Display Spinner while waiting for some process to finish
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How can I show spinner till command line finish it is job? In other words, If I am running a script and I want to show spinner while this script is running and the spinner disappears when the script finish it is job.
Bellow is a common spinner code:
i=1
sp="/-|"
echo -n ' '
while true
do
printf "b$sp:i++%$#sp:1"
done
How can I link the previous spinner code to a command to let it show spinner while the command is running and the spinner disappears when the command finish it is job? If I include the command inside the loop it will loop with the spinner so what is the solution in this case?
bash
add a comment |
How can I show spinner till command line finish it is job? In other words, If I am running a script and I want to show spinner while this script is running and the spinner disappears when the script finish it is job.
Bellow is a common spinner code:
i=1
sp="/-|"
echo -n ' '
while true
do
printf "b$sp:i++%$#sp:1"
done
How can I link the previous spinner code to a command to let it show spinner while the command is running and the spinner disappears when the command finish it is job? If I include the command inside the loop it will loop with the spinner so what is the solution in this case?
bash
add a comment |
How can I show spinner till command line finish it is job? In other words, If I am running a script and I want to show spinner while this script is running and the spinner disappears when the script finish it is job.
Bellow is a common spinner code:
i=1
sp="/-|"
echo -n ' '
while true
do
printf "b$sp:i++%$#sp:1"
done
How can I link the previous spinner code to a command to let it show spinner while the command is running and the spinner disappears when the command finish it is job? If I include the command inside the loop it will loop with the spinner so what is the solution in this case?
bash
How can I show spinner till command line finish it is job? In other words, If I am running a script and I want to show spinner while this script is running and the spinner disappears when the script finish it is job.
Bellow is a common spinner code:
i=1
sp="/-|"
echo -n ' '
while true
do
printf "b$sp:i++%$#sp:1"
done
How can I link the previous spinner code to a command to let it show spinner while the command is running and the spinner disappears when the command finish it is job? If I include the command inside the loop it will loop with the spinner so what is the solution in this case?
bash
bash
asked Aug 24 '15 at 17:03
user88036
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Have your while loop watch for your real command to exit. I'll assume a Linux environment that has /proc entries for each PID, but you could slice it other ways:
#!/bin/bash
# your real command here, instead of sleep
sleep 7 &
PID=$!
i=1
sp="/-|"
echo -n ' '
while [ -d /proc/$PID ]
do
printf "b$sp:i++%$#sp:1"
done
answered Aug 24 '15 at 17:22
Jeff SchallerJeff Schaller
41.1k1056131
3
This is a busy loop that will eat up cpu resources. I'd suggest having a delay of some kind in your while loop.
– ACase
Jul 20 '16 at 14:36
add a comment |
This shell script should do what you're looking for:
#!/usr/bin/env bash
show_spinner()
/-'
local temp
while ps a
("$@") &
show_spinner "$!"
You can invoke it like this to display a spinner while the command sleep 10 is running:
$ spinner sleep 10
answered Apr 14 '16 at 21:03
jsearsjsears
17114
See also stackoverflow.com/a/20369590/2908724
– bishop
Oct 21 '16 at 17:28
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Have your while loop watch for your real command to exit. I'll assume a Linux environment that has /proc entries for each PID, but you could slice it other ways:
#!/bin/bash
# your real command here, instead of sleep
sleep 7 &
PID=$!
i=1
sp="/-|"
echo -n ' '
while [ -d /proc/$PID ]
do
printf "b$sp:i++%$#sp:1"
done
answered Aug 24 '15 at 17:22
Jeff SchallerJeff Schaller
41.1k1056131
3
This is a busy loop that will eat up cpu resources. I'd suggest having a delay of some kind in your while loop.
– ACase
Jul 20 '16 at 14:36
add a comment |
Have your while loop watch for your real command to exit. I'll assume a Linux environment that has /proc entries for each PID, but you could slice it other ways:
#!/bin/bash
# your real command here, instead of sleep
sleep 7 &
PID=$!
i=1
sp="/-|"
echo -n ' '
while [ -d /proc/$PID ]
do
printf "b$sp:i++%$#sp:1"
done
answered Aug 24 '15 at 17:22
Jeff SchallerJeff Schaller
41.1k1056131
3
This is a busy loop that will eat up cpu resources. I'd suggest having a delay of some kind in your while loop.
– ACase
Jul 20 '16 at 14:36
add a comment |
Have your while loop watch for your real command to exit. I'll assume a Linux environment that has /proc entries for each PID, but you could slice it other ways:
#!/bin/bash
# your real command here, instead of sleep
sleep 7 &
PID=$!
i=1
sp="/-|"
echo -n ' '
while [ -d /proc/$PID ]
do
printf "b$sp:i++%$#sp:1"
done
answered Aug 24 '15 at 17:22
Jeff SchallerJeff Schaller
41.1k1056131
Have your while loop watch for your real command to exit. I'll assume a Linux environment that has /proc entries for each PID, but you could slice it other ways:
#!/bin/bash
# your real command here, instead of sleep
sleep 7 &
PID=$!
i=1
sp="/-|"
echo -n ' '
while [ -d /proc/$PID ]
do
printf "b$sp:i++%$#sp:1"
done
answered Aug 24 '15 at 17:22
Jeff SchallerJeff Schaller
41.1k1056131
answered Aug 24 '15 at 17:22
Jeff SchallerJeff Schaller
41.1k1056131
answered Aug 24 '15 at 17:22
Jeff SchallerJeff Schaller
41.1k1056131
answered Aug 24 '15 at 17:22
Jeff SchallerJeff Schaller
41.1k1056131
41.1k1056131
3
This is a busy loop that will eat up cpu resources. I'd suggest having a delay of some kind in your while loop.
– ACase
Jul 20 '16 at 14:36
add a comment |
3
This is a busy loop that will eat up cpu resources. I'd suggest having a delay of some kind in your while loop.
– ACase
Jul 20 '16 at 14:36
3
3
This is a busy loop that will eat up cpu resources. I'd suggest having a delay of some kind in your while loop.
– ACase
Jul 20 '16 at 14:36
This is a busy loop that will eat up cpu resources. I'd suggest having a delay of some kind in your while loop.
– ACase
Jul 20 '16 at 14:36
add a comment |
This shell script should do what you're looking for:
#!/usr/bin/env bash
show_spinner()
/-'
local temp
while ps a
("$@") &
show_spinner "$!"
You can invoke it like this to display a spinner while the command sleep 10 is running:
$ spinner sleep 10
answered Apr 14 '16 at 21:03
jsearsjsears
17114
See also stackoverflow.com/a/20369590/2908724
– bishop
Oct 21 '16 at 17:28
add a comment |
This shell script should do what you're looking for:
#!/usr/bin/env bash
show_spinner()
/-'
local temp
while ps a
("$@") &
show_spinner "$!"
You can invoke it like this to display a spinner while the command sleep 10 is running:
$ spinner sleep 10
answered Apr 14 '16 at 21:03
jsearsjsears
17114
See also stackoverflow.com/a/20369590/2908724
– bishop
Oct 21 '16 at 17:28
add a comment |
This shell script should do what you're looking for:
#!/usr/bin/env bash
show_spinner()
/-'
local temp
while ps a
("$@") &
show_spinner "$!"
You can invoke it like this to display a spinner while the command sleep 10 is running:
$ spinner sleep 10
answered Apr 14 '16 at 21:03
jsearsjsears
17114
This shell script should do what you're looking for:
#!/usr/bin/env bash
show_spinner()
/-'
local temp
while ps a
("$@") &
show_spinner "$!"
You can invoke it like this to display a spinner while the command sleep 10 is running:
$ spinner sleep 10
answered Apr 14 '16 at 21:03
jsearsjsears
17114
answered Apr 14 '16 at 21:03
jsearsjsears
17114
answered Apr 14 '16 at 21:03
jsearsjsears
17114
answered Apr 14 '16 at 21:03
jsearsjsears
17114
17114
See also stackoverflow.com/a/20369590/2908724
– bishop
Oct 21 '16 at 17:28
add a comment |
See also stackoverflow.com/a/20369590/2908724
– bishop
Oct 21 '16 at 17:28
See also stackoverflow.com/a/20369590/2908724
– bishop
Oct 21 '16 at 17:28
See also stackoverflow.com/a/20369590/2908724
– bishop
Oct 21 '16 at 17:28
add a comment |
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