TikZ: Align array of matrices
Clash Royale CLAN TAG#URR8PPP
4
The following code:
documentclass[tikz,border=1mm]standalone
usepackagetikz
usetikzlibrarymatrix, positioning
tikzset
matrixstyle/.style=
matrix of nodes,
nodes=
draw
begindocument
begintikzpicture
matrix (M) [matrixstyle]
.1 & .1 \
.1 & .1 \
;
beginscope [local bounding box=MA, shift=(M.west), left = 0cm of M.west]
matrix (M11) [matrixstyle]
.1 & .0 \
.5 & .0 \
;
matrix (M12) [matrixstyle, right = 0cm of M11]
.2 & .0 \
.3 & .9 \
;
matrix (M21) [matrixstyle, below = 0cm of M11]
.0 & .0 \
.0 & .2 \
;
matrix (M22) [matrixstyle, right = 0cm of M21]
.3 & .0 \
.3 & .9 \
;
endscope
matrix (N) [matrixstyle, left = 1cm of MA.west]
.2 & .2 \
.2 & .2 \
;
endtikzpicture
enddocument
produces the following output:
The output should show six matrices. Four in the middle. And one matrix each on the right and left side of the matrix array. However, I did not manage to place the matrix M to the right of the matrix array MA. The error is probably in the following line
beginscope [local bounding box=MA, shift=(M.west), left = 0cm of M.west]
What is the right way to do it? Why does my approach not work?
tikz-pgf
edited Jan 11 at 18:35
Bernard
168k771195
asked Jan 11 at 18:27
SamuelSamuel
537211
add a comment |
4
The following code:
documentclass[tikz,border=1mm]standalone
usepackagetikz
usetikzlibrarymatrix, positioning
tikzset
matrixstyle/.style=
matrix of nodes,
nodes=
draw
begindocument
begintikzpicture
matrix (M) [matrixstyle]
.1 & .1 \
.1 & .1 \
;
beginscope [local bounding box=MA, shift=(M.west), left = 0cm of M.west]
matrix (M11) [matrixstyle]
.1 & .0 \
.5 & .0 \
;
matrix (M12) [matrixstyle, right = 0cm of M11]
.2 & .0 \
.3 & .9 \
;
matrix (M21) [matrixstyle, below = 0cm of M11]
.0 & .0 \
.0 & .2 \
;
matrix (M22) [matrixstyle, right = 0cm of M21]
.3 & .0 \
.3 & .9 \
;
endscope
matrix (N) [matrixstyle, left = 1cm of MA.west]
.2 & .2 \
.2 & .2 \
;
endtikzpicture
enddocument
produces the following output:
The output should show six matrices. Four in the middle. And one matrix each on the right and left side of the matrix array. However, I did not manage to place the matrix M to the right of the matrix array MA. The error is probably in the following line
beginscope [local bounding box=MA, shift=(M.west), left = 0cm of M.west]
What is the right way to do it? Why does my approach not work?
tikz-pgf
edited Jan 11 at 18:35
Bernard
168k771195
asked Jan 11 at 18:27
SamuelSamuel
537211
add a comment |
4
4
4
1
The following code:
documentclass[tikz,border=1mm]standalone
usepackagetikz
usetikzlibrarymatrix, positioning
tikzset
matrixstyle/.style=
matrix of nodes,
nodes=
draw
begindocument
begintikzpicture
matrix (M) [matrixstyle]
.1 & .1 \
.1 & .1 \
;
beginscope [local bounding box=MA, shift=(M.west), left = 0cm of M.west]
matrix (M11) [matrixstyle]
.1 & .0 \
.5 & .0 \
;
matrix (M12) [matrixstyle, right = 0cm of M11]
.2 & .0 \
.3 & .9 \
;
matrix (M21) [matrixstyle, below = 0cm of M11]
.0 & .0 \
.0 & .2 \
;
matrix (M22) [matrixstyle, right = 0cm of M21]
.3 & .0 \
.3 & .9 \
;
endscope
matrix (N) [matrixstyle, left = 1cm of MA.west]
.2 & .2 \
.2 & .2 \
;
endtikzpicture
enddocument
produces the following output:
The output should show six matrices. Four in the middle. And one matrix each on the right and left side of the matrix array. However, I did not manage to place the matrix M to the right of the matrix array MA. The error is probably in the following line
beginscope [local bounding box=MA, shift=(M.west), left = 0cm of M.west]
What is the right way to do it? Why does my approach not work?
tikz-pgf
edited Jan 11 at 18:35
Bernard
168k771195
asked Jan 11 at 18:27
SamuelSamuel
537211
The following code:
documentclass[tikz,border=1mm]standalone
usepackagetikz
usetikzlibrarymatrix, positioning
tikzset
matrixstyle/.style=
matrix of nodes,
nodes=
draw
begindocument
begintikzpicture
matrix (M) [matrixstyle]
.1 & .1 \
.1 & .1 \
;
beginscope [local bounding box=MA, shift=(M.west), left = 0cm of M.west]
matrix (M11) [matrixstyle]
.1 & .0 \
.5 & .0 \
;
matrix (M12) [matrixstyle, right = 0cm of M11]
.2 & .0 \
.3 & .9 \
;
matrix (M21) [matrixstyle, below = 0cm of M11]
.0 & .0 \
.0 & .2 \
;
matrix (M22) [matrixstyle, right = 0cm of M21]
.3 & .0 \
.3 & .9 \
;
endscope
matrix (N) [matrixstyle, left = 1cm of MA.west]
.2 & .2 \
.2 & .2 \
;
endtikzpicture
enddocument
produces the following output:
The output should show six matrices. Four in the middle. And one matrix each on the right and left side of the matrix array. However, I did not manage to place the matrix M to the right of the matrix array MA. The error is probably in the following line
beginscope [local bounding box=MA, shift=(M.west), left = 0cm of M.west]
What is the right way to do it? Why does my approach not work?
tikz-pgf
tikz-pgf
edited Jan 11 at 18:35
Bernard
168k771195
asked Jan 11 at 18:27
SamuelSamuel
537211
edited Jan 11 at 18:35
Bernard
168k771195
asked Jan 11 at 18:27
SamuelSamuel
537211
edited Jan 11 at 18:35
Bernard
168k771195
edited Jan 11 at 18:35
Bernard
168k771195
edited Jan 11 at 18:35
Bernard
168k771195
168k771195
asked Jan 11 at 18:27
SamuelSamuel
537211
asked Jan 11 at 18:27
SamuelSamuel
537211
asked Jan 11 at 18:27
SamuelSamuel
537211
537211
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
5
like this?
matrices you can consider as nodes, so their positioning is with positioning library is straightforward:
documentclass[tikz,border=1mm]standalone
usetikzlibrarymatrix, positioning
begindocument
begintikzpicture[
node distance = 1mm and 2mm,
every matrix/.style = matrix of nodes,
nodes=draw,
column sep=-pgflinewidth,
row sep=-pgflinewidth
]
matrix (m1)
.2 & .2 \
.2 & .2 \
;
matrix (m11) [above right=of m1.east]
.1 & .0 \
.5 & .0 \
;
matrix (m12) [right=of m11]
.1 & .1 \
.1 & .1 \
;
matrix (m21) [below right= of m1.east]
.0 & .0 \
.0 & .2 \
;
matrix (m22) [right = of m21]
.3 & .0 \
.3 & .9 \
;
matrix (m2) [right = of m1 -| m12.east]
.2 & .0 \
.3 & .9 \
;
endtikzpicture
enddocument
answered Jan 11 at 18:43
ZarkoZarko
123k865161
What doesright = of m1 -| m12.eastmean? Especially the-|part.
– Samuel
Jan 12 at 16:21
Is it possible to define the four matrices in the middle as a single object that can be moved and resized? I want to resize the four matrices in the middle to have the same size as the matrices on the left and on the right.
– Samuel
Jan 12 at 16:27
@Samuel, this is new question in which you need to show (by sketch), how you like scale and shift a group of matrices. probably solution require a different solution as is shown in both answers. i think, that both answers perfectly solve the problem described in this question, therefore it is time, that you accept one of them.
– Zarko
Jan 13 at 0:21
add a comment |
6
Although not exactly the same, something very similar can be done with some tabular and without TiKZ.
documentclassarticle
newcommandmytab[4]%
begintabular[c]c
hline
#1\hline
#3\hline
endtabular
begindocument
mytab.2.2.2.2
begintabular[c]cccc
mytab.1.0.5.2 & mytab.1.1.1.1
\[.5cm]
mytab.0.0.0.2 & mytab.3.0.3.9
endtabular
mytab.2.0.3.9
enddocument
EDIT: or even better with ytableau package
documentclassarticle
usepackageytableau
newcommandmytab[4]%
beginytableau
#1\
#3\
endytableau
begindocument
ytableausetupcentertableaux
mytab.2.2.2.2
begintabular[c]cccc
mytab.1.0.5.2 & mytab.1.1.1.1
\[.5cm]
mytab.0.0.0.2 & mytab.3.0.3.9
endtabular
mytab.2.0.3.9
enddocument
answered Jan 11 at 19:22
IgnasiIgnasi
92.7k4166308
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
5
like this?
matrices you can consider as nodes, so their positioning is with positioning library is straightforward:
documentclass[tikz,border=1mm]standalone
usetikzlibrarymatrix, positioning
begindocument
begintikzpicture[
node distance = 1mm and 2mm,
every matrix/.style = matrix of nodes,
nodes=draw,
column sep=-pgflinewidth,
row sep=-pgflinewidth
]
matrix (m1)
.2 & .2 \
.2 & .2 \
;
matrix (m11) [above right=of m1.east]
.1 & .0 \
.5 & .0 \
;
matrix (m12) [right=of m11]
.1 & .1 \
.1 & .1 \
;
matrix (m21) [below right= of m1.east]
.0 & .0 \
.0 & .2 \
;
matrix (m22) [right = of m21]
.3 & .0 \
.3 & .9 \
;
matrix (m2) [right = of m1 -| m12.east]
.2 & .0 \
.3 & .9 \
;
endtikzpicture
enddocument
answered Jan 11 at 18:43
ZarkoZarko
123k865161
What doesright = of m1 -| m12.eastmean? Especially the-|part.
– Samuel
Jan 12 at 16:21
Is it possible to define the four matrices in the middle as a single object that can be moved and resized? I want to resize the four matrices in the middle to have the same size as the matrices on the left and on the right.
– Samuel
Jan 12 at 16:27
@Samuel, this is new question in which you need to show (by sketch), how you like scale and shift a group of matrices. probably solution require a different solution as is shown in both answers. i think, that both answers perfectly solve the problem described in this question, therefore it is time, that you accept one of them.
– Zarko
Jan 13 at 0:21
add a comment |
5
like this?
matrices you can consider as nodes, so their positioning is with positioning library is straightforward:
documentclass[tikz,border=1mm]standalone
usetikzlibrarymatrix, positioning
begindocument
begintikzpicture[
node distance = 1mm and 2mm,
every matrix/.style = matrix of nodes,
nodes=draw,
column sep=-pgflinewidth,
row sep=-pgflinewidth
]
matrix (m1)
.2 & .2 \
.2 & .2 \
;
matrix (m11) [above right=of m1.east]
.1 & .0 \
.5 & .0 \
;
matrix (m12) [right=of m11]
.1 & .1 \
.1 & .1 \
;
matrix (m21) [below right= of m1.east]
.0 & .0 \
.0 & .2 \
;
matrix (m22) [right = of m21]
.3 & .0 \
.3 & .9 \
;
matrix (m2) [right = of m1 -| m12.east]
.2 & .0 \
.3 & .9 \
;
endtikzpicture
enddocument
answered Jan 11 at 18:43
ZarkoZarko
123k865161
What doesright = of m1 -| m12.eastmean? Especially the-|part.
– Samuel
Jan 12 at 16:21
Is it possible to define the four matrices in the middle as a single object that can be moved and resized? I want to resize the four matrices in the middle to have the same size as the matrices on the left and on the right.
– Samuel
Jan 12 at 16:27
@Samuel, this is new question in which you need to show (by sketch), how you like scale and shift a group of matrices. probably solution require a different solution as is shown in both answers. i think, that both answers perfectly solve the problem described in this question, therefore it is time, that you accept one of them.
– Zarko
Jan 13 at 0:21
add a comment |
5
5
5
like this?
matrices you can consider as nodes, so their positioning is with positioning library is straightforward:
documentclass[tikz,border=1mm]standalone
usetikzlibrarymatrix, positioning
begindocument
begintikzpicture[
node distance = 1mm and 2mm,
every matrix/.style = matrix of nodes,
nodes=draw,
column sep=-pgflinewidth,
row sep=-pgflinewidth
]
matrix (m1)
.2 & .2 \
.2 & .2 \
;
matrix (m11) [above right=of m1.east]
.1 & .0 \
.5 & .0 \
;
matrix (m12) [right=of m11]
.1 & .1 \
.1 & .1 \
;
matrix (m21) [below right= of m1.east]
.0 & .0 \
.0 & .2 \
;
matrix (m22) [right = of m21]
.3 & .0 \
.3 & .9 \
;
matrix (m2) [right = of m1 -| m12.east]
.2 & .0 \
.3 & .9 \
;
endtikzpicture
enddocument
answered Jan 11 at 18:43
ZarkoZarko
123k865161
like this?
matrices you can consider as nodes, so their positioning is with positioning library is straightforward:
documentclass[tikz,border=1mm]standalone
usetikzlibrarymatrix, positioning
begindocument
begintikzpicture[
node distance = 1mm and 2mm,
every matrix/.style = matrix of nodes,
nodes=draw,
column sep=-pgflinewidth,
row sep=-pgflinewidth
]
matrix (m1)
.2 & .2 \
.2 & .2 \
;
matrix (m11) [above right=of m1.east]
.1 & .0 \
.5 & .0 \
;
matrix (m12) [right=of m11]
.1 & .1 \
.1 & .1 \
;
matrix (m21) [below right= of m1.east]
.0 & .0 \
.0 & .2 \
;
matrix (m22) [right = of m21]
.3 & .0 \
.3 & .9 \
;
matrix (m2) [right = of m1 -| m12.east]
.2 & .0 \
.3 & .9 \
;
endtikzpicture
enddocument
answered Jan 11 at 18:43
ZarkoZarko
123k865161
edited Jan 11 at 19:00
answered Jan 11 at 18:43
ZarkoZarko
123k865161
answered Jan 11 at 18:43
ZarkoZarko
123k865161
answered Jan 11 at 18:43
ZarkoZarko
123k865161
123k865161
What doesright = of m1 -| m12.eastmean? Especially the-|part.
– Samuel
Jan 12 at 16:21
Is it possible to define the four matrices in the middle as a single object that can be moved and resized? I want to resize the four matrices in the middle to have the same size as the matrices on the left and on the right.
– Samuel
Jan 12 at 16:27
@Samuel, this is new question in which you need to show (by sketch), how you like scale and shift a group of matrices. probably solution require a different solution as is shown in both answers. i think, that both answers perfectly solve the problem described in this question, therefore it is time, that you accept one of them.
– Zarko
Jan 13 at 0:21
add a comment |
What doesright = of m1 -| m12.eastmean? Especially the-|part.
– Samuel
Jan 12 at 16:21
Is it possible to define the four matrices in the middle as a single object that can be moved and resized? I want to resize the four matrices in the middle to have the same size as the matrices on the left and on the right.
– Samuel
Jan 12 at 16:27
@Samuel, this is new question in which you need to show (by sketch), how you like scale and shift a group of matrices. probably solution require a different solution as is shown in both answers. i think, that both answers perfectly solve the problem described in this question, therefore it is time, that you accept one of them.
– Zarko
Jan 13 at 0:21
What does
right = of m1 -| m12.east mean? Especially the -| part.– Samuel
Jan 12 at 16:21
What does
right = of m1 -| m12.east mean? Especially the -| part.– Samuel
Jan 12 at 16:21
Is it possible to define the four matrices in the middle as a single object that can be moved and resized? I want to resize the four matrices in the middle to have the same size as the matrices on the left and on the right.
– Samuel
Jan 12 at 16:27
Is it possible to define the four matrices in the middle as a single object that can be moved and resized? I want to resize the four matrices in the middle to have the same size as the matrices on the left and on the right.
– Samuel
Jan 12 at 16:27
@Samuel, this is new question in which you need to show (by sketch), how you like scale and shift a group of matrices. probably solution require a different solution as is shown in both answers. i think, that both answers perfectly solve the problem described in this question, therefore it is time, that you accept one of them.
– Zarko
Jan 13 at 0:21
@Samuel, this is new question in which you need to show (by sketch), how you like scale and shift a group of matrices. probably solution require a different solution as is shown in both answers. i think, that both answers perfectly solve the problem described in this question, therefore it is time, that you accept one of them.
– Zarko
Jan 13 at 0:21
add a comment |
6
Although not exactly the same, something very similar can be done with some tabular and without TiKZ.
documentclassarticle
newcommandmytab[4]%
begintabular[c]c
hline
#1\hline
#3\hline
endtabular
begindocument
mytab.2.2.2.2
begintabular[c]cccc
mytab.1.0.5.2 & mytab.1.1.1.1
\[.5cm]
mytab.0.0.0.2 & mytab.3.0.3.9
endtabular
mytab.2.0.3.9
enddocument
EDIT: or even better with ytableau package
documentclassarticle
usepackageytableau
newcommandmytab[4]%
beginytableau
#1\
#3\
endytableau
begindocument
ytableausetupcentertableaux
mytab.2.2.2.2
begintabular[c]cccc
mytab.1.0.5.2 & mytab.1.1.1.1
\[.5cm]
mytab.0.0.0.2 & mytab.3.0.3.9
endtabular
mytab.2.0.3.9
enddocument
answered Jan 11 at 19:22
IgnasiIgnasi
92.7k4166308
add a comment |
6
Although not exactly the same, something very similar can be done with some tabular and without TiKZ.
documentclassarticle
newcommandmytab[4]%
begintabular[c]c
hline
#1\hline
#3\hline
endtabular
begindocument
mytab.2.2.2.2
begintabular[c]cccc
mytab.1.0.5.2 & mytab.1.1.1.1
\[.5cm]
mytab.0.0.0.2 & mytab.3.0.3.9
endtabular
mytab.2.0.3.9
enddocument
EDIT: or even better with ytableau package
documentclassarticle
usepackageytableau
newcommandmytab[4]%
beginytableau
#1\
#3\
endytableau
begindocument
ytableausetupcentertableaux
mytab.2.2.2.2
begintabular[c]cccc
mytab.1.0.5.2 & mytab.1.1.1.1
\[.5cm]
mytab.0.0.0.2 & mytab.3.0.3.9
endtabular
mytab.2.0.3.9
enddocument
answered Jan 11 at 19:22
IgnasiIgnasi
92.7k4166308
add a comment |
6
6
6
Although not exactly the same, something very similar can be done with some tabular and without TiKZ.
documentclassarticle
newcommandmytab[4]%
begintabular[c]c
hline
#1\hline
#3\hline
endtabular
begindocument
mytab.2.2.2.2
begintabular[c]cccc
mytab.1.0.5.2 & mytab.1.1.1.1
\[.5cm]
mytab.0.0.0.2 & mytab.3.0.3.9
endtabular
mytab.2.0.3.9
enddocument
EDIT: or even better with ytableau package
documentclassarticle
usepackageytableau
newcommandmytab[4]%
beginytableau
#1\
#3\
endytableau
begindocument
ytableausetupcentertableaux
mytab.2.2.2.2
begintabular[c]cccc
mytab.1.0.5.2 & mytab.1.1.1.1
\[.5cm]
mytab.0.0.0.2 & mytab.3.0.3.9
endtabular
mytab.2.0.3.9
enddocument
answered Jan 11 at 19:22
IgnasiIgnasi
92.7k4166308
Although not exactly the same, something very similar can be done with some tabular and without TiKZ.
documentclassarticle
newcommandmytab[4]%
begintabular[c]c
hline
#1\hline
#3\hline
endtabular
begindocument
mytab.2.2.2.2
begintabular[c]cccc
mytab.1.0.5.2 & mytab.1.1.1.1
\[.5cm]
mytab.0.0.0.2 & mytab.3.0.3.9
endtabular
mytab.2.0.3.9
enddocument
EDIT: or even better with ytableau package
documentclassarticle
usepackageytableau
newcommandmytab[4]%
beginytableau
#1\
#3\
endytableau
begindocument
ytableausetupcentertableaux
mytab.2.2.2.2
begintabular[c]cccc
mytab.1.0.5.2 & mytab.1.1.1.1
\[.5cm]
mytab.0.0.0.2 & mytab.3.0.3.9
endtabular
mytab.2.0.3.9
enddocument
answered Jan 11 at 19:22
IgnasiIgnasi
92.7k4166308
edited Jan 11 at 19:44
answered Jan 11 at 19:22
IgnasiIgnasi
92.7k4166308
answered Jan 11 at 19:22
IgnasiIgnasi
92.7k4166308
answered Jan 11 at 19:22
IgnasiIgnasi
92.7k4166308
92.7k4166308
add a comment |
add a comment |
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