Why does sound behave differently in water than in air?
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I noticed in some experiments at home that sound does not behave the same in water than in air. Is there a good scientific explanation to this?
I noticed that the sound sounded distorted in water but not in air.
I also used a software that I could use to hear the sound as if I had ears that are meant for underwater. I do not have the files because they are self wiped after I am done
acoustics water air home-experiment
edited Jan 30 at 2:32
Chair
4,24672137
asked Jan 29 at 20:57
LunaLuna
1
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add a comment |
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I noticed in some experiments at home that sound does not behave the same in water than in air. Is there a good scientific explanation to this?
I noticed that the sound sounded distorted in water but not in air.
I also used a software that I could use to hear the sound as if I had ears that are meant for underwater. I do not have the files because they are self wiped after I am done
acoustics water air home-experiment
edited Jan 30 at 2:32
Chair
4,24672137
asked Jan 29 at 20:57
LunaLuna
1
$endgroup$
add a comment |
$begingroup$
I noticed in some experiments at home that sound does not behave the same in water than in air. Is there a good scientific explanation to this?
I noticed that the sound sounded distorted in water but not in air.
I also used a software that I could use to hear the sound as if I had ears that are meant for underwater. I do not have the files because they are self wiped after I am done
acoustics water air home-experiment
edited Jan 30 at 2:32
Chair
4,24672137
asked Jan 29 at 20:57
LunaLuna
1
$endgroup$
I noticed in some experiments at home that sound does not behave the same in water than in air. Is there a good scientific explanation to this?
I noticed that the sound sounded distorted in water but not in air.
I also used a software that I could use to hear the sound as if I had ears that are meant for underwater. I do not have the files because they are self wiped after I am done
acoustics water air home-experiment
acoustics water air home-experiment
edited Jan 30 at 2:32
Chair
4,24672137
asked Jan 29 at 20:57
LunaLuna
1
edited Jan 30 at 2:32
Chair
4,24672137
asked Jan 29 at 20:57
LunaLuna
1
edited Jan 30 at 2:32
Chair
4,24672137
edited Jan 30 at 2:32
Chair
4,24672137
edited Jan 30 at 2:32
Chair
4,24672137
4,24672137
asked Jan 29 at 20:57
LunaLuna
1
asked Jan 29 at 20:57
LunaLuna
1
asked Jan 29 at 20:57
LunaLuna
1
1
add a comment |
add a comment |
3 Answers
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Human ears are evolved to furnish a good impedance match between sound waves traveling in air, and the nerve array inside your ear that turns vibrations into electrical impulses. This means that the greatest possible amount of sound wave energy will be conveyed to those nerves, across the greatest possible range of different frequencies.
The characteristic impedance of water as a sound-carrying medium is completely different from that of air. When you immerse your ear in water, there will be a significant impedance mismatch between your ear and the water. The sound waves in the water will be poorly matched to your ear, which will make the sounds faint, and the sounds you do hear will be distorted because some frequencies will be attenuated more than others.
edited Feb 3 at 20:50
pppqqq
2,81921736
answered Jan 29 at 23:18
niels nielsenniels nielsen
19.2k52959
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When any wave enters a different medium, the wavelength and direction can change (from the refractive index of the medium). For example, there is a 33% change in refraction between water and air (for light).
Sound waves are less affected than waves at light speeds, but there is still an effect.
http://hyperphysics.phy-astr.gsu.edu/hbase/Sound/refrac.html
answered Jan 29 at 21:55
CanaCoderCanaCoder
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You can think of waves in matter, whether light waves or sounds waves, as acting on tiny tuning forks.
Light is scattered, reflected, etc, by being re-radiated by atoms. Like with a tuning fork, There's a characteristic frequency, the Natural Frequency, at which the electron in an atom will oscillate ideally leading to less dampening. Other frequencies are absorbed. this gives rise to objects having a characteristic color. Natural Frequency gives color.
A similar principle applies to sound. Materials treat different wavelengths differently in transmission, re-radiation, etc. Strike a tuning fork, its natural freqency yields a characteristic tone.
So as mentioned above, the ear is attuned to certain wave properties in the air, and the air itself propagates sound in a characteristic way.
Water transmits sounds differently, the composite "tuning forks" are stiffer. Then the transfer of the tuning forks of water to the tuning forks of the ear also have a different relation to the air sound relationship.
Paul G. Hewitt's Conceptual Physics has a really good treatment of this in non-mathematical terms.
answered Jan 30 at 15:12
R. RomeroR. Romero
3606
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
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active
oldest
votes
$begingroup$
Human ears are evolved to furnish a good impedance match between sound waves traveling in air, and the nerve array inside your ear that turns vibrations into electrical impulses. This means that the greatest possible amount of sound wave energy will be conveyed to those nerves, across the greatest possible range of different frequencies.
The characteristic impedance of water as a sound-carrying medium is completely different from that of air. When you immerse your ear in water, there will be a significant impedance mismatch between your ear and the water. The sound waves in the water will be poorly matched to your ear, which will make the sounds faint, and the sounds you do hear will be distorted because some frequencies will be attenuated more than others.
edited Feb 3 at 20:50
pppqqq
2,81921736
answered Jan 29 at 23:18
niels nielsenniels nielsen
19.2k52959
$endgroup$
add a comment |
$begingroup$
Human ears are evolved to furnish a good impedance match between sound waves traveling in air, and the nerve array inside your ear that turns vibrations into electrical impulses. This means that the greatest possible amount of sound wave energy will be conveyed to those nerves, across the greatest possible range of different frequencies.
The characteristic impedance of water as a sound-carrying medium is completely different from that of air. When you immerse your ear in water, there will be a significant impedance mismatch between your ear and the water. The sound waves in the water will be poorly matched to your ear, which will make the sounds faint, and the sounds you do hear will be distorted because some frequencies will be attenuated more than others.
edited Feb 3 at 20:50
pppqqq
2,81921736
answered Jan 29 at 23:18
niels nielsenniels nielsen
19.2k52959
$endgroup$
add a comment |
$begingroup$
Human ears are evolved to furnish a good impedance match between sound waves traveling in air, and the nerve array inside your ear that turns vibrations into electrical impulses. This means that the greatest possible amount of sound wave energy will be conveyed to those nerves, across the greatest possible range of different frequencies.
The characteristic impedance of water as a sound-carrying medium is completely different from that of air. When you immerse your ear in water, there will be a significant impedance mismatch between your ear and the water. The sound waves in the water will be poorly matched to your ear, which will make the sounds faint, and the sounds you do hear will be distorted because some frequencies will be attenuated more than others.
edited Feb 3 at 20:50
pppqqq
2,81921736
answered Jan 29 at 23:18
niels nielsenniels nielsen
19.2k52959
$endgroup$
Human ears are evolved to furnish a good impedance match between sound waves traveling in air, and the nerve array inside your ear that turns vibrations into electrical impulses. This means that the greatest possible amount of sound wave energy will be conveyed to those nerves, across the greatest possible range of different frequencies.
The characteristic impedance of water as a sound-carrying medium is completely different from that of air. When you immerse your ear in water, there will be a significant impedance mismatch between your ear and the water. The sound waves in the water will be poorly matched to your ear, which will make the sounds faint, and the sounds you do hear will be distorted because some frequencies will be attenuated more than others.
edited Feb 3 at 20:50
pppqqq
2,81921736
answered Jan 29 at 23:18
niels nielsenniels nielsen
19.2k52959
edited Feb 3 at 20:50
pppqqq
2,81921736
edited Feb 3 at 20:50
pppqqq
2,81921736
edited Feb 3 at 20:50
pppqqq
2,81921736
2,81921736
answered Jan 29 at 23:18
niels nielsenniels nielsen
19.2k52959
answered Jan 29 at 23:18
niels nielsenniels nielsen
19.2k52959
answered Jan 29 at 23:18
niels nielsenniels nielsen
19.2k52959
19.2k52959
add a comment |
add a comment |
$begingroup$
When any wave enters a different medium, the wavelength and direction can change (from the refractive index of the medium). For example, there is a 33% change in refraction between water and air (for light).
Sound waves are less affected than waves at light speeds, but there is still an effect.
http://hyperphysics.phy-astr.gsu.edu/hbase/Sound/refrac.html
answered Jan 29 at 21:55
CanaCoderCanaCoder
214
$endgroup$
add a comment |
$begingroup$
When any wave enters a different medium, the wavelength and direction can change (from the refractive index of the medium). For example, there is a 33% change in refraction between water and air (for light).
Sound waves are less affected than waves at light speeds, but there is still an effect.
http://hyperphysics.phy-astr.gsu.edu/hbase/Sound/refrac.html
answered Jan 29 at 21:55
CanaCoderCanaCoder
214
$endgroup$
add a comment |
$begingroup$
When any wave enters a different medium, the wavelength and direction can change (from the refractive index of the medium). For example, there is a 33% change in refraction between water and air (for light).
Sound waves are less affected than waves at light speeds, but there is still an effect.
http://hyperphysics.phy-astr.gsu.edu/hbase/Sound/refrac.html
answered Jan 29 at 21:55
CanaCoderCanaCoder
214
$endgroup$
When any wave enters a different medium, the wavelength and direction can change (from the refractive index of the medium). For example, there is a 33% change in refraction between water and air (for light).
Sound waves are less affected than waves at light speeds, but there is still an effect.
http://hyperphysics.phy-astr.gsu.edu/hbase/Sound/refrac.html
answered Jan 29 at 21:55
CanaCoderCanaCoder
214
answered Jan 29 at 21:55
CanaCoderCanaCoder
214
answered Jan 29 at 21:55
CanaCoderCanaCoder
214
answered Jan 29 at 21:55
CanaCoderCanaCoder
214
214
add a comment |
add a comment |
$begingroup$
You can think of waves in matter, whether light waves or sounds waves, as acting on tiny tuning forks.
Light is scattered, reflected, etc, by being re-radiated by atoms. Like with a tuning fork, There's a characteristic frequency, the Natural Frequency, at which the electron in an atom will oscillate ideally leading to less dampening. Other frequencies are absorbed. this gives rise to objects having a characteristic color. Natural Frequency gives color.
A similar principle applies to sound. Materials treat different wavelengths differently in transmission, re-radiation, etc. Strike a tuning fork, its natural freqency yields a characteristic tone.
So as mentioned above, the ear is attuned to certain wave properties in the air, and the air itself propagates sound in a characteristic way.
Water transmits sounds differently, the composite "tuning forks" are stiffer. Then the transfer of the tuning forks of water to the tuning forks of the ear also have a different relation to the air sound relationship.
Paul G. Hewitt's Conceptual Physics has a really good treatment of this in non-mathematical terms.
answered Jan 30 at 15:12
R. RomeroR. Romero
3606
$endgroup$
add a comment |
$begingroup$
You can think of waves in matter, whether light waves or sounds waves, as acting on tiny tuning forks.
Light is scattered, reflected, etc, by being re-radiated by atoms. Like with a tuning fork, There's a characteristic frequency, the Natural Frequency, at which the electron in an atom will oscillate ideally leading to less dampening. Other frequencies are absorbed. this gives rise to objects having a characteristic color. Natural Frequency gives color.
A similar principle applies to sound. Materials treat different wavelengths differently in transmission, re-radiation, etc. Strike a tuning fork, its natural freqency yields a characteristic tone.
So as mentioned above, the ear is attuned to certain wave properties in the air, and the air itself propagates sound in a characteristic way.
Water transmits sounds differently, the composite "tuning forks" are stiffer. Then the transfer of the tuning forks of water to the tuning forks of the ear also have a different relation to the air sound relationship.
Paul G. Hewitt's Conceptual Physics has a really good treatment of this in non-mathematical terms.
answered Jan 30 at 15:12
R. RomeroR. Romero
3606
$endgroup$
add a comment |
$begingroup$
You can think of waves in matter, whether light waves or sounds waves, as acting on tiny tuning forks.
Light is scattered, reflected, etc, by being re-radiated by atoms. Like with a tuning fork, There's a characteristic frequency, the Natural Frequency, at which the electron in an atom will oscillate ideally leading to less dampening. Other frequencies are absorbed. this gives rise to objects having a characteristic color. Natural Frequency gives color.
A similar principle applies to sound. Materials treat different wavelengths differently in transmission, re-radiation, etc. Strike a tuning fork, its natural freqency yields a characteristic tone.
So as mentioned above, the ear is attuned to certain wave properties in the air, and the air itself propagates sound in a characteristic way.
Water transmits sounds differently, the composite "tuning forks" are stiffer. Then the transfer of the tuning forks of water to the tuning forks of the ear also have a different relation to the air sound relationship.
Paul G. Hewitt's Conceptual Physics has a really good treatment of this in non-mathematical terms.
answered Jan 30 at 15:12
R. RomeroR. Romero
3606
$endgroup$
You can think of waves in matter, whether light waves or sounds waves, as acting on tiny tuning forks.
Light is scattered, reflected, etc, by being re-radiated by atoms. Like with a tuning fork, There's a characteristic frequency, the Natural Frequency, at which the electron in an atom will oscillate ideally leading to less dampening. Other frequencies are absorbed. this gives rise to objects having a characteristic color. Natural Frequency gives color.
A similar principle applies to sound. Materials treat different wavelengths differently in transmission, re-radiation, etc. Strike a tuning fork, its natural freqency yields a characteristic tone.
So as mentioned above, the ear is attuned to certain wave properties in the air, and the air itself propagates sound in a characteristic way.
Water transmits sounds differently, the composite "tuning forks" are stiffer. Then the transfer of the tuning forks of water to the tuning forks of the ear also have a different relation to the air sound relationship.
Paul G. Hewitt's Conceptual Physics has a really good treatment of this in non-mathematical terms.
answered Jan 30 at 15:12
R. RomeroR. Romero
3606
answered Jan 30 at 15:12
R. RomeroR. Romero
3606
answered Jan 30 at 15:12
R. RomeroR. Romero
3606
answered Jan 30 at 15:12
R. RomeroR. Romero
3606
3606
add a comment |
add a comment |
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