How do I list, map and “print if count>0” with Java 8 / stream API?

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP












19















Here's my code as per now.



List<Cat> cats = petStore.getCatsForSale();

if (!cats.empty)
logger.info("Processing for cats: " + cats.size());

for (Cat cat : cats)
cat.giveFood();



My colleague writes realy nice code using the Java stream API. I tried to rewrite it as one streaming statement, but I got stuck.



petStore.getCatsForSale().stream.forEach(cat -> cat.giveFood)
.countTheCats().thenDo(logger.info("Total number of cats: " + x)); // Incorrect... is this possible?


How can I do this? Ideally I want a single streaming statement...










share|improve this question



















  • 2





    What is count? Do you expect a log statement for every non empty cat?

    – Tim Biegeleisen
    Feb 5 at 8:26















19















Here's my code as per now.



List<Cat> cats = petStore.getCatsForSale();

if (!cats.empty)
logger.info("Processing for cats: " + cats.size());

for (Cat cat : cats)
cat.giveFood();



My colleague writes realy nice code using the Java stream API. I tried to rewrite it as one streaming statement, but I got stuck.



petStore.getCatsForSale().stream.forEach(cat -> cat.giveFood)
.countTheCats().thenDo(logger.info("Total number of cats: " + x)); // Incorrect... is this possible?


How can I do this? Ideally I want a single streaming statement...










share|improve this question



















  • 2





    What is count? Do you expect a log statement for every non empty cat?

    – Tim Biegeleisen
    Feb 5 at 8:26













19












19








19


1






Here's my code as per now.



List<Cat> cats = petStore.getCatsForSale();

if (!cats.empty)
logger.info("Processing for cats: " + cats.size());

for (Cat cat : cats)
cat.giveFood();



My colleague writes realy nice code using the Java stream API. I tried to rewrite it as one streaming statement, but I got stuck.



petStore.getCatsForSale().stream.forEach(cat -> cat.giveFood)
.countTheCats().thenDo(logger.info("Total number of cats: " + x)); // Incorrect... is this possible?


How can I do this? Ideally I want a single streaming statement...










share|improve this question
















Here's my code as per now.



List<Cat> cats = petStore.getCatsForSale();

if (!cats.empty)
logger.info("Processing for cats: " + cats.size());

for (Cat cat : cats)
cat.giveFood();



My colleague writes realy nice code using the Java stream API. I tried to rewrite it as one streaming statement, but I got stuck.



petStore.getCatsForSale().stream.forEach(cat -> cat.giveFood)
.countTheCats().thenDo(logger.info("Total number of cats: " + x)); // Incorrect... is this possible?


How can I do this? Ideally I want a single streaming statement...







java java-8 functional-programming java-stream






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Feb 5 at 17:44









Peter Mortensen

13.7k1986112




13.7k1986112










asked Feb 5 at 8:21









vikingstevevikingsteve

25.8k1179116




25.8k1179116







  • 2





    What is count? Do you expect a log statement for every non empty cat?

    – Tim Biegeleisen
    Feb 5 at 8:26












  • 2





    What is count? Do you expect a log statement for every non empty cat?

    – Tim Biegeleisen
    Feb 5 at 8:26







2




2





What is count? Do you expect a log statement for every non empty cat?

– Tim Biegeleisen
Feb 5 at 8:26





What is count? Do you expect a log statement for every non empty cat?

– Tim Biegeleisen
Feb 5 at 8:26












4 Answers
4






active

oldest

votes


















11














I am not sure why you want to use streams as the current loop solutions works, but you may as well use a Stream<List<Cat>>:



Stream.of(petStore.getCatsForSale())
.filter(cats -> !cats.isEmpty())
.flatMap(cats ->
logger.info("Processing for cats: " + cats.size());
return cats.stream();
)
.forEach(Cat::giveFood);


Maybe an optimization:



Stream.of(petStore.getCatsForSale())
.filter(cats -> !cats.isEmpty())
.peek(cats -> logger.info("Processing for cats: " + cats.size()))
.flatMap(Collection::stream)
.forEach(Cat::giveFood);


Or use this other variant:



Stream.of(petStore.getCatsForSale())
.filter(cats -> !cats.isEmpty())
.mapToInt(cats ->
cats.forEach(Cat::giveFood);
return cats.size();
)
.findAny()
.ifPresent(count -> logger.info("Processing for cats: " + count));





share|improve this answer




















  • 3





    @CommonMan not really, its empty vs non-empty here. I doubt Optional would be useful here much.

    – nullpointer
    Feb 5 at 8:47






  • 3





    @nullpointer I don't really like any of the solutions here except the one from you, I think using Streams for everyday logic is just overkill and makes it extremly hard to understand the simplest of logic

    – Lino
    Feb 5 at 8:53






  • 1





    @Spara so that I have a "wrapper"-stream around the Cat-list (Stream<List<Cat>>) which allows me to operate on the whole list at once, but still inside the stream. Using cats.stream() though will give you a stream over all cats (Stream<Cat>)

    – Lino
    Feb 5 at 8:56






  • 3





    @Lino well, it already is! :P

    – nullpointer
    Feb 5 at 8:58






  • 3





    @vikingsteve Do not prefer fancy streams over readability.

    – ETO
    Feb 5 at 9:21


















18














Your current code is much better without a stream and can further be cut short to:



if (!cats.isEmpty()) 
logger.info("Processing for cats: " + cats.size());

cats.forEach(Cat::giveFood); // Assuming giveFood is a stateless operation





share|improve this answer

























  • Hi and thx for answer. Can this be done in a one liner? Of course I can write "if (!cats.isEmpty()) logger.info("...") but the purpose of this question is to write it with streams

    – vikingsteve
    Feb 5 at 8:43






  • 3





    In my opinion, is this the only acceptable solution. Don't do everything with Streams just because a tutorial told you so, just by looking at every answer here it's clear what the intentions of this one here is, but for every other? It's just a mess

    – Lino
    Feb 5 at 8:59


















4














cats.stream()
.peek(Cat::giveFood)
.findAny().ifPresent(cat -> logger.info("Processing for cats: " + cats.size()));





share|improve this answer




















  • 5





    Starting from java-9 you may leave your cats hungry ))). Execution of peek is not guaranteed anymore. Please read javadoc for more details.

    – ETO
    Feb 5 at 9:00






  • 1





    @ETO Please look at tags. It says java-8!

    – oleg.cherednik
    Feb 5 at 9:06







  • 3





    @oleg.cherednik I think ETO wanted to say that this solution may only work for java-8 which makes it not a favorable solution when one wants to migrate the version upwards :)

    – Lino
    Feb 5 at 9:11






  • 2





    @oleg.cherednik Yes, I know. Using peek for non-debugging purposes is considered harmful anyway.

    – ETO
    Feb 5 at 9:11






  • 3





    Moreover, starting from February 2019 there is no long-term support of java-8 for cemmercial users. So if you write java-8 code, consider avoiding potential migration bugs. One may not notice that java-9's peek is not working as it did before. Thus your code will have a hidden unobvious bug.

    – ETO
    Feb 5 at 9:17



















2














I agree with @Lino. This is another alternative based on his idea:



List<Cat> cats = petStore.getCatsForSale();

cats.stream().limit(1)
.flatMap(c ->
logger.info("Processing for cats: " + cats.size());
return cats.stream();
).forEach(Cat::giveFood);





share|improve this answer

























  • Why not use an IntStream.range(1)? No need to use cats.stream().limit(1) that way

    – Lino
    Feb 5 at 8:54






  • 1





    @Lino because of empty list

    – David Pérez Cabrera
    Feb 5 at 8:55










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4 Answers
4






active

oldest

votes








4 Answers
4






active

oldest

votes









active

oldest

votes






active

oldest

votes









11














I am not sure why you want to use streams as the current loop solutions works, but you may as well use a Stream<List<Cat>>:



Stream.of(petStore.getCatsForSale())
.filter(cats -> !cats.isEmpty())
.flatMap(cats ->
logger.info("Processing for cats: " + cats.size());
return cats.stream();
)
.forEach(Cat::giveFood);


Maybe an optimization:



Stream.of(petStore.getCatsForSale())
.filter(cats -> !cats.isEmpty())
.peek(cats -> logger.info("Processing for cats: " + cats.size()))
.flatMap(Collection::stream)
.forEach(Cat::giveFood);


Or use this other variant:



Stream.of(petStore.getCatsForSale())
.filter(cats -> !cats.isEmpty())
.mapToInt(cats ->
cats.forEach(Cat::giveFood);
return cats.size();
)
.findAny()
.ifPresent(count -> logger.info("Processing for cats: " + count));





share|improve this answer




















  • 3





    @CommonMan not really, its empty vs non-empty here. I doubt Optional would be useful here much.

    – nullpointer
    Feb 5 at 8:47






  • 3





    @nullpointer I don't really like any of the solutions here except the one from you, I think using Streams for everyday logic is just overkill and makes it extremly hard to understand the simplest of logic

    – Lino
    Feb 5 at 8:53






  • 1





    @Spara so that I have a "wrapper"-stream around the Cat-list (Stream<List<Cat>>) which allows me to operate on the whole list at once, but still inside the stream. Using cats.stream() though will give you a stream over all cats (Stream<Cat>)

    – Lino
    Feb 5 at 8:56






  • 3





    @Lino well, it already is! :P

    – nullpointer
    Feb 5 at 8:58






  • 3





    @vikingsteve Do not prefer fancy streams over readability.

    – ETO
    Feb 5 at 9:21















11














I am not sure why you want to use streams as the current loop solutions works, but you may as well use a Stream<List<Cat>>:



Stream.of(petStore.getCatsForSale())
.filter(cats -> !cats.isEmpty())
.flatMap(cats ->
logger.info("Processing for cats: " + cats.size());
return cats.stream();
)
.forEach(Cat::giveFood);


Maybe an optimization:



Stream.of(petStore.getCatsForSale())
.filter(cats -> !cats.isEmpty())
.peek(cats -> logger.info("Processing for cats: " + cats.size()))
.flatMap(Collection::stream)
.forEach(Cat::giveFood);


Or use this other variant:



Stream.of(petStore.getCatsForSale())
.filter(cats -> !cats.isEmpty())
.mapToInt(cats ->
cats.forEach(Cat::giveFood);
return cats.size();
)
.findAny()
.ifPresent(count -> logger.info("Processing for cats: " + count));





share|improve this answer




















  • 3





    @CommonMan not really, its empty vs non-empty here. I doubt Optional would be useful here much.

    – nullpointer
    Feb 5 at 8:47






  • 3





    @nullpointer I don't really like any of the solutions here except the one from you, I think using Streams for everyday logic is just overkill and makes it extremly hard to understand the simplest of logic

    – Lino
    Feb 5 at 8:53






  • 1





    @Spara so that I have a "wrapper"-stream around the Cat-list (Stream<List<Cat>>) which allows me to operate on the whole list at once, but still inside the stream. Using cats.stream() though will give you a stream over all cats (Stream<Cat>)

    – Lino
    Feb 5 at 8:56






  • 3





    @Lino well, it already is! :P

    – nullpointer
    Feb 5 at 8:58






  • 3





    @vikingsteve Do not prefer fancy streams over readability.

    – ETO
    Feb 5 at 9:21













11












11








11







I am not sure why you want to use streams as the current loop solutions works, but you may as well use a Stream<List<Cat>>:



Stream.of(petStore.getCatsForSale())
.filter(cats -> !cats.isEmpty())
.flatMap(cats ->
logger.info("Processing for cats: " + cats.size());
return cats.stream();
)
.forEach(Cat::giveFood);


Maybe an optimization:



Stream.of(petStore.getCatsForSale())
.filter(cats -> !cats.isEmpty())
.peek(cats -> logger.info("Processing for cats: " + cats.size()))
.flatMap(Collection::stream)
.forEach(Cat::giveFood);


Or use this other variant:



Stream.of(petStore.getCatsForSale())
.filter(cats -> !cats.isEmpty())
.mapToInt(cats ->
cats.forEach(Cat::giveFood);
return cats.size();
)
.findAny()
.ifPresent(count -> logger.info("Processing for cats: " + count));





share|improve this answer















I am not sure why you want to use streams as the current loop solutions works, but you may as well use a Stream<List<Cat>>:



Stream.of(petStore.getCatsForSale())
.filter(cats -> !cats.isEmpty())
.flatMap(cats ->
logger.info("Processing for cats: " + cats.size());
return cats.stream();
)
.forEach(Cat::giveFood);


Maybe an optimization:



Stream.of(petStore.getCatsForSale())
.filter(cats -> !cats.isEmpty())
.peek(cats -> logger.info("Processing for cats: " + cats.size()))
.flatMap(Collection::stream)
.forEach(Cat::giveFood);


Or use this other variant:



Stream.of(petStore.getCatsForSale())
.filter(cats -> !cats.isEmpty())
.mapToInt(cats ->
cats.forEach(Cat::giveFood);
return cats.size();
)
.findAny()
.ifPresent(count -> logger.info("Processing for cats: " + count));






share|improve this answer














share|improve this answer



share|improve this answer








edited Feb 5 at 17:46









Peter Mortensen

13.7k1986112




13.7k1986112










answered Feb 5 at 8:36









LinoLino

9,65722041




9,65722041







  • 3





    @CommonMan not really, its empty vs non-empty here. I doubt Optional would be useful here much.

    – nullpointer
    Feb 5 at 8:47






  • 3





    @nullpointer I don't really like any of the solutions here except the one from you, I think using Streams for everyday logic is just overkill and makes it extremly hard to understand the simplest of logic

    – Lino
    Feb 5 at 8:53






  • 1





    @Spara so that I have a "wrapper"-stream around the Cat-list (Stream<List<Cat>>) which allows me to operate on the whole list at once, but still inside the stream. Using cats.stream() though will give you a stream over all cats (Stream<Cat>)

    – Lino
    Feb 5 at 8:56






  • 3





    @Lino well, it already is! :P

    – nullpointer
    Feb 5 at 8:58






  • 3





    @vikingsteve Do not prefer fancy streams over readability.

    – ETO
    Feb 5 at 9:21












  • 3





    @CommonMan not really, its empty vs non-empty here. I doubt Optional would be useful here much.

    – nullpointer
    Feb 5 at 8:47






  • 3





    @nullpointer I don't really like any of the solutions here except the one from you, I think using Streams for everyday logic is just overkill and makes it extremly hard to understand the simplest of logic

    – Lino
    Feb 5 at 8:53






  • 1





    @Spara so that I have a "wrapper"-stream around the Cat-list (Stream<List<Cat>>) which allows me to operate on the whole list at once, but still inside the stream. Using cats.stream() though will give you a stream over all cats (Stream<Cat>)

    – Lino
    Feb 5 at 8:56






  • 3





    @Lino well, it already is! :P

    – nullpointer
    Feb 5 at 8:58






  • 3





    @vikingsteve Do not prefer fancy streams over readability.

    – ETO
    Feb 5 at 9:21







3




3





@CommonMan not really, its empty vs non-empty here. I doubt Optional would be useful here much.

– nullpointer
Feb 5 at 8:47





@CommonMan not really, its empty vs non-empty here. I doubt Optional would be useful here much.

– nullpointer
Feb 5 at 8:47




3




3





@nullpointer I don't really like any of the solutions here except the one from you, I think using Streams for everyday logic is just overkill and makes it extremly hard to understand the simplest of logic

– Lino
Feb 5 at 8:53





@nullpointer I don't really like any of the solutions here except the one from you, I think using Streams for everyday logic is just overkill and makes it extremly hard to understand the simplest of logic

– Lino
Feb 5 at 8:53




1




1





@Spara so that I have a "wrapper"-stream around the Cat-list (Stream<List<Cat>>) which allows me to operate on the whole list at once, but still inside the stream. Using cats.stream() though will give you a stream over all cats (Stream<Cat>)

– Lino
Feb 5 at 8:56





@Spara so that I have a "wrapper"-stream around the Cat-list (Stream<List<Cat>>) which allows me to operate on the whole list at once, but still inside the stream. Using cats.stream() though will give you a stream over all cats (Stream<Cat>)

– Lino
Feb 5 at 8:56




3




3





@Lino well, it already is! :P

– nullpointer
Feb 5 at 8:58





@Lino well, it already is! :P

– nullpointer
Feb 5 at 8:58




3




3





@vikingsteve Do not prefer fancy streams over readability.

– ETO
Feb 5 at 9:21





@vikingsteve Do not prefer fancy streams over readability.

– ETO
Feb 5 at 9:21













18














Your current code is much better without a stream and can further be cut short to:



if (!cats.isEmpty()) 
logger.info("Processing for cats: " + cats.size());

cats.forEach(Cat::giveFood); // Assuming giveFood is a stateless operation





share|improve this answer

























  • Hi and thx for answer. Can this be done in a one liner? Of course I can write "if (!cats.isEmpty()) logger.info("...") but the purpose of this question is to write it with streams

    – vikingsteve
    Feb 5 at 8:43






  • 3





    In my opinion, is this the only acceptable solution. Don't do everything with Streams just because a tutorial told you so, just by looking at every answer here it's clear what the intentions of this one here is, but for every other? It's just a mess

    – Lino
    Feb 5 at 8:59















18














Your current code is much better without a stream and can further be cut short to:



if (!cats.isEmpty()) 
logger.info("Processing for cats: " + cats.size());

cats.forEach(Cat::giveFood); // Assuming giveFood is a stateless operation





share|improve this answer

























  • Hi and thx for answer. Can this be done in a one liner? Of course I can write "if (!cats.isEmpty()) logger.info("...") but the purpose of this question is to write it with streams

    – vikingsteve
    Feb 5 at 8:43






  • 3





    In my opinion, is this the only acceptable solution. Don't do everything with Streams just because a tutorial told you so, just by looking at every answer here it's clear what the intentions of this one here is, but for every other? It's just a mess

    – Lino
    Feb 5 at 8:59













18












18








18







Your current code is much better without a stream and can further be cut short to:



if (!cats.isEmpty()) 
logger.info("Processing for cats: " + cats.size());

cats.forEach(Cat::giveFood); // Assuming giveFood is a stateless operation





share|improve this answer















Your current code is much better without a stream and can further be cut short to:



if (!cats.isEmpty()) 
logger.info("Processing for cats: " + cats.size());

cats.forEach(Cat::giveFood); // Assuming giveFood is a stateless operation






share|improve this answer














share|improve this answer



share|improve this answer








edited Feb 5 at 17:48









Peter Mortensen

13.7k1986112




13.7k1986112










answered Feb 5 at 8:36









nullpointernullpointer

43.2k10101200




43.2k10101200












  • Hi and thx for answer. Can this be done in a one liner? Of course I can write "if (!cats.isEmpty()) logger.info("...") but the purpose of this question is to write it with streams

    – vikingsteve
    Feb 5 at 8:43






  • 3





    In my opinion, is this the only acceptable solution. Don't do everything with Streams just because a tutorial told you so, just by looking at every answer here it's clear what the intentions of this one here is, but for every other? It's just a mess

    – Lino
    Feb 5 at 8:59

















  • Hi and thx for answer. Can this be done in a one liner? Of course I can write "if (!cats.isEmpty()) logger.info("...") but the purpose of this question is to write it with streams

    – vikingsteve
    Feb 5 at 8:43






  • 3





    In my opinion, is this the only acceptable solution. Don't do everything with Streams just because a tutorial told you so, just by looking at every answer here it's clear what the intentions of this one here is, but for every other? It's just a mess

    – Lino
    Feb 5 at 8:59
















Hi and thx for answer. Can this be done in a one liner? Of course I can write "if (!cats.isEmpty()) logger.info("...") but the purpose of this question is to write it with streams

– vikingsteve
Feb 5 at 8:43





Hi and thx for answer. Can this be done in a one liner? Of course I can write "if (!cats.isEmpty()) logger.info("...") but the purpose of this question is to write it with streams

– vikingsteve
Feb 5 at 8:43




3




3





In my opinion, is this the only acceptable solution. Don't do everything with Streams just because a tutorial told you so, just by looking at every answer here it's clear what the intentions of this one here is, but for every other? It's just a mess

– Lino
Feb 5 at 8:59





In my opinion, is this the only acceptable solution. Don't do everything with Streams just because a tutorial told you so, just by looking at every answer here it's clear what the intentions of this one here is, but for every other? It's just a mess

– Lino
Feb 5 at 8:59











4














cats.stream()
.peek(Cat::giveFood)
.findAny().ifPresent(cat -> logger.info("Processing for cats: " + cats.size()));





share|improve this answer




















  • 5





    Starting from java-9 you may leave your cats hungry ))). Execution of peek is not guaranteed anymore. Please read javadoc for more details.

    – ETO
    Feb 5 at 9:00






  • 1





    @ETO Please look at tags. It says java-8!

    – oleg.cherednik
    Feb 5 at 9:06







  • 3





    @oleg.cherednik I think ETO wanted to say that this solution may only work for java-8 which makes it not a favorable solution when one wants to migrate the version upwards :)

    – Lino
    Feb 5 at 9:11






  • 2





    @oleg.cherednik Yes, I know. Using peek for non-debugging purposes is considered harmful anyway.

    – ETO
    Feb 5 at 9:11






  • 3





    Moreover, starting from February 2019 there is no long-term support of java-8 for cemmercial users. So if you write java-8 code, consider avoiding potential migration bugs. One may not notice that java-9's peek is not working as it did before. Thus your code will have a hidden unobvious bug.

    – ETO
    Feb 5 at 9:17
















4














cats.stream()
.peek(Cat::giveFood)
.findAny().ifPresent(cat -> logger.info("Processing for cats: " + cats.size()));





share|improve this answer




















  • 5





    Starting from java-9 you may leave your cats hungry ))). Execution of peek is not guaranteed anymore. Please read javadoc for more details.

    – ETO
    Feb 5 at 9:00






  • 1





    @ETO Please look at tags. It says java-8!

    – oleg.cherednik
    Feb 5 at 9:06







  • 3





    @oleg.cherednik I think ETO wanted to say that this solution may only work for java-8 which makes it not a favorable solution when one wants to migrate the version upwards :)

    – Lino
    Feb 5 at 9:11






  • 2





    @oleg.cherednik Yes, I know. Using peek for non-debugging purposes is considered harmful anyway.

    – ETO
    Feb 5 at 9:11






  • 3





    Moreover, starting from February 2019 there is no long-term support of java-8 for cemmercial users. So if you write java-8 code, consider avoiding potential migration bugs. One may not notice that java-9's peek is not working as it did before. Thus your code will have a hidden unobvious bug.

    – ETO
    Feb 5 at 9:17














4












4








4







cats.stream()
.peek(Cat::giveFood)
.findAny().ifPresent(cat -> logger.info("Processing for cats: " + cats.size()));





share|improve this answer















cats.stream()
.peek(Cat::giveFood)
.findAny().ifPresent(cat -> logger.info("Processing for cats: " + cats.size()));






share|improve this answer














share|improve this answer



share|improve this answer








edited Feb 5 at 8:48

























answered Feb 5 at 8:38









oleg.cherednikoleg.cherednik

7,08821118




7,08821118







  • 5





    Starting from java-9 you may leave your cats hungry ))). Execution of peek is not guaranteed anymore. Please read javadoc for more details.

    – ETO
    Feb 5 at 9:00






  • 1





    @ETO Please look at tags. It says java-8!

    – oleg.cherednik
    Feb 5 at 9:06







  • 3





    @oleg.cherednik I think ETO wanted to say that this solution may only work for java-8 which makes it not a favorable solution when one wants to migrate the version upwards :)

    – Lino
    Feb 5 at 9:11






  • 2





    @oleg.cherednik Yes, I know. Using peek for non-debugging purposes is considered harmful anyway.

    – ETO
    Feb 5 at 9:11






  • 3





    Moreover, starting from February 2019 there is no long-term support of java-8 for cemmercial users. So if you write java-8 code, consider avoiding potential migration bugs. One may not notice that java-9's peek is not working as it did before. Thus your code will have a hidden unobvious bug.

    – ETO
    Feb 5 at 9:17













  • 5





    Starting from java-9 you may leave your cats hungry ))). Execution of peek is not guaranteed anymore. Please read javadoc for more details.

    – ETO
    Feb 5 at 9:00






  • 1





    @ETO Please look at tags. It says java-8!

    – oleg.cherednik
    Feb 5 at 9:06







  • 3





    @oleg.cherednik I think ETO wanted to say that this solution may only work for java-8 which makes it not a favorable solution when one wants to migrate the version upwards :)

    – Lino
    Feb 5 at 9:11






  • 2





    @oleg.cherednik Yes, I know. Using peek for non-debugging purposes is considered harmful anyway.

    – ETO
    Feb 5 at 9:11






  • 3





    Moreover, starting from February 2019 there is no long-term support of java-8 for cemmercial users. So if you write java-8 code, consider avoiding potential migration bugs. One may not notice that java-9's peek is not working as it did before. Thus your code will have a hidden unobvious bug.

    – ETO
    Feb 5 at 9:17








5




5





Starting from java-9 you may leave your cats hungry ))). Execution of peek is not guaranteed anymore. Please read javadoc for more details.

– ETO
Feb 5 at 9:00





Starting from java-9 you may leave your cats hungry ))). Execution of peek is not guaranteed anymore. Please read javadoc for more details.

– ETO
Feb 5 at 9:00




1




1





@ETO Please look at tags. It says java-8!

– oleg.cherednik
Feb 5 at 9:06






@ETO Please look at tags. It says java-8!

– oleg.cherednik
Feb 5 at 9:06





3




3





@oleg.cherednik I think ETO wanted to say that this solution may only work for java-8 which makes it not a favorable solution when one wants to migrate the version upwards :)

– Lino
Feb 5 at 9:11





@oleg.cherednik I think ETO wanted to say that this solution may only work for java-8 which makes it not a favorable solution when one wants to migrate the version upwards :)

– Lino
Feb 5 at 9:11




2




2





@oleg.cherednik Yes, I know. Using peek for non-debugging purposes is considered harmful anyway.

– ETO
Feb 5 at 9:11





@oleg.cherednik Yes, I know. Using peek for non-debugging purposes is considered harmful anyway.

– ETO
Feb 5 at 9:11




3




3





Moreover, starting from February 2019 there is no long-term support of java-8 for cemmercial users. So if you write java-8 code, consider avoiding potential migration bugs. One may not notice that java-9's peek is not working as it did before. Thus your code will have a hidden unobvious bug.

– ETO
Feb 5 at 9:17






Moreover, starting from February 2019 there is no long-term support of java-8 for cemmercial users. So if you write java-8 code, consider avoiding potential migration bugs. One may not notice that java-9's peek is not working as it did before. Thus your code will have a hidden unobvious bug.

– ETO
Feb 5 at 9:17












2














I agree with @Lino. This is another alternative based on his idea:



List<Cat> cats = petStore.getCatsForSale();

cats.stream().limit(1)
.flatMap(c ->
logger.info("Processing for cats: " + cats.size());
return cats.stream();
).forEach(Cat::giveFood);





share|improve this answer

























  • Why not use an IntStream.range(1)? No need to use cats.stream().limit(1) that way

    – Lino
    Feb 5 at 8:54






  • 1





    @Lino because of empty list

    – David Pérez Cabrera
    Feb 5 at 8:55















2














I agree with @Lino. This is another alternative based on his idea:



List<Cat> cats = petStore.getCatsForSale();

cats.stream().limit(1)
.flatMap(c ->
logger.info("Processing for cats: " + cats.size());
return cats.stream();
).forEach(Cat::giveFood);





share|improve this answer

























  • Why not use an IntStream.range(1)? No need to use cats.stream().limit(1) that way

    – Lino
    Feb 5 at 8:54






  • 1





    @Lino because of empty list

    – David Pérez Cabrera
    Feb 5 at 8:55













2












2








2







I agree with @Lino. This is another alternative based on his idea:



List<Cat> cats = petStore.getCatsForSale();

cats.stream().limit(1)
.flatMap(c ->
logger.info("Processing for cats: " + cats.size());
return cats.stream();
).forEach(Cat::giveFood);





share|improve this answer















I agree with @Lino. This is another alternative based on his idea:



List<Cat> cats = petStore.getCatsForSale();

cats.stream().limit(1)
.flatMap(c ->
logger.info("Processing for cats: " + cats.size());
return cats.stream();
).forEach(Cat::giveFood);






share|improve this answer














share|improve this answer



share|improve this answer








edited Feb 5 at 17:49









Peter Mortensen

13.7k1986112




13.7k1986112










answered Feb 5 at 8:48









David Pérez CabreraDavid Pérez Cabrera

4,08321331




4,08321331












  • Why not use an IntStream.range(1)? No need to use cats.stream().limit(1) that way

    – Lino
    Feb 5 at 8:54






  • 1





    @Lino because of empty list

    – David Pérez Cabrera
    Feb 5 at 8:55

















  • Why not use an IntStream.range(1)? No need to use cats.stream().limit(1) that way

    – Lino
    Feb 5 at 8:54






  • 1





    @Lino because of empty list

    – David Pérez Cabrera
    Feb 5 at 8:55
















Why not use an IntStream.range(1)? No need to use cats.stream().limit(1) that way

– Lino
Feb 5 at 8:54





Why not use an IntStream.range(1)? No need to use cats.stream().limit(1) that way

– Lino
Feb 5 at 8:54




1




1





@Lino because of empty list

– David Pérez Cabrera
Feb 5 at 8:55





@Lino because of empty list

– David Pérez Cabrera
Feb 5 at 8:55

















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