Three stubborn siblings
Clash Royale CLAN TAG#URR8PPP
$begingroup$
2560147913
Three stubborn siblings,
of which only one is whole,
making history is their goal.
What word am I looking for?
riddle mathematics word
edited Jan 19 at 18:43
Rand al'Thor
69.6k14231465
asked Jan 19 at 17:11
JAhlenJAhlen
854
$endgroup$
add a comment |
$begingroup$
2560147913
Three stubborn siblings,
of which only one is whole,
making history is their goal.
What word am I looking for?
riddle mathematics word
edited Jan 19 at 18:43
Rand al'Thor
69.6k14231465
asked Jan 19 at 17:11
JAhlenJAhlen
854
$endgroup$
add a comment |
$begingroup$
2560147913
Three stubborn siblings,
of which only one is whole,
making history is their goal.
What word am I looking for?
riddle mathematics word
edited Jan 19 at 18:43
Rand al'Thor
69.6k14231465
asked Jan 19 at 17:11
JAhlenJAhlen
854
$endgroup$
2560147913
Three stubborn siblings,
of which only one is whole,
making history is their goal.
What word am I looking for?
riddle mathematics word
riddle mathematics word
edited Jan 19 at 18:43
Rand al'Thor
69.6k14231465
asked Jan 19 at 17:11
JAhlenJAhlen
854
edited Jan 19 at 18:43
Rand al'Thor
69.6k14231465
asked Jan 19 at 17:11
JAhlenJAhlen
854
edited Jan 19 at 18:43
Rand al'Thor
69.6k14231465
edited Jan 19 at 18:43
Rand al'Thor
69.6k14231465
edited Jan 19 at 18:43
Rand al'Thor
69.6k14231465
69.6k14231465
asked Jan 19 at 17:11
JAhlenJAhlen
854
asked Jan 19 at 17:11
JAhlenJAhlen
854
asked Jan 19 at 17:11
JAhlenJAhlen
854
854
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
The answer is
EPIC.
Because the number is
the product of three important mathematical/physical constants: $e$, $pi$, and $c$.
Confession:
I Googled it.
answered Jan 19 at 18:43
Rand al'ThorRand al'Thor
69.6k14231465
$endgroup$
$begingroup$
That's correct. (ROT13: Gbb onq gung ahzore jnf nyernql ba tbbtyr, vg znqr zl evqqyr gbb rnfl. V jvyy purpx orggre arkg gvzr :-))
$endgroup$
– JAhlen
Jan 19 at 19:22
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The answer is
EPIC.
Because the number is
the product of three important mathematical/physical constants: $e$, $pi$, and $c$.
Confession:
I Googled it.
answered Jan 19 at 18:43
Rand al'ThorRand al'Thor
69.6k14231465
$endgroup$
$begingroup$
That's correct. (ROT13: Gbb onq gung ahzore jnf nyernql ba tbbtyr, vg znqr zl evqqyr gbb rnfl. V jvyy purpx orggre arkg gvzr :-))
$endgroup$
– JAhlen
Jan 19 at 19:22
add a comment |
$begingroup$
The answer is
EPIC.
Because the number is
the product of three important mathematical/physical constants: $e$, $pi$, and $c$.
Confession:
I Googled it.
answered Jan 19 at 18:43
Rand al'ThorRand al'Thor
69.6k14231465
$endgroup$
$begingroup$
That's correct. (ROT13: Gbb onq gung ahzore jnf nyernql ba tbbtyr, vg znqr zl evqqyr gbb rnfl. V jvyy purpx orggre arkg gvzr :-))
$endgroup$
– JAhlen
Jan 19 at 19:22
add a comment |
$begingroup$
The answer is
EPIC.
Because the number is
the product of three important mathematical/physical constants: $e$, $pi$, and $c$.
Confession:
I Googled it.
answered Jan 19 at 18:43
Rand al'ThorRand al'Thor
69.6k14231465
$endgroup$
The answer is
EPIC.
Because the number is
the product of three important mathematical/physical constants: $e$, $pi$, and $c$.
Confession:
I Googled it.
answered Jan 19 at 18:43
Rand al'ThorRand al'Thor
69.6k14231465
answered Jan 19 at 18:43
Rand al'ThorRand al'Thor
69.6k14231465
answered Jan 19 at 18:43
Rand al'ThorRand al'Thor
69.6k14231465
answered Jan 19 at 18:43
Rand al'ThorRand al'Thor
69.6k14231465
69.6k14231465
$begingroup$
That's correct. (ROT13: Gbb onq gung ahzore jnf nyernql ba tbbtyr, vg znqr zl evqqyr gbb rnfl. V jvyy purpx orggre arkg gvzr :-))
$endgroup$
– JAhlen
Jan 19 at 19:22
add a comment |
$begingroup$
That's correct. (ROT13: Gbb onq gung ahzore jnf nyernql ba tbbtyr, vg znqr zl evqqyr gbb rnfl. V jvyy purpx orggre arkg gvzr :-))
$endgroup$
– JAhlen
Jan 19 at 19:22
$begingroup$
That's correct. (ROT13: Gbb onq gung ahzore jnf nyernql ba tbbtyr, vg znqr zl evqqyr gbb rnfl. V jvyy purpx orggre arkg gvzr :-))
$endgroup$
– JAhlen
Jan 19 at 19:22
$begingroup$
That's correct. (ROT13: Gbb onq gung ahzore jnf nyernql ba tbbtyr, vg znqr zl evqqyr gbb rnfl. V jvyy purpx orggre arkg gvzr :-))
$endgroup$
– JAhlen
Jan 19 at 19:22
add a comment |
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