it exactly because the two rings kept connecting if I followed the same orientation. I don't know enough about double ring compounds to even hazard a guess.
Is there a automatic naming engine out there?
A compound called British Impregnite found in The Scientific method by Louis F. Fieser p.137
organic-chemistry nomenclature molecular-structure
organic-chemistry nomenclature molecular-structure
edited Feb 27 at 19:36
andselisk
18.6k657122
asked Feb 27 at 19:16
KalleMPKalleMP
431218
edited Feb 27 at 19:36
andselisk
18.6k657122
asked Feb 27 at 19:16
KalleMPKalleMP
431218
edited Feb 27 at 19:36
andselisk
18.6k657122
edited Feb 27 at 19:36
andselisk
18.6k657122
edited Feb 27 at 19:36
andselisk
18.6k657122
18.6k657122
asked Feb 27 at 19:16
KalleMPKalleMP
431218
asked Feb 27 at 19:16
KalleMPKalleMP
431218
asked Feb 27 at 19:16
KalleMPKalleMP
431218
431218
1
$begingroup$
Try Chemspider chemspider.com
$endgroup$
– Waylander
Feb 27 at 19:28
4
$begingroup$
Chemdoodle thinks it is [N-Chloro(2,4-dichlorophenyl)amino]phenylformaldehyde but there is probably a less systematic version as well.
$endgroup$
– matt_black
Feb 27 at 19:36
4
$begingroup$
@matt_black Wow, that's like most complicated, but very much not systematic name I've seen.
$endgroup$
– Mithoron
Feb 27 at 19:51
5
$begingroup$
@matt_black That's Chemdoodle being Chemdoodle, I think:)
$endgroup$
– andselisk
Feb 27 at 19:54
add a comment |
1
$begingroup$
Try Chemspider chemspider.com
$endgroup$
– Waylander
Feb 27 at 19:28
4
$begingroup$
Chemdoodle thinks it is [N-Chloro(2,4-dichlorophenyl)amino]phenylformaldehyde but there is probably a less systematic version as well.
$endgroup$
– matt_black
Feb 27 at 19:36
4
$begingroup$
@matt_black Wow, that's like most complicated, but very much not systematic name I've seen.
$endgroup$
– Mithoron
Feb 27 at 19:51
5
$begingroup$
@matt_black That's Chemdoodle being Chemdoodle, I think:)
$endgroup$
– andselisk
Feb 27 at 19:54
1
1
$begingroup$
Try Chemspider chemspider.com
$endgroup$
– Waylander
Feb 27 at 19:28
$begingroup$
Try Chemspider chemspider.com
$endgroup$
– Waylander
Feb 27 at 19:28
4
4
$begingroup$
Chemdoodle thinks it is [N-Chloro(2,4-dichlorophenyl)amino]phenylformaldehyde but there is probably a less systematic version as well.
$endgroup$
– matt_black
Feb 27 at 19:36
$begingroup$
Chemdoodle thinks it is [N-Chloro(2,4-dichlorophenyl)amino]phenylformaldehyde but there is probably a less systematic version as well.
$endgroup$
– matt_black
Feb 27 at 19:36
4
4
$begingroup$
@matt_black Wow, that's like most complicated, but very much not systematic name I've seen.
$endgroup$
– Mithoron
Feb 27 at 19:51
$begingroup$
@matt_black Wow, that's like most complicated, but very much not systematic name I've seen.
$endgroup$
– Mithoron
Feb 27 at 19:51
5
5
$begingroup$
@matt_black That's Chemdoodle being Chemdoodle, I think:)
$endgroup$
– andselisk
Feb 27 at 19:54
$begingroup$
@matt_black That's Chemdoodle being Chemdoodle, I think:)
$endgroup$
– andselisk
Feb 27 at 19:54
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Well, let's reconstruct that starting from the very right side, where it says a $ceC_6H_5$. The ring and the $ceCO$ group would be a benzaldehyde if it had an $ceH$ instead of an $ceN$, right? Or a benzoic acid if it was $ceOH$ instead of $ceN$. So what would it be if it had an $ceNH_2$-group? It would be a benzamide. If the $ceN$ is substituted with for example a chloride we call that N-chlorobenzamide. And now we have another $ceN$-centered ligand, the second phenyl ring. The ring has three positions, the one where it's connected to the rest of the molecule would be 1, so that makes a 2,4-dichlorophenyl.
Summarizing we get N-chloro-N-(2,4-dichlorophenyl)benzamide
edited Feb 27 at 19:37
Loong♦
34k884177
answered Feb 27 at 19:32
JustanotherchemistJustanotherchemist
2,034721
$endgroup$
$begingroup$
Thank you for the steps, it gives me great comfort to know it is no more complicated than Finnish grammar. To humour an inorganic chemistry fan like me how do you know to start with the right hand side? Is the fact that the one ring has a carbon attached the reason it is first? Could the substance be named by starting from the other ring?
$endgroup$
– KalleMP
Feb 28 at 21:35
1
$begingroup$
Intuition, the benzene ring + the carbonyl group directly reminded me of benzaldehyde. With an N-Cl attached it didn't become any harder as I showed above. From the other side I had to guess. A benzene ring with an N could be derived from Aniline, there are so called Benzanilides but the other way around it was much easier as it already had a name.
$endgroup$
– Justanotherchemist
Mar 1 at 7:44
add a comment |
$begingroup$
There is a paper [1] reporting a structural investigation of aromatic N-chloroamides.
They investigated polymorphs of similar compound they refer to as N-chloro-N-phenylbenzamide:
Chlorinated product, I suspect, is indeed is going to be named N‐chloro‐N‐(2,4‐dichlorophenyl)benzamide, as the first answer suggested.
References
- Naumov, P.; Topcu, Y.; Eckert-Maksić, M.; Glasovac, Z.; Pavošević, F.; Kochunnoonny, M.; Hara, H. Photoinduced Rearrangement of Aromatic N-Chloroamides to Chloroaromatic Amides in the Solid State: Inverted $Π_ceN–Σ_ceN$ Occupational Stability of Amidyl Radicals. The Journal of Physical Chemistry A 2011, 115 (26), 7834–7848. https://doi.org/10.1021/jp203771c.
answered Feb 27 at 19:52
andseliskandselisk
18.6k657122
$endgroup$
$begingroup$
Thank you for your research and input. I am not sure why there are two N's if they refer to the one nitrogen. How does one know what to do if there were two nitrogens?
$endgroup$
– KalleMP
Mar 1 at 20:22
1
$begingroup$
I'm glad I could help. Two N-'s reflect the fact there are two groups attached to the same nitrogen; if there were more than one nitrogen, prime(s)'and superscripted numerical locants would be used to differentiate nitrogen atoms.
$endgroup$
– andselisk
Mar 2 at 4:28
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "431"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fchemistry.stackexchange.com%2fquestions%2f110160%2fwhat-would-the-chemical-name-be-for-c13h8cl3no%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Well, let's reconstruct that starting from the very right side, where it says a $ceC_6H_5$. The ring and the $ceCO$ group would be a benzaldehyde if it had an $ceH$ instead of an $ceN$, right? Or a benzoic acid if it was $ceOH$ instead of $ceN$. So what would it be if it had an $ceNH_2$-group? It would be a benzamide. If the $ceN$ is substituted with for example a chloride we call that N-chlorobenzamide. And now we have another $ceN$-centered ligand, the second phenyl ring. The ring has three positions, the one where it's connected to the rest of the molecule would be 1, so that makes a 2,4-dichlorophenyl.
Summarizing we get N-chloro-N-(2,4-dichlorophenyl)benzamide
edited Feb 27 at 19:37
Loong♦
34k884177
answered Feb 27 at 19:32
JustanotherchemistJustanotherchemist
2,034721
$endgroup$
$begingroup$
Thank you for the steps, it gives me great comfort to know it is no more complicated than Finnish grammar. To humour an inorganic chemistry fan like me how do you know to start with the right hand side? Is the fact that the one ring has a carbon attached the reason it is first? Could the substance be named by starting from the other ring?
$endgroup$
– KalleMP
Feb 28 at 21:35
1
$begingroup$
Intuition, the benzene ring + the carbonyl group directly reminded me of benzaldehyde. With an N-Cl attached it didn't become any harder as I showed above. From the other side I had to guess. A benzene ring with an N could be derived from Aniline, there are so called Benzanilides but the other way around it was much easier as it already had a name.
$endgroup$
– Justanotherchemist
Mar 1 at 7:44
add a comment |
$begingroup$
Well, let's reconstruct that starting from the very right side, where it says a $ceC_6H_5$. The ring and the $ceCO$ group would be a benzaldehyde if it had an $ceH$ instead of an $ceN$, right? Or a benzoic acid if it was $ceOH$ instead of $ceN$. So what would it be if it had an $ceNH_2$-group? It would be a benzamide. If the $ceN$ is substituted with for example a chloride we call that N-chlorobenzamide. And now we have another $ceN$-centered ligand, the second phenyl ring. The ring has three positions, the one where it's connected to the rest of the molecule would be 1, so that makes a 2,4-dichlorophenyl.
Summarizing we get N-chloro-N-(2,4-dichlorophenyl)benzamide
edited Feb 27 at 19:37
Loong♦
34k884177
answered Feb 27 at 19:32
JustanotherchemistJustanotherchemist
2,034721
$endgroup$
$begingroup$
Thank you for the steps, it gives me great comfort to know it is no more complicated than Finnish grammar. To humour an inorganic chemistry fan like me how do you know to start with the right hand side? Is the fact that the one ring has a carbon attached the reason it is first? Could the substance be named by starting from the other ring?
$endgroup$
– KalleMP
Feb 28 at 21:35
1
$begingroup$
Intuition, the benzene ring + the carbonyl group directly reminded me of benzaldehyde. With an N-Cl attached it didn't become any harder as I showed above. From the other side I had to guess. A benzene ring with an N could be derived from Aniline, there are so called Benzanilides but the other way around it was much easier as it already had a name.
$endgroup$
– Justanotherchemist
Mar 1 at 7:44
add a comment |
$begingroup$
Well, let's reconstruct that starting from the very right side, where it says a $ceC_6H_5$. The ring and the $ceCO$ group would be a benzaldehyde if it had an $ceH$ instead of an $ceN$, right? Or a benzoic acid if it was $ceOH$ instead of $ceN$. So what would it be if it had an $ceNH_2$-group? It would be a benzamide. If the $ceN$ is substituted with for example a chloride we call that N-chlorobenzamide. And now we have another $ceN$-centered ligand, the second phenyl ring. The ring has three positions, the one where it's connected to the rest of the molecule would be 1, so that makes a 2,4-dichlorophenyl.
Summarizing we get N-chloro-N-(2,4-dichlorophenyl)benzamide
edited Feb 27 at 19:37
Loong♦
34k884177
answered Feb 27 at 19:32
JustanotherchemistJustanotherchemist
2,034721
$endgroup$
Well, let's reconstruct that starting from the very right side, where it says a $ceC_6H_5$. The ring and the $ceCO$ group would be a benzaldehyde if it had an $ceH$ instead of an $ceN$, right? Or a benzoic acid if it was $ceOH$ instead of $ceN$. So what would it be if it had an $ceNH_2$-group? It would be a benzamide. If the $ceN$ is substituted with for example a chloride we call that N-chlorobenzamide. And now we have another $ceN$-centered ligand, the second phenyl ring. The ring has three positions, the one where it's connected to the rest of the molecule would be 1, so that makes a 2,4-dichlorophenyl.
Summarizing we get N-chloro-N-(2,4-dichlorophenyl)benzamide
edited Feb 27 at 19:37
Loong♦
34k884177
answered Feb 27 at 19:32
JustanotherchemistJustanotherchemist
2,034721
edited Feb 27 at 19:37
Loong♦
34k884177
edited Feb 27 at 19:37
Loong♦
34k884177
edited Feb 27 at 19:37
Loong♦
34k884177
34k884177
answered Feb 27 at 19:32
JustanotherchemistJustanotherchemist
2,034721
answered Feb 27 at 19:32
JustanotherchemistJustanotherchemist
2,034721
answered Feb 27 at 19:32
JustanotherchemistJustanotherchemist
2,034721
2,034721
$begingroup$
Thank you for the steps, it gives me great comfort to know it is no more complicated than Finnish grammar. To humour an inorganic chemistry fan like me how do you know to start with the right hand side? Is the fact that the one ring has a carbon attached the reason it is first? Could the substance be named by starting from the other ring?
$endgroup$
– KalleMP
Feb 28 at 21:35
1
$begingroup$
Intuition, the benzene ring + the carbonyl group directly reminded me of benzaldehyde. With an N-Cl attached it didn't become any harder as I showed above. From the other side I had to guess. A benzene ring with an N could be derived from Aniline, there are so called Benzanilides but the other way around it was much easier as it already had a name.
$endgroup$
– Justanotherchemist
Mar 1 at 7:44
add a comment |
$begingroup$
Thank you for the steps, it gives me great comfort to know it is no more complicated than Finnish grammar. To humour an inorganic chemistry fan like me how do you know to start with the right hand side? Is the fact that the one ring has a carbon attached the reason it is first? Could the substance be named by starting from the other ring?
$endgroup$
– KalleMP
Feb 28 at 21:35
1
$begingroup$
Intuition, the benzene ring + the carbonyl group directly reminded me of benzaldehyde. With an N-Cl attached it didn't become any harder as I showed above. From the other side I had to guess. A benzene ring with an N could be derived from Aniline, there are so called Benzanilides but the other way around it was much easier as it already had a name.
$endgroup$
– Justanotherchemist
Mar 1 at 7:44
$begingroup$
Thank you for the steps, it gives me great comfort to know it is no more complicated than Finnish grammar. To humour an inorganic chemistry fan like me how do you know to start with the right hand side? Is the fact that the one ring has a carbon attached the reason it is first? Could the substance be named by starting from the other ring?
$endgroup$
– KalleMP
Feb 28 at 21:35
$begingroup$
Thank you for the steps, it gives me great comfort to know it is no more complicated than Finnish grammar. To humour an inorganic chemistry fan like me how do you know to start with the right hand side? Is the fact that the one ring has a carbon attached the reason it is first? Could the substance be named by starting from the other ring?
$endgroup$
– KalleMP
Feb 28 at 21:35
1
1
$begingroup$
Intuition, the benzene ring + the carbonyl group directly reminded me of benzaldehyde. With an N-Cl attached it didn't become any harder as I showed above. From the other side I had to guess. A benzene ring with an N could be derived from Aniline, there are so called Benzanilides but the other way around it was much easier as it already had a name.
$endgroup$
– Justanotherchemist
Mar 1 at 7:44
$begingroup$
Intuition, the benzene ring + the carbonyl group directly reminded me of benzaldehyde. With an N-Cl attached it didn't become any harder as I showed above. From the other side I had to guess. A benzene ring with an N could be derived from Aniline, there are so called Benzanilides but the other way around it was much easier as it already had a name.
$endgroup$
– Justanotherchemist
Mar 1 at 7:44
add a comment |
$begingroup$
There is a paper [1] reporting a structural investigation of aromatic N-chloroamides.
They investigated polymorphs of similar compound they refer to as N-chloro-N-phenylbenzamide:
Chlorinated product, I suspect, is indeed is going to be named N‐chloro‐N‐(2,4‐dichlorophenyl)benzamide, as the first answer suggested.
References
- Naumov, P.; Topcu, Y.; Eckert-Maksić, M.; Glasovac, Z.; Pavošević, F.; Kochunnoonny, M.; Hara, H. Photoinduced Rearrangement of Aromatic N-Chloroamides to Chloroaromatic Amides in the Solid State: Inverted $Π_ceN–Σ_ceN$ Occupational Stability of Amidyl Radicals. The Journal of Physical Chemistry A 2011, 115 (26), 7834–7848. https://doi.org/10.1021/jp203771c.
answered Feb 27 at 19:52
andseliskandselisk
18.6k657122
$endgroup$
$begingroup$
Thank you for your research and input. I am not sure why there are two N's if they refer to the one nitrogen. How does one know what to do if there were two nitrogens?
$endgroup$
– KalleMP
Mar 1 at 20:22
1
$begingroup$
I'm glad I could help. Two N-'s reflect the fact there are two groups attached to the same nitrogen; if there were more than one nitrogen, prime(s)'and superscripted numerical locants would be used to differentiate nitrogen atoms.
$endgroup$
– andselisk
Mar 2 at 4:28
add a comment |
$begingroup$
There is a paper [1] reporting a structural investigation of aromatic N-chloroamides.
They investigated polymorphs of similar compound they refer to as N-chloro-N-phenylbenzamide:
Chlorinated product, I suspect, is indeed is going to be named N‐chloro‐N‐(2,4‐dichlorophenyl)benzamide, as the first answer suggested.
References
- Naumov, P.; Topcu, Y.; Eckert-Maksić, M.; Glasovac, Z.; Pavošević, F.; Kochunnoonny, M.; Hara, H. Photoinduced Rearrangement of Aromatic N-Chloroamides to Chloroaromatic Amides in the Solid State: Inverted $Π_ceN–Σ_ceN$ Occupational Stability of Amidyl Radicals. The Journal of Physical Chemistry A 2011, 115 (26), 7834–7848. https://doi.org/10.1021/jp203771c.
answered Feb 27 at 19:52
andseliskandselisk
18.6k657122
$endgroup$
$begingroup$
Thank you for your research and input. I am not sure why there are two N's if they refer to the one nitrogen. How does one know what to do if there were two nitrogens?
$endgroup$
– KalleMP
Mar 1 at 20:22
1
$begingroup$
I'm glad I could help. Two N-'s reflect the fact there are two groups attached to the same nitrogen; if there were more than one nitrogen, prime(s)'and superscripted numerical locants would be used to differentiate nitrogen atoms.
$endgroup$
– andselisk
Mar 2 at 4:28
add a comment |
$begingroup$
There is a paper [1] reporting a structural investigation of aromatic N-chloroamides.
They investigated polymorphs of similar compound they refer to as N-chloro-N-phenylbenzamide:
Chlorinated product, I suspect, is indeed is going to be named N‐chloro‐N‐(2,4‐dichlorophenyl)benzamide, as the first answer suggested.
References
- Naumov, P.; Topcu, Y.; Eckert-Maksić, M.; Glasovac, Z.; Pavošević, F.; Kochunnoonny, M.; Hara, H. Photoinduced Rearrangement of Aromatic N-Chloroamides to Chloroaromatic Amides in the Solid State: Inverted $Π_ceN–Σ_ceN$ Occupational Stability of Amidyl Radicals. The Journal of Physical Chemistry A 2011, 115 (26), 7834–7848. https://doi.org/10.1021/jp203771c.
answered Feb 27 at 19:52
andseliskandselisk
18.6k657122
$endgroup$
There is a paper [1] reporting a structural investigation of aromatic N-chloroamides.
They investigated polymorphs of similar compound they refer to as N-chloro-N-phenylbenzamide:
Chlorinated product, I suspect, is indeed is going to be named N‐chloro‐N‐(2,4‐dichlorophenyl)benzamide, as the first answer suggested.
References
- Naumov, P.; Topcu, Y.; Eckert-Maksić, M.; Glasovac, Z.; Pavošević, F.; Kochunnoonny, M.; Hara, H. Photoinduced Rearrangement of Aromatic N-Chloroamides to Chloroaromatic Amides in the Solid State: Inverted $Π_ceN–Σ_ceN$ Occupational Stability of Amidyl Radicals. The Journal of Physical Chemistry A 2011, 115 (26), 7834–7848. https://doi.org/10.1021/jp203771c.
answered Feb 27 at 19:52
andseliskandselisk
18.6k657122
answered Feb 27 at 19:52
andseliskandselisk
18.6k657122
answered Feb 27 at 19:52
andseliskandselisk
18.6k657122
answered Feb 27 at 19:52
andseliskandselisk
18.6k657122
18.6k657122
$begingroup$
Thank you for your research and input. I am not sure why there are two N's if they refer to the one nitrogen. How does one know what to do if there were two nitrogens?
$endgroup$
– KalleMP
Mar 1 at 20:22
1
$begingroup$
I'm glad I could help. Two N-'s reflect the fact there are two groups attached to the same nitrogen; if there were more than one nitrogen, prime(s)'and superscripted numerical locants would be used to differentiate nitrogen atoms.
$endgroup$
– andselisk
Mar 2 at 4:28
add a comment |
$begingroup$
Thank you for your research and input. I am not sure why there are two N's if they refer to the one nitrogen. How does one know what to do if there were two nitrogens?
$endgroup$
– KalleMP
Mar 1 at 20:22
1
$begingroup$
I'm glad I could help. Two N-'s reflect the fact there are two groups attached to the same nitrogen; if there were more than one nitrogen, prime(s)'and superscripted numerical locants would be used to differentiate nitrogen atoms.
$endgroup$
– andselisk
Mar 2 at 4:28
$begingroup$
Thank you for your research and input. I am not sure why there are two N's if they refer to the one nitrogen. How does one know what to do if there were two nitrogens?
$endgroup$
– KalleMP
Mar 1 at 20:22
$begingroup$
Thank you for your research and input. I am not sure why there are two N's if they refer to the one nitrogen. How does one know what to do if there were two nitrogens?
$endgroup$
– KalleMP
Mar 1 at 20:22
1
1
$begingroup$
I'm glad I could help. Two N-'s reflect the fact there are two groups attached to the same nitrogen; if there were more than one nitrogen, prime(s)
' and superscripted numerical locants would be used to differentiate nitrogen atoms.$endgroup$
– andselisk
Mar 2 at 4:28
$begingroup$
I'm glad I could help. Two N-'s reflect the fact there are two groups attached to the same nitrogen; if there were more than one nitrogen, prime(s)
' and superscripted numerical locants would be used to differentiate nitrogen atoms.$endgroup$
– andselisk
Mar 2 at 4:28
add a comment |
Thanks for contributing an answer to Chemistry Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fchemistry.stackexchange.com%2fquestions%2f110160%2fwhat-would-the-chemical-name-be-for-c13h8cl3no%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
$begingroup$
Try Chemspider chemspider.com
$endgroup$
– Waylander
Feb 27 at 19:28
4
$begingroup$
Chemdoodle thinks it is [N-Chloro(2,4-dichlorophenyl)amino]phenylformaldehyde but there is probably a less systematic version as well.
$endgroup$
– matt_black
Feb 27 at 19:36
4
$begingroup$
@matt_black Wow, that's like most complicated, but very much not systematic name I've seen.
$endgroup$
– Mithoron
Feb 27 at 19:51
5
$begingroup$
@matt_black That's Chemdoodle being Chemdoodle, I think:)
$endgroup$
– andselisk
Feb 27 at 19:54