mjhjmtu

I would like to inquire about an error message that I get when I run the command "find". In the following paragraph, I will explain what I am trying to accomplish.

I have a parent folder. Inside this folder there are many subfolders. Inside each subfolder there are plenty of sub-sub folders. I would like to list the sub-sub folders that contain a specific number of files. I ran for loop as follows:

#!/bin/bash
in=PATH_TO_THE_PARENT_FOLDER

for i in $in/*; do
find $i -maxdepth 1 -type d -print0 | xargs -0 -I sh -c 'echo -e $(find | wc -l) ' | sort -n | grep -w 69 | awk 'print $2' #69 represent the total number of files within a folder
done

This code output the following error message "sh: MPR_Range: No such file or directory". I Googled looking for an explanation for what "sh: MPR_Range" means, but I couldn't find any answer.

Assume you have a file called foo&bar. xargs will now run the command

sh -c 'echo -e $(find foo&bar | wc -l) foo&bar' 

That runs echo and find in the background, and two copies of bar. Similarly for foo;bar, and $(bar).

Don't use in the argument to sh -c, instead, give the filename as a separate argument, i.e.

... |xargs sh -c 'echo -e $(find "$1" | wc -l) "$1"' sh | ...

In addition, you could use find -exec instead of xargs:

find -type d -exec sh -c 'echo ...' ; 

I'm also not exactly sure if the sort is necessary, if you running grep to find lines with particular numbers anyway.