mjhjmtu

I need to look into a particular directory and list the number of files per level. The directory is pretty large, about 10-15 levels deep. For instance, if I have the following:

D1
|
|-- D2A (5 files in this directory)
| |-- D3A (6 files in this directory)
| |-- D3B (7 Files in this directory)
|
|-- D2B (1 file in this directory)

Then it should tell me that level 3 has 13 files and level 2 has 6 files (or 6+13, doesn't matter). Can Tree accomplish this? I've tried around mixing the options but it does not seem to work.

find . -type d | 
perl -ne 'BEGIN sub cnt $file=shift; $c="find $file -maxdepth 1 -type f chomp; printf "%s %sn", $_, cnt($_)' | 
perl -ne '/^(.*) (d*)$/; $_scalar(split ///, $1)+=$2; END printf "Depth %d has %d files.n", @$_ for map [$_,$_$_] sort keys %_ '

Results:

Depth 1 has 7 files.
Depth 2 has 2353 files.
Depth 3 has 2558 files.
Depth 4 has 8242 files.
Depth 5 has 6452 files.
Depth 6 has 674 files.
Depth 7 has 1112 files.
Depth 8 has 64 files.
Depth 9 has 154 files.

tree | sed 's/ //g;s/`/|/g;s/-.*//g' | sort | uniq -c | grep |

Results:

 35 |
 186 ||
 1408 |||
 691 ||||

The pipe (|) character indicates the depth.

I doubt if tree can accomplish this. However, find can:

find . -mindepth 3 -maxdepth 3 -type f | wc -l

would return the number of files at level 3.