How to delete old backups based on a date in file name?

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up vote
5
down vote

favorite
2












I have a daily backups named like this:



yyyymmddhhmm.zip // pattern
201503200100.zip // backup from 20. 3. 2015 1:00


I'm trying to create a script that deletes all backups older than 3 days. The script should be also able to delete all other files in the folder not matching the pattern (but there would be a switch for that in the script to disable this).



To determine the file age I don't want to use backups timestamps as other programs also manipulate with the files and it can be tampered.



With the help of: Remove files older than 5 days in UNIX (date in file name, not timestamp)
I got:



#!/bin/bash

DELETE_OTHERS=yes
BACKUPS_PATH=/mnt/!ARCHIVE/!backups/
THRESHOLD=$(date -d "3 days ago" +%Y%m%d%H%M)

ls -1 $BACKUPS_PATH????????????.zip |
while read A DATE B FILE
do
[[ $DATE -le $THRESHOLD ]] && rm -v $BACKUPS_PATH$FILE
done

if [ $DELETE_OTHERS == "yes" ]; then
rm $BACKUPS_PATH*.* // but I don't know how to not-delete the files matching pattern
fi


But it keeps saying:



rm: missing operand


Where is the problem and how to complete the script?










share|improve this question























  • Do you actually have a ! at the beginning of your ARCHIVE and backups directory names? If so, why in the world would you want to complicate your life in such a way?
    – terdon
    Mar 21 '15 at 17:09










  • Yes I have. I'm using ! to keep the one or two key directories on top of the file listings when there is a lot of other files/folders in that directory and it is sorted by name. I am all ears if there is a better technique for that :)
    – Joudicek Jouda
    Mar 21 '15 at 19:13






  • 1




    I just add aa or similar to the name, for example aabackups. That way, you don't need to escape special characters. It's a matter of personal preference though.
    – terdon
    Mar 21 '15 at 20:34














up vote
5
down vote

favorite
2












I have a daily backups named like this:



yyyymmddhhmm.zip // pattern
201503200100.zip // backup from 20. 3. 2015 1:00


I'm trying to create a script that deletes all backups older than 3 days. The script should be also able to delete all other files in the folder not matching the pattern (but there would be a switch for that in the script to disable this).



To determine the file age I don't want to use backups timestamps as other programs also manipulate with the files and it can be tampered.



With the help of: Remove files older than 5 days in UNIX (date in file name, not timestamp)
I got:



#!/bin/bash

DELETE_OTHERS=yes
BACKUPS_PATH=/mnt/!ARCHIVE/!backups/
THRESHOLD=$(date -d "3 days ago" +%Y%m%d%H%M)

ls -1 $BACKUPS_PATH????????????.zip |
while read A DATE B FILE
do
[[ $DATE -le $THRESHOLD ]] && rm -v $BACKUPS_PATH$FILE
done

if [ $DELETE_OTHERS == "yes" ]; then
rm $BACKUPS_PATH*.* // but I don't know how to not-delete the files matching pattern
fi


But it keeps saying:



rm: missing operand


Where is the problem and how to complete the script?










share|improve this question























  • Do you actually have a ! at the beginning of your ARCHIVE and backups directory names? If so, why in the world would you want to complicate your life in such a way?
    – terdon
    Mar 21 '15 at 17:09










  • Yes I have. I'm using ! to keep the one or two key directories on top of the file listings when there is a lot of other files/folders in that directory and it is sorted by name. I am all ears if there is a better technique for that :)
    – Joudicek Jouda
    Mar 21 '15 at 19:13






  • 1




    I just add aa or similar to the name, for example aabackups. That way, you don't need to escape special characters. It's a matter of personal preference though.
    – terdon
    Mar 21 '15 at 20:34












up vote
5
down vote

favorite
2









up vote
5
down vote

favorite
2






2





I have a daily backups named like this:



yyyymmddhhmm.zip // pattern
201503200100.zip // backup from 20. 3. 2015 1:00


I'm trying to create a script that deletes all backups older than 3 days. The script should be also able to delete all other files in the folder not matching the pattern (but there would be a switch for that in the script to disable this).



To determine the file age I don't want to use backups timestamps as other programs also manipulate with the files and it can be tampered.



With the help of: Remove files older than 5 days in UNIX (date in file name, not timestamp)
I got:



#!/bin/bash

DELETE_OTHERS=yes
BACKUPS_PATH=/mnt/!ARCHIVE/!backups/
THRESHOLD=$(date -d "3 days ago" +%Y%m%d%H%M)

ls -1 $BACKUPS_PATH????????????.zip |
while read A DATE B FILE
do
[[ $DATE -le $THRESHOLD ]] && rm -v $BACKUPS_PATH$FILE
done

if [ $DELETE_OTHERS == "yes" ]; then
rm $BACKUPS_PATH*.* // but I don't know how to not-delete the files matching pattern
fi


But it keeps saying:



rm: missing operand


Where is the problem and how to complete the script?










share|improve this question















I have a daily backups named like this:



yyyymmddhhmm.zip // pattern
201503200100.zip // backup from 20. 3. 2015 1:00


I'm trying to create a script that deletes all backups older than 3 days. The script should be also able to delete all other files in the folder not matching the pattern (but there would be a switch for that in the script to disable this).



To determine the file age I don't want to use backups timestamps as other programs also manipulate with the files and it can be tampered.



With the help of: Remove files older than 5 days in UNIX (date in file name, not timestamp)
I got:



#!/bin/bash

DELETE_OTHERS=yes
BACKUPS_PATH=/mnt/!ARCHIVE/!backups/
THRESHOLD=$(date -d "3 days ago" +%Y%m%d%H%M)

ls -1 $BACKUPS_PATH????????????.zip |
while read A DATE B FILE
do
[[ $DATE -le $THRESHOLD ]] && rm -v $BACKUPS_PATH$FILE
done

if [ $DELETE_OTHERS == "yes" ]; then
rm $BACKUPS_PATH*.* // but I don't know how to not-delete the files matching pattern
fi


But it keeps saying:



rm: missing operand


Where is the problem and how to complete the script?







bash shell-script scripting file-management






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Apr 13 '17 at 12:36









Community

1




1










asked Mar 21 '15 at 15:42









Joudicek Jouda

166126




166126











  • Do you actually have a ! at the beginning of your ARCHIVE and backups directory names? If so, why in the world would you want to complicate your life in such a way?
    – terdon
    Mar 21 '15 at 17:09










  • Yes I have. I'm using ! to keep the one or two key directories on top of the file listings when there is a lot of other files/folders in that directory and it is sorted by name. I am all ears if there is a better technique for that :)
    – Joudicek Jouda
    Mar 21 '15 at 19:13






  • 1




    I just add aa or similar to the name, for example aabackups. That way, you don't need to escape special characters. It's a matter of personal preference though.
    – terdon
    Mar 21 '15 at 20:34
















  • Do you actually have a ! at the beginning of your ARCHIVE and backups directory names? If so, why in the world would you want to complicate your life in such a way?
    – terdon
    Mar 21 '15 at 17:09










  • Yes I have. I'm using ! to keep the one or two key directories on top of the file listings when there is a lot of other files/folders in that directory and it is sorted by name. I am all ears if there is a better technique for that :)
    – Joudicek Jouda
    Mar 21 '15 at 19:13






  • 1




    I just add aa or similar to the name, for example aabackups. That way, you don't need to escape special characters. It's a matter of personal preference though.
    – terdon
    Mar 21 '15 at 20:34















Do you actually have a ! at the beginning of your ARCHIVE and backups directory names? If so, why in the world would you want to complicate your life in such a way?
– terdon
Mar 21 '15 at 17:09




Do you actually have a ! at the beginning of your ARCHIVE and backups directory names? If so, why in the world would you want to complicate your life in such a way?
– terdon
Mar 21 '15 at 17:09












Yes I have. I'm using ! to keep the one or two key directories on top of the file listings when there is a lot of other files/folders in that directory and it is sorted by name. I am all ears if there is a better technique for that :)
– Joudicek Jouda
Mar 21 '15 at 19:13




Yes I have. I'm using ! to keep the one or two key directories on top of the file listings when there is a lot of other files/folders in that directory and it is sorted by name. I am all ears if there is a better technique for that :)
– Joudicek Jouda
Mar 21 '15 at 19:13




1




1




I just add aa or similar to the name, for example aabackups. That way, you don't need to escape special characters. It's a matter of personal preference though.
– terdon
Mar 21 '15 at 20:34




I just add aa or similar to the name, for example aabackups. That way, you don't need to escape special characters. It's a matter of personal preference though.
– terdon
Mar 21 '15 at 20:34










3 Answers
3






active

oldest

votes

















up vote
6
down vote



accepted










The first problem in your code is that you are parsing ls. This means it will break very easily, if you have any spaces in your file or directory names for example. You should use shell globbing or find instead.



A bigger problem is that you are not reading the data correctly. Your code:



ls -1 | while read A DATE B FILE


will never populate $FILE. The output of ls -1 is just a list of filenames so, unless those file names contain whitespace, only the first of the 4 variables you give to read will be populated.



Here's a working version of your script:



#!/usr/bin/env bash

DELETE_OTHERS=yes
BACKUPS_PATH=/mnt/!ARCHIVE/!backups
THRESHOLD=$(date -d "3 days ago" +%Y%m%d%H%M)

## Find all files in $BACKUPS_PATH. The -type f means only files
## and the -maxdepth 1 ensures that any files in subdirectories are
## not included. Combined with -print0 (separate file names with ),
## IFS= (don't break on whitespace), "-d ''" (records end on '') , it can
## deal with all file names.
find $BACKUPS_PATH -maxdepth 1 -type f -print0 | while IFS= read -d '' -r file
do
## Does this file name match the pattern (13 digits, then .zip)?
if [[ "$(basename "$file")" =~ ^[0-9]12.zip$ ]]
then
## Delete the file if it's older than the $THR
[ "$(basename "$file" .zip)" -le "$THRESHOLD" ] && rm -v -- "$file"
else
## If the file does not match the pattern, delete if
## DELETE_OTHERS is set to "yes"
[ $DELETE_OTHERS == "yes" ] && rm -v -- "$file"
fi
done





share|improve this answer





























    up vote
    0
    down vote













    don't you forget the sed line between ls -1 and while read, this line IS important.



    for first question I would suggest: (a awk remplacement I was unable to find a sed equivalent)



    ls -1 $BACKUPS_PATH????????????.zip |
    awk -F. 'printf "%s %sn",$1,$0 ;' |
    while read DATE FILE
    do
    [[ $DATE -le $THRESHOLD ]] && rm -v $BACKUPS_PATH$FILE
    done


    provided shell arithmetic are at least 37 bit wise to do the $DATE -le $THRESHOLD testing.






    share|improve this answer






















    • This breaks on whitespace and other strange characters.
      – terdon
      Mar 21 '15 at 17:45


















    up vote
    0
    down vote













    In FreeBSD use:
    Example: find all files in /usr/home/foobar owned by foobar that are older than 5760 minutes (4 days) and delete them.



    find /usr/home/foobar -user foobar -type f -mmin +5760 -delete





    share|improve this answer








    New contributor




    Santiago Staviski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.

















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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      6
      down vote



      accepted










      The first problem in your code is that you are parsing ls. This means it will break very easily, if you have any spaces in your file or directory names for example. You should use shell globbing or find instead.



      A bigger problem is that you are not reading the data correctly. Your code:



      ls -1 | while read A DATE B FILE


      will never populate $FILE. The output of ls -1 is just a list of filenames so, unless those file names contain whitespace, only the first of the 4 variables you give to read will be populated.



      Here's a working version of your script:



      #!/usr/bin/env bash

      DELETE_OTHERS=yes
      BACKUPS_PATH=/mnt/!ARCHIVE/!backups
      THRESHOLD=$(date -d "3 days ago" +%Y%m%d%H%M)

      ## Find all files in $BACKUPS_PATH. The -type f means only files
      ## and the -maxdepth 1 ensures that any files in subdirectories are
      ## not included. Combined with -print0 (separate file names with ),
      ## IFS= (don't break on whitespace), "-d ''" (records end on '') , it can
      ## deal with all file names.
      find $BACKUPS_PATH -maxdepth 1 -type f -print0 | while IFS= read -d '' -r file
      do
      ## Does this file name match the pattern (13 digits, then .zip)?
      if [[ "$(basename "$file")" =~ ^[0-9]12.zip$ ]]
      then
      ## Delete the file if it's older than the $THR
      [ "$(basename "$file" .zip)" -le "$THRESHOLD" ] && rm -v -- "$file"
      else
      ## If the file does not match the pattern, delete if
      ## DELETE_OTHERS is set to "yes"
      [ $DELETE_OTHERS == "yes" ] && rm -v -- "$file"
      fi
      done





      share|improve this answer


























        up vote
        6
        down vote



        accepted










        The first problem in your code is that you are parsing ls. This means it will break very easily, if you have any spaces in your file or directory names for example. You should use shell globbing or find instead.



        A bigger problem is that you are not reading the data correctly. Your code:



        ls -1 | while read A DATE B FILE


        will never populate $FILE. The output of ls -1 is just a list of filenames so, unless those file names contain whitespace, only the first of the 4 variables you give to read will be populated.



        Here's a working version of your script:



        #!/usr/bin/env bash

        DELETE_OTHERS=yes
        BACKUPS_PATH=/mnt/!ARCHIVE/!backups
        THRESHOLD=$(date -d "3 days ago" +%Y%m%d%H%M)

        ## Find all files in $BACKUPS_PATH. The -type f means only files
        ## and the -maxdepth 1 ensures that any files in subdirectories are
        ## not included. Combined with -print0 (separate file names with ),
        ## IFS= (don't break on whitespace), "-d ''" (records end on '') , it can
        ## deal with all file names.
        find $BACKUPS_PATH -maxdepth 1 -type f -print0 | while IFS= read -d '' -r file
        do
        ## Does this file name match the pattern (13 digits, then .zip)?
        if [[ "$(basename "$file")" =~ ^[0-9]12.zip$ ]]
        then
        ## Delete the file if it's older than the $THR
        [ "$(basename "$file" .zip)" -le "$THRESHOLD" ] && rm -v -- "$file"
        else
        ## If the file does not match the pattern, delete if
        ## DELETE_OTHERS is set to "yes"
        [ $DELETE_OTHERS == "yes" ] && rm -v -- "$file"
        fi
        done





        share|improve this answer
























          up vote
          6
          down vote



          accepted







          up vote
          6
          down vote



          accepted






          The first problem in your code is that you are parsing ls. This means it will break very easily, if you have any spaces in your file or directory names for example. You should use shell globbing or find instead.



          A bigger problem is that you are not reading the data correctly. Your code:



          ls -1 | while read A DATE B FILE


          will never populate $FILE. The output of ls -1 is just a list of filenames so, unless those file names contain whitespace, only the first of the 4 variables you give to read will be populated.



          Here's a working version of your script:



          #!/usr/bin/env bash

          DELETE_OTHERS=yes
          BACKUPS_PATH=/mnt/!ARCHIVE/!backups
          THRESHOLD=$(date -d "3 days ago" +%Y%m%d%H%M)

          ## Find all files in $BACKUPS_PATH. The -type f means only files
          ## and the -maxdepth 1 ensures that any files in subdirectories are
          ## not included. Combined with -print0 (separate file names with ),
          ## IFS= (don't break on whitespace), "-d ''" (records end on '') , it can
          ## deal with all file names.
          find $BACKUPS_PATH -maxdepth 1 -type f -print0 | while IFS= read -d '' -r file
          do
          ## Does this file name match the pattern (13 digits, then .zip)?
          if [[ "$(basename "$file")" =~ ^[0-9]12.zip$ ]]
          then
          ## Delete the file if it's older than the $THR
          [ "$(basename "$file" .zip)" -le "$THRESHOLD" ] && rm -v -- "$file"
          else
          ## If the file does not match the pattern, delete if
          ## DELETE_OTHERS is set to "yes"
          [ $DELETE_OTHERS == "yes" ] && rm -v -- "$file"
          fi
          done





          share|improve this answer














          The first problem in your code is that you are parsing ls. This means it will break very easily, if you have any spaces in your file or directory names for example. You should use shell globbing or find instead.



          A bigger problem is that you are not reading the data correctly. Your code:



          ls -1 | while read A DATE B FILE


          will never populate $FILE. The output of ls -1 is just a list of filenames so, unless those file names contain whitespace, only the first of the 4 variables you give to read will be populated.



          Here's a working version of your script:



          #!/usr/bin/env bash

          DELETE_OTHERS=yes
          BACKUPS_PATH=/mnt/!ARCHIVE/!backups
          THRESHOLD=$(date -d "3 days ago" +%Y%m%d%H%M)

          ## Find all files in $BACKUPS_PATH. The -type f means only files
          ## and the -maxdepth 1 ensures that any files in subdirectories are
          ## not included. Combined with -print0 (separate file names with ),
          ## IFS= (don't break on whitespace), "-d ''" (records end on '') , it can
          ## deal with all file names.
          find $BACKUPS_PATH -maxdepth 1 -type f -print0 | while IFS= read -d '' -r file
          do
          ## Does this file name match the pattern (13 digits, then .zip)?
          if [[ "$(basename "$file")" =~ ^[0-9]12.zip$ ]]
          then
          ## Delete the file if it's older than the $THR
          [ "$(basename "$file" .zip)" -le "$THRESHOLD" ] && rm -v -- "$file"
          else
          ## If the file does not match the pattern, delete if
          ## DELETE_OTHERS is set to "yes"
          [ $DELETE_OTHERS == "yes" ] && rm -v -- "$file"
          fi
          done






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Mar 21 '15 at 17:47

























          answered Mar 21 '15 at 17:38









          terdon

          126k31243418




          126k31243418






















              up vote
              0
              down vote













              don't you forget the sed line between ls -1 and while read, this line IS important.



              for first question I would suggest: (a awk remplacement I was unable to find a sed equivalent)



              ls -1 $BACKUPS_PATH????????????.zip |
              awk -F. 'printf "%s %sn",$1,$0 ;' |
              while read DATE FILE
              do
              [[ $DATE -le $THRESHOLD ]] && rm -v $BACKUPS_PATH$FILE
              done


              provided shell arithmetic are at least 37 bit wise to do the $DATE -le $THRESHOLD testing.






              share|improve this answer






















              • This breaks on whitespace and other strange characters.
                – terdon
                Mar 21 '15 at 17:45















              up vote
              0
              down vote













              don't you forget the sed line between ls -1 and while read, this line IS important.



              for first question I would suggest: (a awk remplacement I was unable to find a sed equivalent)



              ls -1 $BACKUPS_PATH????????????.zip |
              awk -F. 'printf "%s %sn",$1,$0 ;' |
              while read DATE FILE
              do
              [[ $DATE -le $THRESHOLD ]] && rm -v $BACKUPS_PATH$FILE
              done


              provided shell arithmetic are at least 37 bit wise to do the $DATE -le $THRESHOLD testing.






              share|improve this answer






















              • This breaks on whitespace and other strange characters.
                – terdon
                Mar 21 '15 at 17:45













              up vote
              0
              down vote










              up vote
              0
              down vote









              don't you forget the sed line between ls -1 and while read, this line IS important.



              for first question I would suggest: (a awk remplacement I was unable to find a sed equivalent)



              ls -1 $BACKUPS_PATH????????????.zip |
              awk -F. 'printf "%s %sn",$1,$0 ;' |
              while read DATE FILE
              do
              [[ $DATE -le $THRESHOLD ]] && rm -v $BACKUPS_PATH$FILE
              done


              provided shell arithmetic are at least 37 bit wise to do the $DATE -le $THRESHOLD testing.






              share|improve this answer














              don't you forget the sed line between ls -1 and while read, this line IS important.



              for first question I would suggest: (a awk remplacement I was unable to find a sed equivalent)



              ls -1 $BACKUPS_PATH????????????.zip |
              awk -F. 'printf "%s %sn",$1,$0 ;' |
              while read DATE FILE
              do
              [[ $DATE -le $THRESHOLD ]] && rm -v $BACKUPS_PATH$FILE
              done


              provided shell arithmetic are at least 37 bit wise to do the $DATE -le $THRESHOLD testing.







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Mar 21 '15 at 16:57

























              answered Mar 21 '15 at 16:50









              Archemar

              19.4k93468




              19.4k93468











              • This breaks on whitespace and other strange characters.
                – terdon
                Mar 21 '15 at 17:45

















              • This breaks on whitespace and other strange characters.
                – terdon
                Mar 21 '15 at 17:45
















              This breaks on whitespace and other strange characters.
              – terdon
              Mar 21 '15 at 17:45





              This breaks on whitespace and other strange characters.
              – terdon
              Mar 21 '15 at 17:45











              up vote
              0
              down vote













              In FreeBSD use:
              Example: find all files in /usr/home/foobar owned by foobar that are older than 5760 minutes (4 days) and delete them.



              find /usr/home/foobar -user foobar -type f -mmin +5760 -delete





              share|improve this answer








              New contributor




              Santiago Staviski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.





















                up vote
                0
                down vote













                In FreeBSD use:
                Example: find all files in /usr/home/foobar owned by foobar that are older than 5760 minutes (4 days) and delete them.



                find /usr/home/foobar -user foobar -type f -mmin +5760 -delete





                share|improve this answer








                New contributor




                Santiago Staviski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.



















                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote









                  In FreeBSD use:
                  Example: find all files in /usr/home/foobar owned by foobar that are older than 5760 minutes (4 days) and delete them.



                  find /usr/home/foobar -user foobar -type f -mmin +5760 -delete





                  share|improve this answer








                  New contributor




                  Santiago Staviski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  In FreeBSD use:
                  Example: find all files in /usr/home/foobar owned by foobar that are older than 5760 minutes (4 days) and delete them.



                  find /usr/home/foobar -user foobar -type f -mmin +5760 -delete






                  share|improve this answer








                  New contributor




                  Santiago Staviski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  share|improve this answer



                  share|improve this answer






                  New contributor




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                  answered Nov 19 at 16:40









                  Santiago Staviski

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                  Santiago Staviski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.






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