Change a word based upon the file content

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











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I have a file which contains timestamp and date in the second column. If the line contains one of the word then it need to be replace like below. Any help is appreciated.



File:
a smallint
b timestamp
c date
d varchar

O/P:
a smallint
dateformat(b,'YYYY-MM-DD HH:NN:SS.sss')
dateformat(c.'YYYY-MM-DD')
d varchar


If I execute this below command as a single awk then I am getting output but if I use else condition then I am getting error.



awk 'if ($2=="timestamp") $3="dataformat("; ; print $3 $1 ",'''YYYY-MM-DD HH':'NN':'SS'.'sss)" else ($2=="date") $3="dataformat("; ; print $3 $1 ",'''YYYY-MM-DD)" ' test.out 


Error:
awk: if ($2=="timestamp") $3="dataformat("; ; print $3 $1 ",'YYYY-MM-DD HH:NN:SS.sss)" else ($2=="date") $3="dataformat("; ; print $3 $1 ",'YYYY-MM-DD)"
awk: ^ syntax error
awk: if ($2=="timestamp") $3="dataformat("; ; print $3 $1 ",'YYYY-MM-DD HH:NN:SS.sss)" else ($2=="date") $3="dataformat("; ; print $3 $1 ",'YYYY-MM-DD)"
awk: ^ syntax error










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    up vote
    0
    down vote

    favorite












    I have a file which contains timestamp and date in the second column. If the line contains one of the word then it need to be replace like below. Any help is appreciated.



    File:
    a smallint
    b timestamp
    c date
    d varchar

    O/P:
    a smallint
    dateformat(b,'YYYY-MM-DD HH:NN:SS.sss')
    dateformat(c.'YYYY-MM-DD')
    d varchar


    If I execute this below command as a single awk then I am getting output but if I use else condition then I am getting error.



    awk 'if ($2=="timestamp") $3="dataformat("; ; print $3 $1 ",'''YYYY-MM-DD HH':'NN':'SS'.'sss)" else ($2=="date") $3="dataformat("; ; print $3 $1 ",'''YYYY-MM-DD)" ' test.out 


    Error:
    awk: if ($2=="timestamp") $3="dataformat("; ; print $3 $1 ",'YYYY-MM-DD HH:NN:SS.sss)" else ($2=="date") $3="dataformat("; ; print $3 $1 ",'YYYY-MM-DD)"
    awk: ^ syntax error
    awk: if ($2=="timestamp") $3="dataformat("; ; print $3 $1 ",'YYYY-MM-DD HH:NN:SS.sss)" else ($2=="date") $3="dataformat("; ; print $3 $1 ",'YYYY-MM-DD)"
    awk: ^ syntax error










    share|improve this question







    New contributor




    Josh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.





















      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I have a file which contains timestamp and date in the second column. If the line contains one of the word then it need to be replace like below. Any help is appreciated.



      File:
      a smallint
      b timestamp
      c date
      d varchar

      O/P:
      a smallint
      dateformat(b,'YYYY-MM-DD HH:NN:SS.sss')
      dateformat(c.'YYYY-MM-DD')
      d varchar


      If I execute this below command as a single awk then I am getting output but if I use else condition then I am getting error.



      awk 'if ($2=="timestamp") $3="dataformat("; ; print $3 $1 ",'''YYYY-MM-DD HH':'NN':'SS'.'sss)" else ($2=="date") $3="dataformat("; ; print $3 $1 ",'''YYYY-MM-DD)" ' test.out 


      Error:
      awk: if ($2=="timestamp") $3="dataformat("; ; print $3 $1 ",'YYYY-MM-DD HH:NN:SS.sss)" else ($2=="date") $3="dataformat("; ; print $3 $1 ",'YYYY-MM-DD)"
      awk: ^ syntax error
      awk: if ($2=="timestamp") $3="dataformat("; ; print $3 $1 ",'YYYY-MM-DD HH:NN:SS.sss)" else ($2=="date") $3="dataformat("; ; print $3 $1 ",'YYYY-MM-DD)"
      awk: ^ syntax error










      share|improve this question







      New contributor




      Josh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      I have a file which contains timestamp and date in the second column. If the line contains one of the word then it need to be replace like below. Any help is appreciated.



      File:
      a smallint
      b timestamp
      c date
      d varchar

      O/P:
      a smallint
      dateformat(b,'YYYY-MM-DD HH:NN:SS.sss')
      dateformat(c.'YYYY-MM-DD')
      d varchar


      If I execute this below command as a single awk then I am getting output but if I use else condition then I am getting error.



      awk 'if ($2=="timestamp") $3="dataformat("; ; print $3 $1 ",'''YYYY-MM-DD HH':'NN':'SS'.'sss)" else ($2=="date") $3="dataformat("; ; print $3 $1 ",'''YYYY-MM-DD)" ' test.out 


      Error:
      awk: if ($2=="timestamp") $3="dataformat("; ; print $3 $1 ",'YYYY-MM-DD HH:NN:SS.sss)" else ($2=="date") $3="dataformat("; ; print $3 $1 ",'YYYY-MM-DD)"
      awk: ^ syntax error
      awk: if ($2=="timestamp") $3="dataformat("; ; print $3 $1 ",'YYYY-MM-DD HH:NN:SS.sss)" else ($2=="date") $3="dataformat("; ; print $3 $1 ",'YYYY-MM-DD)"
      awk: ^ syntax error







      shell-script shell






      share|improve this question







      New contributor




      Josh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question







      New contributor




      Josh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question






      New contributor




      Josh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 22 mins ago









      Josh

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      Josh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Josh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.

























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