mjhjmtu

How to increment variables dynamically.
I have written below script but it is giving an error.

#!/bin/bash
X='101 Hari BAN'
for i in "$X[@]"
 do
 "V"$j=`echo $i|cut -d' ' -f$j` 
 echo "V"$j
 j=`expr $j + 1`
 done

Output should be,

V1=101
V2=Hari
V3=BAN

First of all, if you are using bash and you want to iterate over separate things, then use an array:

X=( 101 Hari BAN "many words" "a * in the sky" )

This allows you to handle string that contain whitespaces and filename globbing patterns correctly by appropriately quoting those strings.

Then loop over the array:

X=( 101 Hari BAN "many words" "a * in the sky" )

for item in "$X[@]"; do

done

Then, it's a matter of outputting the result. For this we use a counter and printf:

X=( 101 Hari BAN "many words" "a * in the sky" )

n=0
for item in "$X[@]"; do
 printf 'V%d=%sn' "$(( ++n ))" "$item"
done

The printf format string V%d=%sn means "The character V followed by an integer, then a = and some string. End with newline". The integer and string is taken from the remaining arguments to printf. The variable n is incremented before being used by the printf.

Add the correct #!-line pointing to your bash interpreter and you're done.

The output would be

V1=101
V2=Hari
V3=BAN
V4=many words
V5=a * in the sky

According to comments below, you were expecting V1, V2 to be variables, but they obviously are just text in the output.

Again, what I think you need here is not separate variables but an array.

In fact, the array that we already have, X already contains the necessary data, so we could just rename it.

#!/bin/bash

V=( 101 Hari BAN )

for i in "$!V[@]"; do
 printf 'V[%s] = %sn' "$i" "$V[i]"
done

That is, you simply use $V[0], $V[1], etc. to access the elements of the array V.