Rename multiple files to decrement number in file name?

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2















I have incorrectly named files which are unsynced by -1. The problem is I need to rename 1000s of them.



  • DBGC180_805754

  • DBGC180_805755

  • DBGC180_805756

to



  • DBGC180_805753

  • DBGC180_805754

  • DBGC180_805755

I would prefer using bash scripts or a unix command.










share|improve this question
























  • If you were on Mac OS X this would be a perfect use case for Name Mangler.

    – Wildcard
    Sep 29 '16 at 6:26






  • 1





    It's not 100% clear how the input files look like. Do all files have the same prefix DBGC180? Is 805753 the smallest number? Are there numbers with more or less than 6 digits? Are there numbers which shall not be renamed, e.g. <805753?

    – rudimeier
    Sep 29 '16 at 10:16
















2















I have incorrectly named files which are unsynced by -1. The problem is I need to rename 1000s of them.



  • DBGC180_805754

  • DBGC180_805755

  • DBGC180_805756

to



  • DBGC180_805753

  • DBGC180_805754

  • DBGC180_805755

I would prefer using bash scripts or a unix command.










share|improve this question
























  • If you were on Mac OS X this would be a perfect use case for Name Mangler.

    – Wildcard
    Sep 29 '16 at 6:26






  • 1





    It's not 100% clear how the input files look like. Do all files have the same prefix DBGC180? Is 805753 the smallest number? Are there numbers with more or less than 6 digits? Are there numbers which shall not be renamed, e.g. <805753?

    – rudimeier
    Sep 29 '16 at 10:16














2












2








2


1






I have incorrectly named files which are unsynced by -1. The problem is I need to rename 1000s of them.



  • DBGC180_805754

  • DBGC180_805755

  • DBGC180_805756

to



  • DBGC180_805753

  • DBGC180_805754

  • DBGC180_805755

I would prefer using bash scripts or a unix command.










share|improve this question
















I have incorrectly named files which are unsynced by -1. The problem is I need to rename 1000s of them.



  • DBGC180_805754

  • DBGC180_805755

  • DBGC180_805756

to



  • DBGC180_805753

  • DBGC180_805754

  • DBGC180_805755

I would prefer using bash scripts or a unix command.







rename filenames recursive






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share|improve this question













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share|improve this question








edited Sep 29 '16 at 7:24









Wildcard

23.2k1067171




23.2k1067171










asked Sep 27 '16 at 16:48









iamunixiamunix

141




141












  • If you were on Mac OS X this would be a perfect use case for Name Mangler.

    – Wildcard
    Sep 29 '16 at 6:26






  • 1





    It's not 100% clear how the input files look like. Do all files have the same prefix DBGC180? Is 805753 the smallest number? Are there numbers with more or less than 6 digits? Are there numbers which shall not be renamed, e.g. <805753?

    – rudimeier
    Sep 29 '16 at 10:16


















  • If you were on Mac OS X this would be a perfect use case for Name Mangler.

    – Wildcard
    Sep 29 '16 at 6:26






  • 1





    It's not 100% clear how the input files look like. Do all files have the same prefix DBGC180? Is 805753 the smallest number? Are there numbers with more or less than 6 digits? Are there numbers which shall not be renamed, e.g. <805753?

    – rudimeier
    Sep 29 '16 at 10:16

















If you were on Mac OS X this would be a perfect use case for Name Mangler.

– Wildcard
Sep 29 '16 at 6:26





If you were on Mac OS X this would be a perfect use case for Name Mangler.

– Wildcard
Sep 29 '16 at 6:26




1




1





It's not 100% clear how the input files look like. Do all files have the same prefix DBGC180? Is 805753 the smallest number? Are there numbers with more or less than 6 digits? Are there numbers which shall not be renamed, e.g. <805753?

– rudimeier
Sep 29 '16 at 10:16






It's not 100% clear how the input files look like. Do all files have the same prefix DBGC180? Is 805753 the smallest number? Are there numbers with more or less than 6 digits? Are there numbers which shall not be renamed, e.g. <805753?

– rudimeier
Sep 29 '16 at 10:16











7 Answers
7






active

oldest

votes


















3














  1. Move the files to rename into a subdirectory (without changing their name).

  2. Rename the files from the subdirectory into the original directory.

There are two reasons I recommend step 1, even if it's possible to do without it:



  • If the command is interrupted, you can resume where you left off, since it's immediately obvious which files have already been renamed and which ones haven't.

  • You don't need to worry about doing the renaming in the wrong order and overwriting one of the existing files.

Untested shell snippet (relying on the fact that the number to decrement never has any leading zeros):



mkdir to_decrement
for x in DBGC180_80575[4-9] DBGC180_8057[6-9]? DBGC180_805[8-9]?? DBGC180_80[6-9]??? DBGC180_8[1-9]???? DBGC180_9?????; do
mv "$x" to_decrement/
done
cd to_decrement
for x in *; do
number="$x##*_"
mv -i -- "$x" "../$x%_*_$((number-1))"
done
cd ..
rmdir to_decrement


With zsh, you can make this a lot simpler, thanks to its numeric range glob, its built-in mv which avoids running into command line length limits, and its pattern-based mass renaming function. In zsh:



autoload -U zmv
zmodload -m -F zsh/files b:zf_*
mkdir to_decrement
zf_mv DBGC180_<805754-> to_decrement/
zmv 'to_decrement/(*)_(*)' '$1_$(($2-1))'
rmdir to_decrement





share|improve this answer

























  • I don't understand what is the sense behind your complicated globbing patterns. Why you don't want to rename say DBGC180_805750 but DBGC180_9yyyyy is included? Moreover the chance is high that there are too many files for one command line.

    – rudimeier
    Sep 29 '16 at 9:29












  • @rudimeier My understanding of the requirements is that only files with a number ≥805754 must be renumbered, and there are files with a smaller number that must not be renumbered. Good point about the command line length, I'll add a note about this.

    – Gilles
    Sep 29 '16 at 9:56











  • @rudimeier My understanding is that 805753 does not exist, but (at least some of) 805752, 805751, etc. do

    – Gilles
    Sep 29 '16 at 10:06











  • I see, comment to the question added.

    – rudimeier
    Sep 29 '16 at 10:18


















2














You can do this:



# smallestfilenum..largestfilenum

for i in 805754..999999; do
mv "DBGC180_$i" "DBGC180_$(($i-1))";
done


Try it with a small number (say 805754..805758) to make sure it works as you expect it. Be aware that if a file already exists with the new name, it will be overwritten.






share|improve this answer




















  • 1





    Most 'mv' implementations have a -n option to prevent overwriting. Of course, if you use that, you'll then have the problem of not knowing which names were changed and which were the originals. I recommend renaming to a temporary directory, and checking the results before moving them back: mkdir tmp && for i in 805754..999999; do mv "DBGC180_$i" "tmp/DBGC180_$(($i-1))"; done && mv -n tmp/* . && rmdir tmp Or mkdir tmp && mv DBGC180_* tmp/; for i in 805754..999999; do mv -n "tmp/DBGC180_$i" "DBGC180_$(($i-1))"; done && rmdir tmp. If the rmdir fails, you need some manual fixing.

    – Toby Speight
    Sep 29 '16 at 10:44


















0














So, you want to rename DBGC180_805754 to DBGC180_805753,...55 to ...54 and so forth. That's the problem I'll address.



First, put this script somewhere in your PATH, call it waltinator.



#!/bin/bash
#step through the parameters
while [[ -n "$1" ]] ; do
oldname="$1"
# shift the arguments left
shift;
# strip off the fixed part of the old name
oldnum=$oldname##DBGC180_
# decrement the number (this is what was wanted, right?)
newnum=$(( $oldnum - 1 ))
# build the new, improved filename
newname="DBGC180_$newnum"
if [[ -f "$newname" ]] ; then
printf "Cannot rename $oldname to $newname, $newname exists.n" >&2
exit 1
fi
mv --no-clobber "$oldname" "$newname"
done
exit 0


For the next step, assume that the script is in $HOME/bin/waltinator, and you have does chmod +x $HOME/bin/waltinator.



find . -type f -name 'BDGC180_[0-9][0-9][0-9][0-9][0-9][0-9]` -print | 
sort |
xargs $HOME/bin/waltinator


The find finds files (in no particular order), whose names match the shell glob pattern "BDGC180_ followed by 6 digits ([0-9]). Since we want a sorted list (it would be a failure to rename ...97 to ...96 before renaming ...96) we run the output of find through sort. Then we use xargs to take the (sorted) list of filenames, and build a command to pass the (sorted) list of filenames to $HOME/bin/waltinator. Read man xargs if you need to shorten the arg list.



For that matter, read:



for page in bash mv find sort xargs ; do
man "$page"
done





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    0














    If you want to rename those specific files then here is the solution (static).
    First rename and move those files into sub directory.
    From there move those files to current directory



    #!/bin/bash
    # rename.sh

    #make a subdirectory
    mkdir -p subDir

    #move all files to subdirectory with rename
    for i in 5754..6754; do
    mv "DBGC180_80$i" "./subDir/DBGC180_80$(($i-1))";
    done

    #move all files from subdirectory to current directory
    for j in 5754..6754; do
    mv "./subDir/DBGC180_80$(($j-1))" "./DBGC180_80$(($j-1))"
    done

    #remove subdirectory
    rmdir subDir


    This program can be modified to be generic (dynamic)






    share|improve this answer























    • Huh? Why, in your "move from subdir to current dir" code block, do you even bother with j-1 (since you're doing it twice)? Why not just change the numbers used for iteration?

      – Wildcard
      Sep 29 '16 at 6:22











    • Of course, it can be done as you said. I kept it in a single line.

      – firoj_mujawar
      Oct 3 '16 at 7:49



















    0














    Use rename to substitute each number with itself minus 1.



    $ rename -v 's/d6/sprintf("%06",($&-1))/e' 


    Notes




    • rename uses Perl expressions to rename filenames.


    • s specifies that rename will substitute some or all of the filenames that match the regular expression pattern.

    • Perl substitution expressions are structured as such.

      • s/PATTERN/REPLACEMENT/MODIFIER



    • d6 is the pattern that rename will search for and substitute. This is 6 decimal digits.


    • $ is the variable storing the substring that matched d6 (in this case the "substring" is an int).


    • sprintf("%06",($&-1)) retrieves the value stored in $, decrements it, then returns this value as the replacement. The %06 is there to handle leading zeroes.


    • e specified that rename evaluates the replacement as if it were a Perl statement, and uses its return value as the replacement text.


    • -v makes rename echo what it is doing.

    If you want to be extra safe use the flag -n so that rename only tells you what it would do instead of doing it.



    This appears to only work for decrementing so handle this with care.






    share|improve this answer






























      -1














      Wow, this was trickier than I expected.



      As Gilles pointed out, considering the number of files to be handled, you should rename them in a way that won't give you problems if the command is interrupted. The command below does that.



      I wrote this command to be fairly robust against failures. Note that we explicitly exclude files where the number has a leading 0; if you have files like that, post a comment and I'll include a command to deal with them.



      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' -exec sh -c 'for f; do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented"; done' find-sh-decrement + && find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' -exec sh -c 'for f; do mv -i "$f" "$f%.decremented"; done' find-sh-remove-prefix +


      With line wrappings (can still be copied and pasted):



      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' 
      -exec sh -c 'for f;
      do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented";
      done' find-sh-decrement + &&
      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented'
      -exec sh -c 'for f;
      do mv -i "$f" "$f%.decremented";
      done' find-sh-remove-prefix +



      Explanation of the parts (this could use some formatting cleanup):



      ##### Recursively find regular files in the current directory...
      find . -type f
      ##### whose name matches this exact pattern...
      -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]'
      ##### and run the following shell script...
      -exec sh -c
      ##### (shell script: ) for every file given as an argument...
      'for f;
      ##### rename the file, prompting for confirmation for any overwrites...
      do mv -i
      ##### from the original file name...
      "$f"
      ##### to the file name decremented by 1, with '.decremented' afterward...
      "$f%_*_$(($f##*_-1)).decremented";
      ##### (End of shell script)
      done'
      ##### on as many found files as possible at once,
      ##### using the name "find-sh-decrement" for error reporting.
      find-sh-decrement +
      ##### If that completes successfully...
      &&
      ##### Pass through again and remove the ".decremented" prefix.
      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' -exec sh -c 'for f; do mv -i "$f" "$f%.decremented"; done' find-sh-remove-prefix +



      Test results:



      $ ls
      DBGC180_805754 DBGC180_805755 DBGC180_805756
      $ cat DBGC180_805754
      This file started as DBGC180_805754
      $ cat DBGC180_805755
      This file started as DBGC180_805755
      $ cat DBGC180_805756
      This file started as DBGC180_805756
      $ find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' -exec sh -c 'for f; do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented"; done' find-sh-decrement + && find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' -exec sh -c 'for f; do mv -i "$f" "$f%.decremented"; done' find-sh-remove-prefix +
      $ ls
      DBGC180_805753 DBGC180_805754 DBGC180_805755
      $ cat DBGC180_805753
      This file started as DBGC180_805754
      $ cat DBGC180_805754
      This file started as DBGC180_805755
      $ cat DBGC180_805755
      This file started as DBGC180_805756
      $


      For extra safety, run the first find command and inspect the results for yourself before you run the second command to remove the .decremented suffix.



      Run this:



      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' 
      -exec sh -c 'for f;
      do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented";
      done' find-sh-decrement +


      Then inspect results, and then run this:



      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' 
      -exec sh -c 'for f;
      do mv -i "$f" "$f%.decremented";
      done' find-sh-remove-prefix +





      share|improve this answer

























      • Why the downvote? This does exactly what was requested, and is quite clean in my opinion.

        – Wildcard
        Oct 3 '16 at 14:34



















      -1














      Use awk to create a fully expanded rename script:



      find . -name "DBGC180_*" |sort |awk -F "_" 'print "mv -i "$0" "$1"_"$2-1' >/tmp/rename.sh


      You can review the script before executing. This is the unique feature of this solution. Then execute it:



      sh -e -x /tmp/rename.sh


      Notes



      • you may improve the find pattern, the question is not 100% clear about what files has to be renamed.


      • sort is important to not overwrite existing files


      • mv option -i makes it extra-safe to never overwrite files


      • sh option -e is to abort the script in case of error


      • sh option -x prints a trace to see what was done so far in case the script is interrupted (to make recovery possible). You could also use mv -v instead if supported.





      share|improve this answer

























      • Down voters! Please comment whats wrong here.

        – rudimeier
        Sep 29 '16 at 11:12











      • Your added explanations are good, and the script may work fine for the exact use case of the Original Poster. However, it is definitely not robust. (My own definition of robust: Does not produce unexpected output in the face of unexpected input.) There are a great many caveats if the script would be modified and used more generally, and you don't note these: (1) It won't handle whitespace correctly, or even underscores, if they appear within directory names (i.e. not truly recursive); (cont'd)

        – Wildcard
        Sep 29 '16 at 19:51











      • (cont'd) (2) It won't handle file extensions (see what happens if you give it the file DBGC180_5555.txt, for instance); (3) If the script is interrupted partway through there is no way to tell which files have been renamed and which haven't been.

        – Wildcard
        Sep 29 '16 at 19:51











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      7 Answers
      7






      active

      oldest

      votes








      7 Answers
      7






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      3














      1. Move the files to rename into a subdirectory (without changing their name).

      2. Rename the files from the subdirectory into the original directory.

      There are two reasons I recommend step 1, even if it's possible to do without it:



      • If the command is interrupted, you can resume where you left off, since it's immediately obvious which files have already been renamed and which ones haven't.

      • You don't need to worry about doing the renaming in the wrong order and overwriting one of the existing files.

      Untested shell snippet (relying on the fact that the number to decrement never has any leading zeros):



      mkdir to_decrement
      for x in DBGC180_80575[4-9] DBGC180_8057[6-9]? DBGC180_805[8-9]?? DBGC180_80[6-9]??? DBGC180_8[1-9]???? DBGC180_9?????; do
      mv "$x" to_decrement/
      done
      cd to_decrement
      for x in *; do
      number="$x##*_"
      mv -i -- "$x" "../$x%_*_$((number-1))"
      done
      cd ..
      rmdir to_decrement


      With zsh, you can make this a lot simpler, thanks to its numeric range glob, its built-in mv which avoids running into command line length limits, and its pattern-based mass renaming function. In zsh:



      autoload -U zmv
      zmodload -m -F zsh/files b:zf_*
      mkdir to_decrement
      zf_mv DBGC180_<805754-> to_decrement/
      zmv 'to_decrement/(*)_(*)' '$1_$(($2-1))'
      rmdir to_decrement





      share|improve this answer

























      • I don't understand what is the sense behind your complicated globbing patterns. Why you don't want to rename say DBGC180_805750 but DBGC180_9yyyyy is included? Moreover the chance is high that there are too many files for one command line.

        – rudimeier
        Sep 29 '16 at 9:29












      • @rudimeier My understanding of the requirements is that only files with a number ≥805754 must be renumbered, and there are files with a smaller number that must not be renumbered. Good point about the command line length, I'll add a note about this.

        – Gilles
        Sep 29 '16 at 9:56











      • @rudimeier My understanding is that 805753 does not exist, but (at least some of) 805752, 805751, etc. do

        – Gilles
        Sep 29 '16 at 10:06











      • I see, comment to the question added.

        – rudimeier
        Sep 29 '16 at 10:18















      3














      1. Move the files to rename into a subdirectory (without changing their name).

      2. Rename the files from the subdirectory into the original directory.

      There are two reasons I recommend step 1, even if it's possible to do without it:



      • If the command is interrupted, you can resume where you left off, since it's immediately obvious which files have already been renamed and which ones haven't.

      • You don't need to worry about doing the renaming in the wrong order and overwriting one of the existing files.

      Untested shell snippet (relying on the fact that the number to decrement never has any leading zeros):



      mkdir to_decrement
      for x in DBGC180_80575[4-9] DBGC180_8057[6-9]? DBGC180_805[8-9]?? DBGC180_80[6-9]??? DBGC180_8[1-9]???? DBGC180_9?????; do
      mv "$x" to_decrement/
      done
      cd to_decrement
      for x in *; do
      number="$x##*_"
      mv -i -- "$x" "../$x%_*_$((number-1))"
      done
      cd ..
      rmdir to_decrement


      With zsh, you can make this a lot simpler, thanks to its numeric range glob, its built-in mv which avoids running into command line length limits, and its pattern-based mass renaming function. In zsh:



      autoload -U zmv
      zmodload -m -F zsh/files b:zf_*
      mkdir to_decrement
      zf_mv DBGC180_<805754-> to_decrement/
      zmv 'to_decrement/(*)_(*)' '$1_$(($2-1))'
      rmdir to_decrement





      share|improve this answer

























      • I don't understand what is the sense behind your complicated globbing patterns. Why you don't want to rename say DBGC180_805750 but DBGC180_9yyyyy is included? Moreover the chance is high that there are too many files for one command line.

        – rudimeier
        Sep 29 '16 at 9:29












      • @rudimeier My understanding of the requirements is that only files with a number ≥805754 must be renumbered, and there are files with a smaller number that must not be renumbered. Good point about the command line length, I'll add a note about this.

        – Gilles
        Sep 29 '16 at 9:56











      • @rudimeier My understanding is that 805753 does not exist, but (at least some of) 805752, 805751, etc. do

        – Gilles
        Sep 29 '16 at 10:06











      • I see, comment to the question added.

        – rudimeier
        Sep 29 '16 at 10:18













      3












      3








      3







      1. Move the files to rename into a subdirectory (without changing their name).

      2. Rename the files from the subdirectory into the original directory.

      There are two reasons I recommend step 1, even if it's possible to do without it:



      • If the command is interrupted, you can resume where you left off, since it's immediately obvious which files have already been renamed and which ones haven't.

      • You don't need to worry about doing the renaming in the wrong order and overwriting one of the existing files.

      Untested shell snippet (relying on the fact that the number to decrement never has any leading zeros):



      mkdir to_decrement
      for x in DBGC180_80575[4-9] DBGC180_8057[6-9]? DBGC180_805[8-9]?? DBGC180_80[6-9]??? DBGC180_8[1-9]???? DBGC180_9?????; do
      mv "$x" to_decrement/
      done
      cd to_decrement
      for x in *; do
      number="$x##*_"
      mv -i -- "$x" "../$x%_*_$((number-1))"
      done
      cd ..
      rmdir to_decrement


      With zsh, you can make this a lot simpler, thanks to its numeric range glob, its built-in mv which avoids running into command line length limits, and its pattern-based mass renaming function. In zsh:



      autoload -U zmv
      zmodload -m -F zsh/files b:zf_*
      mkdir to_decrement
      zf_mv DBGC180_<805754-> to_decrement/
      zmv 'to_decrement/(*)_(*)' '$1_$(($2-1))'
      rmdir to_decrement





      share|improve this answer















      1. Move the files to rename into a subdirectory (without changing their name).

      2. Rename the files from the subdirectory into the original directory.

      There are two reasons I recommend step 1, even if it's possible to do without it:



      • If the command is interrupted, you can resume where you left off, since it's immediately obvious which files have already been renamed and which ones haven't.

      • You don't need to worry about doing the renaming in the wrong order and overwriting one of the existing files.

      Untested shell snippet (relying on the fact that the number to decrement never has any leading zeros):



      mkdir to_decrement
      for x in DBGC180_80575[4-9] DBGC180_8057[6-9]? DBGC180_805[8-9]?? DBGC180_80[6-9]??? DBGC180_8[1-9]???? DBGC180_9?????; do
      mv "$x" to_decrement/
      done
      cd to_decrement
      for x in *; do
      number="$x##*_"
      mv -i -- "$x" "../$x%_*_$((number-1))"
      done
      cd ..
      rmdir to_decrement


      With zsh, you can make this a lot simpler, thanks to its numeric range glob, its built-in mv which avoids running into command line length limits, and its pattern-based mass renaming function. In zsh:



      autoload -U zmv
      zmodload -m -F zsh/files b:zf_*
      mkdir to_decrement
      zf_mv DBGC180_<805754-> to_decrement/
      zmv 'to_decrement/(*)_(*)' '$1_$(($2-1))'
      rmdir to_decrement






      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Sep 29 '16 at 10:05

























      answered Sep 29 '16 at 1:31









      GillesGilles

      545k12911071623




      545k12911071623












      • I don't understand what is the sense behind your complicated globbing patterns. Why you don't want to rename say DBGC180_805750 but DBGC180_9yyyyy is included? Moreover the chance is high that there are too many files for one command line.

        – rudimeier
        Sep 29 '16 at 9:29












      • @rudimeier My understanding of the requirements is that only files with a number ≥805754 must be renumbered, and there are files with a smaller number that must not be renumbered. Good point about the command line length, I'll add a note about this.

        – Gilles
        Sep 29 '16 at 9:56











      • @rudimeier My understanding is that 805753 does not exist, but (at least some of) 805752, 805751, etc. do

        – Gilles
        Sep 29 '16 at 10:06











      • I see, comment to the question added.

        – rudimeier
        Sep 29 '16 at 10:18

















      • I don't understand what is the sense behind your complicated globbing patterns. Why you don't want to rename say DBGC180_805750 but DBGC180_9yyyyy is included? Moreover the chance is high that there are too many files for one command line.

        – rudimeier
        Sep 29 '16 at 9:29












      • @rudimeier My understanding of the requirements is that only files with a number ≥805754 must be renumbered, and there are files with a smaller number that must not be renumbered. Good point about the command line length, I'll add a note about this.

        – Gilles
        Sep 29 '16 at 9:56











      • @rudimeier My understanding is that 805753 does not exist, but (at least some of) 805752, 805751, etc. do

        – Gilles
        Sep 29 '16 at 10:06











      • I see, comment to the question added.

        – rudimeier
        Sep 29 '16 at 10:18
















      I don't understand what is the sense behind your complicated globbing patterns. Why you don't want to rename say DBGC180_805750 but DBGC180_9yyyyy is included? Moreover the chance is high that there are too many files for one command line.

      – rudimeier
      Sep 29 '16 at 9:29






      I don't understand what is the sense behind your complicated globbing patterns. Why you don't want to rename say DBGC180_805750 but DBGC180_9yyyyy is included? Moreover the chance is high that there are too many files for one command line.

      – rudimeier
      Sep 29 '16 at 9:29














      @rudimeier My understanding of the requirements is that only files with a number ≥805754 must be renumbered, and there are files with a smaller number that must not be renumbered. Good point about the command line length, I'll add a note about this.

      – Gilles
      Sep 29 '16 at 9:56





      @rudimeier My understanding of the requirements is that only files with a number ≥805754 must be renumbered, and there are files with a smaller number that must not be renumbered. Good point about the command line length, I'll add a note about this.

      – Gilles
      Sep 29 '16 at 9:56













      @rudimeier My understanding is that 805753 does not exist, but (at least some of) 805752, 805751, etc. do

      – Gilles
      Sep 29 '16 at 10:06





      @rudimeier My understanding is that 805753 does not exist, but (at least some of) 805752, 805751, etc. do

      – Gilles
      Sep 29 '16 at 10:06













      I see, comment to the question added.

      – rudimeier
      Sep 29 '16 at 10:18





      I see, comment to the question added.

      – rudimeier
      Sep 29 '16 at 10:18













      2














      You can do this:



      # smallestfilenum..largestfilenum

      for i in 805754..999999; do
      mv "DBGC180_$i" "DBGC180_$(($i-1))";
      done


      Try it with a small number (say 805754..805758) to make sure it works as you expect it. Be aware that if a file already exists with the new name, it will be overwritten.






      share|improve this answer




















      • 1





        Most 'mv' implementations have a -n option to prevent overwriting. Of course, if you use that, you'll then have the problem of not knowing which names were changed and which were the originals. I recommend renaming to a temporary directory, and checking the results before moving them back: mkdir tmp && for i in 805754..999999; do mv "DBGC180_$i" "tmp/DBGC180_$(($i-1))"; done && mv -n tmp/* . && rmdir tmp Or mkdir tmp && mv DBGC180_* tmp/; for i in 805754..999999; do mv -n "tmp/DBGC180_$i" "DBGC180_$(($i-1))"; done && rmdir tmp. If the rmdir fails, you need some manual fixing.

        – Toby Speight
        Sep 29 '16 at 10:44















      2














      You can do this:



      # smallestfilenum..largestfilenum

      for i in 805754..999999; do
      mv "DBGC180_$i" "DBGC180_$(($i-1))";
      done


      Try it with a small number (say 805754..805758) to make sure it works as you expect it. Be aware that if a file already exists with the new name, it will be overwritten.






      share|improve this answer




















      • 1





        Most 'mv' implementations have a -n option to prevent overwriting. Of course, if you use that, you'll then have the problem of not knowing which names were changed and which were the originals. I recommend renaming to a temporary directory, and checking the results before moving them back: mkdir tmp && for i in 805754..999999; do mv "DBGC180_$i" "tmp/DBGC180_$(($i-1))"; done && mv -n tmp/* . && rmdir tmp Or mkdir tmp && mv DBGC180_* tmp/; for i in 805754..999999; do mv -n "tmp/DBGC180_$i" "DBGC180_$(($i-1))"; done && rmdir tmp. If the rmdir fails, you need some manual fixing.

        – Toby Speight
        Sep 29 '16 at 10:44













      2












      2








      2







      You can do this:



      # smallestfilenum..largestfilenum

      for i in 805754..999999; do
      mv "DBGC180_$i" "DBGC180_$(($i-1))";
      done


      Try it with a small number (say 805754..805758) to make sure it works as you expect it. Be aware that if a file already exists with the new name, it will be overwritten.






      share|improve this answer















      You can do this:



      # smallestfilenum..largestfilenum

      for i in 805754..999999; do
      mv "DBGC180_$i" "DBGC180_$(($i-1))";
      done


      Try it with a small number (say 805754..805758) to make sure it works as you expect it. Be aware that if a file already exists with the new name, it will be overwritten.







      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Sep 27 '16 at 18:04

























      answered Sep 27 '16 at 17:52









      Alberto RiveraAlberto Rivera

      1799




      1799







      • 1





        Most 'mv' implementations have a -n option to prevent overwriting. Of course, if you use that, you'll then have the problem of not knowing which names were changed and which were the originals. I recommend renaming to a temporary directory, and checking the results before moving them back: mkdir tmp && for i in 805754..999999; do mv "DBGC180_$i" "tmp/DBGC180_$(($i-1))"; done && mv -n tmp/* . && rmdir tmp Or mkdir tmp && mv DBGC180_* tmp/; for i in 805754..999999; do mv -n "tmp/DBGC180_$i" "DBGC180_$(($i-1))"; done && rmdir tmp. If the rmdir fails, you need some manual fixing.

        – Toby Speight
        Sep 29 '16 at 10:44












      • 1





        Most 'mv' implementations have a -n option to prevent overwriting. Of course, if you use that, you'll then have the problem of not knowing which names were changed and which were the originals. I recommend renaming to a temporary directory, and checking the results before moving them back: mkdir tmp && for i in 805754..999999; do mv "DBGC180_$i" "tmp/DBGC180_$(($i-1))"; done && mv -n tmp/* . && rmdir tmp Or mkdir tmp && mv DBGC180_* tmp/; for i in 805754..999999; do mv -n "tmp/DBGC180_$i" "DBGC180_$(($i-1))"; done && rmdir tmp. If the rmdir fails, you need some manual fixing.

        – Toby Speight
        Sep 29 '16 at 10:44







      1




      1





      Most 'mv' implementations have a -n option to prevent overwriting. Of course, if you use that, you'll then have the problem of not knowing which names were changed and which were the originals. I recommend renaming to a temporary directory, and checking the results before moving them back: mkdir tmp && for i in 805754..999999; do mv "DBGC180_$i" "tmp/DBGC180_$(($i-1))"; done && mv -n tmp/* . && rmdir tmp Or mkdir tmp && mv DBGC180_* tmp/; for i in 805754..999999; do mv -n "tmp/DBGC180_$i" "DBGC180_$(($i-1))"; done && rmdir tmp. If the rmdir fails, you need some manual fixing.

      – Toby Speight
      Sep 29 '16 at 10:44





      Most 'mv' implementations have a -n option to prevent overwriting. Of course, if you use that, you'll then have the problem of not knowing which names were changed and which were the originals. I recommend renaming to a temporary directory, and checking the results before moving them back: mkdir tmp && for i in 805754..999999; do mv "DBGC180_$i" "tmp/DBGC180_$(($i-1))"; done && mv -n tmp/* . && rmdir tmp Or mkdir tmp && mv DBGC180_* tmp/; for i in 805754..999999; do mv -n "tmp/DBGC180_$i" "DBGC180_$(($i-1))"; done && rmdir tmp. If the rmdir fails, you need some manual fixing.

      – Toby Speight
      Sep 29 '16 at 10:44











      0














      So, you want to rename DBGC180_805754 to DBGC180_805753,...55 to ...54 and so forth. That's the problem I'll address.



      First, put this script somewhere in your PATH, call it waltinator.



      #!/bin/bash
      #step through the parameters
      while [[ -n "$1" ]] ; do
      oldname="$1"
      # shift the arguments left
      shift;
      # strip off the fixed part of the old name
      oldnum=$oldname##DBGC180_
      # decrement the number (this is what was wanted, right?)
      newnum=$(( $oldnum - 1 ))
      # build the new, improved filename
      newname="DBGC180_$newnum"
      if [[ -f "$newname" ]] ; then
      printf "Cannot rename $oldname to $newname, $newname exists.n" >&2
      exit 1
      fi
      mv --no-clobber "$oldname" "$newname"
      done
      exit 0


      For the next step, assume that the script is in $HOME/bin/waltinator, and you have does chmod +x $HOME/bin/waltinator.



      find . -type f -name 'BDGC180_[0-9][0-9][0-9][0-9][0-9][0-9]` -print | 
      sort |
      xargs $HOME/bin/waltinator


      The find finds files (in no particular order), whose names match the shell glob pattern "BDGC180_ followed by 6 digits ([0-9]). Since we want a sorted list (it would be a failure to rename ...97 to ...96 before renaming ...96) we run the output of find through sort. Then we use xargs to take the (sorted) list of filenames, and build a command to pass the (sorted) list of filenames to $HOME/bin/waltinator. Read man xargs if you need to shorten the arg list.



      For that matter, read:



      for page in bash mv find sort xargs ; do
      man "$page"
      done





      share|improve this answer



























        0














        So, you want to rename DBGC180_805754 to DBGC180_805753,...55 to ...54 and so forth. That's the problem I'll address.



        First, put this script somewhere in your PATH, call it waltinator.



        #!/bin/bash
        #step through the parameters
        while [[ -n "$1" ]] ; do
        oldname="$1"
        # shift the arguments left
        shift;
        # strip off the fixed part of the old name
        oldnum=$oldname##DBGC180_
        # decrement the number (this is what was wanted, right?)
        newnum=$(( $oldnum - 1 ))
        # build the new, improved filename
        newname="DBGC180_$newnum"
        if [[ -f "$newname" ]] ; then
        printf "Cannot rename $oldname to $newname, $newname exists.n" >&2
        exit 1
        fi
        mv --no-clobber "$oldname" "$newname"
        done
        exit 0


        For the next step, assume that the script is in $HOME/bin/waltinator, and you have does chmod +x $HOME/bin/waltinator.



        find . -type f -name 'BDGC180_[0-9][0-9][0-9][0-9][0-9][0-9]` -print | 
        sort |
        xargs $HOME/bin/waltinator


        The find finds files (in no particular order), whose names match the shell glob pattern "BDGC180_ followed by 6 digits ([0-9]). Since we want a sorted list (it would be a failure to rename ...97 to ...96 before renaming ...96) we run the output of find through sort. Then we use xargs to take the (sorted) list of filenames, and build a command to pass the (sorted) list of filenames to $HOME/bin/waltinator. Read man xargs if you need to shorten the arg list.



        For that matter, read:



        for page in bash mv find sort xargs ; do
        man "$page"
        done





        share|improve this answer

























          0












          0








          0







          So, you want to rename DBGC180_805754 to DBGC180_805753,...55 to ...54 and so forth. That's the problem I'll address.



          First, put this script somewhere in your PATH, call it waltinator.



          #!/bin/bash
          #step through the parameters
          while [[ -n "$1" ]] ; do
          oldname="$1"
          # shift the arguments left
          shift;
          # strip off the fixed part of the old name
          oldnum=$oldname##DBGC180_
          # decrement the number (this is what was wanted, right?)
          newnum=$(( $oldnum - 1 ))
          # build the new, improved filename
          newname="DBGC180_$newnum"
          if [[ -f "$newname" ]] ; then
          printf "Cannot rename $oldname to $newname, $newname exists.n" >&2
          exit 1
          fi
          mv --no-clobber "$oldname" "$newname"
          done
          exit 0


          For the next step, assume that the script is in $HOME/bin/waltinator, and you have does chmod +x $HOME/bin/waltinator.



          find . -type f -name 'BDGC180_[0-9][0-9][0-9][0-9][0-9][0-9]` -print | 
          sort |
          xargs $HOME/bin/waltinator


          The find finds files (in no particular order), whose names match the shell glob pattern "BDGC180_ followed by 6 digits ([0-9]). Since we want a sorted list (it would be a failure to rename ...97 to ...96 before renaming ...96) we run the output of find through sort. Then we use xargs to take the (sorted) list of filenames, and build a command to pass the (sorted) list of filenames to $HOME/bin/waltinator. Read man xargs if you need to shorten the arg list.



          For that matter, read:



          for page in bash mv find sort xargs ; do
          man "$page"
          done





          share|improve this answer













          So, you want to rename DBGC180_805754 to DBGC180_805753,...55 to ...54 and so forth. That's the problem I'll address.



          First, put this script somewhere in your PATH, call it waltinator.



          #!/bin/bash
          #step through the parameters
          while [[ -n "$1" ]] ; do
          oldname="$1"
          # shift the arguments left
          shift;
          # strip off the fixed part of the old name
          oldnum=$oldname##DBGC180_
          # decrement the number (this is what was wanted, right?)
          newnum=$(( $oldnum - 1 ))
          # build the new, improved filename
          newname="DBGC180_$newnum"
          if [[ -f "$newname" ]] ; then
          printf "Cannot rename $oldname to $newname, $newname exists.n" >&2
          exit 1
          fi
          mv --no-clobber "$oldname" "$newname"
          done
          exit 0


          For the next step, assume that the script is in $HOME/bin/waltinator, and you have does chmod +x $HOME/bin/waltinator.



          find . -type f -name 'BDGC180_[0-9][0-9][0-9][0-9][0-9][0-9]` -print | 
          sort |
          xargs $HOME/bin/waltinator


          The find finds files (in no particular order), whose names match the shell glob pattern "BDGC180_ followed by 6 digits ([0-9]). Since we want a sorted list (it would be a failure to rename ...97 to ...96 before renaming ...96) we run the output of find through sort. Then we use xargs to take the (sorted) list of filenames, and build a command to pass the (sorted) list of filenames to $HOME/bin/waltinator. Read man xargs if you need to shorten the arg list.



          For that matter, read:



          for page in bash mv find sort xargs ; do
          man "$page"
          done






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Sep 27 '16 at 17:44









          waltinatorwaltinator

          75049




          75049





















              0














              If you want to rename those specific files then here is the solution (static).
              First rename and move those files into sub directory.
              From there move those files to current directory



              #!/bin/bash
              # rename.sh

              #make a subdirectory
              mkdir -p subDir

              #move all files to subdirectory with rename
              for i in 5754..6754; do
              mv "DBGC180_80$i" "./subDir/DBGC180_80$(($i-1))";
              done

              #move all files from subdirectory to current directory
              for j in 5754..6754; do
              mv "./subDir/DBGC180_80$(($j-1))" "./DBGC180_80$(($j-1))"
              done

              #remove subdirectory
              rmdir subDir


              This program can be modified to be generic (dynamic)






              share|improve this answer























              • Huh? Why, in your "move from subdir to current dir" code block, do you even bother with j-1 (since you're doing it twice)? Why not just change the numbers used for iteration?

                – Wildcard
                Sep 29 '16 at 6:22











              • Of course, it can be done as you said. I kept it in a single line.

                – firoj_mujawar
                Oct 3 '16 at 7:49
















              0














              If you want to rename those specific files then here is the solution (static).
              First rename and move those files into sub directory.
              From there move those files to current directory



              #!/bin/bash
              # rename.sh

              #make a subdirectory
              mkdir -p subDir

              #move all files to subdirectory with rename
              for i in 5754..6754; do
              mv "DBGC180_80$i" "./subDir/DBGC180_80$(($i-1))";
              done

              #move all files from subdirectory to current directory
              for j in 5754..6754; do
              mv "./subDir/DBGC180_80$(($j-1))" "./DBGC180_80$(($j-1))"
              done

              #remove subdirectory
              rmdir subDir


              This program can be modified to be generic (dynamic)






              share|improve this answer























              • Huh? Why, in your "move from subdir to current dir" code block, do you even bother with j-1 (since you're doing it twice)? Why not just change the numbers used for iteration?

                – Wildcard
                Sep 29 '16 at 6:22











              • Of course, it can be done as you said. I kept it in a single line.

                – firoj_mujawar
                Oct 3 '16 at 7:49














              0












              0








              0







              If you want to rename those specific files then here is the solution (static).
              First rename and move those files into sub directory.
              From there move those files to current directory



              #!/bin/bash
              # rename.sh

              #make a subdirectory
              mkdir -p subDir

              #move all files to subdirectory with rename
              for i in 5754..6754; do
              mv "DBGC180_80$i" "./subDir/DBGC180_80$(($i-1))";
              done

              #move all files from subdirectory to current directory
              for j in 5754..6754; do
              mv "./subDir/DBGC180_80$(($j-1))" "./DBGC180_80$(($j-1))"
              done

              #remove subdirectory
              rmdir subDir


              This program can be modified to be generic (dynamic)






              share|improve this answer













              If you want to rename those specific files then here is the solution (static).
              First rename and move those files into sub directory.
              From there move those files to current directory



              #!/bin/bash
              # rename.sh

              #make a subdirectory
              mkdir -p subDir

              #move all files to subdirectory with rename
              for i in 5754..6754; do
              mv "DBGC180_80$i" "./subDir/DBGC180_80$(($i-1))";
              done

              #move all files from subdirectory to current directory
              for j in 5754..6754; do
              mv "./subDir/DBGC180_80$(($j-1))" "./DBGC180_80$(($j-1))"
              done

              #remove subdirectory
              rmdir subDir


              This program can be modified to be generic (dynamic)







              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Sep 29 '16 at 5:37









              firoj_mujawarfiroj_mujawar

              4517




              4517












              • Huh? Why, in your "move from subdir to current dir" code block, do you even bother with j-1 (since you're doing it twice)? Why not just change the numbers used for iteration?

                – Wildcard
                Sep 29 '16 at 6:22











              • Of course, it can be done as you said. I kept it in a single line.

                – firoj_mujawar
                Oct 3 '16 at 7:49


















              • Huh? Why, in your "move from subdir to current dir" code block, do you even bother with j-1 (since you're doing it twice)? Why not just change the numbers used for iteration?

                – Wildcard
                Sep 29 '16 at 6:22











              • Of course, it can be done as you said. I kept it in a single line.

                – firoj_mujawar
                Oct 3 '16 at 7:49

















              Huh? Why, in your "move from subdir to current dir" code block, do you even bother with j-1 (since you're doing it twice)? Why not just change the numbers used for iteration?

              – Wildcard
              Sep 29 '16 at 6:22





              Huh? Why, in your "move from subdir to current dir" code block, do you even bother with j-1 (since you're doing it twice)? Why not just change the numbers used for iteration?

              – Wildcard
              Sep 29 '16 at 6:22













              Of course, it can be done as you said. I kept it in a single line.

              – firoj_mujawar
              Oct 3 '16 at 7:49






              Of course, it can be done as you said. I kept it in a single line.

              – firoj_mujawar
              Oct 3 '16 at 7:49












              0














              Use rename to substitute each number with itself minus 1.



              $ rename -v 's/d6/sprintf("%06",($&-1))/e' 


              Notes




              • rename uses Perl expressions to rename filenames.


              • s specifies that rename will substitute some or all of the filenames that match the regular expression pattern.

              • Perl substitution expressions are structured as such.

                • s/PATTERN/REPLACEMENT/MODIFIER



              • d6 is the pattern that rename will search for and substitute. This is 6 decimal digits.


              • $ is the variable storing the substring that matched d6 (in this case the "substring" is an int).


              • sprintf("%06",($&-1)) retrieves the value stored in $, decrements it, then returns this value as the replacement. The %06 is there to handle leading zeroes.


              • e specified that rename evaluates the replacement as if it were a Perl statement, and uses its return value as the replacement text.


              • -v makes rename echo what it is doing.

              If you want to be extra safe use the flag -n so that rename only tells you what it would do instead of doing it.



              This appears to only work for decrementing so handle this with care.






              share|improve this answer



























                0














                Use rename to substitute each number with itself minus 1.



                $ rename -v 's/d6/sprintf("%06",($&-1))/e' 


                Notes




                • rename uses Perl expressions to rename filenames.


                • s specifies that rename will substitute some or all of the filenames that match the regular expression pattern.

                • Perl substitution expressions are structured as such.

                  • s/PATTERN/REPLACEMENT/MODIFIER



                • d6 is the pattern that rename will search for and substitute. This is 6 decimal digits.


                • $ is the variable storing the substring that matched d6 (in this case the "substring" is an int).


                • sprintf("%06",($&-1)) retrieves the value stored in $, decrements it, then returns this value as the replacement. The %06 is there to handle leading zeroes.


                • e specified that rename evaluates the replacement as if it were a Perl statement, and uses its return value as the replacement text.


                • -v makes rename echo what it is doing.

                If you want to be extra safe use the flag -n so that rename only tells you what it would do instead of doing it.



                This appears to only work for decrementing so handle this with care.






                share|improve this answer

























                  0












                  0








                  0







                  Use rename to substitute each number with itself minus 1.



                  $ rename -v 's/d6/sprintf("%06",($&-1))/e' 


                  Notes




                  • rename uses Perl expressions to rename filenames.


                  • s specifies that rename will substitute some or all of the filenames that match the regular expression pattern.

                  • Perl substitution expressions are structured as such.

                    • s/PATTERN/REPLACEMENT/MODIFIER



                  • d6 is the pattern that rename will search for and substitute. This is 6 decimal digits.


                  • $ is the variable storing the substring that matched d6 (in this case the "substring" is an int).


                  • sprintf("%06",($&-1)) retrieves the value stored in $, decrements it, then returns this value as the replacement. The %06 is there to handle leading zeroes.


                  • e specified that rename evaluates the replacement as if it were a Perl statement, and uses its return value as the replacement text.


                  • -v makes rename echo what it is doing.

                  If you want to be extra safe use the flag -n so that rename only tells you what it would do instead of doing it.



                  This appears to only work for decrementing so handle this with care.






                  share|improve this answer













                  Use rename to substitute each number with itself minus 1.



                  $ rename -v 's/d6/sprintf("%06",($&-1))/e' 


                  Notes




                  • rename uses Perl expressions to rename filenames.


                  • s specifies that rename will substitute some or all of the filenames that match the regular expression pattern.

                  • Perl substitution expressions are structured as such.

                    • s/PATTERN/REPLACEMENT/MODIFIER



                  • d6 is the pattern that rename will search for and substitute. This is 6 decimal digits.


                  • $ is the variable storing the substring that matched d6 (in this case the "substring" is an int).


                  • sprintf("%06",($&-1)) retrieves the value stored in $, decrements it, then returns this value as the replacement. The %06 is there to handle leading zeroes.


                  • e specified that rename evaluates the replacement as if it were a Perl statement, and uses its return value as the replacement text.


                  • -v makes rename echo what it is doing.

                  If you want to be extra safe use the flag -n so that rename only tells you what it would do instead of doing it.



                  This appears to only work for decrementing so handle this with care.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Mar 5 at 2:23









                  coffee-dancoffee-dan

                  1




                  1





















                      -1














                      Wow, this was trickier than I expected.



                      As Gilles pointed out, considering the number of files to be handled, you should rename them in a way that won't give you problems if the command is interrupted. The command below does that.



                      I wrote this command to be fairly robust against failures. Note that we explicitly exclude files where the number has a leading 0; if you have files like that, post a comment and I'll include a command to deal with them.



                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' -exec sh -c 'for f; do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented"; done' find-sh-decrement + && find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' -exec sh -c 'for f; do mv -i "$f" "$f%.decremented"; done' find-sh-remove-prefix +


                      With line wrappings (can still be copied and pasted):



                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' 
                      -exec sh -c 'for f;
                      do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented";
                      done' find-sh-decrement + &&
                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented'
                      -exec sh -c 'for f;
                      do mv -i "$f" "$f%.decremented";
                      done' find-sh-remove-prefix +



                      Explanation of the parts (this could use some formatting cleanup):



                      ##### Recursively find regular files in the current directory...
                      find . -type f
                      ##### whose name matches this exact pattern...
                      -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]'
                      ##### and run the following shell script...
                      -exec sh -c
                      ##### (shell script: ) for every file given as an argument...
                      'for f;
                      ##### rename the file, prompting for confirmation for any overwrites...
                      do mv -i
                      ##### from the original file name...
                      "$f"
                      ##### to the file name decremented by 1, with '.decremented' afterward...
                      "$f%_*_$(($f##*_-1)).decremented";
                      ##### (End of shell script)
                      done'
                      ##### on as many found files as possible at once,
                      ##### using the name "find-sh-decrement" for error reporting.
                      find-sh-decrement +
                      ##### If that completes successfully...
                      &&
                      ##### Pass through again and remove the ".decremented" prefix.
                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' -exec sh -c 'for f; do mv -i "$f" "$f%.decremented"; done' find-sh-remove-prefix +



                      Test results:



                      $ ls
                      DBGC180_805754 DBGC180_805755 DBGC180_805756
                      $ cat DBGC180_805754
                      This file started as DBGC180_805754
                      $ cat DBGC180_805755
                      This file started as DBGC180_805755
                      $ cat DBGC180_805756
                      This file started as DBGC180_805756
                      $ find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' -exec sh -c 'for f; do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented"; done' find-sh-decrement + && find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' -exec sh -c 'for f; do mv -i "$f" "$f%.decremented"; done' find-sh-remove-prefix +
                      $ ls
                      DBGC180_805753 DBGC180_805754 DBGC180_805755
                      $ cat DBGC180_805753
                      This file started as DBGC180_805754
                      $ cat DBGC180_805754
                      This file started as DBGC180_805755
                      $ cat DBGC180_805755
                      This file started as DBGC180_805756
                      $


                      For extra safety, run the first find command and inspect the results for yourself before you run the second command to remove the .decremented suffix.



                      Run this:



                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' 
                      -exec sh -c 'for f;
                      do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented";
                      done' find-sh-decrement +


                      Then inspect results, and then run this:



                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' 
                      -exec sh -c 'for f;
                      do mv -i "$f" "$f%.decremented";
                      done' find-sh-remove-prefix +





                      share|improve this answer

























                      • Why the downvote? This does exactly what was requested, and is quite clean in my opinion.

                        – Wildcard
                        Oct 3 '16 at 14:34
















                      -1














                      Wow, this was trickier than I expected.



                      As Gilles pointed out, considering the number of files to be handled, you should rename them in a way that won't give you problems if the command is interrupted. The command below does that.



                      I wrote this command to be fairly robust against failures. Note that we explicitly exclude files where the number has a leading 0; if you have files like that, post a comment and I'll include a command to deal with them.



                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' -exec sh -c 'for f; do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented"; done' find-sh-decrement + && find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' -exec sh -c 'for f; do mv -i "$f" "$f%.decremented"; done' find-sh-remove-prefix +


                      With line wrappings (can still be copied and pasted):



                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' 
                      -exec sh -c 'for f;
                      do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented";
                      done' find-sh-decrement + &&
                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented'
                      -exec sh -c 'for f;
                      do mv -i "$f" "$f%.decremented";
                      done' find-sh-remove-prefix +



                      Explanation of the parts (this could use some formatting cleanup):



                      ##### Recursively find regular files in the current directory...
                      find . -type f
                      ##### whose name matches this exact pattern...
                      -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]'
                      ##### and run the following shell script...
                      -exec sh -c
                      ##### (shell script: ) for every file given as an argument...
                      'for f;
                      ##### rename the file, prompting for confirmation for any overwrites...
                      do mv -i
                      ##### from the original file name...
                      "$f"
                      ##### to the file name decremented by 1, with '.decremented' afterward...
                      "$f%_*_$(($f##*_-1)).decremented";
                      ##### (End of shell script)
                      done'
                      ##### on as many found files as possible at once,
                      ##### using the name "find-sh-decrement" for error reporting.
                      find-sh-decrement +
                      ##### If that completes successfully...
                      &&
                      ##### Pass through again and remove the ".decremented" prefix.
                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' -exec sh -c 'for f; do mv -i "$f" "$f%.decremented"; done' find-sh-remove-prefix +



                      Test results:



                      $ ls
                      DBGC180_805754 DBGC180_805755 DBGC180_805756
                      $ cat DBGC180_805754
                      This file started as DBGC180_805754
                      $ cat DBGC180_805755
                      This file started as DBGC180_805755
                      $ cat DBGC180_805756
                      This file started as DBGC180_805756
                      $ find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' -exec sh -c 'for f; do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented"; done' find-sh-decrement + && find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' -exec sh -c 'for f; do mv -i "$f" "$f%.decremented"; done' find-sh-remove-prefix +
                      $ ls
                      DBGC180_805753 DBGC180_805754 DBGC180_805755
                      $ cat DBGC180_805753
                      This file started as DBGC180_805754
                      $ cat DBGC180_805754
                      This file started as DBGC180_805755
                      $ cat DBGC180_805755
                      This file started as DBGC180_805756
                      $


                      For extra safety, run the first find command and inspect the results for yourself before you run the second command to remove the .decremented suffix.



                      Run this:



                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' 
                      -exec sh -c 'for f;
                      do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented";
                      done' find-sh-decrement +


                      Then inspect results, and then run this:



                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' 
                      -exec sh -c 'for f;
                      do mv -i "$f" "$f%.decremented";
                      done' find-sh-remove-prefix +





                      share|improve this answer

























                      • Why the downvote? This does exactly what was requested, and is quite clean in my opinion.

                        – Wildcard
                        Oct 3 '16 at 14:34














                      -1












                      -1








                      -1







                      Wow, this was trickier than I expected.



                      As Gilles pointed out, considering the number of files to be handled, you should rename them in a way that won't give you problems if the command is interrupted. The command below does that.



                      I wrote this command to be fairly robust against failures. Note that we explicitly exclude files where the number has a leading 0; if you have files like that, post a comment and I'll include a command to deal with them.



                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' -exec sh -c 'for f; do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented"; done' find-sh-decrement + && find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' -exec sh -c 'for f; do mv -i "$f" "$f%.decremented"; done' find-sh-remove-prefix +


                      With line wrappings (can still be copied and pasted):



                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' 
                      -exec sh -c 'for f;
                      do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented";
                      done' find-sh-decrement + &&
                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented'
                      -exec sh -c 'for f;
                      do mv -i "$f" "$f%.decremented";
                      done' find-sh-remove-prefix +



                      Explanation of the parts (this could use some formatting cleanup):



                      ##### Recursively find regular files in the current directory...
                      find . -type f
                      ##### whose name matches this exact pattern...
                      -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]'
                      ##### and run the following shell script...
                      -exec sh -c
                      ##### (shell script: ) for every file given as an argument...
                      'for f;
                      ##### rename the file, prompting for confirmation for any overwrites...
                      do mv -i
                      ##### from the original file name...
                      "$f"
                      ##### to the file name decremented by 1, with '.decremented' afterward...
                      "$f%_*_$(($f##*_-1)).decremented";
                      ##### (End of shell script)
                      done'
                      ##### on as many found files as possible at once,
                      ##### using the name "find-sh-decrement" for error reporting.
                      find-sh-decrement +
                      ##### If that completes successfully...
                      &&
                      ##### Pass through again and remove the ".decremented" prefix.
                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' -exec sh -c 'for f; do mv -i "$f" "$f%.decremented"; done' find-sh-remove-prefix +



                      Test results:



                      $ ls
                      DBGC180_805754 DBGC180_805755 DBGC180_805756
                      $ cat DBGC180_805754
                      This file started as DBGC180_805754
                      $ cat DBGC180_805755
                      This file started as DBGC180_805755
                      $ cat DBGC180_805756
                      This file started as DBGC180_805756
                      $ find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' -exec sh -c 'for f; do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented"; done' find-sh-decrement + && find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' -exec sh -c 'for f; do mv -i "$f" "$f%.decremented"; done' find-sh-remove-prefix +
                      $ ls
                      DBGC180_805753 DBGC180_805754 DBGC180_805755
                      $ cat DBGC180_805753
                      This file started as DBGC180_805754
                      $ cat DBGC180_805754
                      This file started as DBGC180_805755
                      $ cat DBGC180_805755
                      This file started as DBGC180_805756
                      $


                      For extra safety, run the first find command and inspect the results for yourself before you run the second command to remove the .decremented suffix.



                      Run this:



                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' 
                      -exec sh -c 'for f;
                      do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented";
                      done' find-sh-decrement +


                      Then inspect results, and then run this:



                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' 
                      -exec sh -c 'for f;
                      do mv -i "$f" "$f%.decremented";
                      done' find-sh-remove-prefix +





                      share|improve this answer















                      Wow, this was trickier than I expected.



                      As Gilles pointed out, considering the number of files to be handled, you should rename them in a way that won't give you problems if the command is interrupted. The command below does that.



                      I wrote this command to be fairly robust against failures. Note that we explicitly exclude files where the number has a leading 0; if you have files like that, post a comment and I'll include a command to deal with them.



                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' -exec sh -c 'for f; do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented"; done' find-sh-decrement + && find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' -exec sh -c 'for f; do mv -i "$f" "$f%.decremented"; done' find-sh-remove-prefix +


                      With line wrappings (can still be copied and pasted):



                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' 
                      -exec sh -c 'for f;
                      do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented";
                      done' find-sh-decrement + &&
                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented'
                      -exec sh -c 'for f;
                      do mv -i "$f" "$f%.decremented";
                      done' find-sh-remove-prefix +



                      Explanation of the parts (this could use some formatting cleanup):



                      ##### Recursively find regular files in the current directory...
                      find . -type f
                      ##### whose name matches this exact pattern...
                      -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]'
                      ##### and run the following shell script...
                      -exec sh -c
                      ##### (shell script: ) for every file given as an argument...
                      'for f;
                      ##### rename the file, prompting for confirmation for any overwrites...
                      do mv -i
                      ##### from the original file name...
                      "$f"
                      ##### to the file name decremented by 1, with '.decremented' afterward...
                      "$f%_*_$(($f##*_-1)).decremented";
                      ##### (End of shell script)
                      done'
                      ##### on as many found files as possible at once,
                      ##### using the name "find-sh-decrement" for error reporting.
                      find-sh-decrement +
                      ##### If that completes successfully...
                      &&
                      ##### Pass through again and remove the ".decremented" prefix.
                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' -exec sh -c 'for f; do mv -i "$f" "$f%.decremented"; done' find-sh-remove-prefix +



                      Test results:



                      $ ls
                      DBGC180_805754 DBGC180_805755 DBGC180_805756
                      $ cat DBGC180_805754
                      This file started as DBGC180_805754
                      $ cat DBGC180_805755
                      This file started as DBGC180_805755
                      $ cat DBGC180_805756
                      This file started as DBGC180_805756
                      $ find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' -exec sh -c 'for f; do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented"; done' find-sh-decrement + && find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' -exec sh -c 'for f; do mv -i "$f" "$f%.decremented"; done' find-sh-remove-prefix +
                      $ ls
                      DBGC180_805753 DBGC180_805754 DBGC180_805755
                      $ cat DBGC180_805753
                      This file started as DBGC180_805754
                      $ cat DBGC180_805754
                      This file started as DBGC180_805755
                      $ cat DBGC180_805755
                      This file started as DBGC180_805756
                      $


                      For extra safety, run the first find command and inspect the results for yourself before you run the second command to remove the .decremented suffix.



                      Run this:



                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9]' 
                      -exec sh -c 'for f;
                      do mv -i "$f" "$f%_*_$(($f##*_-1)).decremented";
                      done' find-sh-decrement +


                      Then inspect results, and then run this:



                      find . -type f -name 'DBGC180_[1-9][0-9][0-9][0-9][0-9][0-9].decremented' 
                      -exec sh -c 'for f;
                      do mv -i "$f" "$f%.decremented";
                      done' find-sh-remove-prefix +






                      share|improve this answer














                      share|improve this answer



                      share|improve this answer








                      edited Apr 13 '17 at 12:36









                      Community

                      1




                      1










                      answered Sep 29 '16 at 6:56









                      WildcardWildcard

                      23.2k1067171




                      23.2k1067171












                      • Why the downvote? This does exactly what was requested, and is quite clean in my opinion.

                        – Wildcard
                        Oct 3 '16 at 14:34


















                      • Why the downvote? This does exactly what was requested, and is quite clean in my opinion.

                        – Wildcard
                        Oct 3 '16 at 14:34

















                      Why the downvote? This does exactly what was requested, and is quite clean in my opinion.

                      – Wildcard
                      Oct 3 '16 at 14:34






                      Why the downvote? This does exactly what was requested, and is quite clean in my opinion.

                      – Wildcard
                      Oct 3 '16 at 14:34












                      -1














                      Use awk to create a fully expanded rename script:



                      find . -name "DBGC180_*" |sort |awk -F "_" 'print "mv -i "$0" "$1"_"$2-1' >/tmp/rename.sh


                      You can review the script before executing. This is the unique feature of this solution. Then execute it:



                      sh -e -x /tmp/rename.sh


                      Notes



                      • you may improve the find pattern, the question is not 100% clear about what files has to be renamed.


                      • sort is important to not overwrite existing files


                      • mv option -i makes it extra-safe to never overwrite files


                      • sh option -e is to abort the script in case of error


                      • sh option -x prints a trace to see what was done so far in case the script is interrupted (to make recovery possible). You could also use mv -v instead if supported.





                      share|improve this answer

























                      • Down voters! Please comment whats wrong here.

                        – rudimeier
                        Sep 29 '16 at 11:12











                      • Your added explanations are good, and the script may work fine for the exact use case of the Original Poster. However, it is definitely not robust. (My own definition of robust: Does not produce unexpected output in the face of unexpected input.) There are a great many caveats if the script would be modified and used more generally, and you don't note these: (1) It won't handle whitespace correctly, or even underscores, if they appear within directory names (i.e. not truly recursive); (cont'd)

                        – Wildcard
                        Sep 29 '16 at 19:51











                      • (cont'd) (2) It won't handle file extensions (see what happens if you give it the file DBGC180_5555.txt, for instance); (3) If the script is interrupted partway through there is no way to tell which files have been renamed and which haven't been.

                        – Wildcard
                        Sep 29 '16 at 19:51















                      -1














                      Use awk to create a fully expanded rename script:



                      find . -name "DBGC180_*" |sort |awk -F "_" 'print "mv -i "$0" "$1"_"$2-1' >/tmp/rename.sh


                      You can review the script before executing. This is the unique feature of this solution. Then execute it:



                      sh -e -x /tmp/rename.sh


                      Notes



                      • you may improve the find pattern, the question is not 100% clear about what files has to be renamed.


                      • sort is important to not overwrite existing files


                      • mv option -i makes it extra-safe to never overwrite files


                      • sh option -e is to abort the script in case of error


                      • sh option -x prints a trace to see what was done so far in case the script is interrupted (to make recovery possible). You could also use mv -v instead if supported.





                      share|improve this answer

























                      • Down voters! Please comment whats wrong here.

                        – rudimeier
                        Sep 29 '16 at 11:12











                      • Your added explanations are good, and the script may work fine for the exact use case of the Original Poster. However, it is definitely not robust. (My own definition of robust: Does not produce unexpected output in the face of unexpected input.) There are a great many caveats if the script would be modified and used more generally, and you don't note these: (1) It won't handle whitespace correctly, or even underscores, if they appear within directory names (i.e. not truly recursive); (cont'd)

                        – Wildcard
                        Sep 29 '16 at 19:51











                      • (cont'd) (2) It won't handle file extensions (see what happens if you give it the file DBGC180_5555.txt, for instance); (3) If the script is interrupted partway through there is no way to tell which files have been renamed and which haven't been.

                        – Wildcard
                        Sep 29 '16 at 19:51













                      -1












                      -1








                      -1







                      Use awk to create a fully expanded rename script:



                      find . -name "DBGC180_*" |sort |awk -F "_" 'print "mv -i "$0" "$1"_"$2-1' >/tmp/rename.sh


                      You can review the script before executing. This is the unique feature of this solution. Then execute it:



                      sh -e -x /tmp/rename.sh


                      Notes



                      • you may improve the find pattern, the question is not 100% clear about what files has to be renamed.


                      • sort is important to not overwrite existing files


                      • mv option -i makes it extra-safe to never overwrite files


                      • sh option -e is to abort the script in case of error


                      • sh option -x prints a trace to see what was done so far in case the script is interrupted (to make recovery possible). You could also use mv -v instead if supported.





                      share|improve this answer















                      Use awk to create a fully expanded rename script:



                      find . -name "DBGC180_*" |sort |awk -F "_" 'print "mv -i "$0" "$1"_"$2-1' >/tmp/rename.sh


                      You can review the script before executing. This is the unique feature of this solution. Then execute it:



                      sh -e -x /tmp/rename.sh


                      Notes



                      • you may improve the find pattern, the question is not 100% clear about what files has to be renamed.


                      • sort is important to not overwrite existing files


                      • mv option -i makes it extra-safe to never overwrite files


                      • sh option -e is to abort the script in case of error


                      • sh option -x prints a trace to see what was done so far in case the script is interrupted (to make recovery possible). You could also use mv -v instead if supported.






                      share|improve this answer














                      share|improve this answer



                      share|improve this answer








                      edited Sep 29 '16 at 11:11

























                      answered Sep 27 '16 at 19:53









                      rudimeierrudimeier

                      5,6421832




                      5,6421832












                      • Down voters! Please comment whats wrong here.

                        – rudimeier
                        Sep 29 '16 at 11:12











                      • Your added explanations are good, and the script may work fine for the exact use case of the Original Poster. However, it is definitely not robust. (My own definition of robust: Does not produce unexpected output in the face of unexpected input.) There are a great many caveats if the script would be modified and used more generally, and you don't note these: (1) It won't handle whitespace correctly, or even underscores, if they appear within directory names (i.e. not truly recursive); (cont'd)

                        – Wildcard
                        Sep 29 '16 at 19:51











                      • (cont'd) (2) It won't handle file extensions (see what happens if you give it the file DBGC180_5555.txt, for instance); (3) If the script is interrupted partway through there is no way to tell which files have been renamed and which haven't been.

                        – Wildcard
                        Sep 29 '16 at 19:51

















                      • Down voters! Please comment whats wrong here.

                        – rudimeier
                        Sep 29 '16 at 11:12











                      • Your added explanations are good, and the script may work fine for the exact use case of the Original Poster. However, it is definitely not robust. (My own definition of robust: Does not produce unexpected output in the face of unexpected input.) There are a great many caveats if the script would be modified and used more generally, and you don't note these: (1) It won't handle whitespace correctly, or even underscores, if they appear within directory names (i.e. not truly recursive); (cont'd)

                        – Wildcard
                        Sep 29 '16 at 19:51











                      • (cont'd) (2) It won't handle file extensions (see what happens if you give it the file DBGC180_5555.txt, for instance); (3) If the script is interrupted partway through there is no way to tell which files have been renamed and which haven't been.

                        – Wildcard
                        Sep 29 '16 at 19:51
















                      Down voters! Please comment whats wrong here.

                      – rudimeier
                      Sep 29 '16 at 11:12





                      Down voters! Please comment whats wrong here.

                      – rudimeier
                      Sep 29 '16 at 11:12













                      Your added explanations are good, and the script may work fine for the exact use case of the Original Poster. However, it is definitely not robust. (My own definition of robust: Does not produce unexpected output in the face of unexpected input.) There are a great many caveats if the script would be modified and used more generally, and you don't note these: (1) It won't handle whitespace correctly, or even underscores, if they appear within directory names (i.e. not truly recursive); (cont'd)

                      – Wildcard
                      Sep 29 '16 at 19:51





                      Your added explanations are good, and the script may work fine for the exact use case of the Original Poster. However, it is definitely not robust. (My own definition of robust: Does not produce unexpected output in the face of unexpected input.) There are a great many caveats if the script would be modified and used more generally, and you don't note these: (1) It won't handle whitespace correctly, or even underscores, if they appear within directory names (i.e. not truly recursive); (cont'd)

                      – Wildcard
                      Sep 29 '16 at 19:51













                      (cont'd) (2) It won't handle file extensions (see what happens if you give it the file DBGC180_5555.txt, for instance); (3) If the script is interrupted partway through there is no way to tell which files have been renamed and which haven't been.

                      – Wildcard
                      Sep 29 '16 at 19:51





                      (cont'd) (2) It won't handle file extensions (see what happens if you give it the file DBGC180_5555.txt, for instance); (3) If the script is interrupted partway through there is no way to tell which files have been renamed and which haven't been.

                      – Wildcard
                      Sep 29 '16 at 19:51

















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