Order a list of zipfiles, by date modified, then unzip them in that order
Clash Royale CLAN TAG#URR8PPP
I have a list of zip files, that must be extracted by date modified, they contain updated images and the strange way the local mls provides them means that newer zip files container newer versions of those images.
How I can run a command to list the files, then unzip them in that order, oldest to newest?
I can output the list correctly in ls, but cannot get it to work.
ls -tr photo20* | -exec unzip -o -d /home/tar/public_html/images/listing_photos/idx/ ;
zip xargs exec
edited May 17 '18 at 17:48
David Moles
172114
asked Jan 30 '14 at 23:08
Paul CullenPaul Cullen
11
migrated from serverfault.com Jan 31 '14 at 20:53
This question came from our site for system and network administrators.
add a comment |
I have a list of zip files, that must be extracted by date modified, they contain updated images and the strange way the local mls provides them means that newer zip files container newer versions of those images.
How I can run a command to list the files, then unzip them in that order, oldest to newest?
I can output the list correctly in ls, but cannot get it to work.
ls -tr photo20* | -exec unzip -o -d /home/tar/public_html/images/listing_photos/idx/ ;
zip xargs exec
edited May 17 '18 at 17:48
David Moles
172114
asked Jan 30 '14 at 23:08
Paul CullenPaul Cullen
11
migrated from serverfault.com Jan 31 '14 at 20:53
This question came from our site for system and network administrators.
add a comment |
I have a list of zip files, that must be extracted by date modified, they contain updated images and the strange way the local mls provides them means that newer zip files container newer versions of those images.
How I can run a command to list the files, then unzip them in that order, oldest to newest?
I can output the list correctly in ls, but cannot get it to work.
ls -tr photo20* | -exec unzip -o -d /home/tar/public_html/images/listing_photos/idx/ ;
zip xargs exec
edited May 17 '18 at 17:48
David Moles
172114
asked Jan 30 '14 at 23:08
Paul CullenPaul Cullen
11
I have a list of zip files, that must be extracted by date modified, they contain updated images and the strange way the local mls provides them means that newer zip files container newer versions of those images.
How I can run a command to list the files, then unzip them in that order, oldest to newest?
I can output the list correctly in ls, but cannot get it to work.
ls -tr photo20* | -exec unzip -o -d /home/tar/public_html/images/listing_photos/idx/ ;
zip xargs exec
zip xargs exec
edited May 17 '18 at 17:48
David Moles
172114
asked Jan 30 '14 at 23:08
Paul CullenPaul Cullen
11
edited May 17 '18 at 17:48
David Moles
172114
asked Jan 30 '14 at 23:08
Paul CullenPaul Cullen
11
edited May 17 '18 at 17:48
David Moles
172114
edited May 17 '18 at 17:48
David Moles
172114
edited May 17 '18 at 17:48
David Moles
172114
172114
asked Jan 30 '14 at 23:08
Paul CullenPaul Cullen
11
asked Jan 30 '14 at 23:08
Paul CullenPaul Cullen
11
asked Jan 30 '14 at 23:08
Paul CullenPaul Cullen
11
11
migrated from serverfault.com Jan 31 '14 at 20:53
This question came from our site for system and network administrators.
migrated from serverfault.com Jan 31 '14 at 20:53
This question came from our site for system and network administrators.
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
How about this:
$ for f in *.zip; do ls -rt | unzip -d "$f%*.zip" "$f"; done
answered Feb 2 '14 at 13:18
ILMostro_7ILMostro_7
1,5181322
add a comment |
Try (untested):
for i in $(ls -rt *.zip)
do
unzip $i
done
answered Feb 17 at 18:46
JucaPiramaJucaPirama
1215
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
How about this:
$ for f in *.zip; do ls -rt | unzip -d "$f%*.zip" "$f"; done
answered Feb 2 '14 at 13:18
ILMostro_7ILMostro_7
1,5181322
add a comment |
How about this:
$ for f in *.zip; do ls -rt | unzip -d "$f%*.zip" "$f"; done
answered Feb 2 '14 at 13:18
ILMostro_7ILMostro_7
1,5181322
add a comment |
How about this:
$ for f in *.zip; do ls -rt | unzip -d "$f%*.zip" "$f"; done
answered Feb 2 '14 at 13:18
ILMostro_7ILMostro_7
1,5181322
How about this:
$ for f in *.zip; do ls -rt | unzip -d "$f%*.zip" "$f"; done
answered Feb 2 '14 at 13:18
ILMostro_7ILMostro_7
1,5181322
answered Feb 2 '14 at 13:18
ILMostro_7ILMostro_7
1,5181322
answered Feb 2 '14 at 13:18
ILMostro_7ILMostro_7
1,5181322
answered Feb 2 '14 at 13:18
ILMostro_7ILMostro_7
1,5181322
1,5181322
add a comment |
add a comment |
Try (untested):
for i in $(ls -rt *.zip)
do
unzip $i
done
answered Feb 17 at 18:46
JucaPiramaJucaPirama
1215
add a comment |
Try (untested):
for i in $(ls -rt *.zip)
do
unzip $i
done
answered Feb 17 at 18:46
JucaPiramaJucaPirama
1215
add a comment |
Try (untested):
for i in $(ls -rt *.zip)
do
unzip $i
done
answered Feb 17 at 18:46
JucaPiramaJucaPirama
1215
Try (untested):
for i in $(ls -rt *.zip)
do
unzip $i
done
answered Feb 17 at 18:46
JucaPiramaJucaPirama
1215
answered Feb 17 at 18:46
JucaPiramaJucaPirama
1215
answered Feb 17 at 18:46
JucaPiramaJucaPirama
1215
answered Feb 17 at 18:46
JucaPiramaJucaPirama
1215
1215
add a comment |
add a comment |
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